C PROGRAMS - SARASWATHI RAMALINGAM

LAB EXERCISE 6 - 10
R SARASWATHI
SRI AKILANDESWARI WOMENS COLLEGE

Ex: 6. To Compute GCD and
LCM String Manipulation.
#include <stdio.h>
int gcd(int x, int y); //function prototype
int main()
{
int num1, num2, hcf, lcm;
printf("Enter two integer Values:n");
scanf("%d %d", &num1, &num2);
hcf = gcd(num1, num2);
printf("GCD: %d", hcf);
printf("nLCM: %d", (num1 * num2) / hcf);
return 0;
}
//recursive function
int gcd(int x, int y)
{
if (y == 0) //recursion termination condition
{
return x;
}
else
{
return gcd(y, x % y); //calls itself
}
}

Output
Enter two integer Values:
5
10
GCD: 5
LCM: 10

Ex:7 Operations on string such
as length, concatenation,
reverse, counting, and copy of a
string to another.

String Manipulation
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
void main()
{ char str1[20],str2[20];
int ch,i,j,length,count=0;
do { printf("tMENU");
printf("n------------------------------n");
printf("1:Find Length of String");
printf("n2:Find Reverse of String");
printf("n3:Concatenate Strings");
printf("n4:Copy String ");
printf("n5:Vowels Counting");
printf("n6:Exit");
printf("n------------------------------n");
printf("nEnter your choice: ");
scanf("%d",&ch); switch(ch)
{
case 1:
printf("Enter String: ");
scanf("%s",str1);
i=strlen(str1);
printf("Length of String : %dnn",i);
break;

String Manipulation
case 2:
printf("Enter String: ");
scanf("%s",str1);
length=strlen(str1);
for(i = length - 1; i >= 0; i--)
{
printf("%c", str1[i]);
}
printf(" : Reverse stringn");
break;
case 3:
printf("nEnter First String: ");
scanf("%s",str1);
printf("Enter Second string: ");
scanf("%s",str2);
strcat(str1,str2);
printf("String After Concatenation : %snn",str1);
break;

String Manipulation
case 4:
printf("Enter a String1: ");
scanf("%s",str1);
printf("Enter a String2: ");
scanf("%s",str2);
printf("nString Before
Copied:nString1="%s",String2="%s"n",str1,str2);
strcpy(str2,str1);
printf("-----------------------------------------------n");
printf(""We are copying string String1 to String2" n");
printf("-----------------------------------------------n");
printf("String After
Copied:nString1="%s",String2="%s"nn",str1,str2);
break;

case 5:
printf("nEnter a String:[without space]t");
scanf("%s", str1);
length = strlen(str1);
for(i = 0; i < length; i++)
{
if(str1[i] == 'a' || str1[i] == 'e' || str1[i] == 'i' || str1[i] == 'o' || str1[i]
== 'u' || str1[i] == 'A' || str1[i] == 'E' || str1[i] == 'I'
|| str1[i] == 'O' || str1[i] == 'U')
count++;
}
printf("Total Vowels:%d n",count);
break;
case 6:
exit(0);
break;
default:
printf("Invalid Input. Please Enter valid Input.nn ");
} }
while(ch!=6);}

Output
MENU
------------------------------
1:Find Length of String
2:Find Reverse of String
3:Concatenate Strings
4:Copy String
5:Vowels Counting
6:Exit
------------------------------
Enter your choice: 1
Enter String: Structure
Length of String : 9

MENU
------------------------------
4:Copy String
5:Vowels Counting
6:Exit
------------------------------
Enter String: union
noinu : Reverse string
MENU
------------------------------
4:Copy String
5:Vowels Counting
6:Exit
------------------------------
Enter First String: Pointer
Enter Second string: Adree ss
String After Concatenation : PointerAdress

MENU
------------------------------
4:Copy String
5:Vowels Counting
6:Exit
------------------------------
Enter a String:[without space] Variables
Total Vowels:4
MENU
------------------------------
4:Copy String
5:Vowels Counting
6:Exit
------------------------------

Ex:8 Matrix Addition,
Subtraction, Multiplication,
Transpose of n x m matrices.

Matrix Manipulation
#include<stdio.h>
void main()
{
int r1,r2,c1,c2,i,j,k;
int m1[15][15],m2[15][15],a[15][15],s[15][15],m[15][15],t[15][15];
printf("ntt MATRIX MANIPULATION ");
printf("ntt ******************** ");
printf("n Enter the no.of rows and columns for matrix 1: ");
printf("n rows:");
scanf("%d",&r1);
printf("n columns:");
scanf("%d",&c1);
printf("Enter the values of martix 1: n");
for(i=1;i<=r1;i++)
for(j=1;j<=c1;j++)
scanf("%d",&m1[i][j]);
printf("n Enter the rows and columns of matrix 2: ");
printf("n rows:");
scanf("%d",&r2);
printf("columns:");
scanf("%d",&c2);

