He laplace method for special nonlinear partial differential equations
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This document presents the He-Laplace method for solving nonlinear partial differential equations. The method combines Laplace transforms, homotopy perturbation method, and He's polynomials. It is shown that the He-Laplace method can easily handle nonlinear terms through the use of He's polynomials and provides better results than traditional methods. An example demonstrates the application of the He-Laplace method to solve a nonlinear parabolic-hyperbolic partial differential equation.
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He-Laplace Method for Special Nonlinear Partial Differential
Equations
Hradyesh Kumar Mishra
Department of Mathematics,Jaypee University of Engineering & Technology,Guna-473226(M.P) India,Email:
hk.mishra@juet.ac.in
Abstract
In this article, we consider Cauchy problem for the nonlinear parabolic-hyperbolic partial differential equations.
These equations are solved by He-Laplace method.. It is shown that, in He-Laplace method, the nonlinear terms
of differential equation can be easily handled by the use of He’s polynomials and provides better results.
Keywords: Laplace transform method, Homotopy perturbation method, Partial differential equations, He’s
polynomials.
AMS Subject classification: 35G10; 35G15; 35G25; 35G30; 74S30.
1. Introduction
Nonlinearity exists everywhere and nature is nonlinear in general. The search for a better and easy to use
tool for the solution of nonlinear equations that illuminate the nonlinear phenomena of real life problems of
science and engineering has recently received a continuing interest. Various methods, therefore, were proposed
to find approximate solutions of nonlinear equations. Some of the classical analytic methods are Lyapunov’s
artificial small parameter method [17], perturbation techniques [6,23,22, 25]. The Laplace decomposition
method have been used to solve nonlinear differential equations [1-4, 16, 19, 20, 27]. J.H.He developed the
homotopy perturbation method (HPM) [6-13,14-15,21,24,26] by merging the standard homotopy and
perturbation for solving various physical problems.Furthermore, the homotopy perturbation method is also
combined with the well-known Laplace transformation method [18] which is known as Laplace homotopy
perturbation method.
In this paper, the main objective is to solve partial differential equations by using He-Laplace method.
It is worth mentioning that He-Laplace method is an elegant combination of the Laplace transformation, the
homotopy perturbation method and He’s polynomials. The use of He’s polynomials in the nonlinear term was
first introduced by Ghorbani [5, 23]. This paper contains basic idea of homotopy perturbation method in section
2, He-Laplace method in section 3, examples in section 4 and conclusions in section 5 respectively.
2. Basic idea of homotopy perturbation method
Consider the following nonlinear differential equation
)1(,0)()( Ω∈=− rrfyA
with the boundary conditions of
)2(,,0, Γ∈=
∂
∂
r
n
y
yB
where A, B, )(rf and Γ are a general differential operator, a boundary operator, a known analytic function and
the boundary of the domain Ω , respectively.
The operator A can generally be divided into a linear part L and a nonlinear part N. Eq. (1) may therefore be
written as:
)3(,0)()()( =−+ rfyNyL
By the homotopy technique, we construct a homotopy Rprv →×Ω ]1,0[:),( which satisfies:
( ) ( ) ( ) ( )[ ] ( ) ( )[ ] )4(01, 0 =−+−−= rfvApyLvLppvH
or
( ) ( ) ( ) ( ) ( ) ( )[ ] )5(0, 00 =−++−= rfvNpyLpyLvLpvH
where ]1,0[∈p is an embedding parameter, while 0y is an initial approximation of Eq.(1), which satisfies the
boundary conditions. Obviously,from Eqs.(4) and (5)
we will have:](https://image.slidesharecdn.com/he-laplacemethodforspecialnonlinearpartialdifferentialequations-130619021300-phpapp02/85/He-laplace-method-for-special-nonlinear-partial-differential-equations-1-320.jpg)
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( ) ( ) ( ) )6(,00, 0 =−= yLvLvH
( ) )7(,0)()(1, =−= rfvAvH
The changing process of p from zero to unity is just that of ( )prv , from 0y to )(ry . In topology, this is
called deformation, while ( ) )( 0yLvL − and )()( rfvA − are called homotopy. If the embedding parameter
p is considered as a small parameter, applying the classical perturbation technique, we can assume that the
solution of Eqs.(4) and (5) can be written as a power series in p :
)8(..............................3
3
2
2
10 ∞++++= vpvppvvv
Setting 1=p in Eq.(8), we have
)9(................................210
1
lim +++==
→
vvvy vp
The combination of the perturbation method and the homotopy method is called the HPM, which eliminates the
drawbacks of the traditional perturbation methods while keeping all its advantages. The series (9) is convergent
for most cases. However, the convergent rate depends on the nonlinear operator )(vA . Moreover, He [6] made
the following suggestions:
(1)The second derivative of )(vN with respect to v must be small because the parameter may be relatively
large, i.e. 1→p .
