Chapter_14_-_Acids_and_Bases.ppt

Acids and Bases
Topics to be covered:
• Definitions of acids and bases;
• Bronsted’s conjugate acid-base pairs concept;
• Determination of [H3O+
], [OH-
], and pH for strong acids and
strong bases;
• Determination of [H3O+
], [OH-
], pH, Ka, or Kb, and percent
ionization for weak acids and weak bases;
• Predicting acid/base properties of salts (ionic compounds) and
oxides of metals and nonmetals;
• The effect of molecular structures and bond energy on the
strength of acids and bases.

Acids and Bases
• Arrhenius definition:
Acid: substance that increases [H3O+] in solution;
Base: substance that increases [OH-] in solution;
• Brnsted-Lowry definition:
Acid: reactant that donates proton in a reaction;
Base: reactant that accepts proton in a reaction;
• Lewis definition: - in the formation of covalent bonds,
Acid: one that accept electron-pairs
Base: one that donate electron-pairs

Strong and Weak Acids
• Strong acids ionize completely in aqueous solution:
• HCl(aq) + H2O  H3O+
(aq) + Cl-
(aq);
• H2SO4(aq) + H2O  H3O+
(aq) + HSO4
-
(aq);
• Weak acids ionize only partially in aqueous solution:
• HF(aq) + H2O ⇌ H3O+
(aq) + F-
(aq);
• HOCl(aq) + H2O ⇌ H3O+
(aq) + ClO-
(aq).

Complete Ionization of Hydrochloric Acid

Dissociations of Strong and Weak Acids

Strong and Weak Bases
• Strong bases ionize completely in aqueous solution:
NaOH(aq)  Na+
(aq) + OH-
(aq);
Ba(OH)2(aq)  Ba2+
(aq) + 2 OH-
(aq);
• Weak bases ionize only partially in aqueous solution:
NH3(aq) + H2O  NH4
+
(aq) + OH-
(aq);
PO4
3-
(aq) + H2O  HPO4
2-
(aq) + OH-
(aq)

Brønsted-Lowry: Conjugate Acids & Bases
• Consider the following equilibrium:
HA + B ⇌ BH+
+ A-
;
Acid1 Base2 Conjugate Conjugate
acid2 base1
• A-
is the conjugate base to acid HA;
HA & A-
are conjugate acid-base pair;
• BH+ is the conjugate acid to base B;
BH+ & B are also conjugate acid-base pair.

Brønsted-Lowry’s Acid-Base Reaction

Brønsted’s Conjugate Acid-Base Pairs

Examples of Conjugate Acid-Base Pairs
HNO3 – NO3
-
H2SO4 – HSO4
-
H3O+
– H2O
HF – F-
H3PO4 – H2PO4
-
CH3COOH – CH3COO-
H2PO4
-
– HPO4
2-
NH4
+
– NH3
H2O – OH-

Exercise #1: Conjugate Acids & Bases
Write the formulas of the conjugate bases for the
following acids:
(a) H2CO3 (b) HSO4
-
(c) Al(H2O)6
3+
(d) Cr(OH)3(H2O)3
(Answer: (a) HCO3-; (b) SO4
2-
; (c) Al(H2O)5(OH)2+
;
(d) Cr(OH)4(H2O)2
-
)

Exercise #2: Conjugate Acids and Bases
Write the formulas of the conjugate acids for the
following bases:
(a) NH3 (b) CO3
2-
(c) C5H5N
(d) Al(OH)3(H2O)3
(Answer: (a) NH4
+
; (b) HCO3
-
; (c) C5H5NH+
;
(d) Al(OH)2(H2O)4
+
)

Acid Strength and Ionization Constants
• For the ionization or dissociation equilibrium of an
acid in aqueous solution, such as:
HA(aq) + H2O  H3O+
(aq) + A-
(aq);
The ionization or dissociation constant is
expressed as follows:
The values of Ka indicate the relative strength of the
acids. Strong acids have very large Ka, while weak
acids have small Ka’s (Ka << 1)
[HA]
]
][A
O
[H -
3


a
K

Chapter_14_-_Acids_and_Bases.ppt

Relative Strength of Acids and Their
Conjugate Bases
Acids Conjugate Bases
Very Strong Very Weak
Strong Weak
Weak Strong
Very Weak Very Strong
______________________________
• Strong acids lose protons very readily  weak
conjugate bases;
• Weak acids do not lose protons very readily  strong
conjugate bases.

