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Chapter 14 Chemical Kinetics Chemistry, The Central Science , 11th edition Theodore L. Brown; H. Eugene LeMay, Jr.; Bruce E. Bursten and Catherine J. Murphy Donna Narsavage Heald Siena College Loudonville, NY    2009, Prentice Hall
Which expression correctly states the rate of reaction? N 2 ( g )   +  3 H 2 ( g )   2 NH 3 ( g )
Which expression correctly states the rate of reaction? N 2 ( g )   +  3 H 2 ( g )   2 NH 3 ( g )
What is the rate law for the reaction? Rate =  k [A][B] 2 Rate =  k [A][B] Rate =  k [A] 2 [B] Rate =  k [A] Rate =  k [B] 2.0 x 10 – 4 0.20 0.20 1.0 x 10 – 4 0.20 0.10 1.0  x  10 – 4 0.10 0.10 Initial Rate  M /s [B] [A] A  +  2 B   products
What is the rate law for the reaction? Rate =  k [A][B] 2 Rate =  k [A][B] Rate =  k [A] 2 [B] Rate =  k [A] Rate =  k [B] 2.0 x 10 – 4 0.20 0.20 1.0 x 10 – 4 0.20 0.10 1.0  x  10 – 4 0.10 0.10 Initial Rate  M /s [B] [A] A  +  2 B   products
What is the rate law for the reaction? Rate =  k [A][B] 2 Rate =  k [A][B] Rate =  k [A] 2 [B] Rate =  k [A] 2 [B] 4 Rate =  k [B] 8.0 x 10 – 4 0.20 0.20 4.0 x 10 – 4 0.20 0.10 1.0 x 10 – 4 0.10 0.10 Initial Rate  M /s [B] [A] 2 A  +  B   products
What is the rate law for the reaction? Rate =  k [A][B] 2 Rate =  k [A][B] Rate =  k [A] 2 [B] Rate =  k [A] 2 [B] 4 Rate =  k [B] 8.0 x 10 – 4 0.20 0.20 4.0 x 10 – 4 0.20 0.10 1.0 x 10 – 4 0.10 0.10 Initial Rate  M /s [B] [A] 2 A  +  B   products
What are the units of the rate constant for a reaction with a rate law of: M  s M 2  s M – 1  s – 1 M – 1  s – 2 M – 2  s – 1 Rate =  k [A][B]
What are the units of the rate constant for a reaction with a rate law of: M  s M 2  s M – 1  s – 1 M – 1  s – 2 M – 2  s – 1 Rate =  k [A][B]
If  t 1/2  = 500 s for a first-order reaction, how long will it take for the concentration of a reactant to decrease to 1/8 of its original value?  2 x 500 = 1000 s 3 x 500 = 1500 s 4 x 500 = 2000 s 5 x 500 = 2500 s 8 x 500 = 4000 s
If  t 1/2  = 500 s for a first-order reaction, how long will it take for the concentration of a reactant to decrease to 1/8 of its original value?  2 x 500 = 1000 s 3 x 500 = 1500 s 4 x 500 = 2000 s 5 x 500 = 2500 s 8 x 500 = 4000 s

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Ch12 questions II

  • 1. Chapter 14 Chemical Kinetics Chemistry, The Central Science , 11th edition Theodore L. Brown; H. Eugene LeMay, Jr.; Bruce E. Bursten and Catherine J. Murphy Donna Narsavage Heald Siena College Loudonville, NY  2009, Prentice Hall
  • 2. Which expression correctly states the rate of reaction? N 2 ( g ) + 3 H 2 ( g ) 2 NH 3 ( g )
  • 3. Which expression correctly states the rate of reaction? N 2 ( g ) + 3 H 2 ( g ) 2 NH 3 ( g )
  • 4. What is the rate law for the reaction? Rate = k [A][B] 2 Rate = k [A][B] Rate = k [A] 2 [B] Rate = k [A] Rate = k [B] 2.0 x 10 – 4 0.20 0.20 1.0 x 10 – 4 0.20 0.10 1.0 x 10 – 4 0.10 0.10 Initial Rate M /s [B] [A] A + 2 B products
  • 5. What is the rate law for the reaction? Rate = k [A][B] 2 Rate = k [A][B] Rate = k [A] 2 [B] Rate = k [A] Rate = k [B] 2.0 x 10 – 4 0.20 0.20 1.0 x 10 – 4 0.20 0.10 1.0 x 10 – 4 0.10 0.10 Initial Rate M /s [B] [A] A + 2 B products
  • 6. What is the rate law for the reaction? Rate = k [A][B] 2 Rate = k [A][B] Rate = k [A] 2 [B] Rate = k [A] 2 [B] 4 Rate = k [B] 8.0 x 10 – 4 0.20 0.20 4.0 x 10 – 4 0.20 0.10 1.0 x 10 – 4 0.10 0.10 Initial Rate M /s [B] [A] 2 A + B products
  • 7. What is the rate law for the reaction? Rate = k [A][B] 2 Rate = k [A][B] Rate = k [A] 2 [B] Rate = k [A] 2 [B] 4 Rate = k [B] 8.0 x 10 – 4 0.20 0.20 4.0 x 10 – 4 0.20 0.10 1.0 x 10 – 4 0.10 0.10 Initial Rate M /s [B] [A] 2 A + B products
  • 8. What are the units of the rate constant for a reaction with a rate law of: M s M 2 s M – 1 s – 1 M – 1 s – 2 M – 2 s – 1 Rate = k [A][B]
  • 9. What are the units of the rate constant for a reaction with a rate law of: M s M 2 s M – 1 s – 1 M – 1 s – 2 M – 2 s – 1 Rate = k [A][B]
  • 10. If t 1/2 = 500 s for a first-order reaction, how long will it take for the concentration of a reactant to decrease to 1/8 of its original value? 2 x 500 = 1000 s 3 x 500 = 1500 s 4 x 500 = 2000 s 5 x 500 = 2500 s 8 x 500 = 4000 s
  • 11. If t 1/2 = 500 s for a first-order reaction, how long will it take for the concentration of a reactant to decrease to 1/8 of its original value? 2 x 500 = 1000 s 3 x 500 = 1500 s 4 x 500 = 2000 s 5 x 500 = 2500 s 8 x 500 = 4000 s