Matrix Manipulation
printf("n Enter the values of matrix 2: n");
for(i=1;i<=r2;i++)
for(j=1;j<=c2;j++)
scanf("%d",&m2[i][j]);
printf("n MATRIX ADDITION ");
printf("n --------------- n");
if(r1==r2&&c1==c2)
{
for(i=1;i<=r1;i++)
{
for(j=1;j<=c1;j++)
{
a[i][j]=m1[i][j]+m2[i][j];
printf("t%d",a[i][j]);
}
printf("n");
}}
else
printf("n matrix addition is not possible");
printf("n MATRIX SUBTRACTION");
printf("n ------------------ n");

Matrix Manipulation
if(r1==r2&&c1==c2)
{ for(i=1;i<=r1;i++)
{ for(j=1;j<=c1;j++)
{
s[i][j]=m1[i][j]-m2[i][j];
printf("t%d",s[i][j]);
}
printf("n");
}}
else
printf("nmatrix subtraction is not possible");
printf("n MATRIX MULTIPLICATIONS");
printf("n ---------------------- n");
if(r2==c1)
{
for(i=1;i<=r1;i++)
{
printf("n");
for(j=1;j<=c2;j++)
{
m[i][j]=0;
for(k=1;k<=r2;k++)
m[i][j]=m[i][j]+(m1[i][k]*m2[k][j]);
}}}

Matrix Manipulation
else
printf("n multiplication is not possible");
for(i=1;i<=r1;i++)
{
for(j=1;j<=c2;j++)
printf("t%d",m[i][j]);
printf("n");
}
printf("nTRANSPOSE OF MATRIXn");
printf("n ---------------------- n");
for(i=1;i<=r1;i++)
{
for(j=1;j<=c1;j++)
t[i][j]=m1[j][i];
}
for(i=1;i<=c1;i++)
{
for(j=1;j<=r1;j++)
printf("t %d",t[i][j]);
printf("n");
}
getch();
}

Output
MATRIX MANIPULATION
********************
Enter the no.of rows and columns for matrix 1:
rows:3
columns:3
Enter the values of martix 1:
2 4 6 8 10 12 14 16 18
Enter the rows and columns of matrix 2:
rows:3
columns:3
Enter the values of matrix 2:
3 6 9 12 15 18 21 24 27

MATRIX ADDITION
--------------------------
5 10 15
20 25 30
35 40 45
MATRIX SUBTRACTION
------------------------------
-1 -2 -3
-4 -5 -6
-7 -8 -9
MATRIX MULTIPLICATIONS
--------------------------------
180 216 252
396 486 576
612 756 900
TRANSPOSE OF MATRIX
2 8 14
4 10 16
6 12 18

Ex: 9. Inverse of a square
matrix.
#include<stdio.h>
int main(){
int a[3][3],i,j;
float determinant=0;
printf("Enter the 9 elements of matrix[Transpose of 3X3 Matrix]: ");
for(i=0;i<3;i++)
for(j=0;j<3;j++)
scanf("%d",&a[i][j]);
printf("nThe matrix isn");
for(i=0;i<3;i++){
printf("n");
for(j=0;j<3;j++)
printf("%dt",a[i][j]);
}
for(i=0;i<3;i++)
determinant = determinant + (a[0][i]*(a[1][(i+1)%3]*a[2][(i+2)%3] - a[1][(i+2)%3]*a[2][(i+1)%3]));
printf("nInverse of matrix is: nn");
for(i=0;i<3;i++){
for(j=0;j<3;j++)
printf("%.2ft",((a[(i+1)%3][(j+1)%3] * a[(i+2)%3][(j+2)%3]) - (a[(i+1)%3][(j+2)%3]*a[(i+2)%3][(j+1)%3]))/
determinant);

printf("nInverse of matrix is: nn");
for(i=0;i<3;i++){
for(j=0;j<3;j++)
printf("%.2ft",((a[(i+1)%3][(j+1)%3]
* a[(i+2)%3][(j+2)%3]) -
(a[(i+1)%3][(j+2)%3]*a[(i+2)%3][(j+1)%3]))/
determinant);
printf("n");
}
return 0;
}

Output
Enter the 9 elements of matrix: 3
5
2
1
5
8
3
9
2
The matrix is
3 5 2
1 5 8
3 9 2
Inverse of matrix is:
0.70 -0.25 0.07
-0.09 -0.00 0.14
-0.34 0.25 -0.11

Ex: 10. Binary Search
#include <stdio.h>
int main()
{
int c, first, last, middle, n, search, array[100];
printf("Enter number of elementsn");
scanf("%d", &n);
printf("Enter %d unique integersn", n);
for (c = 0; c < n; c++)
scanf("%d", &array[c]);
printf("Enter value to findn");
scanf("%d", &search);
first = 0;
last = n - 1;
middle = (first+last)/2;
while (first <= last) {

if (array[middle] < search)
first = middle + 1;
else if (array[middle] == search) {
printf("%d found at location
%d.n", search, middle+1);
break;
}
else
last = middle - 1;
middle = (first + last)/2;
}
if (first > last)
printf("Not found! %d isn't present in the
list.n", search);
return 0;
}

Output
Enter number of elements
5
Enter 5 unique integers
8
6
4
3
2
Enter value to find
4
found at location 3
Enter number of elements
5
Enter 5 integers
2
3
4
5
6
Enter value to find
8
Not found! 8 isn't present in the list

C PROGRAMS - SARASWATHI RAMALINGAM

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