Geometry unit 3.7
 The ratio of its vertical rise to its horizontal 
run. 
 Steepness 
Slope = m = 
Vertical rise 
Horizontal run
Find the slopes. 
8  
 m 
2 
8 
2 
m  
-8 
2 
 4 
4 
m   2 
2 
2 
4
 of a line containing two points with 
coordinates (x1, y1) and (x2, y2) is 
given by the formula 
y  
y 
2 1 
x x 
2 1 
m 
 

Slopes 
y  
y 
2 1 
x x 
2 1 
m 
 
 
5  
5 
  
1 3 
 
All horizontal 
lines have a 0 
slope 
All vertical lines 
have an 
undefined 
slope 
0 
  0 
4 
y  
y 
2 1 
x x 
2 1 
m 
 
 
  
 
4 3 
 
6 6 
 7 
  undefined 
0
 Rise (upward) as you move left to right 
Line slopes 
up from left 
to right 
y 
x
 Fall (downward) as you move left to right 
Line slopes 
down from 
left to right 
y 
x
Find the slope using the 
slope formula. 
y  
y 
2 1 
x x 
2 1 
m 
 
 
7 
 
8 
  
 
5 2 
  
2 6 
7 
 
8 
 
 
y  
y 
2 1 
x x 
2 1 
m 
 
 
0   
1 
  
4 0 
 
1 
 
4 
 
1 
 
4
 Describes how a quantity is changing over 
time. 
 The slope of a line can be used to 
determine the Rate of Change 
y 
 
x 
 
 
Change in quantity (y) 
Change in time (x)
Recreation: For one manufacturer of camping equipment, 
between 1990 and 2000 annual sales increased by $7.4 million 
per year. In 2000, the total sales were $85.9 million. If the 
sales increase at the same rate, what will be the total sales in 
2010? 
y  
y 
2 1 
x x 
2 1 
m 
 
 
 
7.4 
1 
y  
85.9 2 
 
2010 2000 
85.9 
7.4 2  
10 
1 
 
y 
7.4(10) = y2 – 85.9 
74.0 = y2 – 85.9 
+85.9 +85.9 
159.9 mill. = y2
 Slope-Intercept Form - 
y = mx + b 
slope y-intercept 
 Point-Slope Form - 
y – y1 = m(x – x1) 
y-coordinate slope x-coordinate
1 
2 
y  x  
3 
1 
2 
y  x  
3 
1.) The equation is in slope-intercept form y = mx + b 
2 
3 
The slope is 
y-intercept (0, 1) 
2.) Plot the point (0, 1) 
2 
3.) Use the slope , from 
3 
the point (0, 1) go up 2, 
right 3
y  3x 1 
1.) The equation is in slope-intercept form y = mx + b 
1 
2 
y  x  
3 
The slope is 3 
y-intercept (0, 1) 
2.) Plot the point (0, 1) 
3.) Use the slope 3, from 
the point (0, 1) go up 3, 
right 1
1.) The equation is in point-slope form y – y1 = m(x – x1) 
The slope is -2 
Point on line (-3, 3) 
2.) Plot the point (-3, 3) 
3.) Use the slope -2, from 
the point (-3, 3) go 
down 2, right 1
1 
y  2   x  
( 4) 
3 
1.) The equation is in point-slope form y – y1 = m(x – x1) 
1 
 The slope is 
3 
Point on line (4, 2) 
2.) Plot the point (4, 2) 
1 
 
3.) Use the slope , from 
3 
the point (4, 2) go 
down 1, right 3
 If we know the slope and at least one point 
 If we have the slope and y-intercept, use the 
slope-intercept form; y = mx + b 
 If we have the slope and a point, use the 
point-slope form; y – y1 = m(x – x1)
What is an equation of the line with slope 3 
and y-intercept -5? 
 Start with the slope-intercept form of 
the equation 
y = mx + b 
y = 3x + (-5) Substitute 3 for m, and -5 
for b 
y = 3x - 5 Simplify
What is an equation of the line through point 
(-1, 5) with slope 2? 
 Start with the point-slope form of the 
equation 
y – y1 = m(x – x1) 
y – 5 = 2(x - (-1)) Substitute 2 for m, and -1 
in for x1 and 5 in for y1 
y – 5 = 2(x + 1) Simplify
What is an equation of the line with 
1 
 
