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CLASS 8 FORCE & PRESSURE

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SouvikChatterjee53

The document serves as an introduction to the concepts of force and pressure in physics, explaining key definitions, calculations, and examples related to how forces can cause movement or change the shape of objects. It emphasizes the significance of the moment of force (torque) and factors affecting the turning effect of force, highlighting practical applications such as using a spanner or opening a door. Additionally, it covers the concepts of pressure, its units, and how it depends on thrust and area, alongside real-world implications of these principles.

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WELCOME TO MY CLASS Mr. Souvik Chatterjee M.Sc (Physics),B.Ed
FORCE & PRESSURE Turning effect of force (moment of force): Concept , definition and calculation Pressure Definition Unit Calculation of pressure in simple cases Pressure exerted by liquids (Qualitative Only) Pressure exerted by gases – Atmospheric pressure (qualitative only)
FORCE A force is a cause (push or pull) which tends to result in movement or change in size or shape of the body. A force when applied as push or pull on a stationary body which is free to move, can produce motion in it and if applied on a moving body, it can change the speed of motion of body (i.e can speed up or slow down the moving body) or it can change both the speed and direction of motion.
EXAMPLES  A grass roller initially at rest when pulled, begins to move.  A fielder when catches a ball, stops the moving ball  A moving car slows down on appling brakes on it  A push on a swinging girl speeds up her swing  A player when applies force by his hockey stick on the ball, the direction of motion of ball changes. When force is applied as stretch or squeeze on a body which is not free to move, it changes the size or shape of the body  On stretching a rubber string, its length increases  On squeezing a tube of gum, its shape changes. Thus we can define force as,  Force is that cause which changes the state of the body (either the state of rest or the state of motion) or it changes the size or shape of the body.
KEY POINTS  The speed of a body is defined as the distance travelled by it in one second  Speed up means more distance travelled in one second and slow down means less distance travelled in one second.  A force does not change the mass of the body on which it is applied  We can not see a force. However, we can see or feel the effect of a force.  A force is expressed by stating both its magnitude and direction  A force is represented by an arrow (→). The length of arrow is a measure of its magnitude and the arrow head shows the direction.
UNIT OF FORCE  S.I unit of force is newton (N).  One newton is defined as the force which when applied on a moving body of mass 1 kg in the direction of its motion, increases its speed by 1 m/s in one second.  The force of attraction exerted on a body by earth is called the weight of the body or the force of gravity that acts on the body.  Force of gravity (or weight) of a body is different at different places on earth.  At a place, the force of gravity on a body of mass 1 kg is called 1 kgf or 10N. In other words, 1N is the force of gravity at a place on 0.1 kg (100 g) mass. Thus, the unit of force kgf and N are related as: 1 kgf = 10 N In other words, one newton is the force that we have to exert to hold a mass of 100 g on our palm.
KEY POINTS A body in which the inter-spacing between its constituents particles do not change when a force is applied on it, is called a rigid body and if it changes, the body is called a non-rigid body. A force when applied on a rigid body can cause only the change in motion of the body. But a force when applied on a non-rigid body can cause both the change in its size or shape and motion in it.
TURNING EFFECT OF FORCE If a force is applied on a stationary body, it starts moving in a straight line in the direction of force as shown in the above picture
. If a body is not free to move, but it is pivoted at a suitable point, it begins to turn about that fixed point. The vertical axis passing through the pivoted point is called axis of rotation.
A force (push or pull) has a turning effect on a body which is not free to move in a straight line, but is pivoted at a point about which it can turn
FACTORS AFFECTING THE TURNING OF A BODY The turning effect of a force on a body depends on the following two factors: 1. The magnitude of the force applied: Larger the magnitude of force applied, more is the turning effect of the body. 1. The perpendicular distance of the force from the pivoted point: Larger the perpendicular distance of point at which the force the force is applied, from the pivoted point , more is the turning effect.
SOME EXAMPLES OF DAILY LIFE
To open a door, we apply a force (push or pull) F normal to the door at its handle B which is pivoted at the maximum distance from the hinges as shown in the above diagram. We notice that if we apply the force at a point near the hinge , much greater force required to open the door and if the force is applied at the hinge , we will not be able to open the door howsoever large the force may be. Thus, the handle is pivoted near the free end of the door so that a smaller force at a larger perpendicular distance, produces the required turning effect of force to open or shut the door.
