Chapter 19
Chemical
Thermodynamics
First Law of Thermodynamics
• You will recall from Chapter 5 that
energy cannot be created nor
destroyed.
• Therefore, the total energy of the
universe is a constant.
• Energy can, however, be converted
from one form to another or transferred
from a system to the surroundings or
vice versa.
Spontaneous Processes
• Spontaneous processes
are those that can
proceed without any
outside intervention.
• The gas in vessel B will
spontaneously effuse into
vessel A, but once the
gas is in both vessels, it
will not spontaneously
return to vessel B.
Spontaneous Processes
Processes that are
spontaneous in one
direction are
nonspontaneous in
the reverse
direction.
Spontaneous Processes
• Processes that are spontaneous at one
temperature may be nonspontaneous at other
temperatures.
• Above 0 C it is spontaneous for ice to melt.
• Below 0 C the reverse process is spontaneous.
Reversible Processes
In a reversible
process the system
changes in such a
way that the system
and surroundings
can be put back in
their original states
by exactly reversing
the process.
Irreversible Processes
• Irreversible processes cannot be undone by
exactly reversing the change to the system.
• Spontaneous processes are irreversible.
Entropy
• Entropy (S) is a term coined by Rudolph
Clausius in the 19th century.
• Clausius was convinced of the
significance of the ratio of heat
delivered and the temperature at which
it is delivered, .
q
T
Entropy
• Entropy can be thought of as a measure
of the randomness of a system.
• It is related to the various modes of
motion in molecules.
Entropy
• Like total energy, E, and enthalpy, H,
entropy is a state function.
• Therefore,
S = Sfinal  Sinitial
Entropy
For a process occurring at constant
temperature (an isothermal process), the
change in entropy is equal to the heat that
would be transferred if the process were
reversible divided by the temperature:
S =
qrev
T
Second Law of Thermodynamics
The second law of thermodynamics
states that the entropy of the universe
increases for spontaneous processes,
and the entropy of the universe does
not change for reversible processes.
Second Law of Thermodynamics
In other words:
For reversible processes:
Suniv = Ssystem + Ssurroundings = 0
For irreversible processes:
Suniv = Ssystem + Ssurroundings > 0
Second Law of Thermodynamics
These last truths mean that as a result
of all spontaneous processes the
entropy of the universe increases.
Entropy on the Molecular Scale
• Ludwig Boltzmann described the concept of
entropy on the molecular level.
• Temperature is a measure of the average
kinetic energy of the molecules in a sample.
Entropy on the Molecular Scale
• Molecules exhibit several types of motion:
– Translational: Movement of the entire molecule from
one place to another.
– Vibrational: Periodic motion of atoms within a molecule.
– Rotational: Rotation of the molecule on about an axis or
rotation about  bonds.
Entropy on the Molecular Scale
• Boltzmann envisioned the motions of a sample of
molecules at a particular instant in time.
– This would be akin to taking a snapshot of all the
molecules.
• He referred to this sampling as a microstate of the
thermodynamic system.
Entropy on the Molecular Scale
• Each thermodynamic state has a specific number of
microstates, W, associated with it.
• Entropy is
S = k lnW
where k is the Boltzmann constant, 1.38  1023
J/K.
Entropy on the Molecular Scale
• The change in entropy for a process,
then, is
S = k lnWfinal  k lnWinitial
lnWfinal
lnWinitial
S = k ln
• Entropy increases with the number of
microstates in the system.
Entropy on the Molecular Scale
• The number of microstates and,
therefore, the entropy tends to increase
with increases in
– Temperature.
– Volume.
– The number of independently moving
molecules.
Entropy and Physical States
• Entropy increases with
the freedom of motion
of molecules.
• Therefore,
S(g) > S(l) > S(s)
Solutions
Generally, when
a solid is
dissolved in a
solvent, entropy
increases.
Entropy Changes
• In general, entropy
increases when
– Gases are formed from
liquids and solids;
– Liquids or solutions are
formed from solids;
– The number of gas
molecules increases;
– The number of moles
increases.
Third Law of Thermodynamics
The entropy of a pure crystalline
substance at absolute zero is 0.
Standard Entropies
• These are molar entropy
values of substances in
their standard states.
• Standard entropies tend
to increase with
increasing molar mass.
Standard Entropies
Larger and more complex molecules have
greater entropies.
Entropy Changes
Entropy changes for a reaction can be
estimated in a manner analogous to that by
which H is estimated:
S = nS(products) — mS(reactants)
where n and m are the coefficients in the
balanced chemical equation.
