How would you write this in MARIE assembly languageint count = 0;.pdf
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The document provides an example of a program written in MARIE assembly language that performs a simple arithmetic operation. It initializes variables, performs a loop to increment a count by 3 until it exceeds a certain number, and then divides the count by another number to produce an output. The document includes low-level assembly instructions for variable manipulation and control flow.
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![How would you write this in MARIE assembly language?
int count = 0;
int number = 30;
int otherNum = 10;
while ( count <= number)
count += 3;
output = count/otherNum;
Solution
Answer:
.zero 1
main:
push rbp
mov rbp, rsp
mov DWORD PTR [rbp-4], 0
mov DWORD PTR [rbp-8], 30
mov DWORD PTR [rbp-12], 10
.L3:
mov eax, DWORD PTR [rbp-4]
cmp eax, DWORD PTR [rbp-8]
jg .L2
add DWORD PTR [rbp-4], 3
jmp .L3
.L2:
mov eax, DWORD PTR [rbp-4]
cdq
idiv DWORD PTR [rbp-12]
mov DWORD PTR [rbp-16], eax
mov eax, 0
pop rbp
ret
__static_initialization_and_destruction_0(int, int):
push rbp
mov rbp, rsp](https://image.slidesharecdn.com/howwouldyouwritethisinmarieassemblylanguageintcount0-230706013643-47dee92a/85/How-would-you-write-this-in-MARIE-assembly-languageint-count-0-pdf-1-320.jpg)
![sub rsp, 16
mov DWORD PTR [rbp-4], edi
mov DWORD PTR [rbp-8], esi
cmp DWORD PTR [rbp-4], 1
jne .L7
cmp DWORD PTR [rbp-8], 65535
jne .L7
mov edi, OFFSET FLAT:std::__ioinit
call std::ios_base::Init::Init()
mov edx, OFFSET FLAT:__dso_handle
mov esi, OFFSET FLAT:std::__ioinit
mov edi, OFFSET FLAT:std::ios_base::Init::~Init()
call __cxa_atexit
.L7:
nop
leave
ret
push rbp
mov rbp, rsp
mov esi, 65535
mov edi, 1
call __static_initialization_and_destruction_0(int, int)
pop rbp
ret](https://image.slidesharecdn.com/howwouldyouwritethisinmarieassemblylanguageintcount0-230706013643-47dee92a/85/How-would-you-write-this-in-MARIE-assembly-languageint-count-0-pdf-2-320.jpg)
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How would you write this in MARIE assembly languageint count = 0;.pdf
- 1. How would you write this in MARIE assembly language? int count = 0; int number = 30; int otherNum = 10; while ( count <= number) count += 3; output = count/otherNum; Solution Answer: .zero 1 main: push rbp mov rbp, rsp mov DWORD PTR [rbp-4], 0 mov DWORD PTR [rbp-8], 30 mov DWORD PTR [rbp-12], 10 .L3: mov eax, DWORD PTR [rbp-4] cmp eax, DWORD PTR [rbp-8] jg .L2 add DWORD PTR [rbp-4], 3 jmp .L3 .L2: mov eax, DWORD PTR [rbp-4] cdq idiv DWORD PTR [rbp-12] mov DWORD PTR [rbp-16], eax mov eax, 0 pop rbp ret __static_initialization_and_destruction_0(int, int): push rbp mov rbp, rsp
- 2. sub rsp, 16 mov DWORD PTR [rbp-4], edi mov DWORD PTR [rbp-8], esi cmp DWORD PTR [rbp-4], 1 jne .L7 cmp DWORD PTR [rbp-8], 65535 jne .L7 mov edi, OFFSET FLAT:std::__ioinit call std::ios_base::Init::Init() mov edx, OFFSET FLAT:__dso_handle mov esi, OFFSET FLAT:std::__ioinit mov edi, OFFSET FLAT:std::ios_base::Init::~Init() call __cxa_atexit .L7: nop leave ret push rbp mov rbp, rsp mov esi, 65535 mov edi, 1 call __static_initialization_and_destruction_0(int, int) pop rbp ret