SPANNER
A spanner used to tighten or loosen a nut, has a long handle to produce a large turning effect by a small force applied at the end of its handle as shown in the above diagram
POTTERS WHEEL
A potter’s wheel has wheel pivoted at the centre. The potter turns the wheel by means of a stick at the rim of the wheel as shown in the above figure.
CLASS 8 FORCE & PRESSURE
A carpenter uses a drill machine which is pivoted with a handle so that by applying a less force at the end of handle, the drill can be turned easily.
CLASS 8 FORCE & PRESSURE
To turn a steering wheel in a car or truck, the driver applies force at a point on the rim of the wheel as shown in the previous figure
CLASS 8 FORCE & PRESSURE
In a bicycle to turn the wheel, the force is applied on the pedal so that distance of force from the axle of wheel is increased.
From the above examples, we conclude that the turning of a body about the pivot depends not only on the magnitude of the force, but it also depends on the perpendicular distance of the force from the point of rotation.  Larger the perpendicular distance, less the force needed to turn the body. Actually the turning effect on a body depends on the product of both the magnitude of force and the perpendicular distance of the force from the pivoted point. This product is called the moment of force (or torque). In other words, a body turns (or rotates) about the pivoted point due to the moment of force.
MOMENT OF FORCE • The moment of force is equal to the product of the magnitude of the force and the perpendicular distance of the force from the pivoted point.
CLASS 8 FORCE & PRESSURE
Consider a body which is pivoted at a point O. If a force F is applied on the body in the direction FP as shown in the above diagram , the force is unable to produce linear motion of the body in its direction because the body is not free to move, but this force turns (or rotates) the body about the point O, in the direction shown by the arrow.  In the above diagram, the perpendicular distance of the force F from the pivoted point O is OP. Therefore, Moment of force about point O= Force X perpendicular distance of force from the point O= F X OP
CLASS 8 FORCE & PRESSURE
KEY POINTS For producing maximum turning effect on a body by a given force, the force applied on the body at a point for which the perpendicular distance of the force from the pivoted point is maximum so that the given force may provide the maximum torque to turn the body.
UNIT OF MOMENT OF FORCE Unit of moment of force=Unit of force X Unit of distance The S.I unit of force is newton and that of distance metre. So, the S.I unit of moment of force is newton-metre (N- m). This not same as joule (J). C.G.S unit of moment of force is dyne-cm. But if the force is measured in gravitational unit, then the unit of moment of force in S.I unit is kgf-m and in C.G.S unit is gf-cm.
THE RELATION BETWEEN UNITS 1 N m= 1N X 1m = 105 dyne X 102 cm = 107 dyne cm 1 kgf m= 1 kgf X 1m =10 N X 1m =10 N m 1 gf cm= 1gf X 1cm =1000 dyne X 1cm =1000 dyne cm
KEY POINTS Conventionally, if the effect on the body is to turn it anticlockwise, moment of force is called anticlockwise moment and it is taken positive. If the effect on the body is to turn it clockwise, the moment of force is called clockwise moment is taken negative. The direction of rotation of a body can be changed either by changing the point a which the force is applied or by changing the direction of force applied as shown in the next diagram
CLASS 8 FORCE & PRESSURE
PROBLEMS FROM CONCISE PHYSICS 1.Find the moment of force of 20 N about an axis of rotation at distance 0.5 m from the force. Moment= Force X Distance =(20 X 0.5) = 10 N m 2. The moment of force of 25N about a point is 2.5 N m. Find the perpendicular distance of force from the point. Perpendicular Distance=Moment/Force= 2.5/25=0.1 m= (0.1 X 100) cm= 10 cm
3.A spanner of length 10 cm used to open a nut by applying a minimum force of 5.0 N. Calculate the moment of force required. Distance=10 cm= 10/100= 0.1 m Moment= (5.0 X 0.1)= 0.5 N m 4.A wheel of diameter 2 m can be rotated about an axis passing through its centre by a moment of force equal to 2.0 N m. What minimum force must be applied on its rim? Force=Moment /Distance =2.0/2 = 1 N
