[10] degrees of freedom assignment
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This document contains examples of calculating degrees of freedom (DOF) for different mechanical systems using the formula DOF = 3(N - 1) - 2J, where N is the number of links and J is the number of joints. The examples show DOF values of 2, 2, 1, 0, and 3 for systems with varying numbers of links (N) and joints (J).
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[10] degrees of freedom assignment
- 1. 1. N = 7 J = 8 DOF = 3(N – 1) – 2J = 3(6) – 2(8) DOF = 2 2. N = 4 J = 3 H = 1 DOF = 3(N – 1) – 2J - H = 3(3) – 2(3) – 1 DOF = 2 3. N = 8 J = DOF = 3(N – 1) – 2J = 3(7) – 2(10) DOF = 1
- 2. 4. N = 5 J = DOF = 3(N – 1) – 2J = 3(4) – 2(6) DOF = 0 5. N = 8 J = DOF = 3(N – 1) – 2J = 3(7) – 2(9) DOF = 3