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Ch10 30
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Ch10 30
1.
Exercice 30
a 1 2 1 AB = 2a 2 4 4 − 2a − 1 4 a 2−a a−2 2a 4 a a + + = 2a − 4 4 − 2a 2a − 4 4 − 2a 4 4 2 a + + 2−a a−2 2−a a−2 2a − 4 0 1 0 = 2a − 4 2 − a = 0 0 1 2−a
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