PRESSURE The thrust per unit area is called pressure. If a thrust F acts on an area A, the pressure P is:
UNIT OF PRESSURE S.I unit of thrust is newton and that of area is So the S.I unit of pressure is newton/metre2.( N/m2 ). This unit is also called pascal. Thus, 1 pascal is the pressure exerted by a thrust of 1 newton on a surface of area 1metre2 i.e
The bigger unit of pressure is kilo pascal (symbol kPa) where, 1 kPa=1000 Pa If thrust is measured in kgf and area in cm2, then pressure is expressed in unit kgf / cm2  The atmospheric pressure is generally expressed in a unit atm where 1 atm = 76 cm of mercury column = 1.013 X 105 Pa
FACTORS AFFECTING PRESSURE The pressure on a surface depends on the following two factors:  1.On the area of the surface on which thrust acts: More the area, Less is the pressure. Inversely proportional  2.On the magnitude of thrust acting on the surface. More the thrust, More the pressure Directly proportinal
NUMERICALS FROM CONCISE PHYSICS Numerical 5- A normal force of 200 N acts on the area of 0.02 m2. Find the pressure in pascal. Ans. P= F/A= 200/0.02 = 10,000 Pa Numerical 6- Find the thrust to exert a pressure of 50,000 pascal on the area 0f 0.05 m2 Ans F = P X A = 50,000 X 0.05 = 2500 N
Numerical-7 Find the area of a body which experiences a pressure of 50,000 Pa by a thrust of 100 N. Ans. A = F/P=100/50000 = 1/500 = 0.002 m2  Numerical-8 Calculate the pressure in pascal exerted by a force of 300 N acting normally on the area of 30 cm2  Ans. Area= 30 cm2 = 30/(10000) m2 = 0.003 m2  Pressure = 300/0.003 = 100000 Pa
Numerical-9 How much thrust will be required to exert a pressure of 20,000 Pa on an area of 1 cm2 ? Ans. Area = 1 cm2= 1/10000 m2 Thrust = 20,000 X 1/10000 = 2 N. Numerical-10 The base of a container measures 15 cm X 20 cm. It is placed on the table top. If the weight of the container is 60 N, what is the pressure exerted by the container on the table top?. Ans. Area= (15 X 20) cm2= 300 cm2 = 300/10000 m2 = 0.03 m2 Pressure=60/0.03 = 2000 Pa
Numerical-11 Calculate the pressure exerted on a surface of 0.5 m2 by a thrust of 100 kgf. Ans. Thrust=100 kgf = 100 X 10= 1000 N Pressure = 1000/0.5 = 2000 Pa = 200 kgf/m2 Numerical-12 A boy weighing 60 kgf stands on platform of dimension 2.5 cm X 0.5 cm. What pressure in pascal does he exert? Ans. Area = 2.5 X 0.5 = 1.25 cm2 = 1.25/10000 = 0.000125 m2 Thrust= 60 kgf= 60 X 10=600 N Pressure = 600/0.000125 = 4,800,000 N. = 4.8 X 106 Pa
 Numerical-13 The figure shows a brick of weight 2 kgf and dimension 20 cm X 10 cm X 5 cm placed in three different positions on the ground. Find the pressure exerted by the brick in each cases
Ans. (a) Area = (20 X 10)=200 cm2 Pressure = 2/200 = 0.01 kgf/cm2 (b) Area= (5 X 10) = 50 cm2 Pressure= 2/50 = 0.04 kgf/cm2 (c) Area = (20 X 5) =100 cm2  Pressure = 2/100 = 0.02 kgf/cm2
DECREASE IN AREA INCREASE THE PRESSRE 1. A nail or a board pin has one end pointed and sharp while the other end is blunt and flat. On applying force, the pointed end will exert greater pressure as the area of contact is small and hence it will go deep into the given surface.
2.The cutting tools like blade, knife, axe etc have very sharp edges. The sharp edges have very small area of contact, so the pressure applied by a force is more. 3.Pointed heels of footwear exert more pressure on the ground than the regular flat heels. Therefore, a lady with pointed heel sandals finds it difficult to walk on a muddy road than on a tarred road. 4.The narrow heeled sandal of a girl hurts more than the broad heeled shoe of a boy. This is because more pressure is exerted by the girl than that by the boy as her heel is narrow than the heel of the shoe.
INCREASE AREA DECREASES THE PRESSURE 1. Heavy trucks have six to eight tyres instead of the convenient four tyres. More number of tyres are used to increase the area of contact and thereby reduce the pressure on the ground 2. Foundation of buildings are kept wide so that the weight of the building may act on larger area. As a result, it will exert less pressure on the ground. This avoids sinking of buildings into the earth.
