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CHI-SQUARE AND
ANALYSIS OF VARIANCE
𝜒2 1
Content Layout
â€ș Chi-Square
â€ș Characteristics of Chi-Square
â€ș Chi-square Test
â€ș Computational Procedure – Chi Square Test
â€ș Chi Square – Test Of Independence Formulae To Be Used
â€ș Contingency Table
â€ș Analysis Of Variance (ANOVA)
â€ș Assumptions
â€ș Steps in Analysis Of Variance (ANOVA)
â€ș Computational Procedure In ANOVA (One Way)
â€ș Difference Between Chi Square & ANOVA
𝜒2
2
Chi-square (𝜒2)
â€ș The Chi Square statistic is commonly used for testing
relationships between categorical variables. The null
hypothesis of the Chi-Square test is that no relationship
exists on the categorical variables in the population; they
are independent.
𝜒2
3
CHARACTERISTICS OF CHI SQUARE
â€ș Every Chi square distribution extends indefinitely to right
from zero.
â€ș It is skewed to right
â€ș As degree of freedom increases, Chi square curve
become more bell shaped and approaches normal
distribution.
â€ș Its mean is degree of freedom
â€ș Its variance is twice degree of freedom
𝜒2
4
CHI SQUARE (Χ2 TEST)
â€ș Chi Square Test deals with analysis of categorical data in terms of
frequencies / proportions / percentages.
â€ș It is primarily of three types:
‱ Test of Homogeneity:
To determine whether different population are similar w.r.t some
characteristics.
‱ Test of Independence:
Tests whether the characteristics of the elements of the same
population are related or independent.
‱ Test of Goodness of Fit:
To determine whether there is a significant difference between an
observed frequency distribution and theoretical probability distribution.
𝜒2
5
COMPUTATIONAL PROCEDURE – CHI SQUARE TEST
â€ș Formulate Null & Alternative Hypothesis
â€ș State type of test
â€ș Select LOS
â€ș Compute expected frequencies assuming H0 to be true.
â€ș Compute χ2 calculated value using
â€ș 𝜒2 cal= ∑
(ʂ‫ʋ‏ −ʂʁ)
2
ʂʁ
â€ș Extract 𝜒2 crit value from table
â€ș Compare 𝜒2 cal & 𝜒2 crit and make decision
𝜒2
6
CHI SQUARE – TEST OF INDEPENDENCE
FORMULAE TO BE USED
â€ș Computation of expected frequency
â€ș Fe = (RT x CT) / GT
‱ where RT = Row Total, CT = Column Total, GT = Grand Total
â€ș Computation of degree of freedom
â€ș Degree of freedom= (r – 1) (c – 1)
‱ r=No. of rows, c=No. of column
𝜒2
7
CONTIGENCY TABLE
â€ș A table having R rows and C columns. Each row
corresponds to a level of one variable, each column to a
level of another variable. Entries in the body of the table
are the frequencies with which each variable combination
occurred.
𝜒2
8
ANALYSIS OF VARIANCE (ANOVA)
â€ș Analysis of variance (ANOVA) is a collection of statistical
models and their associated estimation procedures (such
as the "variation" among and between groups) used to
analyze the differences among group means in a
sample. ANOVA was developed by statistician and
evolutionary biologist Ronald Fisher.
9
ANALYSIS OF VARIANCE (ANOVA)
â€ș It enables us to test for the significance of the differences
among more than two sample means.
â€ș Using ANOVA, we will be able to make inferences about
whether our samples are drawn from population having the
same mean.
â€ș Examples:
‱ Comparing the mileage of five different brands of cars
‱ Testing which of the four different training methods produces the fastest learning
record
‱ Comparing the average salary of three different companies
â€ș In each of these cases, we would compare the means of more
than two sample means.
â€ș F-Distribution is used to analyze certain situations
𝜒2
10
ASSUMPTIONS
â€ș Populations are normally distributed
â€ș Samples are random and independent
â€ș Population Variances are equal.