(2) The norm of
∂
∂−
v
N
L 1
must be smaller than one so that the series converges.
3. He-Laplace method
Consider the following Cauchy problem for the nonlinear parabolic-hyperbolic differential equation:
,)(2
2
yFy
tt
=
∆−
∂
∂
∆−
∂
∂
(10)
with initial conditions
.....3,2,1,0),.........,(),(),0( ,2,1 ===
∂
∂
kxxxXXX
t
y
ikk
k
φ (11)
where the nonlinear term is represented by ,)(yF and ∆ is the Laplace operator in .n
R we rewrite the eqn(10)
as follows:
,)(2
2
2
2
2
2
yFy
xtxt
=
∂
∂
−
∂
∂
∂
∂
−
∂
∂
or
)(4
4
22
4
2
3
3
3
yF
x
y
tx
y
xt
y
t
y
=
∂
∂
+
∂∂
∂
−
∂∂
∂
−
∂
∂
, (12)
Applying the laplace transform of both sides of (12), we have
[ ] )13()(4
4
22
4
2
3
3
3
yFL
x
y
tx
y
xt
y
L
t
y
L +
∂
∂
−
∂∂
∂
+
∂∂
∂
=
∂
∂
[ ] [ ] )14()()0,()0,()0,(),( 4
4
22
4
2
3
23
yFL
x
y
tx
y
xt
y
LxyxysxystxyLs +
∂
∂
−
∂∂
∂
+
∂∂
∂
=′′−′−−
Using initial conditions (11) in (14), we have
[ ] [ ])()()()(),( 4
4
22
4
2
3
210
23
yFL
x
y
tx
y
xt
y
LxxsxstxyLs +
∂
∂
−
∂∂
∂
+
∂∂
∂
=−−− φφφ (15)](https://image.slidesharecdn.com/he-laplacemethodforspecialnonlinearpartialdifferentialequations-130619021300-phpapp02/85/He-laplace-method-for-special-nonlinear-partial-differential-equations-2-320.jpg)
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[ ] [ ])(
11)()()(
),( 34
4
22
4
2
3
33
2
2
10
yFL
sx
y
tx
y
xt
y
L
ss
x
s
x
s
x
txyL +
∂
∂
−
∂∂
∂
+
∂∂
∂
+++=
φφφ
(16)
Taking inverse Laplace transform, we have
[ ]
+
∂
∂
−
∂∂
∂
+
∂∂
∂
+++= −
)(
11
)(
2
)()(),( 34
4
22
4
2
3
3
1
2
2
10 yFL
sx
y
tx
y
xt
y
L
s
Lx
t
xtxtxy φφφ (17)
Now, we apply homotopy perturbation method[18],
∑
∞
=
=
0
),(),(
n
n
n
txyptxy (18)
Where the term ny are to recursively calculated and the nonlinear term )(yF can be decomposed as
∑
∞
=
=
0
)()(
n
n
n
yHpyF (19)
Here, He’s polynomials nH are given by
....,.........3,2,1,0,
!
