Concepts of Genetics 10th Edition Klug Test Bank

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Copyright © 2012 Pearson Education, Inc.
Concepts of Genetics, 10e (Klug/Cummings/Spencer/Palladino)
Chapter 3 Mendelian Genetics
1) Which of the following groups of scientists were influential around the year 1900 in setting
the stage for our present understanding of transmission genetics?
A) Beadle, Tatum, Lederberg
B) Watson, Crick, Wilkins, Franklin
C) deVries, Correns, Tschermak, Sutton, Boveri
D) Darwin, Mendel, Lamarck
E) Hippocrates, Aristotle, Kolreuter
Answer: C
Section: 3.5
2) Name the single individual whose work in the mid-1800s contributed to our understanding of
the particulate nature of inheritance as well as the basic genetic transmission patterns. With what
organism did this person work?
A) Gregor Mendel; Pisum sativum
B) George Beadle; Neurospora
C) Thomas Hunt Morgan; Drosophila
D) Calvin Bridges; Drosophila
E) Boris Ephrussi; Ephestia
Answer: A
Section: Introduction
3) A recessive allele in tigers causes the white tiger. If two normally pigmented tigers are mated
and produce a white offspring, what percentage of their remaining offspring would be expected
to have normal pigmentation?
A) 25%
B) 50%
C) about 66%
D) 75%
E) about 90%
Answer: D
Section: 3.2
4) Polydactyly is expressed when an individual has extra fingers and/or toes. Assume that a man
with six fingers on each hand and six toes on each foot marries a woman with a normal number
of digits. Having extra digits is caused by a dominant allele. The couple has a son with normal
hands and feet, but the couple's second child has extra digits. What is the probability that their
next child will have polydactyly?
A) 1/32
B) 1/8
C) 7/16
D) 1/2
E) 3/4
Answer: D
Section: 3.2
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5) Tightly curled or wooly hair is caused by a dominant gene in humans. If a heterozygous curly-
haired person marries a person with straight hair, what percentage of their offspring would be
expected to have straight hair?
A) 25% curly
B) 50% straight
C) 75% curly
D) 100% straight
E) It is impossible to predict the outcome.
Answer: B
Section: 3.2
6) Which types of phenotypic ratios are likely to occur in crosses when dealing with a single
gene pair for which all the genotypic combinations are of equal viability?
A) 9:3:3:1, 27:9:9:9:3:3:3:1
B) 1:2:1, 3:1
C) 1:4:6:4:1, 1:1:1:1
D) 12:3:1, 9:7
E) 2:3, 1:2
Answer: B
Section: 3.2
7) Assume that a black guinea pig crossed with an albino guinea pig produced 5 black offspring.
When the albino was crossed with a second black guinea pig, 4 black and 3 albino offspring were
produced. What genetic explanation would apply to these data?
A) albino = recessive; black = recessive
B) albino = dominant; black = incompletely dominant
C) albino and black = codominant
D) albino = recessive; black = dominant
E) None of the answers listed is correct.
Answer: D
Section: 3.2
8) The fundamental Mendelian process that involves the separation of contrasting genetic
elements at the same locus would be called ________.
A) segregation
B) independent assortment
C) continuous variation
D) discontinuous variation
E) dominance or recessiveness
Answer: A
Section: 3.2

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9) The Chi-square test involves a statistical comparison between measured (observed) and
predicted (expected) values. One generally determines degrees of freedom as ________.
A) the number of categories being compared
B) one less than the number of classes being compared
C) one more than the number of classes being compared
D) ten minus the sum of the two categories
E) the sum of the two categories
Answer: B
Section: 3.8
10) Assume that in a series of experiments, plants with round seeds were crossed with plants
with wrinkled seeds and the following offspring were obtained: 220 round and 180 wrinkled.a)
What is the most probable genotype of each parent?
(b) What genotypic and phenotypic ratios are expected?
(c) Based on the information provided in part (b), what are the expected (theoretical) numbers of
progeny (400 total) of each phenotypic class?
Answer:
(a) assuming that round (W) is dominant to wrinkled (w): Ww × ww
(b) 1:1
(c) 200
Section: 3.2
11) In peas, gray seed color is dominant to white. For the purposes of this question, assume that
Mendel crossed plants with gray seeds with each other and the following progeny were
produced: 320 gray and 80 white.
(a) What is the most probable genotype of each parent?
(b) What genotypic and phenotypic ratios are expected in the progeny of such a cross?
Answer:
(a) assuming the following symbols: G = gray and g = white, Gg × Gg
(b) genotypic = 1:2:1, phenotypic = 3:1
Section: 3.2