𝜒2
11
STEPS IN ANALYSIS OF VARIANCE
â€ș Determine one estimate of the population variance from
the variance among the sample means.
â€ș Determine second estimate of the population variance
from the variance within the sample means.
â€ș Compare these two estimates. If they are approximately
equal in value, accept the null hypotheses.
𝜒2
12
COMPUTATIONAL PROCEDURE IN ANOVA (ONE WAY)
â€ș Define Null & Alternative Hypothesis
â€ș Select Significance Level
â€ș Calculate Sum of all observations: T = Æ©x𝑖
â€ș Calculate correction factor: CF = T2 / nT where nT = sample size
â€ș Calculate Sum of squares total, SST = ÎŁ(ÎŁđ‘„đ‘–2) − CF
â€ș Calculate Sum of squares between columns, SSB = ÎŁ((ÎŁđ‘„đ‘–)2/𝑛𝑖) − CF
â€ș Calculate Sum of squares within columns, SSW = SST -SSB
â€ș Calculate 𝑓𝑐𝑎𝑙= 𝑠2𝑏 ∕ 𝑠2w OR 𝑓𝑐𝑎𝑙= 𝜎2𝑏 ∕ 𝜎2w
where s=variance
â€ș Calculate Mean of squares between groups, MSB = SSB / (k – 1) where k = no.
of samples
â€ș Calculate Mean of squares within groups, MSW = SSW / (nT – k)
â€ș Calculate Fcal = MSB / MSW
â€ș Calculate Fcrit = F(dfnum, dfden, α) where dfnum = k – 1, dfden = nT – k
â€ș Compare Fcal & Fcrit and make your statistical & managerial decisions
𝜒2
13
DIFFERENCE BETWEEN CHI SQUARE & ANOVA
CHI SQUARE (Χ2 TEST)
â€ș It enables us to test whether more than
two population proportions can be
considered equal
ANOVA (F TEST)
â€ș Analysis of Variance (ANOVA) enables us
to test whether more than two population
means can be considered equal.
14
THANK YOU!!!
15

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Chi-Square and Analysis of Variance

  • 1. CHI-SQUARE AND ANALYSIS OF VARIANCE 𝜒2 1
  • 2. Content Layout â€ș Chi-Square â€ș Characteristics of Chi-Square â€ș Chi-square Test â€ș Computational Procedure – Chi Square Test â€ș Chi Square – Test Of Independence Formulae To Be Used â€ș Contingency Table â€ș Analysis Of Variance (ANOVA) â€ș Assumptions â€ș Steps in Analysis Of Variance (ANOVA) â€ș Computational Procedure In ANOVA (One Way) â€ș Difference Between Chi Square & ANOVA 𝜒2 2
  • 3. Chi-square (𝜒2) â€ș The Chi Square statistic is commonly used for testing relationships between categorical variables. The null hypothesis of the Chi-Square test is that no relationship exists on the categorical variables in the population; they are independent. 𝜒2 3
  • 4. CHARACTERISTICS OF CHI SQUARE â€ș Every Chi square distribution extends indefinitely to right from zero. â€ș It is skewed to right â€ș As degree of freedom increases, Chi square curve become more bell shaped and approaches normal distribution. â€ș Its mean is degree of freedom â€ș Its variance is twice degree of freedom 𝜒2 4
  • 5. CHI SQUARE (Χ2 TEST) â€ș Chi Square Test deals with analysis of categorical data in terms of frequencies / proportions / percentages. â€ș It is primarily of three types: ‱ Test of Homogeneity: To determine whether different population are similar w.r.t some characteristics. ‱ Test of Independence: Tests whether the characteristics of the elements of the same population are related or independent. ‱ Test of Goodness of Fit: To determine whether there is a significant difference between an observed frequency distribution and theoretical probability distribution. 𝜒2 5