1
)...,,.........,,(
00
210 =
∂
∂
=
=
∞
=
∑ nypF
pn
yyyyH
pi
i
i
n
n
nn
Substituting Eqs.(18) and (19) in (17), we get
∑ ∑∑
∞
=
∞
=
∞
=
−
+
+++=
0 0
3
0
3
1
2
2
10 )20()(
1
),(
1
)(
2
)()(),(
n
n
n
n
n
n
n
n
n
yHpL
s
txypL
s
Lpx
t
xtxtxyp φφφ
Comparing the coefficient of like powers of p, we obtained ..........).........,(),,(),,( 210 txytxytxy . Adding
all these values, we obtain ),( txy .
4. Examples
Example 4.1. Consider the following differential equation [22]:
y
t
y
x
y
y
xtxt
16
6
1
3
1
3
2
22
2
2
2
2
2
2
2
2
−
∂
∂
+
∂
∂
−=
∂
∂
−
∂
∂
∂
∂
−
∂
∂
(21)
with the following condition:
)22(.0)0,(,0)0,(,)0,( 2
2
4
=
∂
∂
=
∂
∂
−= x
t
y
x
t
y
xxy
The exact solution of above problem is given by
34
4),( txtxy +−= .
By applying the aforesaid method subject to the initial conditions, we have
)23(
216
1
9
11
16
1
),( 3
2
22
2
2
3
4
4
22
4
2
3
3
14
∂
∂
+
∂
∂
−+
−
∂
∂
−
∂∂
∂
+
∂∂
∂
+−= −
t
y
x
y
L
s
y
x
y
tx
y
xt
y
L
s
Lxtxy
Now, we apply the homotopy perturbation method, we have
)24()(
11
),(
0 0
3
0
3
14
∑ ∑∑
∞
=
∞
=
∞
=
−
+
+−=
n n
n
n
n
n
n
n
n
yHpL
s
ypL
s
Lpxtxyp
Where, )(yHn are He,s polynomials.
Comparing the coefficient of like powers of p, we have](https://image.slidesharecdn.com/he-laplacemethodforspecialnonlinearpartialdifferentialequations-130619021300-phpapp02/85/He-laplace-method-for-special-nonlinear-partial-differential-equations-3-320.jpg)
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4
0
0
),(: xtxyp −=
3
1
1
4),(: ttxyp =
Hence, the solution of ),( txy is given by
34
10
4
....),(
tx
yytxy
+−=
++=
Which is the exact solution of the problem.
Example 4.2. Consider the following nonlinear PDE [22]:
x
y
t
y
t
y
yy
xtxt ∂
∂
∂
∂
+
∂
∂
=
∂
∂
−
∂
∂
∂
∂
−
∂
∂
2
2
2
2
2
2
2
2
(25)
with the following condition:
)26(.cos)0,(,sin)0,(,cos)0,( 2
2
xx
t
y
xx
t
y
xxy −=
∂
∂
−=
∂
∂
=
The exact solution of above problem is given by
)cos(),( txtxy += .
By applying the aforesaid method subject to the initial conditions, we have
)27(
1
1
cos
!2
sincos),(
2
2
3
4
4
22
4
2
3
3
1
2
∂
∂
∂
∂
+
∂
∂
+
∂
∂
−
∂∂
∂
+
∂∂
∂
+−−= −
x
y
t
y
t
y
yL
s
x
y
tx
y
xt
y
L
s
Lx
t
xtxtxy
Now, we apply the homotopy perturbation method, we have
)28()(
11
cos
!2
sincos),(
0 0
3
0
3
1
2
∑ ∑∑
∞
=
∞
=
∞
=
−
+
+−−=
n n
n
n
n
n
n
n
n
yHpL
s
ypL
s
Lpx
t
xtxtxyp
Where, )(yHn are He,s polynomials.
