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Numbers: Calculations
Jean Paul VEGA
jpvega@ombrosa.fr
Sets of numbers
Order of Operations Mnemonics
 Please Excuse My Dear Aunt Sally
 Parenthesis, Exponent , Multiply, Divide, Add, Subtract
 Be careful when using Calculator
Order of Operations Mnemonics
¿ 36 − 3 −2=31
Order of Operations Mnemonics
Order of Operations Mnemonics
Order of Operations Mnemonics
Factors of 12 are : 1, 2, 3, 4, 6, 12
12 = 1x 3 x 4 or 12 = 2 x 6
Multiples of 12 are: 12, 24, 36
12 = 1 x 12
24 = 2 x 12
36 = 3 x 12
Factors and multiples
Prime number: its integer factors are only 1
and itself: 2, 3, 5, 7, 11, 13, 17, 19
19 = 19 x 1 prime
-19 = 19 x 1 x (-1) not prime
8 = 4 x 2 not prime
Decomposition in prime factors to find Highest
Common Factor HCF and Lowest Commen
Multiple
Prime numbers applications
Decomposition into prime factors
24 75
Decomposition into prime factors
5 square
= 125 5 cube or 5 to the power 3
square root of 25
or 
cube root of 125
cu. root of 1.953125
Power and Roots
(-2) x (-2) = +4 always positive
Cannot take square root of negative
number
cannot but OK
Power and Roots
Power and Roots
Power and Roots
Power and Roots
Power and Roots
HCF Highest common factor
The factors of 12, 18 are 1 and combinations of their prime factors
Factors of 18: 1, 2, 3, 6, 9, 18
Factors of 12: 1, 2, 3, 4, 6, 12 HCF = 6
12
2 6
2 3
3 1
12 = 2 x 2 x 3
HCF Highest common factor
= = =
HCF Highest common factor
= = =
LCM Lowest Common Multiple
Multiples of 18: 18, 36, 72, … LCM = 36
Take common prime factors 2 x 3
Factors of 12: 12, 24, 36, 48 Multiply with remaining factors: 2 x 3 x 2 x 3
LCM = 2 x 2 x 3 x 3 = 36 to get both numbers 12, 18
12
2 6
2 3
3 1
12 = 2 x 2 x 3
LCM Lowest Common Multiple
= = =
LCM Lowest Common Multiple
= = =


Reciprocal or inverse of a number
Fractions, Decimals
Percentages
1 or more units can be divided into equal
parts called fractions:
1 pizza cut into 6 equal slices and eat 3
slices
 and I eat 3 x =
Fractions
P
Im
Proper and Improper Fractions
24 is the largest multiple of 4 below 27
Mixed to Improper Fractions
Multiply and Divide Fractions
¿
1× 2×3
2×2×3
WRONG !!
OK
Multiply Fractions
2
3
× 18=
2
3
×
18
1
=
36
3
2
3
×
3
4
=
6
12
=
1
2
Add and Subtract Fractions
4 × 3
5 ×3
−
1× 5
3× 5
=
12
15
−
5
15
=
7
15
Put all fractions on the
same denominator
Calculations on fractions
Calculations on fractions
Percentages: denominator =100
Exam: 69 marks out of 75
Percentages: denominator =100
Percentages: denominator =100
Percentages: denominator =100
Percentages: denominator =100
Percentages: denominator =100
Percentages Increase and Decrease
A phone price changes from $100 to $120
=
A phone price changes from $120 to $100
=
Percentages Increase and Decrease
A phone price changes from $100 to $120
=
A phone price changes from $120 to $100
=
Percentages Increase and Decrease
New Price =
100% + 12% = 1.12
More rigorous algebra:
Percentages Increase and Decrease
Increase Value X by p% =
Decrease Value X by p% =
You buy a phone $150 before discount of 15%
and pay additional tax of 10%. What is the final
price?
Percentages Increase and Decrease
Increase Value X by p% =
Decrease Value X by p% =
You buy a phone $150 before discount of 15%
and pay additional tax of 10%. What is the final
price?
Simple Interest
Interest in % is money earned on sums deposited by
customers in a bank account or money charged by
banks when customers borrow a sum called the
principal.
With logic, no need to memorize ear
for 1 year
Simple Interest
Simple Interest
Simple Interest
Simple Interest
Simple Interest
Alan invests $500 at 1.5%/year simple interest. After n
years, the total value of his investment is $612.5. Find n
Simple Interest
Alan invests $500 at 1.5%/year simple interest. After n
years, the total value of his investment is $612.5. Find n
Percentages: denominator =100
Start F1 F2 F3 …. …. F11 F12
350
Percentages: denominator =100
Start F1 F2 F3 …. …. F11 F12
350 350x(1.1) 350x 350x 350x
x(1+10%) x(1+10%)
Compounded interest
Compounded interest
Percentages, Ratios, Proportions
Percentages, Ratios, Proportions
% Questions
92% 23
100% Total?
