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M ODELING C OMPLETING THE S QUARE


Use algebra tiles to complete a perfect square trinomial.


                         2
Model the expression x       +
6x.                                    x2      x x x x x x
Arrange the x-tiles to
form part of a square.
                                       x       1    1   1

To complete the square,
                                       x       1    1   1
add nine 1-tiles.                      x       1    1   1


You have completed the square.      x2 + 6x + 9 = (x + 3)2
S OLVING BY C OMPLETING THE S QUARE


   To complete the square of the expression x2 + bx, add the
   square of half the coefficient of x.




                               2              2
                           b       = x+ b
             x2 + bx +   ( ) (
                           2            2    )
Completing the Square


What term should you add to x2 – 8x so that the result is a
perfect square?


S OLUTION
                                                      2
                                                   –8
The coefficient of x is –8, so you should add
to the expression.
                                                 ( 2)  , or 16,



                        2
             –8
     2
    x – 8x +
              2  ( )        = x2 – 8x + 16 = (x – 4)2
Completing the Square



      Factor 2x2 – x – 2 = 0

      S OLUTIO
      N

      2x2 – x – 2 = 0          Write original equation.

          2x2 – x = 2          Add 2 to each side.

          21
       x – 2 x=1               Divide each side by 2.

                 2                   1 1
                                               2    1 2      1
2
x –
    1
    2
      x+ –
           1
          ( )
           4
                 =1+
                         1
                        16
                               Add –
                                    ( •
                                     2 2       ) ( 4)
                                                = –     , or
                                                            16
                               to each side.
Completing the Square


                      2                            1 1
                                                              2    1 2      1
2
x –
    1
    2
      x+ –
           1
           4 ( )      =1+
                           1
                          16
                                             Add –
                                                   (•
                                                   2 2       ) ( 4)
                                                               = –     , or
                                                                              16
                                             to each side.
                  2
              1               17
         (x –
              4   )       =
                              16
                                             Write left side as a fraction.


             x–
                1
                  = ±
                                   17        Find the square root of each side.
                4                  4
                         1
                           ±            17   Add
                                                   1 to each side.
                      x=
                         4              4          4


                      1                 17            1          17
    The solutions are   +                  ≈ 1.28 and   –           ≈ – 0.78.
                      4                 4             4          4
C HOOSING A S OLUTION M ETHOD
Investigating the Quadratic Formula
    Perform the following steps on the general quadratic equation
    ax2 + bx + c = 0 where a ≠ 0.

       ax2 + bx = – c                     Subtract c from each side.

            bx         –c                 Divide each side by a.
       x2 + a + =       a
    bx    b      2    –c          b   2
2
x +
    a
       + ( )
         2a        ( )
                     = a +
                                 2a
                                          Add the square of half the coefficient
                                          of x to each side.
          b
       x + ) = –a + b
                c2               2
      ( 2a         4a            2        Write the left side as a perfect square.


            b    2     – 4ac + b 2        Use a common denominator to express
      ( x+
           2a    )   =       2
                            4a            the right side as a single fraction.
C HOOSING A S OLUTION M ETHOD
Investigating the Quadratic Formula

      b    2     – 4ac + b 2         Use a common denominator to express
 (x+
     2a   )    =        2
                          4a         the right side as a single fraction.


          ±           b − 4ac
                           2
     b                               Find the square root of each side.
  x+    =
     2a                    2a        Include ± on the right side.


        ± b2 − 4ac b                 Solve for x by subtracting the same
     x=           –
                2a              2a   term from each side.


          –b ± b − 4ac
                2
                                     Use a common denominator to express
     x=                              the right side as a single fraction.
                     2a

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Completing the square (1)

  • 1. M ODELING C OMPLETING THE S QUARE Use algebra tiles to complete a perfect square trinomial. 2 Model the expression x + 6x. x2 x x x x x x Arrange the x-tiles to form part of a square. x 1 1 1 To complete the square, x 1 1 1 add nine 1-tiles. x 1 1 1 You have completed the square. x2 + 6x + 9 = (x + 3)2
  • 2. S OLVING BY C OMPLETING THE S QUARE To complete the square of the expression x2 + bx, add the square of half the coefficient of x. 2 2 b = x+ b x2 + bx + ( ) ( 2 2 )
  • 3. Completing the Square What term should you add to x2 – 8x so that the result is a perfect square? S OLUTION 2 –8 The coefficient of x is –8, so you should add to the expression. ( 2) , or 16, 2 –8 2 x – 8x + 2 ( ) = x2 – 8x + 16 = (x – 4)2
  • 4. Completing the Square Factor 2x2 – x – 2 = 0 S OLUTIO N 2x2 – x – 2 = 0 Write original equation. 2x2 – x = 2 Add 2 to each side. 21 x – 2 x=1 Divide each side by 2. 2 1 1 2 1 2 1 2 x – 1 2 x+ – 1 ( ) 4 =1+ 1 16 Add – ( • 2 2 ) ( 4) = – , or 16 to each side.
  • 5. Completing the Square 2 1 1 2 1 2 1 2 x – 1 2 x+ – 1 4 ( ) =1+ 1 16 Add – (• 2 2 ) ( 4) = – , or 16 to each side. 2 1 17 (x – 4 ) = 16 Write left side as a fraction. x– 1 = ± 17 Find the square root of each side. 4 4 1 ± 17 Add 1 to each side. x= 4 4 4 1 17 1 17 The solutions are + ≈ 1.28 and – ≈ – 0.78. 4 4 4 4
  • 6. C HOOSING A S OLUTION M ETHOD Investigating the Quadratic Formula Perform the following steps on the general quadratic equation ax2 + bx + c = 0 where a ≠ 0. ax2 + bx = – c Subtract c from each side. bx –c Divide each side by a. x2 + a + = a bx b 2 –c b 2 2 x + a + ( ) 2a ( ) = a + 2a Add the square of half the coefficient of x to each side. b x + ) = –a + b c2 2 ( 2a 4a 2 Write the left side as a perfect square. b 2 – 4ac + b 2 Use a common denominator to express ( x+ 2a ) = 2 4a the right side as a single fraction.
  • 7. C HOOSING A S OLUTION M ETHOD Investigating the Quadratic Formula b 2 – 4ac + b 2 Use a common denominator to express (x+ 2a ) = 2 4a the right side as a single fraction. ± b − 4ac 2 b Find the square root of each side. x+ = 2a 2a Include ± on the right side. ± b2 − 4ac b Solve for x by subtracting the same x= – 2a 2a term from each side. –b ± b − 4ac 2 Use a common denominator to express x= the right side as a single fraction. 2a