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12) Assume that you have a garden and some pea plants have solid leaves and others have
striped leaves. You conduct a series of crosses [(a) through (e)] and obtain the results given in
the table.
Cross Progeny
solid striped
(a) solid × striped 55 60
(b) solid × solid 36 0
(c) striped × striped 0 65
(d) solid × solid 92 30
(e) solid × striped 44 0
Define gene symbols and give the possible genotypes of the parents of each cross.
Answer:
(a) From cross (d), assume that solid (S) is dominant to striped (s): Ss × ss.
(b) SS × SS or SS × Ss
(c) ss × ss
(d) Ss × Ss
(e) SS × ss
Section: 3.2
13) The phenotype of vestigial (short) wings (vg) in Drosophila melanogaster is caused by a
recessive mutant gene that independently assorts with a recessive gene for hairy (h) body.
Assume that a cross is made between a fly with normal wings and a hairy body and a fly with
vestigial wings and normal body hair. The wild-type F1 flies were crossed among each other to
produce 1024 offspring. Which phenotypes would you expect among the 1024 offspring, and
how many of each phenotype would you expect?
Answer: Phenotypes: wild, vestigial, hairy, vestigial hairy
Numbers expected: wild (576), vestigial (192), hairy (192), vestigial hairy (64)
Section: 3.3
14) Two organisms, AABBCCDDEE and aabbccddee, are mated to produce an F1 that is self-
fertilized. If the capital letters represent dominant, independently assorting alleles:
(a) How many different genotypes will occur in the F2?
(b) What proportion of the F2 genotypes will be recessive for all five loci?
(c) Would you change your answers to (a) and/or (b) if the initial cross occurred between
AAbbCCddee × aaBBccDDEE parents?
(d) Would you change your answers to (a) and/or (b) if the initial cross occurred between
AABBCCDDEE × aabbccddEE parents?
Answer:
(a) 35 = 243
(b) 1/243
(c) no
(d) yes
Section: 3.4

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15) How many different kinds of gametes can be produced by an individual with the genotype
AABbCCddEeFf?
Answer: 23 = 8
Section: 3.4
16) Albinism, lack of pigmentation in humans, results from an autosomal recessive gene (a).
Two parents with normal pigmentation have an albino child.
(a) What is the probability that their next child will be albino?
(b) What is the probability that their next child will be an albino girl?
(c) What is the probability that their next three children will be albino?
Answer:
(a) 1/4
(b) 1/4 × 1/2 = 1/8
(c) 1/4 × 1/4 × 1/4 = 1/64
Section: 3.2
17) Dentinogenesis imperfecta is a rare, autosomal, dominantly inherited disease of the teeth that
occurs in about one in 8000 people (Witkop 1957). The teeth are somewhat brown in color, and
the crowns wear down rapidly. Assume that a male with dentinogenesis imperfecta and no
family history of the disease marries a woman with normal teeth. What is the probability that
(a) their first child will have dentinogenesis imperfecta?
(b) their first two children will have dentinogenesis imperfecta?
(c) their first child will be a girl with dentinogenesis imperfecta?
Answer:
(a) 1/2
(b) 1/2 × 1/2 = 1/4
(c) 1/2 × 1/2 = 1/4
Section: 3.2

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18) A certain type of congenital deafness in humans is caused by a rare autosomal (not X-linked)
dominant gene.
(a) In a mating involving a deaf man and a deaf woman (both heterozygous), would you expect
all the children to be deaf? Explain your answer.
(b) In a mating involving a deaf man and a deaf woman (both heterozygous), could all the
children have normal hearing? Explain your answer.
(c) Another form of deafness is caused by a rare autosomal recessive gene. In a mating involving
a deaf man and a deaf woman, could some of the children have normal hearing? Explain your
answer.
Answer:
(a) No. In a mating involving heterozygotes, three genotypic classes are expected in the
offspring: fully dominant, fully recessive, and heterozygous.
(b) Assuming that the parents are heterozygotes (because the gene is rare), it is possible that all
of the children could have normal hearing.
(c) Since the gene in question is recessive, both of the parents are homozygous and one would
not expect normal hearing in the offspring.
Section: 3.2

