Exercice 22
    (a) a + b + c + a + b − c = 2a + 2b + c − c = 2a + 2b = 2(a + b)
    (b) 2x + 3y + 3x − 2y = 2x + 3x + 3y − 2y = 5x + y
    (c) −6x + 9x − 10y − 20y = 3x − 30y = 3(x − 10y)
    (d) 4x 2 − 4 + 3x 2 − 1 = 4x 3 + 3x 2 − 4 − 1 = 7x 2 − 5
    (e) 8ab − a2 + b2 − 8ab = 8ab − 8ab + b2 − a2 = b2 − a2 = (b − a)(b + a)
    (f) −∆t − (5∆t − 9) = −∆t − 5∆t + 9 = −6∆t + 9 = −3(2∆t − 3)
    (g) 12AL −(−3AS −12AT ) = 12AL +3AS +12AT = 3(4AL +AS +4AT )
    (h) −[16x −(−16x −1)] = −[16x +16x +1] = −[32x +1] = −32x −1
    (i) 1 − (θ − γ − 1) = 1 − θ + γ + 1 = 2 − θ + γ = γ − θ + 2
    (j)

              (3x 0 2 − 4x 0 ) − (12x 0 − x0 3 ) = 3x 0 2 − 4x 0 − 12x 0 + x0 3
               = x0 3 + 3x 0 2 − 16x 0 = x0 (x0 2 + 3x 0 − 16)

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Ch02 22

  • 1. Exercice 22 (a) a + b + c + a + b − c = 2a + 2b + c − c = 2a + 2b = 2(a + b) (b) 2x + 3y + 3x − 2y = 2x + 3x + 3y − 2y = 5x + y (c) −6x + 9x − 10y − 20y = 3x − 30y = 3(x − 10y) (d) 4x 2 − 4 + 3x 2 − 1 = 4x 3 + 3x 2 − 4 − 1 = 7x 2 − 5 (e) 8ab − a2 + b2 − 8ab = 8ab − 8ab + b2 − a2 = b2 − a2 = (b − a)(b + a) (f) −∆t − (5∆t − 9) = −∆t − 5∆t + 9 = −6∆t + 9 = −3(2∆t − 3) (g) 12AL −(−3AS −12AT ) = 12AL +3AS +12AT = 3(4AL +AS +4AT ) (h) −[16x −(−16x −1)] = −[16x +16x +1] = −[32x +1] = −32x −1 (i) 1 − (θ − γ − 1) = 1 − θ + γ + 1 = 2 − θ + γ = γ − θ + 2 (j) (3x 0 2 − 4x 0 ) − (12x 0 − x0 3 ) = 3x 0 2 − 4x 0 − 12x 0 + x0 3 = x0 3 + 3x 0 2 − 16x 0 = x0 (x0 2 + 3x 0 − 16)