Geo distance search with my sql presentation

Geo/Spatial Search with MySQL Alexander Rubin Senior Consultant, MySQL AB

Why Geo Search? Stores: find locations new you Social networks: find friends close to you Online maps: find points of interest near your position Online newspapers/yellow pages: find show times next to you home.

Common Tasks Task: Find 10 nearby hotels and sort by distance What do we have: Given point on Earth: Latitude, Longitude Hotels table: Question: How to calculate distance between us and hotel? Latitude Longitude Hotel Name

Distance between 2 points The Haversine Formula For two points on a sphere (of radius R) with latitudes φ1 and φ2, latitude separation Δφ = φ1 − φ2, and longitude separation Δλ the distance d between the two points:

The Haversine Formula in MySQL R = earth’s radius Δlat = lat2− lat1; Δlong = long2− long1 a = sin²(Δlat/2) + cos(lat1) * cos(lat2) * sin²(Δlong/2) c = 2*atan2(√a, √(1−a)); d = R*c 3956 * 2 * ASIN ( SQRT ( POWER(SIN((orig.lat - dest.lat)*pi()/180 / 2), 2) + COS(orig.lat * pi()/180) * COS(dest.lat * pi()/180) * POWER(SIN((orig.lon - dest.lon) * pi()/180 / 2), 2) ) ) as distance angles need to be in radians

MySQL Query: Find Nearby Hotels set @orig_lat=122.4058; set @orig_lon=37.7907; set @dist=10; SELECT *, 3956 * 2 * ASIN(SQRT( POWER(SIN((@orig_lat - abs( dest.lat)) * pi()/180 / 2), 2) + COS(@orig_lat * pi()/180 ) * COS( abs (dest.lat) * pi()/180) * POWER(SIN((@orig_lon – dest.lon) * pi()/180 / 2), 2) )) as distance FROM hotels dest having distance < @dist ORDER BY distance limit 10; Lat can be negative!

Find Nearby Hotels: Results +----------------+--------+-------+--------+ | hotel_name | lat | lon | dist | +----------------+--------+-------+--------+ | Hotel Astori.. | 122.41 | 37.79 | 0.0054 | | Juliana Hote.. | 122.41 | 37.79 | 0.0069 | | Orchard Gard.. | 122.41 | 37.79 | 0.0345 | | Orchard Gard.. | 122.41 | 37.79 | 0.0345 | ... +----------------+--------+-------+--------+ 10 rows in set (4.10 sec) 4 seconds - very slow for web query!

MySQL Explain query Mysql> Explain … select_type: SIMPLE table: dest type: ALL possible_keys: NULL key: NULL key_len: NULL ref: NULL rows: 1787219 Extra: Using filesort 1 row in set (0.00 sec)

How to speed up the query We only need hotels in 10 miles radius no need to scan the whole table 10 Miles

How to calculate needed coordinates 1 ° of latitude ~= 69 miles 1 ° of longitude ~= cos(latitude)*69 To calculate lon and lat for the rectangle: set lon1 = mylon-dist/abs(cos(radians(mylat))*69); set lon2 = mylon+dist/abs(cos(radians(mylat))*69); set lat1 = mylat-(dist/69); set lat2 = mylat+(dist/69);

Modify the query SELECT destination.*, 3956 * 2 * ASIN(SQRT( POWER(SIN((orig.lat - dest.lat) * pi()/180 / 2), 2) + COS(orig.lat * pi()/180) * COS(dest.lat * pi()/180) * POWER(SIN((orig.lon -dest.lon) * pi()/180 / 2), 2) )) as distance FROM users destination, users origin WHERE origin.id=userid and destination.longitude between lon1 and lon2 and destination.latitude between lat1 and lat2

Stored procedure CREATE PROCEDURE geodist (IN userid int, IN dist int) BEGIN declare mylon double; declare mylat double; declare lon1 float; declare lon2 float; declare lat1 float; declare lat2 float; -- get the original lon and lat for the userid select longitude, latitude into mylon, mylat from users5 where id=userid limit 1; -- calculate lon and lat for the rectangle: set lon1 = mylon-dist/abs(cos(radians(mylat))*69); set lon2 = mylon+dist/abs(cos(radians(mylat))*69); set lat1 = mylat-(dist/69); set lat2 = mylat+(dist/69);