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19) Among dogs, short hair is dominant to long hair and dark coat color is dominant to white
(albino) coat color. Assume that these two coat traits are caused by independently segregating
gene pairs. For each of the crosses given below, write the most probable genotype (or genotypes
if more than one answer is possible) for the parents. It is important that you select a realistic
symbol set and define each symbol below.
Parental Phenotypes Phenotypes of Offspring
Short Long Short Long
Dark Dark Albino Albino
(a) dark, short × dark, long 26 24 0 0
(b) albino, short × albino, short 0 0 102 33
(c) dark, short × albino, short 16 0 16 0
(d) dark, short × dark, short 175 67 61 21
Assume that for cross (d), you were interested in determining whether fur color follows a 3:1
ratio. Set up (but do not complete the calculations) a Chi-square test for these data [fur color in
cross (d)].
Answer: Let A = dark, a = albino and L = short, l = long
(a) AALl × AAll or AALl × Aall
(b) aaLl × aaLl
(c) AaLL × aaLL or AaLl × aaLL or AaLL × aaLl
(d) AaLl × AaLl
x2 = ∑
e
e)-(o 2
= (242 - 243)2 /243 + (82 - 81)2 /81
Section: 3.3, 3.8
20) Which phenotypic ratio is likely to occur in crosses of two completely dominant,
independently segregating gene pairs when both parents are fully heterozygous?
Answer: 9:3:3:1
Section: 3.3
21) Provide simple definitions that distinguish segregation and independent assortment.
Answer: Segregation is the separation of alleles during meiosis; independent assortment states
that a member of one gene pair has an equal and independent opportunity of segregating with
either member of another gene pair.
Section: 3.3
22) In what ways is sample size related to statistical testing?
Answer: By increasing sample size, one increases the reliability of the statistical test and
decreases the likelihood of erroneous conclusions from chance fluctuations in the data.
Section: 3.8

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23) In a Chi-square analysis, what condition causes one to reject (fail to accept) the null
hypothesis?
Answer: usually when the probability value is less than 0.05
Section: 3.8
24) If one is testing a goodness of fit to a 9:3:3:1 ratio, how many degrees of freedom would be
associated with the Chi-square analysis?
Answer: number of classes minus 1 = 3
Section: 3.8
25) Assuming no crossing over between the gene in question and the centromere, when do alleles
segregate during meiosis?
Answer: meiosis I, when homologous chromosomes go to opposite poles
Section: 3.2
26) Assuming a typical monohybrid cross in which one allele is completely dominant to the
other, what ratio is expected if the F1s are crossed?
Answer: 3:1
Section: 3.2
27) Under what conditions does one expect a 9:3:3:1 ratio?
Answer: dihybrid cross (F2) with independently assorting, completely dominant genes
Section: 3.3
28) Under what conditions does one expect a 1:1:1:1 ratio?
Answer: This occurs in a cross involving doubly heterozygous individuals crossed to fully
recessive individuals. The genes involved assort independently.
Section: 3.3
29) What is the probability of flipping a penny and a nickel and obtaining one head and one tail?
Answer: 1/2 (apply the "sum law")
Section: 3.7
30) How many kinds of gametes will be expected from an individual with the genotype
PpCcTTRr?
Answer: 8
Section: 3.4
31) Assume that a Chi-square test was conducted to test the goodness of fit to a 9:3:3:1 ratio and
a Chi-square value of 10.62 was obtained. Should the null hypothesis be accepted?
Answer: no
Section: 3.8

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32) Assume that a Chi-square test was conducted to test the goodness of fit to a 3:1 ratio and that
a Chi-square value of 2.62 was obtained. Should the null hypothesis be accepted? How many
degrees of freedom would be associated with this test of significance?
Answer: yes; 1
Section: 3.8
33) Assume that a Chi-square test provided a probability value of 0.02. Should the null
hypothesis be accepted?
Answer: no
Section: 3.8
34) In studies of human genetics, usually a single individual brings the condition to the attention
of a scientist or physician. When pedigrees are developed to illustrate transmission of the trait,
what term does one use to refer to this individual?
Answer: proband
Section: 3.9
Two parents with normal pigmentation have an albino child. What is the probability that their
next child will be albino?
Answer: 1/4
Section: 3.2
next child will be an albino girl?
Answer: 1/4 × 1/2 = 1/8
Section: 3.2
next three children will be albino?
Answer: 1/4 × 1/4 × 1/4 = 1/64
Section: 3.2
38) The autosomal (not X-linked) gene for brachydactyly, short fingers, is dominant to normal
finger length. Assume that a female with brachydactyly in the heterozygous condition is married
to a man with normal fingers. What is the probability that
(a) their first child will have brachydactyly?
(b) their first two children will have brachydactyly?
(c) their first child will be a brachydactylous girl?
Answer:
(a) 1/2
(b) 1/2 × 1/2 = 1/4
(c) 1/2 × 1/2 = 1/4
Section: 3.2