Entropy Changes in Surroundings
• Heat that flows into or out of the
system changes the entropy of the
surroundings.
• For an isothermal process:
Ssurr =
qsys
T
• At constant pressure, qsys is simply
H for the system.
Entropy Change in the Universe
• The universe is composed of the system
and the surroundings.
• Therefore,
Suniverse = Ssystem + Ssurroundings
• For spontaneous processes
Suniverse > 0
Entropy Change in the Universe
• Since Ssurroundings =
and qsystem = Hsystem
This becomes:
Suniverse = Ssystem +
Multiplying both sides by T, we get
TSuniverse = Hsystem  TSsystem
Hsystem
T
qsystem
T
Gibbs Free Energy
TSuniverse is defined as the Gibbs free
energy, G.
• When Suniverse is positive, G is
negative.
• Therefore, when G is negative, a
process is spontaneous.
Gibbs Free Energy
1. If G is negative, the
forward reaction is
spontaneous.
2. If G is 0, the system
is at equilibrium.
3. If G is positive, the
reaction is
spontaneous in the
reverse direction.
Standard Free Energy Changes
Analogous to standard enthalpies of
formation are standard free energies of
formation, G.
f
G = nG (products)  mG (reactants)
f f
where n and m are the stoichiometric
coefficients.
Free Energy Changes
At temperatures other than 25°C,
G° = H  TS
How does G change with temperature?
Free Energy and Temperature
• There are two parts to the free energy
equation:
 H— the enthalpy term
– TS — the entropy term
• The temperature dependence of free
energy, then comes from the entropy
term.
Free Energy and Temperature
Free Energy and Equilibrium
Under any conditions, standard or
nonstandard, the free energy change
can be found this way:
G = G + RT lnQ
(Under standard conditions, all concentrations are 1 M,
so Q = 1 and lnQ = 0; the last term drops out.)
Free Energy and Equilibrium
• At equilibrium, Q = K, and G = 0.
• The equation becomes
0 = G + RT lnK
• Rearranging, this becomes
G = RT lnK
or,
K = e
-G
RT
POP QUIZ !
POP QUIZ !
• How do cations tend to change the pH
when they are introduced in water ?
• How do anions tend to change the pH when
they are introduced in water ?
• What is the relationship between Ka and
Kb ? Justify by using the couple HF/F-
.
POP QUIZ !
POP QUIZ !

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Chap19_CHE1402_slides(1).ppt of coursecs

  • 2. First Law of Thermodynamics • You will recall from Chapter 5 that energy cannot be created nor destroyed. • Therefore, the total energy of the universe is a constant. • Energy can, however, be converted from one form to another or transferred from a system to the surroundings or vice versa.
  • 3. Spontaneous Processes • Spontaneous processes are those that can proceed without any outside intervention. • The gas in vessel B will spontaneously effuse into vessel A, but once the gas is in both vessels, it will not spontaneously return to vessel B.
  • 4. Spontaneous Processes Processes that are spontaneous in one direction are nonspontaneous in the reverse direction.
  • 5. Spontaneous Processes • Processes that are spontaneous at one temperature may be nonspontaneous at other temperatures. • Above 0 C it is spontaneous for ice to melt. • Below 0 C the reverse process is spontaneous.
  • 6. Reversible Processes In a reversible process the system changes in such a way that the system and surroundings can be put back in their original states by exactly reversing the process.
  • 7. Irreversible Processes • Irreversible processes cannot be undone by exactly reversing the change to the system. • Spontaneous processes are irreversible.
  • 8. Entropy • Entropy (S) is a term coined by Rudolph Clausius in the 19th century. • Clausius was convinced of the significance of the ratio of heat delivered and the temperature at which it is delivered, . q T
  • 9. Entropy • Entropy can be thought of as a measure of the randomness of a system. • It is related to the various modes of motion in molecules.
  • 10. Entropy • Like total energy, E, and enthalpy, H, entropy is a state function. • Therefore, S = Sfinal  Sinitial
  • 11. Entropy For a process occurring at constant temperature (an isothermal process), the change in entropy is equal to the heat that would be transferred if the process were reversible divided by the temperature: S = qrev T
  • 12. Second Law of Thermodynamics The second law of thermodynamics states that the entropy of the universe increases for spontaneous processes, and the entropy of the universe does not change for reversible processes.
  • 13. Second Law of Thermodynamics In other words: For reversible processes: Suniv = Ssystem + Ssurroundings = 0 For irreversible processes: Suniv = Ssystem + Ssurroundings > 0
  • 14. Second Law of Thermodynamics These last truths mean that as a result of all spontaneous processes the entropy of the universe increases.