Stored Procedure, Contd -- run the query: SELECT destination.*, 3956 * 2 * ASIN(SQRT( POWER(SIN((orig.lat - dest.lat) * pi()/180 / 2), 2) + COS(orig.lat * pi()/180) * COS(dest.lat * pi()/180) * POWER(SIN((orig.lon -dest.lon) * pi()/180 / 2), 2) )) as distance FROM users destination, users origin WHERE origin.id=userid and destination.longitude between lon1 and lon2 and destination.latitude between lat1 and lat2 having distance < dist ORDER BY Distance limit 10; END $$

Speed comparison Test data: US and Canada zip code table, 800K records Original query (full table scan): 8 seconds Optimized query (stored procedure): 0.06 to 1.2 seconds (depending upon the number of POIs/records in the given radius)

Stored Procedure: Explain Plan Mysql>CALL geodist(946842, 10)\G table: origin type: const key: PRIMARY key_len: 4 ref: const rows: 1, Extra: Using filesort table: destination type: range key: latitude key_len: 18 ref: NULL rows: 25877, Extra: Using where

Geo Search with Sphinx Sphinx search (www.sphinxsearch.com) since 0.9.8 can perform geo distance searches It is possible to setup an "anchor point" in the api code and then use the "geodist" function and specify the radius. Sphinx Search returns in 0.55 seconds for test data regardless of the radius and zip $ php test.php -i zipdist -s @geodist,asc Query '' retrieved 1000 matches in 0.552 sec.

Speed comparison of all solutions

Different Type of Coordinates Decimal Degrees (what we used) 37.3248 LAT, 121.9163 LON Degrees-minutes-second (used in most GPSes) 37°19′29″N LAT, 121°54′59″E LON Most GPSes can be configured to use Decimal Degrees Other

Converting between coordinates Degrees-Minutes-Seconds to Decimal Degrees : degrees + (minutes/60) + (seconds/3600) CREATE FUNCTION `convert_from_dms` (degrees INT, minutes int, seconds int) RETURNS double DETERMINISTIC BEGIN RETURN degrees + (minutes/60) + (seconds/3600); END $$ mysql>select convert_from_dms (46, 20, 10) as DMS\G dms: 46.33611111

Geo Search with Full Text search Sometimes we need BOTH geo search and full text search Example 1: find 10 nearest POIs, with “school” in the name Example 2: find nearest streets, name contains “OAK” Create FullText index and index on LAT, LON Alter table geonames add fulltext key (name); MySQL will choose which index to use

Geo Search with Full Text search: example Grab POI data from www.geonames.org, upload it to MySQL, add full text index Mysql> SELECT destination.*, 3956 * 2 * ASIN(SQRT(POWER(SIN((orig.lat - dest.lat) * pi()/180 / 2), 2) + COS(orig.lat * pi()/180) * COS(dest.lat * pi()/180) * POWER(SIN((orig.lon -dest.lon) * pi()/180 / 2), 2) )) as distance FROM geonames destination WHERE match(name) against (‘OAK’ in boolean mode) having distance < dist ORDER BY Distance limit 10;

Geo Search with Full Text search: Explain mysql> explain SELECT destination.*, 3956 * 2 * ASIN(SQRT(POWER(SIN(… table: destination type: fulltext possible_keys: name_fulltext key: name_fulltext key_len: 0 ref: rows: 1 Extra: Using where; Using filesort

DEMO DEMO: Find POI near us Use GPS All POIs near GPS point Match keyword

Using MySQL Spatial Extension CREATE TABLE `zipcode_spatial` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `zipcode` char(7) NOT NULL, … `lon` int(11) DEFAULT NULL, `lat` int(11) DEFAULT NULL, `loc` point NOT NULL, PRIMARY KEY (`id`), KEY `zipcode` (`zipcode`), SPATIAL KEY `loc` (`loc`) ) ENGINE=MyISAM;

Zipcode with Spatial Extension mysql> select zipcode, lat, lon, AsText(loc) from zipcode_spatial where city_name = 'Santa Clara' and state ='CA' limit 1\G ****** 1. row******** zipcode: 95050 lat: 373519 lon: 1219520 AsText(loc): POINT(1219520 373519)

Spatial Search: Distance Spatial Extension: no built-in distance function CREATE FUNCTION `distance` (a POINT, b POINT) RETURNS double DETERMINISTIC BEGIN RETURN round(glength(linestringfromwkb (linestring(asbinary(a), asbinary(b))))); END $$ ( forge.mysql.com/tools/tool.php?id=41 )

Spatial Search Example SELECT DISTINCT dest.zipcode, distance(orig.loc, dest.loc) as sdistance FROM zipcode_spatial orig, zipcode_spatial dest WHERE orig.zipcode = '27712' having sdistance < 10 ORDER BY sdistance limit 10;

Geo distance search with my sql presentation

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