Relative Strength of Acids and Their Conjugate Bases

Acid-Base Properties of Water
• Auto-ionization of water:
2H2O  H3O+
(aq) + OH-
(aq)
Kw = [H3O+
][OH-
] = 1.0 x 10-14
at 25o
C
• Water ionizes to produce both H3O+
and OH-
, thus it
has both acid and base properties. Kw is called water
ionization constant.
• Pure water at 25o
C: [H3O+
] = [OH-
] = 1.0 x 10-7
M

Expressing Acidity in pH Scale
• pH = -log[H+
] (note: [H+
] = [H3O+
])
• pOH = -log[OH-
]
• pKw = -log(Kw); pKa = -log(Ka); pKb = -log(Kb)
• For water, Kw = [H3O+
][OH-
] = 1.0 x 10-14
• -log(Kw) = -log [H3O+
] + (-log[OH-
])
• pKw = pH + pOH = 14.00
• At 25o
C, pOH = 14 – pH

Acidity and pH Range
• Acidic solutions:
[H3O+
] > 1.0 x 10-7
M;
pH < 7;
• Basic solutions:
[OH-
] > 1.0 x 10-7
M or [H3O+
] < 1.0 x 10-7
M
pH > 7;
• Neutral solutions:
[H3O+
] = [OH-
] = 1.0 x 10-7
M; pH = 7.00

Relationship between acidity of solution and pH

[H3O+
] and pH of Strong Acids
• Strong acids like HCl and HClO4 ionize completely
in aqueous solution:
HCl(aq) + H2O  H3O+
(aq) + Cl-
(aq);
HClO4(aq) + H2O  H3O+
(aq) + ClO4
-
(aq);
• In solutions of strong monoprotic acids HA, such as
HCl and HClO4,
[H3O+
] = [HA]0
• For example, in 0.10 M HCl, [H3O+
] = 0.10 M, and
pH = -log(0.10) = 1.00

[OH-
] and pH of Strong Bases
• Like strong acids, strong bases also ionize completely in
aqueous solution.
• Examples: NaOH(aq)  Na+
(aq) + OH-
(aq);
Ba(OH)2(aq)  Ba2+
(aq) + 2 OH-
(aq);
• In a base solution such as 0.050 M NaOH,
[OH-
] = [NaOH]0 = 0.050 M;
pOH = -log(0.050 M) = 1.30; pH = 14.00 - 1.30 = 12.70
• In a base solution such as 0.050 M Ba(OH)2,
[OH-
] = 2 x [Ba(OH)2]0 = 0.10 M;
pOH = -log(0.10) = 1.00; pH = 14.00 - 1.00 = 13.00

[H3O+
] and pH of Weak Acids
• In weak acid solutions, [H3O+
] < [HA]0;
• [H3O+
] and pH can be calculated from the initial
concentration of the acid and its Ka value.
• For example, in 0.100 M acetic acid, CH3COOH,
with Ka = 1.8 x 10-5
, [H3O+
] and pH can be calculated
using the “ICE” table.

ICE Table for Acetic Acid
• Ionization: CH3CO2H + H2O  H3O+
+ CH3CO2
-
• 
• Initial [M] 0.100 0.00 0.00
• Change [M] -x +x +x
• Equilm. [M] (0.100 – x) x x
• 
5
-
2
3
2
3
3
10
x
1.8
)
-
0.100
(
COOH]
[CH
]
CO
][CH
O
[H





x
x
Ka

Calculating [H3O+
] from initial concentration
and Ka by approximation method.
• Solving for x in the expression for Ka:
2.873
)
10
x
log(1.34
-
pH
;
M
10
x
1.34
]
O
[H
;
10
x
1.34
10
x
1.8
and
;
10
x
1.8
)
10
x
8
(0.100)(1.
;
10
x
1.8
100
.
0
~
)
-
0.100
(
makes
This
0.10.
~
)
-
(0.10
and
0.100,
0.100)
10
x
(1.8
[HA]
10
x
1.8
)
-
0.100
(
H]
CO
[CH
]
CO
][CH
O
[H
3
-
3
-
3
3
-
6
-
6
-
5
-
2
5
-
2
2
5
-
0
5
-
2
2
3
2
3
3



















x
x
x
x
x
x
x
x
K
x
x
K
a
a

Calculation Percent Ionization
• We calculated that, in 0.10 M CH3COOH, the
concentration of acid that ionizes is 1.34 x 10-3 M.
• The percent ionization of 0.10 M acetic acid:
100
x
)
-
(0.100
100%
[HA]
[HA]
Ionization
%
initial
ionized
x
x