Comparing the coefficient of like powers of p, we have
x
t
xtxtxyp cos
!2
sincos),(:
2
0
0
−−=
xtx
t
x
t
x
t
x
t
x
t
x
t
x
t
txyp 26
5
2
4
2
45443
1
1
cos
!6
3
2sin
!5
cos
!4
sin
!4
cos
!5
sin
!4
cos
!4
sin
!3
),(: ++−++++= .
Hence, the solution of ),( txy is given by
)cos(
sinsincoscos
.........
!5!3
sin.........
!4!2
1cos
..........),(
5342
210
tx
txtx
tt
tx
tt
x
yyytxy
+=
−=
∞−+−−
∞−+−=
+++=
Which is the exact solution of the problem.
5. Conclusions
In this work, we used He-Laplace method for solving nonlinear partial differential parabolic-hyperbolic
equations. The results have been approved the efficiency of this method for solving these problems. It is worth
mentioning that the He-Laplace method is capable of reducing the volume of the computational work and gives
high accuracy in the numerical results.
References](https://image.slidesharecdn.com/he-laplacemethodforspecialnonlinearpartialdifferentialequations-130619021300-phpapp02/85/He-laplace-method-for-special-nonlinear-partial-differential-equations-4-320.jpg)
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[2]Dehghan,M., Weighted finite difference techniques for the one dimensional advection-diffusion equation,
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transfer, Physics Letter A 335(2006)337-341.
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Mathematics and Computation, 151(2004)287-292.
[10] He,J.H., Recent developments of the homotopy perturbation method, Topological methods in Nonlinear
Analysis 31(2008)205-209.
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homogeneous advection equations, Zeitschrift fuer Naturforschung, 65 a (2010)1-5.
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London,UK,1992,English translation.
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Science Letters A1 (2010)263-267.
[19]H.K.Mishra, A comparative study of Variational Iteration method and He-Laplace method, Applied
Mathematics, 3 (2012)1193-1201.
[20]Mohyud-Din, S.T.,Yildirim, A., Homotopy perturbation method for advection problems, Nonlinear Science
Letter A 1(2010)307-312.
[21]Rafei,M., Ganji,D.D., Explicit solutions of helmhotz equation and fifth-order KdV equation using
homotopy perturbation method, International Journal of Nonlinear Sciences and Numerical Simulation
7(2006)321-328.
[22]A.Roozi,E.Alibeiki,S.S.Hosseini,S.M.Shafiof,M.Ebrahimi,Homotopy perturbation method for special
nonlinear partial differential equations, Journal of King Saud University science,23(2011)99-103.
[23]Saberi-Nadjafi, J., Ghorbani, A., He’s homotopy perturbation method: an effective tool for solving nonlinear
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[24]Siddiqui,A.M., Mohmood,R., Ghori,Q.K.., Thin film flow of a third grade fluid on a moving belt by He’s
homotopy perturbation method, International Journal of Nonlinear Sciences and Numerical Simulation
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[25]Sweilam, N.H., Khadar, M.M., Exact solutions of some coupled nonlinear partial differential equations using
the homotopy perturbation method, Computers and Mathematics with Applications, 58(2009)2134-2141.