slope and y-intercept 2? 
2 
 Start with the slope-intercept form of 
the equation 
y = mx + b 
1 
1 
 
y = x + 2  
Substitute for m, and 
2 for b 2 
2
What is an equation of the line through point 
(-1, 4) with slope -3? 
 Start with the point-slope form of the 
equation 
y – y1 = m(x – x1) 
y – 4 = -3(x - (-1)) Substitute -3 for m, and -1 
in for x1 and 4 in for y1 
y – 4 = -3(x + 1) Simplify
 If we know two points on the line 
 Find the slope using the formula 
 Using the point-slope formula 
 Plug in one of the two points 
 Plug in the slope for m
What is an equation of the line through point (-2, -1) 
and point (3, 5)? 
y  
y 
2 1 
x x 
2 1 
m 
 
 Find the slope  
6 
y + 1 = (x + 2) or 
5 
6 
  
 
5 1 
  
6 
 
6 
 
y - 3 = (x - 5) 
5 
3 2 
5 
 
 
5 
 Start with the point-slope form of the equation 
y – y1 = m(x – x1) 
 Plug in the slope and one of the two points
 We don’t need a slope 
 All points on a horizontal line have the 
same y-coordinate; so the equation is y = y1. 
 All points on a vertical line have the same 
x-coordinate; so the equation is x = x1. 
 Where (x1, y1)
What are the equations for the horizontal and 
vertical lines through (2, 4)? 
 The horizontal is y = y1 
y = 4 Substitute 4 for y1 
 The vertical is x = x1 
x = 2 Substitute 2 for x1
What are the equations for the horizontal and 
vertical lines through (4, -3)? 
 The horizontal is y = y1 
y = -3 Substitute -3 for y1 
 The vertical is x = x1 
x = 4 Substitute 4 for x1
All rights belong to their respective owners. 
Copyright Disclaimer Under Section 107 of the Copyright Act 1976, 
allowance is made for "fair use" for purposes such as criticism, comment, 
news reporting, TEACHING, scholarship, and research. 
Fair use is a use permitted by copyright statute that might otherwise be 
infringing. 
Non-profit, EDUCATIONAL or personal use tips the balance in favor of fair 
use.