  • 6. COMPUTATIONAL PROCEDURE – CHI SQUARE TEST â€ș Formulate Null & Alternative Hypothesis â€ș State type of test â€ș Select LOS â€ș Compute expected frequencies assuming H0 to be true. â€ș Compute χ2 calculated value using â€ș 𝜒2 cal= ∑ (ʂ‫ʋ‏ −ʂʁ) 2 ʂʁ â€ș Extract 𝜒2 crit value from table â€ș Compare 𝜒2 cal & 𝜒2 crit and make decision 𝜒2 6
  • 7. CHI SQUARE – TEST OF INDEPENDENCE FORMULAE TO BE USED â€ș Computation of expected frequency â€ș Fe = (RT x CT) / GT ‱ where RT = Row Total, CT = Column Total, GT = Grand Total â€ș Computation of degree of freedom â€ș Degree of freedom= (r – 1) (c – 1) ‱ r=No. of rows, c=No. of column 𝜒2 7
  • 8. CONTIGENCY TABLE â€ș A table having R rows and C columns. Each row corresponds to a level of one variable, each column to a level of another variable. Entries in the body of the table are the frequencies with which each variable combination occurred. 𝜒2 8
  • 9. ANALYSIS OF VARIANCE (ANOVA) â€ș Analysis of variance (ANOVA) is a collection of statistical models and their associated estimation procedures (such as the "variation" among and between groups) used to analyze the differences among group means in a sample. ANOVA was developed by statistician and evolutionary biologist Ronald Fisher. 9
  • 10. ANALYSIS OF VARIANCE (ANOVA) â€ș It enables us to test for the significance of the differences among more than two sample means. â€ș Using ANOVA, we will be able to make inferences about whether our samples are drawn from population having the same mean. â€ș Examples: ‱ Comparing the mileage of five different brands of cars ‱ Testing which of the four different training methods produces the fastest learning record ‱ Comparing the average salary of three different companies â€ș In each of these cases, we would compare the means of more than two sample means. â€ș F-Distribution is used to analyze certain situations 𝜒2 10
  • 11. ASSUMPTIONS â€ș Populations are normally distributed â€ș Samples are random and independent â€ș Population Variances are equal. 𝜒2 11
  • 12. STEPS IN ANALYSIS OF VARIANCE â€ș Determine one estimate of the population variance from the variance among the sample means. â€ș Determine second estimate of the population variance from the variance within the sample means. â€ș Compare these two estimates. If they are approximately equal in value, accept the null hypotheses. 𝜒2 12
  • 13. COMPUTATIONAL PROCEDURE IN ANOVA (ONE WAY) â€ș Define Null & Alternative Hypothesis â€ș Select Significance Level â€ș Calculate Sum of all observations: T = Æ©x𝑖 â€ș Calculate correction factor: CF = T2 / nT where nT = sample size â€ș Calculate Sum of squares total, SST = ÎŁ(ÎŁđ‘„đ‘–2) − CF â€ș Calculate Sum of squares between columns, SSB = ÎŁ((ÎŁđ‘„đ‘–)2/𝑛𝑖) − CF â€ș Calculate Sum of squares within columns, SSW = SST -SSB â€ș Calculate 𝑓𝑐𝑎𝑙= 𝑠2𝑏 ∕ 𝑠2w OR 𝑓𝑐𝑎𝑙= 𝜎2𝑏 ∕ 𝜎2w where s=variance â€ș Calculate Mean of squares between groups, MSB = SSB / (k – 1) where k = no. of samples â€ș Calculate Mean of squares within groups, MSW = SSW / (nT – k) â€ș Calculate Fcal = MSB / MSW â€ș Calculate Fcrit = F(dfnum, dfden, α) where dfnum = k – 1, dfden = nT – k â€ș Compare Fcal & Fcrit and make your statistical & managerial decisions 𝜒2 13
  • 14. DIFFERENCE BETWEEN CHI SQUARE & ANOVA CHI SQUARE (Χ2 TEST) â€ș It enables us to test whether more than two population proportions can be considered equal ANOVA (F TEST) â€ș Analysis of Variance (ANOVA) enables us to test whether more than two population means can be considered equal. 14