1.34%
100%
x
0.100
M
10
x
1.34
~
ionization
%
-3


Increase in Percent Ionization with Dilution
• Percent ionization of weak acid increases as the
dilution increases.
• For example, if [CH3COOH]initial = 0.0100 M
• [CH3COOH]ionized ~ 4.24 x 10-4
M (calculated using
approximation method);
4.24%
100
x
0.0100
10
x
4.24
ionization
Percent
-4



Percent Ionization Increases with Dilution
• At [CH3COOH]initial = 0.00100 M,
• [CH3COOH]ionized = 1.34 x 10-4 M (by approximation)
• The more we dilute the acid solution, the higher the
fraction of the acid that will ionize, which increases
the degree of ionization.
• Is this related to the Le Chatelier’s principle? Explain.
13.4%
100
x
0.00100
10
x
1.34
ionization
Percent
-4



Exercise #3: pH and Percent Ionization
1) Nitrous acid, HNO2, has Ka = 4.0 x 10-4
at 25 o
C.
Calculate the pH and percent ionization of HNO2 in
0.10 M solution of the acid.
(Answer: pH = 2.20; % ionization = 6.3%)
2) Chlorous acid, HOCl, has Ka = 3.5 x 10-8
at 25 o
C.
Calculate the pH and percent ionization of HOCl in
0.10 M solution of the acid.
(Answer: pH = 4.23; % ionization = 0.059%)

[OH-
] and pH of a Weak Base
• In a weak base, [OH-
] < [Base]0;
• [OH-
] and pH can be calculated from the initial
concentration of the base and its Kb value.
• For example, in 0.100 M ammonia, NH3, with Kb =
1.8 x 10-5
, [OH-
] and pH can be calculated using the
following “ICE” table.

ICE Table for the Ionization of Ammonia
• Ionization: NH3 + H2O  NH4
+
+ OH-
• 
• Initial [M] 0.100 0.00 0.00
• Change [M] -x +x +x
• Equilm. [M] (0.100 – x) x x
• 
5
2
3
-
4
10
x
1.8
)
100
.
0
(
]
[NH
]
OH
][
[NH 





x
x
Kb

Calculate [OH-
] from initial concentration and Kb
by approximation method.
• Solving for x in the expression for Kb:
11.127
pH
and
2.873,
pOH
M
10
x
1.34
]
OH
[
;
10
x
1.34
yields
which
,
10
x
1.8
)
10
x
8
(0.100)(1.
;
10
x
1.8
0.100
~
)
-
(0.100
makes
which
0.100,
~
)
-
(0.100
and
0.100,
0.100)
10
x
(1.8
[B]
10
x
1.8
)
100
.
0
(
]
[NH
]
OH
][
[NH
3
-
-
3
-
6
-
5
-
2
5
-
2
2
5
-
0
5
2
3
-
4















 

x
x
x
x
x
x
x
K
x
x
K
b
b

Exercise #4: pH of Strong and Weak Bases
1) Ethylamine, C2H5NH, has Kb = 5.6 x 10-4
. Calculate
the concentration of H3O+
in 0.10 M ethylamine
solution and the pH of the solution?
(Answer: [H3O+
] = 1.3 x 10-12
M; pH = 11.87)
2) Pyridine, C5H5N, has Kb = 1.7 x 10-9
. Calculate the
concentration of H3O+
in 0.020 M pyridine solution
and the pH of the solution?
(Answer: [H3O+
] = 1.7 x 10-9
M; pH = 8.77)