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39) Tightly curled hair is caused by a dominant autosomal gene in humans. If a heterozygous
curly-haired person marries a person with straight hair, what phenotypes (and in what
proportions) are expected in the offspring?
Answer: 1/2 curly (because the curly-haired individual is most likely heterozygous); 1/2 straight
hair
Section: 3.2
40) A certain type of congenital deafness in humans is caused by a rare autosomal dominant
gene. In a mating involving a deaf man and a deaf woman (both heterozygous), would you
expect all the children to be deaf? Explain your answer.
Answer: No. In a mating involving heterozygotes, three genotypic classes are expected in the
offspring: fully dominant, fully recessive, and heterozygous.
Section: 3.2
41) A certain type of congenital deafness in humans is caused by a rare autosomal dominant
gene. In a mating involving a deaf man and a deaf woman, could all the children have normal
hearing? Explain your answer.
Answer: Assuming that the parents are heterozygotes (because the gene is rare), it is possible
that all of the children could have normal hearing.
Section: 3.2
42) A certain type of congenital deafness in humans is caused by a rare autosomal recessive
gene. In a mating involving a deaf man and a deaf woman, could some of the children have
normal hearing? Explain your answer.
Answer: Since the gene in question is recessive, both of the parents are homozygous and one
would not expect normal hearing in the offspring.
Section: 3.2
43) For the purposes of this question, assume that being Rh+ is a consequence of D and that Rh-
individuals are dd. The ability to taste phenylthiocarbamide (PTC) is determined by the gene
symbolized T (tt are nontasters). A female whose mother was Rh- has the MN blood group, is
Rh+ and a nontaster of PTC, and is married to a man who is MM, Rh-, and a nontaster. List the
possible genotypes of the children. Assume that all the loci discussed in this problem are
autosomal and independently assorting.
Answer: MMDdtt, MMddtt, MNDdtt, MNddtt
Section: 3.4
44) What conditions are likely to apply if the progeny from the cross AaBb × AaBb appear in the
9:3:3:1 ratio?
Answer: complete dominance, independent assortment, no gene interaction
Section: 3.3

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45) Assume that a cross is made between a heterozygous tall pea plant and a homozygous short
pea plant. Fifty offspring are produced in the following frequency:
30 = tall
20 = short
(a) What frequency of tall and short plants is expected?
(b) To test the goodness of fit between the observed and expected values, provide the needed
statement of the null hypothesis.
(c) Compute a Chi-square value associated with the appropriate test of significance.
(d) How many degrees of freedom are associated with this test of significance?
Answer:
(a) 1:1 (25 tall and 25 short)
(b) The deviations from a 1:1 ratio (25 tall and 25 short) are due to chance.
(c) x2 = 2
(d) 1
Section: 3.2, 3.8
46) According to Mendel's model, because of ________, all possible combinations of gametes
will be formed in equal frequency.
Answer: independent assortment
Section: Introduction
47) Assuming independent assortment, what proportion of the offspring of the cross AaBbCcDd
× AabbCCdd will have the aabbccdd genotype?
Answer: zero
Section: 3.4
48) In a statistical sense, as the sample size increases, the average deviation from the expected
fraction or ratio is expected to ________.
Answer: decrease
Section: 3.8
49) In a Chi-square test, as the value of the x2 increases, the likelihood of rejecting the null
hypothesis ________.
Answer: increases
Section: 3.8
50) Mendel's postulate of independent assortment is supported by a 1:1:1:1 testcross ratio.
Answer: TRUE
Section: 3.3
51) Mendel's Law of Segregation is supported by a 1:1 testcross ratio.
Answer: TRUE
Section: 3.2

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52) Mendel's discoveries were well received and understood by his contemporaries.
Answer: FALSE
Section: 3.5
53) The nonfunctional form of a gene is called a wild-type allele.
Answer: FALSE
Section: 3.5
54) A gene can have a maximum of two alleles.
Answer: FALSE
Section: 3.5
55) To test Mendel's Law of Segregation, the experimenter needs a minimum of two contrasting
forms of a gene.
Answer: TRUE
Section: 3.2
56) A 1:1 phenotypic ratio is expected from a monohybrid testcross with complete dominance.
Answer: TRUE
Section: 3.2
57) Assuming complete dominance, a 3:1 phenotypic ratio is expected from a monohybrid sib or
self-cross.
Answer: TRUE
Section: 3.2
58) A 9:3:3:1 phenotypic ratio is expected from a dihybrid testcross.
Answer: FALSE
Section: 3.3
Concepts Of Genetics 10th Edition Klug Test Bank
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