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CHAPTER 5
INDICES AND
LOGARITHMS
What is Indices?
Examples of numbers in index
form.
33
(3 cubed or 3 to the power of 3)
25
(2 to the power of 5)
3 and 5 are known as indices.
27=33, 3 is a base and 3 is an index
32=25, 2 is a base and 5 is an index
So , why we use indices?
Indices can make large numbers
much more manageable, as a
large number can be reduced to
just a base and an index.
Eg: 1,048,576
= 220
LAWS OF INDICES
Multiplication of indices with same base:
am  an = am + n
bm + n = bm  bn
Example:
x4 x3 = x4 + 3 = x7
y4y7 = y4+(-7) = y3 =
2x+3 = 2x  23 = 8(2x)
3y – 2 = 3y  32 =
3
y
1
 
2
1
3
3
y
Division of indices with same base:
am ÷ an = am  n
bm  n = bm ÷ bn
Example:
= c9  4 = c5
3x-2 =
4
9
c
c
5
2
p
12
p
4
3
p 5
2

3
p
3
1 
 3
p
3
1

2
3
3
x
Raising an index to a power
(am)n = amn
bmn = (bm)n
EXAMPLE:
(b4)3 = b43 = b12
(32)3 = 323 = 36
(2x)2 = 22x
(2y+1)3 = 23y + 3
32c = (3c)2
(ab)n = anbn
EXAMPLE:
(xy)3 = x3  y3
23  33 = 63
(ab)-2 = a-2  b-2
Law 5:
EXAMPLE:
 
n n
n
a a
b b

 
2 2
2
2 2
3 3

   
2 2
2
2
a a b
b a
b



 
   
2 2 2
2
5 2 2 4
2 5 25
5

  
Other properties of index
Zero index: a0 = 1, a  0
Negative index: a-n
Fractional index:
1
n
a

 
m m
n m n
n
a a a
 
1
n
n
a a

 
2 2
2
3
3
64 64 4
 
Law 5:
EXAMPLE:
 
n n
n
a a
b b

 
2 2
2
2 2
3 3

   
2 2
2
2
a a b
b a
b



 
   
2 2 2
2
5 2 2 4
2 5 25
5

  
Example
Solve
(a) 91 – x = 27
(b) 2p + 1  43 – p =
(c) Solve the simultaneous equation
2x.42y = 8
5x.25-y =
(d) 4x+3 – 4x+2 = 6
1
16
1
125
Solution
(a) x = -0.5
(b) p = 11
(c) x = -1, y = 1
(d) x = -1.5

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10163039.ppt

  • 2. Examples of numbers in index form. 33 (3 cubed or 3 to the power of 3) 25 (2 to the power of 5) 3 and 5 are known as indices. 27=33, 3 is a base and 3 is an index 32=25, 2 is a base and 5 is an index
  • 3. So , why we use indices? Indices can make large numbers much more manageable, as a large number can be reduced to just a base and an index. Eg: 1,048,576 = 220
  • 4. LAWS OF INDICES Multiplication of indices with same base: am  an = am + n bm + n = bm  bn Example: x4 x3 = x4 + 3 = x7 y4y7 = y4+(-7) = y3 = 2x+3 = 2x  23 = 8(2x) 3y – 2 = 3y  32 = 3 y 1   2 1 3 3 y
  • 5. Division of indices with same base: am ÷ an = am  n bm  n = bm ÷ bn Example: = c9  4 = c5 3x-2 = 4 9 c c 5 2 p 12 p 4 3 p 5 2  3 p 3 1   3 p 3 1  2 3 3 x
  • 6. Raising an index to a power (am)n = amn bmn = (bm)n EXAMPLE: (b4)3 = b43 = b12 (32)3 = 323 = 36 (2x)2 = 22x (2y+1)3 = 23y + 3 32c = (3c)2
  • 7. (ab)n = anbn EXAMPLE: (xy)3 = x3  y3 23  33 = 63 (ab)-2 = a-2  b-2
  • 8. Law 5: EXAMPLE:   n n n a a b b    2 2 2 2 2 3 3      2 2 2 2 a a b b a b          2 2 2 2 5 2 2 4 2 5 25 5    
  • 9. Other properties of index Zero index: a0 = 1, a  0 Negative index: a-n Fractional index: 1 n a    m m n m n n a a a   1 n n a a    2 2 2 3 3 64 64 4  
  • 10. Law 5: EXAMPLE:   n n n a a b b    2 2 2 2 2 3 3      2 2 2 2 a a b b a b          2 2 2 2 5 2 2 4 2 5 25 5    
  • 11. Example Solve (a) 91 – x = 27 (b) 2p + 1  43 – p = (c) Solve the simultaneous equation 2x.42y = 8 5x.25-y = (d) 4x+3 – 4x+2 = 6 1 16 1 125
  • 12. Solution (a) x = -0.5 (b) p = 11 (c) x = -1, y = 1 (d) x = -1.5