3. A camel can move more conveniently on sand as compared to a horse. The reason is that the camel has broader feet than horse. The broader feet of the camel provide lesser pressure on the sand and it becomes easier for the camel to walk. In the case of a horse, the area of the feet is less, due to which the pressure is more and hence the feet show tendency to sink inside the sand, making it difficult to walk.
4. Skiers use long flat skis to slide over the snow. The larger the area of contact, the lesser is the pressure on the snow. This helps the skiers to slide comfortably without in the snow. 5. Wide wooden sleepers are placed below the railway tracks so that the pressure exerted by the rail on the ground becomes less. 6. A porter wears turban on his head when he has to carry heavy loads. This helps in increasing the area of contact of load and head so as to reduce the pressure of the load on his head.
LIQUID PRESSURE A solid exerts pressure on a surface due to its own weight. Similarly, liquids have weight. They also exert pressure on the container in which they are kept. A solid exerts pressure only on the surface at its bottom. But a liquid exerts pressure not only on the surface of its container at the bottom, but also sideways, that is , in all directions.
FACTORS AFFECTING LIQUID PRESSURE Pressure at a point in a liquid depend on the following two factor: The height of the liquid column Liquid pressure increases with the height of the liquid column above the point. The density of the liquid Liquid pressure increases with the increase in density of the liquid.
CLASS 8 FORCE & PRESSURE
CLASS 8 FORCE & PRESSURE
CLASS 8 FORCE & PRESSURE
CLASS 8 FORCE & PRESSURE
CONSEQUENCES Thickness of wall of a dam is increased towards the bottom The reason is that the pressure at a point due to a liquid increases with the increase in height of the liquid column above it, so thickness of the wall of a dam is increased towards the bottom so as to withstand the increasing pressure of water. The arrows in the figure show the increasing pressure towards the bottom of the dam
CLASS 8 FORCE & PRESSURE
ATMOSPHERIC PRESSURE Like liquids, gases also exerts pressure. Our earth is surrounded by air to a height of about 200 km. This envelop of air around the earth is called the atmosphere. Air has weight. The weight of air exerts a thrust on earth. The thrust on unit area of the earth surface due to the column of air is called the atmospheric pressure. It is about 100000 Pa. Thus, a thrust of 100,000 N acts on every 1 square metre of the surface of objects on earth.
KEY POINTS We all are under the atmospheric pressure (=100000 Pa). The surface area of an average human body is 2 m2 . Therefore, a total thrust of about 200000 N acts on our body by the atmosphere. However we are not aware of this enormous thrust since the blood in the veins of our body also exerts a pressure ( called blood pressure) which slightly more than atmospheric pressure. The blood pressure makes the effect of atmospheric pressure ineffective.
Standard Value Of Atmospheric Pressure At sea level on earth surface, the atmospheric pressure is 76 cm or 760 mm of mercury column which is equal to 1 atm or 1.013 X10 5 Pa. Atmospheric pressure decreases with increasing altitude i.e as we go higher above the earth surface, the air pressure decreases.
CLASS 8 FORCE & PRESSURE
CLASS 8 FORCE & PRESSURE
SOME EXAMPLES 1.When a drink is sucked with a straw, the air goes into the lungs and thus air pressure in the straw decreases. The atmospheric pressure acting on the drink exerts force on the drink to move up into the straw and then into the mouth.
CLASS 8 FORCE & PRESSURE
2.When we blow air in a balloon, it bulges because of the pressure exerted by the air filled in it. 3.It is due to atmospheric pressure that ink gets filled into a fountain pen. 4. Water is drawn up from a well by a water pump because of the atmospheric pressure acting on water in the well. 5. The syringe gets filled with liquid when its plunger is pulled up due to the atmospheric pressure acting on the liquid.
6. Rubber sucker are used as hook in the kitchen and bathroom. They remain pressed against the wall due to the atmospheric pressure from outside. 7. It is difficult to take out oil from a sealed tin if only one hole is made in it. But if another hole also made, the atmospheric pressure acts on the oil due to air entering in the tin through this hole and the oil then comes out of the tin through the other hole easily.
8. Lizards are able to move on the wall and stay whenever they desire. This is because their feet behave like suction pads, so they remain pressed against the wall due to the atmospheric pressure. 9. The astronaut and mountaineers have to wear special type of suits to protect themselves from adverse effects of low pressure prevailing at the great heights.
