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Notes: Acceleration CW: Speed, Velocity and Acceleration H: Lesson 17 Acceleration
Acceleration February 16, 2009
Objectives Define acceleration and deceleration Describe the relationship between velocity and acceleration Calculate acceleration
Speed – Velocity -
Velocities can be combined. Rowing downstream at 16 km/h southeast on a river which is moving 10 km/h southeast results in a total velocity of 26 km/h southeast.
Rockets are launched in the same direction as the earth rotates.  Added boost of 1800 km/h!
Acceleration the rate of change in velocity
final velocity – initial velocity  time Acceleration
A =  V f  – V i   T Acceleration equation
A =    V   T    is  pronounced delta
Acceleration units km / h /h or km / h 2 m/s/s  m / s 2 km / h /s  kilometers per hour per hour meters per second per second kilometers per hour per second
Example problem A roller coaster’s speed at the top of a hill is 10 m/s. Two seconds later, it reaches the bottom of the hill with a speed of 26 m/s. What is the acceleration of the roller coaster? V i V f t
A =    V   T Acceleration equation
A =    V   T Final velocity = 26 m/s  Initial velocity = 10 m/s Time = 2 s A =  26 m/s – 10 m/s  =  16 m/s  = 8 m/s/s 2s  2s
Deceleration Negative acceleration
Example Problem At the end of a race, a bicycle is decelerated from a velocity of 12 m/s to a rest position in 30 seconds. What is the deceleration of this bicycle? V i V f t
Final velocity = 0 m/s Initial velocity = 12 m/s Time = 30 s
A =    V   T Acceleration equation
A =    V   T Final velocity = 0 m/s Initial velocity = 12 m/s Time = 30 s A =  0 m/s – 12 m/s  =  -12 m/s  = -0.4 m/s/s 30s  30s
 
If a rocket in space is moving at a constant velocity of 9.8 m/s and then uses its propulsion system to accelerate to 12.0 m/s during a 3.0 minute burn, what would be the acceleration of the rocket?  A =  V f  – V i t
If a rocket in space is moving at a constant velocity of  9.8 m/s  and then uses its propulsion system to accelerate to 12.0 m/s during a 3.0 minute burn, what would be the acceleration of the rocket? A =  V f  –  9.8 m/s t
If a rocket in space is moving at a constant velocity of 9.8 m/s and then uses its propulsion system to accelerate to  12.0 m/s  during a 3.0 minute burn, what would be the acceleration of the rocket?  A =  12.0 m/s  – 9.8 m/s t
If a rocket in space is moving at a constant velocity of 9.8 m/s and then uses its propulsion system to accelerate to 12.0 m/s during a  3.0 minute  burn, what would be the acceleration of the rocket?  A =  12.0 m/s – 9.8 m/s 3 min A = 0.73 m/s/min

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Acceleration

  • 1. Notes: Acceleration CW: Speed, Velocity and Acceleration H: Lesson 17 Acceleration
  • 3. Objectives Define acceleration and deceleration Describe the relationship between velocity and acceleration Calculate acceleration
  • 5. Velocities can be combined. Rowing downstream at 16 km/h southeast on a river which is moving 10 km/h southeast results in a total velocity of 26 km/h southeast.
  • 6. Rockets are launched in the same direction as the earth rotates. Added boost of 1800 km/h!
  • 7. Acceleration the rate of change in velocity
  • 8. final velocity – initial velocity time Acceleration
  • 9. A = V f – V i T Acceleration equation
  • 10. A =  V T  is pronounced delta
  • 11. Acceleration units km / h /h or km / h 2 m/s/s m / s 2 km / h /s kilometers per hour per hour meters per second per second kilometers per hour per second
  • 12. Example problem A roller coaster’s speed at the top of a hill is 10 m/s. Two seconds later, it reaches the bottom of the hill with a speed of 26 m/s. What is the acceleration of the roller coaster? V i V f t
  • 13. A =  V T Acceleration equation
  • 14. A =  V T Final velocity = 26 m/s Initial velocity = 10 m/s Time = 2 s A = 26 m/s – 10 m/s = 16 m/s = 8 m/s/s 2s 2s
  • 16. Example Problem At the end of a race, a bicycle is decelerated from a velocity of 12 m/s to a rest position in 30 seconds. What is the deceleration of this bicycle? V i V f t
  • 17. Final velocity = 0 m/s Initial velocity = 12 m/s Time = 30 s
  • 18. A =  V T Acceleration equation
  • 19. A =  V T Final velocity = 0 m/s Initial velocity = 12 m/s Time = 30 s A = 0 m/s – 12 m/s = -12 m/s = -0.4 m/s/s 30s 30s
  • 20.  
  • 21. If a rocket in space is moving at a constant velocity of 9.8 m/s and then uses its propulsion system to accelerate to 12.0 m/s during a 3.0 minute burn, what would be the acceleration of the rocket? A = V f – V i t
  • 22. If a rocket in space is moving at a constant velocity of 9.8 m/s and then uses its propulsion system to accelerate to 12.0 m/s during a 3.0 minute burn, what would be the acceleration of the rocket? A = V f – 9.8 m/s t
  • 23. If a rocket in space is moving at a constant velocity of 9.8 m/s and then uses its propulsion system to accelerate to 12.0 m/s during a 3.0 minute burn, what would be the acceleration of the rocket? A = 12.0 m/s – 9.8 m/s t
  • 24. If a rocket in space is moving at a constant velocity of 9.8 m/s and then uses its propulsion system to accelerate to 12.0 m/s during a 3.0 minute burn, what would be the acceleration of the rocket? A = 12.0 m/s – 9.8 m/s 3 min A = 0.73 m/s/min