![Capacitor with Dielectric (3)
D) Does removing the dielectric from the isolated
capacitor change the energy stored in the capacitor?
21-10-2015 FCI 27
The energy stored in the capacitor before the dielectric was removed was
After the dielectric is removed, the energy is
The energy increases --- we must add energy to pull out the dielectric.
[Or, the polarized dielectric is sucked into the E.]
U
1
2
CV2
1
2
CairV 2
1
2
2.50
2.00
10 6
F
12 V
2
3.60
10 4
J
U
1
2
CairV2
1
2
2.00
10 6
F
30 V
2
9.00
10 4
J](https://image.slidesharecdn.com/ch1-l3-250706133911-a92165df/85/It-is-all-about-Capacitance-and-Dielectrics-27-320.jpg)
It is all about Capacitance and Dielectrics
- 1. 21-10-2015 FCI 1 CHAPTER OUTLINE 1. Definition of Capacitance 2. Calculating Capacitance 3. Combinations of Capacitors 4. Energy Stored in a Charged Capacitor 5. Capacitors with Dielectrics
- 2. 21-10-2015 FCI 2 Capacitors are commonly used in a variety of electric circuits. For instance, they are used to tune the frequency of radio receivers, as filters in power supplies, to eliminate sparking in automobile ignition systems, and as energy- storing devices in electronic flash units. A capacitor consists of two conductors separated by an insulator. The capacitance of a given capacitor depends on its geometry and on the material—called a dielectric— that separates the conductors.
- 3. 1 Definition of Capacitance The capacitance C of a capacitor is defined as the ratio of the magnitude of the charge on either conductor to the magnitude of the potential difference between the conductors: The SI unit of capacitance is the farad (F), Note that by definition capacitance is always a positive quantity. Furthermore, the charge Q and the potential difference ΔV are positive quantities. Because the potential difference increases linearly with the stored charge, the ratio Q / Δ V is constant for a given capacitor. 21-10-2015 FCI 3
- 4. Capacitance The charge, Q, on a capacitor is directly proportional to the potential difference, V, across the capacitor. That is, Q α V Introducing a constant, C, known as the capacitance of the capacitor, we have Q = CV Capacitance of a capacitor is defined as the ratio of charge on one of the capacitor plates to the potential difference between the plates. Charge Q is measured in coulombs, C. Potential difference, V, is measured in volts, V. Capacitance, C, is measured in farads, F. 1 farad is 1 coulomb per volt: 1 F = 1 C V-1 1 farad is a very large unit. It is much more common to use the following: mF = 10-3 F , μF = 10-6 F , nF = 10-9 F , pF = 10-12 F 21-10-2015 FCI 4
- 5. The capacitance of an isolated charged sphere 2 .Calculating Capacitance This expression shows that the capacitance of an isolated charged sphere is proportional to its radius and is independent of both the charge on the sphere and the potential difference. 21-10-2015 FCI 5
- 6. Parallel-Plate Capacitors Two parallel metallic plates of equal area A are separated by a distance d, One plate carries a charge Q , and the other carries a charge -Q . That is, the capacitance of a parallel-plate capacitor is proportional to the area of its plates and inversely proportional to the plate separation 21-10-2015 FCI 6
- 7. Example 1: Parallel-Plate Capacitor 21-10-2015 FCI 7
- 8. 3. Combinations of Capacitors I - Parallel Combination • The individual potential differences across capacitors connected in parallel are the same and are equal to the potential difference applied across the combination. • The total charge on capacitors connected in parallel is the sum of the charges on the individual capacitors for the equivalent capacitor 21-10-2015 FCI 8
- 9. If we extend this treatment to three or more capacitors connected in parallel, we find the equivalent capacitance to be Thus, the equivalent capacitance of a parallel combination of capacitors is the algebraic sum of the individual capacitances and is greater than any of the individual capacitances. 21-10-2015 FCI 9
- 10. II- Series Combination • The charges on capacitors connected in series are the same. • The total potential difference across any number of capacitors connected in series is the sum of the potential differences across the individual capacitors. 21-10-2015 FCI 10
- 11. When this analysis is applied to three or more capacitors connected in series, the relationship for the equivalent capacitance is the inverse of the equivalent capacitance is the algebraic sum of the inverses of the individual capacitances and the equivalent capacitance of a series combination is always less than any individual capacitance in the combination. 21-10-2015 FCI 11
- 13. Question: A and a capacitor are connected in parallel, and this pair of capacitors is then connected in series with a capacitor, as shown in the diagram. What is the equivalent capacitance of the whole combination? What is the charge on the capacitor if the whole combination is connected across the terminals of a V battery? Likewise, what are the charges on the and capacitors? The equivalent capacitance of the and capacitors connected in parallel is When a capacitor is combined in series with a capacitor, the equivalent capacitance of the whole combination is given by Solution: 21-10-2015 FCI 13
- 14. and so The charge delivered by the 6 V battery is This is the charge on the 4µF capacitor, since one of the terminals of the battery is connected directly to one of the plates of this capacitor. The voltage drop across the 4µF capacitor is 21-10-2015 FCI 14
- 16. Example 4: Equivalent Capacitance Find the equivalent capacitance between a and b for the combination of capacitors shown in Figure. All capacitances are in microfarads. 21-10-2015 FCI 16
- 17. 4- Energy Stored in an Electric Field Suppose that, at a given instant, a charge q′ has been transferred from one plate of a capacitor to the other. The potential difference V′ between the plates at that instant will be q′/C. If an extra increment of charge dq′ is then transferred, the increment of work required will be, 21-10-2015 FCI 17 The work required to bring the total capacitor charge up to a final value q is This work is stored as potential energy U in the capacitor, so that or The potential energy of a charged capacitor may be viewed as being stored in the electric field between its plates.