10. Nose bleeding often occurs at high altitudes. The reason is that the atmospheric pressure is low at high altitudes, but the pressure inside the human body does not change. Thus the excess pressure inside our body compared o the atmospheric pressure, causes nose bleeding.

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CLASS 8 FORCE & PRESSURE

  • 1. WELCOME TO MY CLASS Mr. Souvik Chatterjee M.Sc (Physics),B.Ed
  • 2. FORCE & PRESSURE Turning effect of force (moment of force): Concept , definition and calculation Pressure Definition Unit Calculation of pressure in simple cases Pressure exerted by liquids (Qualitative Only) Pressure exerted by gases – Atmospheric pressure (qualitative only)
  • 3. FORCE A force is a cause (push or pull) which tends to result in movement or change in size or shape of the body. A force when applied as push or pull on a stationary body which is free to move, can produce motion in it and if applied on a moving body, it can change the speed of motion of body (i.e can speed up or slow down the moving body) or it can change both the speed and direction of motion.
  • 4. EXAMPLES  A grass roller initially at rest when pulled, begins to move.  A fielder when catches a ball, stops the moving ball  A moving car slows down on appling brakes on it  A push on a swinging girl speeds up her swing  A player when applies force by his hockey stick on the ball, the direction of motion of ball changes. When force is applied as stretch or squeeze on a body which is not free to move, it changes the size or shape of the body  On stretching a rubber string, its length increases  On squeezing a tube of gum, its shape changes. Thus we can define force as,  Force is that cause which changes the state of the body (either the state of rest or the state of motion) or it changes the size or shape of the body.
  • 5. KEY POINTS  The speed of a body is defined as the distance travelled by it in one second  Speed up means more distance travelled in one second and slow down means less distance travelled in one second.  A force does not change the mass of the body on which it is applied  We can not see a force. However, we can see or feel the effect of a force.  A force is expressed by stating both its magnitude and direction  A force is represented by an arrow (→). The length of arrow is a measure of its magnitude and the arrow head shows the direction.
  • 6. UNIT OF FORCE  S.I unit of force is newton (N).  One newton is defined as the force which when applied on a moving body of mass 1 kg in the direction of its motion, increases its speed by 1 m/s in one second.  The force of attraction exerted on a body by earth is called the weight of the body or the force of gravity that acts on the body.  Force of gravity (or weight) of a body is different at different places on earth.  At a place, the force of gravity on a body of mass 1 kg is called 1 kgf or 10N. In other words, 1N is the force of gravity at a place on 0.1 kg (100 g) mass. Thus, the unit of force kgf and N are related as: 1 kgf = 10 N In other words, one newton is the force that we have to exert to hold a mass of 100 g on our palm.
  • 7. KEY POINTS A body in which the inter-spacing between its constituents particles do not change when a force is applied on it, is called a rigid body and if it changes, the body is called a non-rigid body. A force when applied on a rigid body can cause only the change in motion of the body. But a force when applied on a non-rigid body can cause both the change in its size or shape and motion in it.
  • 8. TURNING EFFECT OF FORCE If a force is applied on a stationary body, it starts moving in a straight line in the direction of force as shown in the above picture
  • 9. . If a body is not free to move, but it is pivoted at a suitable point, it begins to turn about that fixed point. The vertical axis passing through the pivoted point is called axis of rotation.
  • 10. A force (push or pull) has a turning effect on a body which is not free to move in a straight line, but is pivoted at a point about which it can turn
  • 11. FACTORS AFFECTING THE TURNING OF A BODY The turning effect of a force on a body depends on the following two factors: 1. The magnitude of the force applied: Larger the magnitude of force applied, more is the turning effect of the body. 1. The perpendicular distance of the force from the pivoted point: Larger the perpendicular distance of point at which the force the force is applied, from the pivoted point , more is the turning effect.
  • 12. SOME EXAMPLES OF DAILY LIFE
  • 13. To open a door, we apply a force (push or pull) F normal to the door at its handle B which is pivoted at the maximum distance from the hinges as shown in the above diagram. We notice that if we apply the force at a point near the hinge , much greater force required to open the door and if the force is applied at the hinge , we will not be able to open the door howsoever large the force may be. Thus, the handle is pivoted near the free end of the door so that a smaller force at a larger perpendicular distance, produces the required turning effect of force to open or shut the door.