Polyprotic Acids
• Acids with more than one ionizable hydrogen ion, such as
H2SO3, H2SO4, H3PO4, H3C6H5O7, etc.
• Their hydrogen ionizes in stages, for example,
H3PO4(aq) + H2O ⇄ H3O+(aq) + H2PO4
-
(aq); Ka1 = 7.5 x 10-3
H2PO4
-
(aq) + H2O ⇄ H3O+(aq) + HPO4
2-
(aq); Ka2 = 6.2 x 10-8
HPO4
2-
(aq) + H2O ⇄ H3O+(aq) + PO4
3-
(aq); Ka3 = 4.8 x 10-13
Acid strength decreases in the order:
H3PO4 >> H2PO4
-
>> HPO4
2-
;
pH of solution is determined mainly by ionization of H3PO4

Exercise #5: pH of H2SO4
1) Calculate the concentrations of H2SO4, H3O+
,
HSO4
-
, and SO4
2-
, in 0.10 M H2SO4 solution. What
is the pH of the solution? (H2SO4 is a strong acid
and HSO4
-
has Ka = 1.2 x 10-2
)
(Answer: [H2SO4] = 0.0 M; [H3O+
] = 0.11 M;
[HSO4
-
] = 0.090 M; [SO4
2-
] = 0.0098 M;
pH = 0.96]

Salts and Their Corresponding Acids & Bases
• Acids and bases from which each of the following
salts are produced.
AcidsBases
• NaClO4
• KNO3
• (NH4)2SO4
• NaC2H3O2
• BaCl2
• Na3PO4

Acid-Base Properties of Salt Solutions
• Soluble salts dissociate completely when
dissolved in water;
• Ions produced may react with water that
release H3O+ and makes the solution acidic, or
produces OH- and makes the solution basic.

Acid-Base Properties of Salt Solutions
• The acid-base property of a salt solution depends on
whether the compound is a product of:
1. Strong acid-strong base reaction: produces neutral salt
2. Strong acid-weak base reaction: produces acidic salt
3. Strong base-weak acid reaction: produces basic salt
4. Weak acid-weak base reaction: produces salt that is
either acidic or basic, depending on the relative strength
of the acid and the base.

Types of Salts and Their Solutions
• Salts of Strong Acid-Strong Base Reactions:
NaCl, NaNO3, KBr, etc.; solutions are neutral
• Salts of Weak Acid-Strong Base Reactions:
NaF, NaNO2, NaC2H3O2, etc.; solutions are basic
• Salts of Strong Acid-Weak Base Reactions:
NH4Cl, NH4NO3, (CH3)2NH2Cl, C5H5NHCl;
Solutions of these salts are acidic
• Salts of Weak Acid-Weak Base Reactions:
NH4C2H3O2, NH4CN, NH4NO2, etc..
These compounds can be acidic, basic, or neutral, which
depends on the relative strength of the acid and the base.

Salts of Strong Acid-Strong Base Reactions
• Dissociation and reaction of a neutral salt:
NaCl(aq)  Na+(aq) + Cl-
(aq);
Na+(aq) + H2O  NR
Cl-
(aq) + H2O  NR
(The concentrations of H3O+ and OH-
in NaCl solution are
the same as in pure water  solution is neutral.)

Salts of Weak Acid-Strong Base Reactions:
• Dissociation and reaction of a basic salt:
NaNO2(aq)  Na+(aq) + NO2
-
(aq);
Na+(aq) + H2O  NR
NO2
-
(aq) + H2O  HNO2(aq) + OH-
(aq)
(The reaction of NO2
-
with water causes [OH-
] > [H3O+]
and the solution becomes basic.)

Salts of Strong Acid-Weak Base Reactions
• Dissociation and reaction of an acidic salt:
NH4NO3(aq)  NH4
+(aq) + NO3
-
(aq);
NH4
+(aq) + H2O  NH3(aq) + H3O+(aq);
NO3
-
(aq) + H2O  NR;
• (The reaction of NH4
+ with water causes [H3O+] > [OH-
], and
the solution becomes acidic.)

