H2 Answers
- 1. 3.20 Balance the following: a) COMBUSTION C3H6 + O2 CO2 + H2O 2C3H6 + 9O2 6CO2 + 6H2O b) DECOMPOSITION NH4NO3 N2O + H2O NH4NO3 N2O + 2H2O c) COMBUSTION C5H6O + O2 CO2 + H2O C5H6O + 6O2 5CO2 + 3H2O d) COMBINATION N2 + H2 NH3 N2 + 3H2 2NH3 e) COMBINATION K2O + H2O KOH K2O + H2O 2KOH
- 2. 3.34 a) Mass of 5.50x10-3 moles of CdS Cd 112 144 gCdS S 32 5.76 x10 −3 molCdS * = 0.829 gCdS molCdS 144 b) Moles of NH4Cl in 112.6g N 14 H1x4=4 Cl 35.5 53.5 1molNH 4Cl 112.6 gNH 4Cl * = 2.10 gNH 4Cl 53.5 gnH 4Cl c) Molecules in 1.305 x 10-2 moles of C6H6 −2 6.02 *10 23 molecules 1.305 *10 molC6 H 6 * = 7.86 *10 23 molecules mol d) Oxygen atoms in 4.88 x 10-3 mol Al(NO3) −3 6.02 *10 23 molecules 9 O atoms 4.88 *10 molAl ( NO3 ) 3 * * = 2.64 *10 23 O atoms mol molecule
- 3. 3.58 C6H12O6 2C2H5OH + 2CO2 2 mol CO 2 a) 0.400 mol EtOH * = 0.800 mol CO 2 1 mol EtOH b) Molecule C6H12O6 C2H5OH CO2 C 12 6 72 C 12 6 24 C 12 1 12 O 16 6 96 O 16 1 16 O 16 2 32 H 1 12 12 H 1 6 6 Total 18 45 44 0 1 mol EtOH 1 mol glucose 180 g glucose 7.5 g EtOH * * * = 15 g glucose 45 g EtOH 2 mol EtOH 1 mol glucose c) 1 mol EtOH 2 mol CO 2 44 g CO 2 7.5 g EtOH * * * = 7.3 g glucose 45 g EtOH 2 mol EtOH 1 mol CO 2
- 4. 3.60 a) Balance: Fe2O3 + CO Fe + CO2 Fe2O3 + 3CO 2Fe + 3CO2 b) 1000g 1 mol Fe 2 O 3 3 mol CO 28 g CO 0.150 Kg Fe 2 O 3 * * * * = 78.95 g CO 1 Kg 159.6 g Fe 2 O 3 1 mol Fe 2 O 3 mol CO c) grams Fe: 1000g 1 mol Fe 2 O 3 2 mol Fe 55.8 g Fe 0.150 Kg Fe 2 O 3 * * * * = 104.9 g Fe 1 Kg 159.6 g Fe 2 O 3 1 mol Fe 2 O 3 mol Fe grams CO2 1000g 1 mol Fe 2 O 3 3 mol CO 2 44 g CO 2 0.150 Kg Fe 2 O 3 * * * * = 124.0 g CO 2 1 Kg 159.6 g Fe 2 O 3 1 mol Fe 2 O 3 mol CO 2 d) Fe2O3 + 3CO 2Fe + 3CO2 150g + 78.9g = 104.9g +124g 228.9g = 228.9 g