  • 15. A spanner used to tighten or loosen a nut, has a long handle to produce a large turning effect by a small force applied at the end of its handle as shown in the above diagram
  • 17. A potter’s wheel has wheel pivoted at the centre. The potter turns the wheel by means of a stick at the rim of the wheel as shown in the above figure.
  • 19. A carpenter uses a drill machine which is pivoted with a handle so that by applying a less force at the end of handle, the drill can be turned easily.
  • 21. To turn a steering wheel in a car or truck, the driver applies force at a point on the rim of the wheel as shown in the previous figure
  • 23. In a bicycle to turn the wheel, the force is applied on the pedal so that distance of force from the axle of wheel is increased.
  • 24. From the above examples, we conclude that the turning of a body about the pivot depends not only on the magnitude of the force, but it also depends on the perpendicular distance of the force from the point of rotation.  Larger the perpendicular distance, less the force needed to turn the body. Actually the turning effect on a body depends on the product of both the magnitude of force and the perpendicular distance of the force from the pivoted point. This product is called the moment of force (or torque). In other words, a body turns (or rotates) about the pivoted point due to the moment of force.
  • 25. MOMENT OF FORCE • The moment of force is equal to the product of the magnitude of the force and the perpendicular distance of the force from the pivoted point.
  • 27. Consider a body which is pivoted at a point O. If a force F is applied on the body in the direction FP as shown in the above diagram , the force is unable to produce linear motion of the body in its direction because the body is not free to move, but this force turns (or rotates) the body about the point O, in the direction shown by the arrow.  In the above diagram, the perpendicular distance of the force F from the pivoted point O is OP. Therefore, Moment of force about point O= Force X perpendicular distance of force from the point O= F X OP
  • 29. KEY POINTS For producing maximum turning effect on a body by a given force, the force applied on the body at a point for which the perpendicular distance of the force from the pivoted point is maximum so that the given force may provide the maximum torque to turn the body.
  • 30. UNIT OF MOMENT OF FORCE Unit of moment of force=Unit of force X Unit of distance The S.I unit of force is newton and that of distance metre. So, the S.I unit of moment of force is newton-metre (N- m). This not same as joule (J). C.G.S unit of moment of force is dyne-cm. But if the force is measured in gravitational unit, then the unit of moment of force in S.I unit is kgf-m and in C.G.S unit is gf-cm.
  • 31. THE RELATION BETWEEN UNITS 1 N m= 1N X 1m = 105 dyne X 102 cm = 107 dyne cm 1 kgf m= 1 kgf X 1m =10 N X 1m =10 N m 1 gf cm= 1gf X 1cm =1000 dyne X 1cm =1000 dyne cm
  • 32. KEY POINTS Conventionally, if the effect on the body is to turn it anticlockwise, moment of force is called anticlockwise moment and it is taken positive. If the effect on the body is to turn it clockwise, the moment of force is called clockwise moment is taken negative. The direction of rotation of a body can be changed either by changing the point a which the force is applied or by changing the direction of force applied as shown in the next diagram
  • 34. PROBLEMS FROM CONCISE PHYSICS 1.Find the moment of force of 20 N about an axis of rotation at distance 0.5 m from the force. Moment= Force X Distance =(20 X 0.5) = 10 N m 2. The moment of force of 25N about a point is 2.5 N m. Find the perpendicular distance of force from the point. Perpendicular Distance=Moment/Force= 2.5/25=0.1 m= (0.1 X 100) cm= 10 cm
  • 35. 3.A spanner of length 10 cm used to open a nut by applying a minimum force of 5.0 N. Calculate the moment of force required. Distance=10 cm= 10/100= 0.1 m Moment= (5.0 X 0.1)= 0.5 N m 4.A wheel of diameter 2 m can be rotated about an axis passing through its centre by a moment of force equal to 2.0 N m. What minimum force must be applied on its rim? Force=Moment /Distance =2.0/2 = 1 N