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[27]Yusufoglu, E., Numerical solution of Duffing equation by the Laplace decomposition algorithm, Applied
Mathematics and Computation, 177(2006)572-580.](https://image.slidesharecdn.com/he-laplacemethodforspecialnonlinearpartialdifferentialequations-130619021300-phpapp02/85/He-laplace-method-for-special-nonlinear-partial-differential-equations-5-320.jpg)
He laplace method for special nonlinear partial differential equations
- 1. Mathematical Theory and Modeling www.iiste.org ISSN 2224-5804 (Paper) ISSN 2225-0522 (Online) Vol.3, No.6, 2013-Selected from International Conference on Recent Trends in Applied Sciences with Engineering Applications 113 He-Laplace Method for Special Nonlinear Partial Differential Equations Hradyesh Kumar Mishra Department of Mathematics,Jaypee University of Engineering & Technology,Guna-473226(M.P) India,Email: hk.mishra@juet.ac.in Abstract In this article, we consider Cauchy problem for the nonlinear parabolic-hyperbolic partial differential equations. These equations are solved by He-Laplace method.. It is shown that, in He-Laplace method, the nonlinear terms of differential equation can be easily handled by the use of He’s polynomials and provides better results. Keywords: Laplace transform method, Homotopy perturbation method, Partial differential equations, He’s polynomials. AMS Subject classification: 35G10; 35G15; 35G25; 35G30; 74S30. 1. Introduction Nonlinearity exists everywhere and nature is nonlinear in general. The search for a better and easy to use tool for the solution of nonlinear equations that illuminate the nonlinear phenomena of real life problems of science and engineering has recently received a continuing interest. Various methods, therefore, were proposed to find approximate solutions of nonlinear equations. Some of the classical analytic methods are Lyapunov’s artificial small parameter method [17], perturbation techniques [6,23,22, 25]. The Laplace decomposition method have been used to solve nonlinear differential equations [1-4, 16, 19, 20, 27]. J.H.He developed the homotopy perturbation method (HPM) [6-13,14-15,21,24,26] by merging the standard homotopy and perturbation for solving various physical problems.Furthermore, the homotopy perturbation method is also combined with the well-known Laplace transformation method [18] which is known as Laplace homotopy perturbation method. In this paper, the main objective is to solve partial differential equations by using He-Laplace method. It is worth mentioning that He-Laplace method is an elegant combination of the Laplace transformation, the homotopy perturbation method and He’s polynomials. The use of He’s polynomials in the nonlinear term was first introduced by Ghorbani [5, 23]. This paper contains basic idea of homotopy perturbation method in section 2, He-Laplace method in section 3, examples in section 4 and conclusions in section 5 respectively. 2. Basic idea of homotopy perturbation method Consider the following nonlinear differential equation )1(,0)()( Ω∈=− rrfyA with the boundary conditions of )2(,,0, Γ∈= ∂ ∂ r n y yB where A, B, )(rf and Γ are a general differential operator, a boundary operator, a known analytic function and the boundary of the domain Ω , respectively. The operator A can generally be divided into a linear part L and a nonlinear part N. Eq. (1) may therefore be written as: )3(,0)()()( =−+ rfyNyL By the homotopy technique, we construct a homotopy Rprv →×Ω ]1,0[:),( which satisfies: ( ) ( ) ( ) ( )[ ] ( ) ( )[ ] )4(01, 0 =−+−−= rfvApyLvLppvH or ( ) ( ) ( ) ( ) ( ) ( )[ ] )5(0, 00 =−++−= rfvNpyLpyLvLpvH where ]1,0[∈p is an embedding parameter, while 0y is an initial approximation of Eq.(1), which satisfies the boundary conditions. Obviously,from Eqs.(4) and (5) we will have:
- 2. Mathematical Theory and Modeling www.iiste.org ISSN 2224-5804 (Paper) ISSN 2225-0522 (Online) Vol.3, No.6, 2013-Selected from International Conference on Recent Trends in Applied Sciences with Engineering Applications 114 ( ) ( ) ( ) )6(,00, 0 =−= yLvLvH ( ) )7(,0)()(1, =−= rfvAvH The changing process of p from zero to unity is just that of ( )prv , from 0y to )(ry . In topology, this is called deformation, while ( ) )( 0yLvL − and )()( rfvA − are called homotopy. If the embedding parameter p is considered as a small parameter, applying the classical perturbation technique, we can assume that the solution of Eqs.(4) and (5) can be written as a power series in p : )8(..............................3 3 2 2 10 ∞++++= vpvppvvv Setting 1=p in Eq.(8), we have )9(................................210 1 lim +++== → vvvy vp The combination of the perturbation method and the homotopy method is called the HPM, which eliminates the drawbacks of the traditional perturbation methods while keeping all its advantages. The series (9) is convergent for most cases. However, the convergent rate depends on the nonlinear operator )(vA . Moreover, He [6] made the following suggestions: (1)The second derivative of )(vN with respect to v must be small because the parameter may be relatively large, i.e. 1→p . (2) The norm of ∂ ∂− v N L 1 must be smaller than one so that the series converges. 3. He-Laplace method Consider the following Cauchy problem for the nonlinear parabolic-hyperbolic differential equation: ,)(2 2 yFy tt = ∆− ∂ ∂ ∆− ∂ ∂ (10) with initial conditions .....3,2,1,0),.........,(),(),0( ,2,1 === ∂ ∂ kxxxXXX t y ikk k φ (11) where the nonlinear term is represented by ,)(yF and ∆ is the Laplace operator in .n R we rewrite the eqn(10) as follows: ,)(2 2 2 2 2 2 yFy xtxt = ∂ ∂ − ∂ ∂ ∂ ∂ − ∂ ∂ or )(4 4 22 4 2 3 3 3 yF x y tx y xt y t y = ∂ ∂ + ∂∂ ∂ − ∂∂ ∂ − ∂ ∂ , (12) Applying the laplace transform of both sides of (12), we have [ ] )13()(4 4 22 4 2 3 3 3 yFL x y tx y xt y L t y L + ∂ ∂ − ∂∂ ∂ + ∂∂ ∂ = ∂ ∂ [ ] [ ] )14()()0,()0,()0,(),( 4 4 22 4 2 3 23 yFL x y tx y xt y LxyxysxystxyLs + ∂ ∂ − ∂∂ ∂ + ∂∂ ∂ =′′−′−− Using initial conditions (11) in (14), we have [ ] [ ])()()()(),( 4 4 22 4 2 3 210 23 yFL x y tx y xt y LxxsxstxyLs + ∂ ∂ − ∂∂ ∂ + ∂∂ ∂ =−−− φφφ (15)
- 3. Mathematical Theory and Modeling www.iiste.org ISSN 2224-5804 (Paper) ISSN 2225-0522 (Online) Vol.3, No.6, 2013-Selected from International Conference on Recent Trends in Applied Sciences with Engineering Applications 115 [ ] [ ])( 11)()()( ),( 34 4 22 4 2 3 33 2 2 10 yFL sx y tx y xt y L ss x s x s x txyL + ∂ ∂ − ∂∂ ∂ + ∂∂ ∂ +++= φφφ (16) Taking inverse Laplace transform, we have [ ] + ∂ ∂ − ∂∂ ∂ + ∂∂ ∂ +++= − )( 11 )( 2 )()(),( 34 4 22 4 2 3 3 1 2 2 10 yFL sx y tx y xt y L s Lx t xtxtxy φφφ (17) Now, we apply homotopy perturbation method[18], ∑ ∞ = = 0 ),(),( n n n txyptxy (18) Where the term ny are to recursively calculated and the nonlinear term )(yF can be decomposed as ∑ ∞ = = 0 )()( n n n yHpyF (19) Here, He’s polynomials nH are given by ....,.........3,2,1,0, ! 