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Geometry unit 3.7

  • 2.  The ratio of its vertical rise to its horizontal run.  Steepness Slope = m = Vertical rise Horizontal run
  • 3. Find the slopes. 8   m 2 8 2 m  -8 2  4 4 m   2 2 2 4
  • 4.  of a line containing two points with coordinates (x1, y1) and (x2, y2) is given by the formula y  y 2 1 x x 2 1 m  
  • 5. Slopes y  y 2 1 x x 2 1 m   5  5   1 3  All horizontal lines have a 0 slope All vertical lines have an undefined slope 0   0 4 y  y 2 1 x x 2 1 m      4 3  6 6  7   undefined 0
  • 6.  Rise (upward) as you move left to right Line slopes up from left to right y x
  • 7.  Fall (downward) as you move left to right Line slopes down from left to right y x
  • 8. Find the slope using the slope formula. y  y 2 1 x x 2 1 m   7  8    5 2   2 6 7  8   y  y 2 1 x x 2 1 m   0   1   4 0  1  4  1  4
  • 9.  Describes how a quantity is changing over time.  The slope of a line can be used to determine the Rate of Change y  x   Change in quantity (y) Change in time (x)
  • 10. Recreation: For one manufacturer of camping equipment, between 1990 and 2000 annual sales increased by $7.4 million per year. In 2000, the total sales were $85.9 million. If the sales increase at the same rate, what will be the total sales in 2010? y  y 2 1 x x 2 1 m    7.4 1 y  85.9 2  2010 2000 85.9 7.4 2  10 1  y 7.4(10) = y2 – 85.9 74.0 = y2 – 85.9 +85.9 +85.9 159.9 mill. = y2
  • 11.  Slope-Intercept Form - y = mx + b slope y-intercept  Point-Slope Form - y – y1 = m(x – x1) y-coordinate slope x-coordinate
  • 12. 1 2 y  x  3 1 2 y  x  3 1.) The equation is in slope-intercept form y = mx + b 2 3 The slope is y-intercept (0, 1) 2.) Plot the point (0, 1) 2 3.) Use the slope , from 3 the point (0, 1) go up 2, right 3
  • 13. y  3x 1 1.) The equation is in slope-intercept form y = mx + b 1 2 y  x  3 The slope is 3 y-intercept (0, 1) 2.) Plot the point (0, 1) 3.) Use the slope 3, from the point (0, 1) go up 3, right 1
  • 14. 1.) The equation is in point-slope form y – y1 = m(x – x1) The slope is -2 Point on line (-3, 3) 2.) Plot the point (-3, 3) 3.) Use the slope -2, from the point (-3, 3) go down 2, right 1
  • 15. 1 y  2   x  ( 4) 3 1.) The equation is in point-slope form y – y1 = m(x – x1) 1  The slope is 3 Point on line (4, 2) 2.) Plot the point (4, 2) 1  3.) Use the slope , from 3 the point (4, 2) go down 1, right 3
  • 16.  If we know the slope and at least one point  If we have the slope and y-intercept, use the slope-intercept form; y = mx + b  If we have the slope and a point, use the point-slope form; y – y1 = m(x – x1)
  • 17. What is an equation of the line with slope 3 and y-intercept -5?  Start with the slope-intercept form of the equation y = mx + b y = 3x + (-5) Substitute 3 for m, and -5 for b y = 3x - 5 Simplify
  • 18. What is an equation of the line through point (-1, 5) with slope 2?  Start with the point-slope form of the equation y – y1 = m(x – x1) y – 5 = 2(x - (-1)) Substitute 2 for m, and -1 in for x1 and 5 in for y1 y – 5 = 2(x + 1) Simplify
  • 19. What is an equation of the line with 1  slope and y-intercept 2? 2  Start with the slope-intercept form of the equation y = mx + b 1 1  y = x + 2  Substitute for m, and 2 for b 2 2
  • 20. What is an equation of the line through point (-1, 4) with slope -3?  Start with the point-slope form of the equation y – y1 = m(x – x1) y – 4 = -3(x - (-1)) Substitute -3 for m, and -1 in for x1 and 4 in for y1 y – 4 = -3(x + 1) Simplify
  • 21.  If we know two points on the line  Find the slope using the formula  Using the point-slope formula  Plug in one of the two points  Plug in the slope for m
  • 22. What is an equation of the line through point (-2, -1) and point (3, 5)? y  y 2 1 x x 2 1 m   Find the slope  6 y + 1 = (x + 2) or 5 6    5 1   6  6  y - 3 = (x - 5) 5 3 2 5   5  Start with the point-slope form of the equation y – y1 = m(x – x1)  Plug in the slope and one of the two points
  • 23.  We don’t need a slope  All points on a horizontal line have the same y-coordinate; so the equation is y = y1.  All points on a vertical line have the same x-coordinate; so the equation is x = x1.  Where (x1, y1)
  • 24. What are the equations for the horizontal and vertical lines through (2, 4)?  The horizontal is y = y1 y = 4 Substitute 4 for y1  The vertical is x = x1 x = 2 Substitute 2 for x1
  • 25. What are the equations for the horizontal and vertical lines through (4, -3)?  The horizontal is y = y1 y = -3 Substitute -3 for y1  The vertical is x = x1 x = 4 Substitute 4 for x1
  • 26. All rights belong to their respective owners. Copyright Disclaimer Under Section 107 of the Copyright Act 1976, allowance is made for "fair use" for purposes such as criticism, comment, news reporting, TEACHING, scholarship, and research. Fair use is a use permitted by copyright statute that might otherwise be infringing. Non-profit, EDUCATIONAL or personal use tips the balance in favor of fair use.