  • 36. PRESSURE The thrust per unit area is called pressure. If a thrust F acts on an area A, the pressure P is:
  • 37. UNIT OF PRESSURE S.I unit of thrust is newton and that of area is So the S.I unit of pressure is newton/metre2.( N/m2 ). This unit is also called pascal. Thus, 1 pascal is the pressure exerted by a thrust of 1 newton on a surface of area 1metre2 i.e
  • 38. The bigger unit of pressure is kilo pascal (symbol kPa) where, 1 kPa=1000 Pa If thrust is measured in kgf and area in cm2, then pressure is expressed in unit kgf / cm2  The atmospheric pressure is generally expressed in a unit atm where 1 atm = 76 cm of mercury column = 1.013 X 105 Pa
  • 39. FACTORS AFFECTING PRESSURE The pressure on a surface depends on the following two factors:  1.On the area of the surface on which thrust acts: More the area, Less is the pressure. Inversely proportional  2.On the magnitude of thrust acting on the surface. More the thrust, More the pressure Directly proportinal
  • 40. NUMERICALS FROM CONCISE PHYSICS Numerical 5- A normal force of 200 N acts on the area of 0.02 m2. Find the pressure in pascal. Ans. P= F/A= 200/0.02 = 10,000 Pa Numerical 6- Find the thrust to exert a pressure of 50,000 pascal on the area 0f 0.05 m2 Ans F = P X A = 50,000 X 0.05 = 2500 N
  • 41. Numerical-7 Find the area of a body which experiences a pressure of 50,000 Pa by a thrust of 100 N. Ans. A = F/P=100/50000 = 1/500 = 0.002 m2  Numerical-8 Calculate the pressure in pascal exerted by a force of 300 N acting normally on the area of 30 cm2  Ans. Area= 30 cm2 = 30/(10000) m2 = 0.003 m2  Pressure = 300/0.003 = 100000 Pa
  • 42. Numerical-9 How much thrust will be required to exert a pressure of 20,000 Pa on an area of 1 cm2 ? Ans. Area = 1 cm2= 1/10000 m2 Thrust = 20,000 X 1/10000 = 2 N. Numerical-10 The base of a container measures 15 cm X 20 cm. It is placed on the table top. If the weight of the container is 60 N, what is the pressure exerted by the container on the table top?. Ans. Area= (15 X 20) cm2= 300 cm2 = 300/10000 m2 = 0.03 m2 Pressure=60/0.03 = 2000 Pa
  • 43. Numerical-11 Calculate the pressure exerted on a surface of 0.5 m2 by a thrust of 100 kgf. Ans. Thrust=100 kgf = 100 X 10= 1000 N Pressure = 1000/0.5 = 2000 Pa = 200 kgf/m2 Numerical-12 A boy weighing 60 kgf stands on platform of dimension 2.5 cm X 0.5 cm. What pressure in pascal does he exert? Ans. Area = 2.5 X 0.5 = 1.25 cm2 = 1.25/10000 = 0.000125 m2 Thrust= 60 kgf= 60 X 10=600 N Pressure = 600/0.000125 = 4,800,000 N. = 4.8 X 106 Pa
  • 44.  Numerical-13 The figure shows a brick of weight 2 kgf and dimension 20 cm X 10 cm X 5 cm placed in three different positions on the ground. Find the pressure exerted by the brick in each cases
  • 45. Ans. (a) Area = (20 X 10)=200 cm2 Pressure = 2/200 = 0.01 kgf/cm2 (b) Area= (5 X 10) = 50 cm2 Pressure= 2/50 = 0.04 kgf/cm2 (c) Area = (20 X 5) =100 cm2  Pressure = 2/100 = 0.02 kgf/cm2
  • 46. DECREASE IN AREA INCREASE THE PRESSRE 1. A nail or a board pin has one end pointed and sharp while the other end is blunt and flat. On applying force, the pointed end will exert greater pressure as the area of contact is small and hence it will go deep into the given surface.
  • 47. 2.The cutting tools like blade, knife, axe etc have very sharp edges. The sharp edges have very small area of contact, so the pressure applied by a force is more. 3.Pointed heels of footwear exert more pressure on the ground than the regular flat heels. Therefore, a lady with pointed heel sandals finds it difficult to walk on a muddy road than on a tarred road. 4.The narrow heeled sandal of a girl hurts more than the broad heeled shoe of a boy. This is because more pressure is exerted by the girl than that by the boy as her heel is narrow than the heel of the shoe.
  • 48. INCREASE AREA DECREASES THE PRESSURE 1. Heavy trucks have six to eight tyres instead of the convenient four tyres. More number of tyres are used to increase the area of contact and thereby reduce the pressure on the ground 2. Foundation of buildings are kept wide so that the weight of the building may act on larger area. As a result, it will exert less pressure on the ground. This avoids sinking of buildings into the earth.