1 )...,,.........,,( 00 210 = ∂ ∂ = = ∞ = ∑ nypF pn yyyyH pi i i n n nn Substituting Eqs.(18) and (19) in (17), we get ∑ ∑∑ ∞ = ∞ = ∞ = − + +++= 0 0 3 0 3 1 2 2 10 )20()( 1 ),( 1 )( 2 )()(),( n n n n n n n n n yHpL s txypL s Lpx t xtxtxyp φφφ Comparing the coefficient of like powers of p, we obtained ..........).........,(),,(),,( 210 txytxytxy . Adding all these values, we obtain ),( txy . 4. Examples Example 4.1. Consider the following differential equation [22]: y t y x y y xtxt 16 6 1 3 1 3 2 22 2 2 2 2 2 2 2 2 − ∂ ∂ + ∂ ∂ −= ∂ ∂ − ∂ ∂ ∂ ∂ − ∂ ∂ (21) with the following condition: )22(.0)0,(,0)0,(,)0,( 2 2 4 = ∂ ∂ = ∂ ∂ −= x t y x t y xxy The exact solution of above problem is given by 34 4),( txtxy +−= . By applying the aforesaid method subject to the initial conditions, we have )23( 216 1 9 11 16 1 ),( 3 2 22 2 2 3 4 4 22 4 2 3 3 14 ∂ ∂ + ∂ ∂ −+ − ∂ ∂ − ∂∂ ∂ + ∂∂ ∂ +−= − t y x y L s y x y tx y xt y L s Lxtxy Now, we apply the homotopy perturbation method, we have )24()( 11 ),( 0 0 3 0 3 14 ∑ ∑∑ ∞ = ∞ = ∞ = − + +−= n n n n n n n n n yHpL s ypL s Lpxtxyp Where, )(yHn are He,s polynomials. Comparing the coefficient of like powers of p, we have
- 4. Mathematical Theory and Modeling www.iiste.org ISSN 2224-5804 (Paper) ISSN 2225-0522 (Online) Vol.3, No.6, 2013-Selected from International Conference on Recent Trends in Applied Sciences with Engineering Applications 116 4 0 0 ),(: xtxyp −= 3 1 1 4),(: ttxyp = Hence, the solution of ),( txy is given by 34 10 4 ....),( tx yytxy +−= ++= Which is the exact solution of the problem. Example 4.2. Consider the following nonlinear PDE [22]: x y t y t y yy xtxt ∂ ∂ ∂ ∂ + ∂ ∂ = ∂ ∂ − ∂ ∂ ∂ ∂ − ∂ ∂ 2 2 2 2 2 2 2 2 (25) with the following condition: )26(.cos)0,(,sin)0,(,cos)0,( 2 2 xx t y xx t y xxy −= ∂ ∂ −= ∂ ∂ = The exact solution of above problem is given by )cos(),( txtxy += . By applying the aforesaid method subject to the initial conditions, we have )27( 1 1 cos !2 sincos),( 2 2 3 4 4 22 4 2 3 3 1 2 ∂ ∂ ∂ ∂ + ∂ ∂ + ∂ ∂ − ∂∂ ∂ + ∂∂ ∂ +−−= − x y t y t y yL s x y tx y xt y L s Lx t xtxtxy Now, we apply the homotopy perturbation method, we have )28()( 11 cos !2 sincos),( 0 0 3 0 3 1 2 ∑ ∑∑ ∞ = ∞ = ∞ = − + +−−= n n n n n n n n n yHpL s ypL s Lpx t xtxtxyp Where, )(yHn are He,s polynomials. Comparing the coefficient of like powers of p, we have x t xtxtxyp cos !2 sincos),(: 2 0 0 −−= xtx t x t x t x t x t x t x t txyp 26 5 2 4 2 45443 1 1 cos !6 3 2sin !5 cos !4 sin !4 cos !5 sin !4 cos !4 sin !3 ),(: ++−++++= . Hence, the solution of ),( txy is given by )cos( sinsincoscos ......... !5!3 sin......... !4!2 1cos ..........),( 5342 210 tx txtx tt tx tt x yyytxy += −= ∞−+−− ∞−+−= +++= Which is the exact solution of the problem. 5. Conclusions In this work, we used He-Laplace method for solving nonlinear partial differential parabolic-hyperbolic equations. The results have been approved the efficiency of this method for solving these problems. It is worth mentioning that the He-Laplace method is capable of reducing the volume of the computational work and gives high accuracy in the numerical results. References
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