![Answers to Creative Assignment<br />3(a)Mr of CH4= 12 + 1x 4 = 16<br />Let x be the Mr of the chemical<br />According to the Graham’s law of diffusion,<br />Rate 1Rate 2 = Mass 2Mass 1 12 = 16x 14 = 16x<br />x = 64<br />Dabao’s age is 64 years old.<br />3(b)The biochemist is a woman (either Shalini or Barbra). <br /> C H<br />No. of mols:81.82/1218.18/1<br />= 6.82= 18.18[1]<br />mole ratio:6.82/6.8218.18/6.82<br />= 1= 2.67[1]<br /> 3: 8<br />empirical formula C3H8<br />Mr = 12 x 3 + 8 x 1 = 44 [1]<br />Therefore, the biochemist is 44 years old<br />3(c)The analytical chemist is a woman (either Shalini or Barbra).<br />2 molesdecomposed24 dm3 oxygen produced = 1 mol<br />x mole decomposed120 dm3 oxygen produced = 5 mol<br />x = 10 mol[1]<br />since 10 mol weigh 340 g<br />1 mol weighs 34 g<br />Mr = 34[1]<br />The analytical chemist is 34 years old.<br />3(d)Let HA be formula of the acid<br />2HA + Ca(OH)2 CaA2 + H2O[1]<br />No. of mol of Ca(OH)2 = 8.0/1000 x 0.40 = 0.0032 [1]<br />Since mol ratio of acid to base is 2:1,<br />No. of mol of HA = 0.0032 x 2 = 0.0064[1]<br />0.0064 mol weighs 0.2368 g<br />thus 1 mol weighs 37 g<br />Mr = 37[1]<br />Bill is 37 and is not the physical chemist.<br />Shalini is the 34 year old analytical chemist (from (c) above). <br />So Barbara must be the biochemist.<br />Bill is either the organic or inorganic chemist.[1]<br />3(e)C2Hx + (2+x/4)O2 2CO2 + x/2H2O[1]<br />No. of moles of CO2 = 52.8/44 = 1.2[1]<br />No. of moles of H2O = 10.8/18 = 0.6[1]<br />From the equation:<br />2 mol CO2:x/2 mol H2O<br />thus, 1.2:0.6<br />Therefore, x/2 = 2 x 0.6/1.2<br />x = 2[1]<br />Mr of C2H2 = 26[1]<br />Fandi is 26 years old and is the inorganic chemist (from (d) above).<br />So Bill must be the organic chemist. And Dabao is the physical chemist.<br />Alternate method for 3(e)<br />Amount of CO2 produced = 52.844 = 1.2mol<br />Mr of H2O = 1x 2 + 16 = 18<br />Amount of H2O produced = 10.818 = 0.60mol<br />Amount of Hydrogen atoms in 0.60mol of H2O is 1.2mol<br />Mol ration of Carbon and hydrogen in hydrocarbon = 1.2 : 1.2<br />= 1: 1<br />Empirical formula of the hydrocarbon is –CH<br />Hence molecular formula is C2H2<br />Mr of C2H2 = 12 x 2 + 1 x 2 = 26<br />Fandi is 26 years old.<br />Fill in the table<br />NameSpecialtyAgeBillOrganic chemist37DabaoPhysical chemist64BarbraBiochemist44ShaliniAnalytical chemist34FandiInorganic chemist26<br />](https://image.slidesharecdn.com/juneholidaymoleconceptassignmentanswers-111005043000-phpapp02/85/June-holiday-mole-concept-assignment-answers-1-320.jpg)
June holiday mole concept assignment answers
- 1. Answers to Creative Assignment<br />3(a)Mr of CH4= 12 + 1x 4 = 16<br />Let x be the Mr of the chemical<br />According to the Graham’s law of diffusion,<br />Rate 1Rate 2 = Mass 2Mass 1 12 = 16x 14 = 16x<br />x = 64<br />Dabao’s age is 64 years old.<br />3(b)The biochemist is a woman (either Shalini or Barbra). <br /> C H<br />No. of mols:81.82/1218.18/1<br />= 6.82= 18.18[1]<br />mole ratio:6.82/6.8218.18/6.82<br />= 1= 2.67[1]<br /> 3: 8<br />empirical formula C3H8<br />Mr = 12 x 3 + 8 x 1 = 44 [1]<br />Therefore, the biochemist is 44 years old<br />3(c)The analytical chemist is a woman (either Shalini or Barbra).<br />2 molesdecomposed24 dm3 oxygen produced = 1 mol<br />x mole decomposed120 dm3 oxygen produced = 5 mol<br />x = 10 mol[1]<br />since 10 mol weigh 340 g<br />1 mol weighs 34 g<br />Mr = 34[1]<br />The analytical chemist is 34 years old.<br />3(d)Let HA be formula of the acid<br />2HA + Ca(OH)2 CaA2 + H2O[1]<br />No. of mol of Ca(OH)2 = 8.0/1000 x 0.40 = 0.0032 [1]<br />Since mol ratio of acid to base is 2:1,<br />No. of mol of HA = 0.0032 x 2 = 0.0064[1]<br />0.0064 mol weighs 0.2368 g<br />thus 1 mol weighs 37 g<br />Mr = 37[1]<br />Bill is 37 and is not the physical chemist.<br />Shalini is the 34 year old analytical chemist (from (c) above). <br />So Barbara must be the biochemist.<br />Bill is either the organic or inorganic chemist.[1]<br />3(e)C2Hx + (2+x/4)O2 2CO2 + x/2H2O[1]<br />No. of moles of CO2 = 52.8/44 = 1.2[1]<br />No. of moles of H2O = 10.8/18 = 0.6[1]<br />From the equation:<br />2 mol CO2:x/2 mol H2O<br />thus, 1.2:0.6<br />Therefore, x/2 = 2 x 0.6/1.2<br />x = 2[1]<br />Mr of C2H2 = 26[1]<br />Fandi is 26 years old and is the inorganic chemist (from (d) above).<br />So Bill must be the organic chemist. And Dabao is the physical chemist.<br />Alternate method for 3(e)<br />Amount of CO2 produced = 52.844 = 1.2mol<br />Mr of H2O = 1x 2 + 16 = 18<br />Amount of H2O produced = 10.818 = 0.60mol<br />Amount of Hydrogen atoms in 0.60mol of H2O is 1.2mol<br />Mol ration of Carbon and hydrogen in hydrocarbon = 1.2 : 1.2<br />= 1: 1<br />Empirical formula of the hydrocarbon is –CH<br />Hence molecular formula is C2H2<br />Mr of C2H2 = 12 x 2 + 1 x 2 = 26<br />Fandi is 26 years old.<br />Fill in the table<br />NameSpecialtyAgeBillOrganic chemist37DabaoPhysical chemist64BarbraBiochemist44ShaliniAnalytical chemist34FandiInorganic chemist26<br />