  • 49. 3. A camel can move more conveniently on sand as compared to a horse. The reason is that the camel has broader feet than horse. The broader feet of the camel provide lesser pressure on the sand and it becomes easier for the camel to walk. In the case of a horse, the area of the feet is less, due to which the pressure is more and hence the feet show tendency to sink inside the sand, making it difficult to walk.
  • 50. 4. Skiers use long flat skis to slide over the snow. The larger the area of contact, the lesser is the pressure on the snow. This helps the skiers to slide comfortably without in the snow. 5. Wide wooden sleepers are placed below the railway tracks so that the pressure exerted by the rail on the ground becomes less. 6. A porter wears turban on his head when he has to carry heavy loads. This helps in increasing the area of contact of load and head so as to reduce the pressure of the load on his head.
  • 51. LIQUID PRESSURE A solid exerts pressure on a surface due to its own weight. Similarly, liquids have weight. They also exert pressure on the container in which they are kept. A solid exerts pressure only on the surface at its bottom. But a liquid exerts pressure not only on the surface of its container at the bottom, but also sideways, that is , in all directions.
  • 52. FACTORS AFFECTING LIQUID PRESSURE Pressure at a point in a liquid depend on the following two factor: The height of the liquid column Liquid pressure increases with the height of the liquid column above the point. The density of the liquid Liquid pressure increases with the increase in density of the liquid.
  • 57. CONSEQUENCES Thickness of wall of a dam is increased towards the bottom The reason is that the pressure at a point due to a liquid increases with the increase in height of the liquid column above it, so thickness of the wall of a dam is increased towards the bottom so as to withstand the increasing pressure of water. The arrows in the figure show the increasing pressure towards the bottom of the dam
  • 59. ATMOSPHERIC PRESSURE Like liquids, gases also exerts pressure. Our earth is surrounded by air to a height of about 200 km. This envelop of air around the earth is called the atmosphere. Air has weight. The weight of air exerts a thrust on earth. The thrust on unit area of the earth surface due to the column of air is called the atmospheric pressure. It is about 100000 Pa. Thus, a thrust of 100,000 N acts on every 1 square metre of the surface of objects on earth.
  • 60. KEY POINTS We all are under the atmospheric pressure (=100000 Pa). The surface area of an average human body is 2 m2 . Therefore, a total thrust of about 200000 N acts on our body by the atmosphere. However we are not aware of this enormous thrust since the blood in the veins of our body also exerts a pressure ( called blood pressure) which slightly more than atmospheric pressure. The blood pressure makes the effect of atmospheric pressure ineffective.
  • 61. Standard Value Of Atmospheric Pressure At sea level on earth surface, the atmospheric pressure is 76 cm or 760 mm of mercury column which is equal to 1 atm or 1.013 X10 5 Pa. Atmospheric pressure decreases with increasing altitude i.e as we go higher above the earth surface, the air pressure decreases.
  • 64. SOME EXAMPLES 1.When a drink is sucked with a straw, the air goes into the lungs and thus air pressure in the straw decreases. The atmospheric pressure acting on the drink exerts force on the drink to move up into the straw and then into the mouth.
  • 66. 2.When we blow air in a balloon, it bulges because of the pressure exerted by the air filled in it. 3.It is due to atmospheric pressure that ink gets filled into a fountain pen. 4. Water is drawn up from a well by a water pump because of the atmospheric pressure acting on water in the well. 5. The syringe gets filled with liquid when its plunger is pulled up due to the atmospheric pressure acting on the liquid.
  • 67. 6. Rubber sucker are used as hook in the kitchen and bathroom. They remain pressed against the wall due to the atmospheric pressure from outside. 7. It is difficult to take out oil from a sealed tin if only one hole is made in it. But if another hole also made, the atmospheric pressure acts on the oil due to air entering in the tin through this hole and the oil then comes out of the tin through the other hole easily.
  • 68. 8. Lizards are able to move on the wall and stay whenever they desire. This is because their feet behave like suction pads, so they remain pressed against the wall due to the atmospheric pressure. 9. The astronaut and mountaineers have to wear special type of suits to protect themselves from adverse effects of low pressure prevailing at the great heights.
  • 69. 10. Nose bleeding often occurs at high altitudes. The reason is that the atmospheric pressure is low at high altitudes, but the pressure inside the human body does not change. Thus the excess pressure inside our body compared o the atmospheric pressure, causes nose bleeding.