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Two Problems on the Application
of Fundamentals of Trigonometry

       SUBMITTED TO: PROF. LAWAS
     SUBMITTED BY: GIANNE ITARALDE




          T/TH 9:40-11:10 CLASS
Problem #1

    A boat with only one passenger is lost at sea. The
passenger, being tired and all, is losing hope that he
might not find land anymore and so, he slept. After a
few hours, he woke up and saw a 115-feet high
lighthouse from a distance.

    The angle of elevation from the boat to the top of
the lighthouse is 10°. How far does he need to travel to
get to land?
Illustration


1
1
5

f
e
e
t
                   10 °

              _?_ feet
Solution
    A
                                        Angle:             Line:
115 feet

                                         A = 80 °           a = 652.1974 ft
                                         B = 10 °           b = 115 ft.
                   c                     C = 90 °
b

                        10 °

    C         unknown             B
               a
To find Angle A:
        Line a:
                            Tan A = _a_ 80= _a_
                               115 (Tan –180 ==(90 + Angle
                                       Tan
                         Tan A Angle 652.1974–_a_)°115 Side
                                  = = A =80°A = = C
                          Angle= Opposite(AngleaAdjacent B)
                                A a 115 (5.6713)feet 10)
                                     180 Side / a
                                      652.1974 80
                                       Angle
                                        b        115
                                                115
                         EquationAnswerfor Tan sum of Angles
                          Equation(SOH-CAH-TOA)
                               Substitute
                                    (Subtract the 80°
                                    Solve
                                      Multiply
                                      Answer
                             Equation (SOH-CAH-TOA)
                          C and Multiply both sides by 115
                                B from 180 °)
                             Tan A is equal to a divided by b
                                      Substitute
Answer to Problem #1


      The passenger needs to travel
      652.1974 feet to get to land.




            652.1974 feet
Problem #2

   The leaning tower of Pisa is tilted at an angle of 4.6°
from the vertical. An observer standing 100m from the
base of the tower measures the angle of elevation to be
30°. Find the height of the tower.
Illustration




_?_ m

     100m      30°
Solution

     A                                     Angle:              Line:
                                            A = 64.6°           a = 100m
                                            B = 30°             b = 55.3526m
  4.6°
     b                   c                  C = 85.4°



                   100m              30°
C                    a                           B
To find Angle C:
        Line b:
              A:

                     10064.6 Sin 50 b
                     0.9033=== =Sin )0.5
                     Sin0.9033 0.5= 30 ) 100
                     b ( ( 0.9033 __50__
                      Sin A
                       (0.9033) = B
                     b 100 A 85.4° (30
                     Angle C = 90 –-4.6 ° +85.4 °)
                       = 55.3526m
                               64.6°
                               180
                      0.9033 b b b b
                        100
                        a 100 0.9033
                                  b
                     Solve andSin sum of 90your 30and
                     Subtract 4.6 ° sidesbe the answer C from 180
                     Multiply both will and Sin
                     Solve for both fromLaw°of B
                     Substitutethatsides by b Sines)
                     Equationthesides byby 100 answer
                                          Angles
                     Divide both 64.6
                     Multiply (Use the 0.9033
                     Law of Sines: Sin A/a = Sin B/b = Sin C/c
Answer to Problem #2


      The Leaning Tower of Pisa is
      55.3526m high.
End of Presentation
             GIANNE ITARALDE’S PROJECT FOR FUNTRIG




SOURCES OF IMAGES:
•H T T P : / / S T A T I C . D D M C D N . C O M
•H T T P : / / W W W . D R A G O A R T . C O M
•H T T P : / / D A T A . G R E A T B U I L D I N G S . C O M
•H T T P : / / B O U . M E

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funtrig presentation

  • 1. Two Problems on the Application of Fundamentals of Trigonometry SUBMITTED TO: PROF. LAWAS SUBMITTED BY: GIANNE ITARALDE T/TH 9:40-11:10 CLASS
  • 2. Problem #1 A boat with only one passenger is lost at sea. The passenger, being tired and all, is losing hope that he might not find land anymore and so, he slept. After a few hours, he woke up and saw a 115-feet high lighthouse from a distance. The angle of elevation from the boat to the top of the lighthouse is 10°. How far does he need to travel to get to land?
  • 3. Illustration 1 1 5 f e e t 10 ° _?_ feet
  • 4. Solution A Angle: Line: 115 feet A = 80 ° a = 652.1974 ft B = 10 ° b = 115 ft. c C = 90 ° b 10 ° C unknown B a To find Angle A: Line a: Tan A = _a_ 80= _a_ 115 (Tan –180 ==(90 + Angle Tan Tan A Angle 652.1974–_a_)°115 Side = = A =80°A = = C Angle= Opposite(AngleaAdjacent B) A a 115 (5.6713)feet 10) 180 Side / a 652.1974 80 Angle b 115 115 EquationAnswerfor Tan sum of Angles Equation(SOH-CAH-TOA) Substitute (Subtract the 80° Solve Multiply Answer Equation (SOH-CAH-TOA) C and Multiply both sides by 115 B from 180 °) Tan A is equal to a divided by b Substitute
  • 5. Answer to Problem #1 The passenger needs to travel 652.1974 feet to get to land. 652.1974 feet
  • 6. Problem #2 The leaning tower of Pisa is tilted at an angle of 4.6° from the vertical. An observer standing 100m from the base of the tower measures the angle of elevation to be 30°. Find the height of the tower.
  • 7. Illustration _?_ m 100m 30°
  • 8. Solution A Angle: Line: A = 64.6° a = 100m B = 30° b = 55.3526m 4.6° b c C = 85.4° 100m 30° C a B To find Angle C: Line b: A: 10064.6 Sin 50 b 0.9033=== =Sin )0.5 Sin0.9033 0.5= 30 ) 100 b ( ( 0.9033 __50__ Sin A (0.9033) = B b 100 A 85.4° (30 Angle C = 90 –-4.6 ° +85.4 °) = 55.3526m 64.6° 180 0.9033 b b b b 100 a 100 0.9033 b Solve andSin sum of 90your 30and Subtract 4.6 ° sidesbe the answer C from 180 Multiply both will and Sin Solve for both fromLaw°of B Substitutethatsides by b Sines) Equationthesides byby 100 answer Angles Divide both 64.6 Multiply (Use the 0.9033 Law of Sines: Sin A/a = Sin B/b = Sin C/c
  • 9. Answer to Problem #2 The Leaning Tower of Pisa is 55.3526m high.
  • 10. End of Presentation GIANNE ITARALDE’S PROJECT FOR FUNTRIG SOURCES OF IMAGES: •H T T P : / / S T A T I C . D D M C D N . C O M •H T T P : / / W W W . D R A G O A R T . C O M •H T T P : / / D A T A . G R E A T B U I L D I N G S . C O M •H T T P : / / B O U . M E