  • 15. Entropy on the Molecular Scale • Ludwig Boltzmann described the concept of entropy on the molecular level. • Temperature is a measure of the average kinetic energy of the molecules in a sample.
  • 16. Entropy on the Molecular Scale • Molecules exhibit several types of motion: – Translational: Movement of the entire molecule from one place to another. – Vibrational: Periodic motion of atoms within a molecule. – Rotational: Rotation of the molecule on about an axis or rotation about  bonds.
  • 17. Entropy on the Molecular Scale • Boltzmann envisioned the motions of a sample of molecules at a particular instant in time. – This would be akin to taking a snapshot of all the molecules. • He referred to this sampling as a microstate of the thermodynamic system.
  • 18. Entropy on the Molecular Scale • Each thermodynamic state has a specific number of microstates, W, associated with it. • Entropy is S = k lnW where k is the Boltzmann constant, 1.38  1023 J/K.
  • 19. Entropy on the Molecular Scale • The change in entropy for a process, then, is S = k lnWfinal  k lnWinitial lnWfinal lnWinitial S = k ln • Entropy increases with the number of microstates in the system.
  • 20. Entropy on the Molecular Scale • The number of microstates and, therefore, the entropy tends to increase with increases in – Temperature. – Volume. – The number of independently moving molecules.
  • 21. Entropy and Physical States • Entropy increases with the freedom of motion of molecules. • Therefore, S(g) > S(l) > S(s)
  • 22. Solutions Generally, when a solid is dissolved in a solvent, entropy increases.
  • 23. Entropy Changes • In general, entropy increases when – Gases are formed from liquids and solids; – Liquids or solutions are formed from solids; – The number of gas molecules increases; – The number of moles increases.
  • 24. Third Law of Thermodynamics The entropy of a pure crystalline substance at absolute zero is 0.
  • 25. Standard Entropies • These are molar entropy values of substances in their standard states. • Standard entropies tend to increase with increasing molar mass.
  • 26. Standard Entropies Larger and more complex molecules have greater entropies.
  • 27. Entropy Changes Entropy changes for a reaction can be estimated in a manner analogous to that by which H is estimated: S = nS(products) — mS(reactants) where n and m are the coefficients in the balanced chemical equation.
  • 28. Entropy Changes in Surroundings • Heat that flows into or out of the system changes the entropy of the surroundings. • For an isothermal process: Ssurr = qsys T • At constant pressure, qsys is simply H for the system.
  • 29. Entropy Change in the Universe • The universe is composed of the system and the surroundings. • Therefore, Suniverse = Ssystem + Ssurroundings • For spontaneous processes Suniverse > 0
  • 30. Entropy Change in the Universe • Since Ssurroundings = and qsystem = Hsystem This becomes: Suniverse = Ssystem + Multiplying both sides by T, we get TSuniverse = Hsystem  TSsystem Hsystem T qsystem T
  • 31. Gibbs Free Energy TSuniverse is defined as the Gibbs free energy, G. • When Suniverse is positive, G is negative. • Therefore, when G is negative, a process is spontaneous.
  • 32. Gibbs Free Energy 1. If G is negative, the forward reaction is spontaneous. 2. If G is 0, the system is at equilibrium. 3. If G is positive, the reaction is spontaneous in the reverse direction.
  • 33. Standard Free Energy Changes Analogous to standard enthalpies of formation are standard free energies of formation, G. f G = nG (products)  mG (reactants) f f where n and m are the stoichiometric coefficients.
  • 34. Free Energy Changes At temperatures other than 25°C, G° = H  TS How does G change with temperature?
  • 35. Free Energy and Temperature • There are two parts to the free energy equation:  H— the enthalpy term – TS — the entropy term • The temperature dependence of free energy, then comes from the entropy term.
  • 36. Free Energy and Temperature
  • 37. Free Energy and Equilibrium Under any conditions, standard or nonstandard, the free energy change can be found this way: G = G + RT lnQ (Under standard conditions, all concentrations are 1 M, so Q = 1 and lnQ = 0; the last term drops out.)
  • 38. Free Energy and Equilibrium • At equilibrium, Q = K, and G = 0. • The equation becomes 0 = G + RT lnK • Rearranging, this becomes G = RT lnK or, K = e -G RT
  • 39. POP QUIZ ! POP QUIZ !
  • 40. • How do cations tend to change the pH when they are introduced in water ? • How do anions tend to change the pH when they are introduced in water ? • What is the relationship between Ka and Kb ? Justify by using the couple HF/F- . POP QUIZ ! POP QUIZ !

Editor's Notes