Salts of Weak Acid-Weak Base Reactions
• Salts produced by reactions of weak acids and weak
bases can be neutral, acidic, or basic, depending on
the relative magnitude of the Ka of the weak acid and
the Kb of the weak base.
• If Ka ~ Kb, salts are neutral; example: NH4C2H3O2
• If Ka > Kb, salts are acidic; example: NH4NO2
• If Ka < Kb, salts are basic; example: NaC2H3O2

Predicting Acid-Base Property of Salts
• Consider a solution containing NH4C2H3O2
• NH4C2H3O2(aq)  NH4
+
(aq) + C2H3O2
-
(aq);
• NH4
+
(aq) + H2O  H3O+
(aq) + NH3(aq); Ka = 5.6 x 10-10
• C2H3O2
-
(aq) + H2O  HC2H3O2(aq) + OH-
(aq); Kb = 5.6 x 10-10
• Ka = Kb = 5.6 x 10-10,  NH4C2H3O2 is neutral

Predicting Acid-Base Property of Salts
• Consider a solution containing (NH4)2SO4
• (NH4)2SO4(aq)  2NH4
+
(aq) + SO4
2-(aq);
• NH4
+
(aq) + H2O  H3O+
(aq) + NH3(aq); Ka = 5.6 x 10-10
• SO4
2-(aq) + H2O  HSO4
-(aq) + OH-(aq); Kb = 8.3 x 10-13
• Ka > Kb  (NH4)2SO4 is acidic;

Predicting Acid-Base Characteristics of Salts
• Now consider a solution containing NH4CN.
• NH4CN(aq)  NH4
+
(aq) + CN-
(aq);
• NH4
+
(aq) + H2O  H3O+
(aq) + NH3(aq); Ka = 5.6 x 10-10
• CN-
(aq) + H2O  HCN(aq) + OH-(aq); Kb = 1.6 x 10-5
• Kb > Ka  NH4CN is basic

Effect of Structure on Acid-Base Properties
• Relative bond strength:
H─F > H─Cl > H─Br > H─I
• Relative acid strength:
HI > HBr > HCl > HF
• (HF is the only weak acid in this group)
• Relative acid strength:
H2Te > H2Se > H2S > H2O (all very weak acids)

Effect of Structure on Acid-Base Properties
• Electronegativity Effect on Relative Strength of Oxo-Acids:
• Same central atom, but different numbers of oxygen atoms:
HOClO3 > HOClO2 > HOClO > HOCl;
• Same number of oxygen, but different central atoms:
1. Trend of electronegativity: F > Cl > Br > I;
2. Trend of relative acidity: HOF > HClO > HOBr > HOI;
3. Relative acidity: CF3COOH > CCl3COOH > CH3COOH
4. Trend of electronegativity: Cl > S > P > Si
5. Relative acidity: HClO4 > H2SO4 > H3PO4 > H4SiO4

Acid-Base Properties of Oxides
• Metal oxides are basic or amphoteric
• Basic oxides:
Na2O(s) + H2O  2NaOH(aq)  2Na+
(aq) + 2OH-
(aq);
MgO(aq) + HCl(aq)  MgCl2(aq) + H2O
• Amphoteric oxides:
Al2O3(s) + HCl(aq)  2AlCl3(aq) + H2O
Al2O3(s) + 2NaOH(aq) + 3H2O  2NaAl(OH)4(aq)

• Nonmetal oxides are acidic;
N2O5 + H2O  2HNO3(aq);
SO3(g) + H2O  H2SO4(aq);
Cl2O7 + H2O  2HClO4(aq)
• Trends:
Acidity increases left to right across a period
SiO2 < P4O10 < SO3 < Cl2O7
Acidity decreases top-to-bottom in periodic table
N2O5 > P4O10 > As2O5 > Sb2O5

• Trend of acid-base properties of oxides in periodic table: from
the most basic (on the left) to the most acidic (on the right):
Na2O, MgO, Al2O3, SiO2, P4O10, SO3, Cl2O7
• Trend of acid-base properties going down a group: most acidic
on the left to the most basic on the right:
N2O5, P4O10 , As2O5, Sb2O5

Lewis Acids and Bases
• Identify the Lewis acids and Lewis bases in the following
reactions:
(a) H2O + CO2(aq)  H2CO3(aq);
(b) Cu2+
(aq) + 4NH3(aq)  Cu(NH3)4
2+
(aq);
(c) AlCl3 + Cl-
 AlCl4
-
;
(d) BF3 + NH3  F3B─NH3

Chapter_14_-_Acids_and_Bases.ppt

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