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ABSTRACT: 
To analyze the motion of a bicyclist as described in the above problem. I will be making explicit relation 
of time with the given velocity-distance relation, and plotting the acceleration, velocity and distance 
against time. 
ANALYSIS: 
S=0 to 40 meters: 
 Velocity is dependent on distance as follows: 
V=0.25*s 
푑푠 
푑푡 
= 0.25 ∗ 푠, => 1 
0.25 
∫ 
푑푠 
푠 
푡 
푡0 
= ∫ 푑푡 
푠 
푠0 
t-t0 = 
1 
0.25 
(ln(s)-ln(s0)) 
s-s0 =0.25*(푒푡 − 푒푡0 
) =>> @s0=0, t0 
t=4*ln(s) 
S=0.25*푒푡 − 0.25 
푑푠 
푑푡 
= 0.25*et =V 
푑^2푠 
푑푡^2 
=0.25*et =a
 To get the time for bicyclist to travel 40 meters : 
t40=4*(ln(40)) 
t40=14.755 sec 
GRAPH: 
15 
10 
5 
0 
v-s 
0 10 20 30 40 50 
velocity 
distance 
Series1 
800000 
600000 
400000 
200000 
0 
v-t(s) 
-5 0 5 10 15 20 
-200000 
velocity 
time 
Series1
30 
25 
20 
15 
10 
5 
0 
a-s 
0 10 20 30 40 50 
700000 
600000 
500000 
400000 
300000 
200000 
100000 
0 
a-t(s) 
-5 0 5 10 15 20 
Observations: 
Here the distance of very infinitesimal range is being covered before the infinitesimal time interval. 
 The motion of this bicyclist seems to be recorded as a sudden motion due to which the time 
factor is defined at the velocity of 0.25m/s not when the distance was one meter. 
 This motion depicts the motion with variable velocity and acceleration at some time t and some 
distance s. 
 The motion is depicting a very rapid increase of velocity and acceleration which seems 
impossible for a human to ride or even a robot cannot run a cycle with this characteristics. 
 This motion can be valid for limited time and short distance, as then it could depict the 
motion of an Olympian cyclist competing in the event. 
acceleration 
distance 
Series1 
-100000 
acceleration 
time 
Series1
Conclusion: 
This data might be related to some Olympic game researcher or a hypothetical over plotting of the 
bicyclist who has a jerky start in the beginning of his ride. 
ANNEXURE: 
TABLE 1: 
s t(s) v(t) a(t) a(s) v(s) 
0 #NUM! #NUM! #NUM! 0 0 
1 0 0.25 0.25 0.625 0.25 
2 2.772589 4 4 1.25 0.5 
3 4.394449 20.25 20.25 1.875 0.75 
4 5.545177 64 64 2.5 1 
5 6.437752 156.25 156.25 3.125 1.25 
6 7.167038 324 324 3.75 1.5 
7 7.783641 600.25 600.25 4.375 1.75 
8 8.317766 1024 1024 5 2 
9 8.788898 1640.25 1640.25 5.625 2.25 
10 9.21034 2500 2500 6.25 2.5 
11 9.591581 3660.25 3660.25 6.875 2.75 
12 9.939627 5184 5184 7.5 3 
13 10.2598 7140.25 7140.25 8.125 3.25 
14 10.55623 9604 9604 8.75 3.5 
15 10.8322 12656.25 12656.25 9.375 3.75 
16 11.09035 16384 16384 10 4 
17 11.33285 20880.25 20880.25 10.625 4.25 
18 11.56149 26244 26244 11.25 4.5 
19 11.77776 32580.25 32580.25 11.875 4.75 
20 11.98293 40000 40000 12.5 5 
21 12.17809 48620.25 48620.25 13.125 5.25 
22 12.36417 58564 58564 13.75 5.5 
23 12.54198 69960.25 69960.25 14.375 5.75 
24 12.71222 82944 82944 15 6 
25 12.8755 97656.25 97656.25 15.625 6.25 
26 13.03239 114244 114244 16.25 6.5 
27 13.18335 132860.3 132860.3 16.875 6.75 
28 13.32882 153664 153664 17.5 7 
29 13.46918 176820.3 176820.3 18.125 7.25 
30 13.60479 202500 202500 18.75 7.5 
31 13.73595 230880.3 230880.3 19.375 7.75 
32 13.86294 262144 262144 20 8 
33 13.98603 296480.3 296480.3 20.625 8.25 
34 14.10544 334084 334084 21.25 8.5
35 14.22139 375156.3 375156.3 21.875 8.75 
36 14.33408 419904 419904 22.5 9 
37 14.44367 468540.3 468540.3 23.125 9.25 
38 14.55034 521284 521284 23.75 9.5 
39 14.65425 578360.3 578360.3 24.375 9.75 
