• GENE LINKAGE & MAPPING
• By A.Arputha Selvaraj
KEY CONCEPT
Genes can be mapped to specific locations on
chromosomes.
Gene linkage was explained through fruit flies.
• Morgan found that linked traits are on the same
chromosome.
• Chromosomes, not genes, assort independently during
meiosis.
Wild type Mutant
• Linked genes are not inherited together every time.
• Chromosomes exchange homologous genes during
meiosis.
Linkage maps estimate distances between genes.
• The closer together two genes are, the more likely they will be
inherited together.
• Cross-over frequencies are related to distances between genes.
– The higher the frequency, the further the genes are apart
• Linkage maps show the relative locations of genes.
• Cross-over frequencies can be converted into map units.
• Ex: A 5% cross-over frequency equals 5 map units.
– gene A and gene B cross over 6.0
percent of the time
– gene B and gene C
cross over 12.5 percent
of the time
– gene A and gene C cross over 18.5 percent of the
time
Draw a linkage map based on the following cross over
percentages:
• A – B = 8%
• B – C = 10%
• A – C = 2%
8.0 2.0
B A C
8.0 + 2.0 = 10.0
Thanks

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GENE MAPPING 2

  • 1. • GENE LINKAGE & MAPPING • By A.Arputha Selvaraj
  • 2. KEY CONCEPT Genes can be mapped to specific locations on chromosomes.
  • 3. Gene linkage was explained through fruit flies. • Morgan found that linked traits are on the same chromosome. • Chromosomes, not genes, assort independently during meiosis. Wild type Mutant
  • 4. • Linked genes are not inherited together every time. • Chromosomes exchange homologous genes during meiosis.
  • 5. Linkage maps estimate distances between genes. • The closer together two genes are, the more likely they will be inherited together. • Cross-over frequencies are related to distances between genes. – The higher the frequency, the further the genes are apart • Linkage maps show the relative locations of genes.
  • 6. • Cross-over frequencies can be converted into map units. • Ex: A 5% cross-over frequency equals 5 map units. – gene A and gene B cross over 6.0 percent of the time – gene B and gene C cross over 12.5 percent of the time – gene A and gene C cross over 18.5 percent of the time
  • 7. Draw a linkage map based on the following cross over percentages: • A – B = 8% • B – C = 10% • A – C = 2% 8.0 2.0 B A C 8.0 + 2.0 = 10.0