×
100
92
×
23
0.92
×
100
92
×
23
Percentages: of what?
Of the buying cost
Percentages, Ratios, Proportions
Of the buying cost
Percentages, Ratios, Proportions
Of the buying cost
Percentages, Ratios, Proportions
Percentages, Ratios, Proportions
Bottles Time
500 15
B? 90
×
90
15
×
90
15
×
500
15
×
500
15
Percentages, Ratios, Proportions
Percentages, Ratios, Proportions
Percentages, Ratios, Proportions
Butter Flour Sugar Currants Cakes
Percentages, Ratios, Proportions
Butter Flour Sugar Currants Cakes
150 500 50 100 18
3 10 1 2 0.36
600 2000 200 400 72
1000 120
×
1000
600 ×
1000
600
×
600
3
×
3
150
Inverse Proportions
Inverse Proportions
People Days
8 6
12 4
×
12
8 ÷
12
8
Ratios
Ratios
Ratios
Red Blue White Green Total
Ratio 7 5 3 1 16
Cars 48000
×
48000
16
Multiply and Divide Fractions
¿
1× 2×3
2×2×3
OK
Multiply and Divide Fractions
¿
1× 2×3
2×2×3
Multiply and Divide Fractions
¿
1× 2×3
2×2×3
OK
Algebra, Factorizing…
Algebra, Factorizing…
Algebra, Factorizing…
Algebra, Factorizing…
Algebra, Factorizing…
Algebra, Factorizing…
WRONG !!
Algebra, Factorizing…
Algebra, Factorizing…
Solving simple linear equations
Solving simple linear equations
Solving simple linear equations
Solving simple linear equations
Solving simple linear equations
There are 32 Plastic cups and 96 Ceramic
cups. After some Ceramic cups were sold, the
number of Ceramic cups left were 3/7 of the
total number of cups left. How many were
sold?
Solving simple linear equations
There are 32 Plastic cups and 96 Ceramic
cups. After some Ceramic cups were sold, the
number of Ceramic cups left were 3/7 of the
total number of cups left. How many were
sold?
Solving simple linear equations
10 years ago, a couple’s average age is 28 years
old. In 8 years’ time, the wife will be 44 years
old. How old is her husband now?
Solving simple linear equations
10 years ago, a couple’s average age is 28 years
old. In 8 years’ time, the wife will be 44 years
old. How old is her husband now?
10 y ago: total age = 28 x 2 = 56
In 8 years: Total = 56 + 10 + 10 + 8 + 8 = 92, 
Husband = 92 -44 =48
Now: Husband =48-8 =40 y
Solving simple linear equations
John’s age is 1/8 of his father’s age now. His
father will be 36 years old in 4 years’ time. How
old will John be when he is 3/5 of his father’s
age?
Solving simple linear equations
John’s age is 1/8 of his father’s age now. His
father will be 36 years old in 4 years’ time. How
old will John be when he is 3/5 of his father’s
age?
J=4 , Father = 32 now
4 + Y = 3/5( 32 + Y)
20 + 5Y = 96 + 3Y  Y=38
J=42 years old
Simultaneous equations: Elimination
Simultaneous equations: Elimination
Simultaneous equations: Elimination
Simultaneous equations: Substitution
Simultaneous equations: Substitution
Simultaneous equations: Substitution
Simultaneous equations
Simultaneous equations
J + K =160
J = K + 8
K = 76 , J = 84 J : K  21 : 19
Wendy’s savings is $720 more than twice of
Tim’s savings. If Wendy has $1680 more than
Tim, how much should Tim give Wendy so that
she will have 5 times as much as Tim?
Simultaneous equations
Simultaneous equations
Wendy’s savings is $720 more than twice of
Tim’s savings. If Wendy has $1680 more than
Tim, how much should Tim give Wendy so that
she will have 5 times as much as Tim? T= $960,
W= $2640, Tim must give $360
W=720 + 2T
W=1680+T
(960-G)x5 = 2640 + G  G= 360
Simultaneous equations
0.6 of the population of town P is equal to 1/4 of the
population in Town Q.
of the population of town P moved to Town Q. After
that there were 3575 more people in town Q than P.
Find the total population P+Q.
Simultaneous equations
0.6 of the population of town P is equal to 1/4 of the
population in Town Q.
of the population of town P moved to Town Q. After
that there were 3575 more people in town Q than P.
Find the total population P+Q. P= 1625, Q= 3900
0.6 P = 0.25Q  Q= 2.4 P
Laws of Indices / Exponents
(𝑎
𝑚
𝑏
𝑛
𝑐
− 𝑝
𝑑
𝑞 )
𝑟
=
(𝑎
𝑚𝑟
𝑏
𝑛𝑟
𝑐
−𝑝 𝑟
𝑑
𝑞𝑟 )
Laws of Indices / Exponents
Laws of Indices / Exponents
Laws of Indices / Exponents

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