40 14.75552 640000 640000 25 10

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Ass 1 f12-11 report engineering dynamics problems

  • 1. ABSTRACT: To analyze the motion of a bicyclist as described in the above problem. I will be making explicit relation of time with the given velocity-distance relation, and plotting the acceleration, velocity and distance against time. ANALYSIS: S=0 to 40 meters:  Velocity is dependent on distance as follows: V=0.25*s 푑푠 푑푡 = 0.25 ∗ 푠, => 1 0.25 ∫ 푑푠 푠 푡 푡0 = ∫ 푑푡 푠 푠0 t-t0 = 1 0.25 (ln(s)-ln(s0)) s-s0 =0.25*(푒푡 − 푒푡0 ) =>> @s0=0, t0 t=4*ln(s) S=0.25*푒푡 − 0.25 푑푠 푑푡 = 0.25*et =V 푑^2푠 푑푡^2 =0.25*et =a
  • 2.  To get the time for bicyclist to travel 40 meters : t40=4*(ln(40)) t40=14.755 sec GRAPH: 15 10 5 0 v-s 0 10 20 30 40 50 velocity distance Series1 800000 600000 400000 200000 0 v-t(s) -5 0 5 10 15 20 -200000 velocity time Series1
  • 3. 30 25 20 15 10 5 0 a-s 0 10 20 30 40 50 700000 600000 500000 400000 300000 200000 100000 0 a-t(s) -5 0 5 10 15 20 Observations: Here the distance of very infinitesimal range is being covered before the infinitesimal time interval.  The motion of this bicyclist seems to be recorded as a sudden motion due to which the time factor is defined at the velocity of 0.25m/s not when the distance was one meter.  This motion depicts the motion with variable velocity and acceleration at some time t and some distance s.  The motion is depicting a very rapid increase of velocity and acceleration which seems impossible for a human to ride or even a robot cannot run a cycle with this characteristics.  This motion can be valid for limited time and short distance, as then it could depict the motion of an Olympian cyclist competing in the event. acceleration distance Series1 -100000 acceleration time Series1
  • 4. Conclusion: This data might be related to some Olympic game researcher or a hypothetical over plotting of the bicyclist who has a jerky start in the beginning of his ride. ANNEXURE: TABLE 1: s t(s) v(t) a(t) a(s) v(s) 0 #NUM! #NUM! #NUM! 0 0 1 0 0.25 0.25 0.625 0.25 2 2.772589 4 4 1.25 0.5 3 4.394449 20.25 20.25 1.875 0.75 4 5.545177 64 64 2.5 1 5 6.437752 156.25 156.25 3.125 1.25 6 7.167038 324 324 3.75 1.5 7 7.783641 600.25 600.25 4.375 1.75 8 8.317766 1024 1024 5 2 9 8.788898 1640.25 1640.25 5.625 2.25 10 9.21034 2500 2500 6.25 2.5 11 9.591581 3660.25 3660.25 6.875 2.75 12 9.939627 5184 5184 7.5 3 13 10.2598 7140.25 7140.25 8.125 3.25 14 10.55623 9604 9604 8.75 3.5 15 10.8322 12656.25 12656.25 9.375 3.75 16 11.09035 16384 16384 10 4 17 11.33285 20880.25 20880.25 10.625 4.25 18 11.56149 26244 26244 11.25 4.5 19 11.77776 32580.25 32580.25 11.875 4.75 20 11.98293 40000 40000 12.5 5 21 12.17809 48620.25 48620.25 13.125 5.25 22 12.36417 58564 58564 13.75 5.5 23 12.54198 69960.25 69960.25 14.375 5.75 24 12.71222 82944 82944 15 6 25 12.8755 97656.25 97656.25 15.625 6.25 26 13.03239 114244 114244 16.25 6.5 27 13.18335 132860.3 132860.3 16.875 6.75 28 13.32882 153664 153664 17.5 7 29 13.46918 176820.3 176820.3 18.125 7.25 30 13.60479 202500 202500 18.75 7.5 31 13.73595 230880.3 230880.3 19.375 7.75 32 13.86294 262144 262144 20 8 33 13.98603 296480.3 296480.3 20.625 8.25 34 14.10544 334084 334084 21.25 8.5
  • 5. 35 14.22139 375156.3 375156.3 21.875 8.75 36 14.33408 419904 419904 22.5 9 37 14.44367 468540.3 468540.3 23.125 9.25 38 14.55034 521284 521284 23.75 9.5 39 14.65425 578360.3 578360.3 24.375 9.75 40 14.75552 640000 640000 25 10