- 18. Energy Density The potential energy per unit volume between parallel-plate capacitor is 21-10-2015 FCI 18 V/d equals the electric field magnitude E due to
- 19. Example: A 10,000 μF capacitor is described as having a maximum working voltage of 25 V. Calculate the energy stored by the capacitor. U = ½ CV2 = ½ x 10,000 x 10-6 x 252 = 3.125 J 21-10-2015 FCI 19
- 20. Capacitor with a Dielectric THE DIELECTRIC CONSTANT The surface charges on the dielectric reduce the electric field inside the dielectric. This reduction in the electric field is described by the dielectric constant k, which is the ratio of the field magnitude “E0 “ without the dielectric to the field magnitude “E “ inside the dielectric: 21-10-2015 FCI 20 Every dielectric material has a characteristic dielectric strength, which is the maximum value of the electric field that it can tolerate without breakdown
- 21. Some Properties of Dielectrics 21-10-2015 FCI 21 Material Dielectric Constant Dielectric Strength (kV/mm) Air (1 atm) 1.00054 3 Polystyrene 2.6 24 Paper 3.5 16 Transformer oil 4.5 Pyrex 4.7 14 Ruby mica 5.4 Porcelain 6.5 Silicon 12 Germanium 16 Ethanol 25 Water (20°C) 80.4 Water (25°C) 78.5 Titania ceramic 130 Strontium titanate 310 8 For a vacuum, .
- 22. 5- Capacitance with a Dielectric 0 air q q C V E d 0 air q q C V E d 0 / E E 21-10-2015 FCI 22 0 1 ( ) air q q q C C E d Ed Ed air C C The capacitance with the dielectric present is increased by a factor of k over the capacitance without the dielectric.
- 23. Energy Stored Before the dielectric is inserted: Energy Stored After the dielectric is inserted: 21-10-2015 FCI 23
- 24. Example 6: A Paper-Filled Capacitor A parallel-plate capacitor has plates of dimensions 2.0 cm by 3.0 cm separated by a 1.0-mm thickness of paper. Find its capacitance. 21-10-2015 FCI 24
- 25. Capacitor with Dielectric A) Consider a parallel plate capacitor with capacitance C = 2.00 F connected to a battery with voltage V = 12.0 V as shown. What is the charge stored in the capacitor? C 10 0 . 6 V 0 . 12 F 10 0 . 2 50 . 2 5 6 CV q 21-10-2015 FCI 25 q CV 2.00 10 6 F 12.0 V 2.40 10 5 C B) Now insert a dielectric with dielectric constant = 2.5 between the plates of the capacitor. What is the charge on the capacitor? C Cair The capacitance of the capacitor is increased The additional charge is provided by the battery.
- 26. Capacitor with Dielectric (2) C) We isolate the charged capacitor with a dielectric by disconnecting it from the battery. We remove the dielectric, keeping the capacitor isolated. What happens to the charge and voltage on the capacitor? 21-10-2015 FCI 26 The charge on the isolated capacitor cannot change because there is nowhere for the charge to flow. Q remains constant. The voltage on the capacitor will be The voltage went up because removing the dielectric increased the electric field and the resulting potential difference between the plates. V q C 6.00 10 5 C 2.00 10 6 F 30.0 V V increases
- 27. Capacitor with Dielectric (3) D) Does removing the dielectric from the isolated capacitor change the energy stored in the capacitor? 21-10-2015 FCI 27 The energy stored in the capacitor before the dielectric was removed was After the dielectric is removed, the energy is The energy increases --- we must add energy to pull out the dielectric. [Or, the polarized dielectric is sucked into the E.] U 1 2 CV2 1 2 CairV 2 1 2 2.50 2.00 10 6 F 12 V 2 3.60 10 4 J U 1 2 CairV2 1 2 2.00 10 6 F 30 V 2 9.00 10 4 J
- 28. Example Given a 7.4 pF air-filled capacitor. You are asked to convert it to a capacitor that can store up to 7.4 J with a maximum voltage of 652 V. What dielectric constant should the material have that you insert to achieve these requirements? Key Idea: The capacitance with the dielectric in place is given by C=Cair and the energy stored is given by So, 21-10-2015 FCI 28
- 29. Question - part 1 A parallel-plate air-filled capacitor has a capacitance of 50 pF. (a) If each of the plates has an area of A=0.35 m2 , what is the separation? A) 12.5 10-1 m B) 6.2 10-2 m C) 1.3 m 21-10-2015 FCI 29 0=8.85 10-12 C2 /Nm2
- 30. Solution Question - part 1 A parallel-plate air-filled capacitor has a capacitance of 50 pF. (a) If each of the plates has an area of A=0.35 m2 , what is the separation? B) 6.2 10-2 m 21-10-2015 FCI 30
- 31. Question - part 2 An air-filled parallel plate capacitor has a capacitance of 50pF. (b) If the region between the plates is now filled with material having a dielectric constant of =2, what is the capacitance? A) the same B) 25 pF C) 100 pF 21-10-2015 FCI 31
- 32. Solution Question - part 2 A air-filled parallel plate capacitor has a capacitance of 50 pF. (b) If the region between the plates is now filled with material having a dielectric constant of =2, what is the capacitance? C) 100 pF 21-10-2015 FCI 32
- 33. Summary The capacitance C of any capacitor is the ratio of the charge Q on either conductor to the potential difference ∆V between them: The equivalent capacitance of a parallel combination of capacitors is The equivalent capacitance of a series combination of capacitors is The energy stored in a capacitor with charge Q is The capacitance increases by a dimensionless factor K, called the dielectric constant: C=Cair 21-10-2015 FCI 33