Kmaps.ppt

ECB2212-Digital Electronics
K-Map
Ms.K.Indra Gandhi
Asst Prof (Sr.Gr) /ECE

Karnaugh Maps (K-Maps)
• A visual way to simplify logic expressions
• It gives the most simplified form of the expression

Rules to obtain the most simplified expression
•Simplification of logic expression using Boolean algebra is awkward
because:
– it lacks specific rules to predict the most suitable next step in the simplification
process
– it is difficult to determine whether the simplest form has been achieved.
•A Karnaugh map is a graphical method used to obtained the most
simplified form of an expression in a standard form (Sum-of-Products or
Product-of-Sums).
•The simplest form of an expression is the one that has the minimum
number of terms with the least number of literals (variables) in each term.
•By simplifying an expression to the one that uses the minimum number of
terms, we ensure that the function will be implemented with the minimum
number of gates.
•By simplifying an expression to the one that uses the least number of
literals for each terms, we ensure that the function will be implemented
with gates that have the minimum number of inputs.

Three-Variable K-Maps
 
 C
B
(0,4)
f  
 B
A
(4,5)
f  
 B
(0,1,4,5)
f  
 A
(0,1,2,3)
f
BC
00
0
01
1
11 10
A
1 0 0 0
1 0 0 0
BC
00
0
01
1
11 10
A
0 0 0 0
1 1 0 0
BC
00
0
01
1
11 10
A
1 1 1 1
0 0 0 0
BC
00
0
01
1
11 10
A
1 1 0 0
1 1 0 0
 
 C
A
(0,4)
f  
 C
A
(4,6)
f  
 C
A
(0,2)
f  
 C
(0,2,4,6)
f
BC
00
0
01
1
11 10
A
0 1 1 0
0 0 0 0
BC
00
0
01
1
11 10
A
0 0 0 0
1 0 0 1
BC
00
0
01
1
11 10
A
1 0 0 1
1 0 0 1
BC
00
0
01
1
11 10
A
1 0 0 1
0 0 0 0

Three-Variable K-Map Examples
BC
00
0
01
1
11 10
A
BC
00
0
01
1
11 10
A
BC
00
0
01
1
11 10
A
BC
00
0
01
1
11 10
A
BC
00
0
01
1
11 10
A
BC
00
0
01
1
11 10
A
1
1 1 1
1
1
1 1
1 1 1
1 1
1
1
1 1
1 1
1 1
1

Four-Variable K-Maps
 


 D
C
B
(0,8)
f  


 D
C
B
(5,13)
f  


 D
B
A
(13,15)
f  


 D
B
A
(4,6)
f
 

 C
A
(2,3,6,7)
f  

 D
B
)
(4,6,12,14
f  

 C
B
)
(2,3,10,11
f  

 D
B
(0,2,8,10)
f
CD
00
00
01
01
11
11
10
10
AB
1 0 0 0
0 0 0 0
0 0 0 0
1 0 0 0
CD
00
00
01
01
11
11
10
10
AB
0 0 0 0
0 1 0 0
0 1 0 0
0 0 0 0
CD
00
00
01
01
11
11
10
10
AB
0 0 0 0
0 0 0 0
0 1 1 0
0 0 0 0
CD
00
00
01
01
11
11
10
10
AB
0 0 0 0
1 0 0 1
0 0 0 0
0 0 0 0
CD
00
00
01
01
11
11
10
10
AB
0 0 1 1
0 0 1 1
0 0 0 0
0 0 0 0
CD
00
00
01
01
11
11
10
10
AB
0 0 0 0
1 0 0 1
1 0 0 1
0 0 0 0
CD
00
00
01
01
11
11
10
10
AB
0 0 1 1
0 0 0 0
0 0 0 0
0 0 1 1
CD
00
00
01
01
11
11
10
10
AB
1 0 0 1
0 0 0 0
0 0 0 0
1 0 0 1

Four-Variable K-Maps
CD
00
00
01
01
11
11
10
10
AB
0 0 0 0
1 1 1 1
0 0 0 0
0 0 0 0
CD
00
00
01
01
11
11
10
10
AB
0 0 1 0
0 0 1 0
0 0 1 0
0 0 1 0
CD
00
00
01
01
11
11
10
10
AB
1 0 1 0
0 1 0 1
1 0 1 0
0 1 0 1
CD
00
00
01
01
11
11
10
10
AB
0 1 0 1
1 0 1 0
0 1 0 1
1 0 1 0
CD
00
00
01
01
11
11
10
10
AB
0 1 1 0
0 1 1 0
0 1 1 0
0 1 1 0
CD
00
00
01
01
11
11
10
10
AB
1 0 0 1
1 0 0 1
1 0 0 1
1 0 0 1
CD
00
00
01
01
11
11
10
10
AB
0 0 0 0
1 1 1 1
1 1 1 1
0 0 0 0
CD
00
00
01
01
11
11
10
10
AB
1 1 1 1
0 0 0 0
0 0 0 0
1 1 1 1
f (4,5,6,7) A B
  
 f (3,7,11,15) C D
  

f (0,3,5,6,9,10,12,15)
  f (1,2,4,7,8,11,13,14)
 
f A B C D
    f A B C D
   
f (1,3,5,7,9,11,13,15)
  f (0,2,4,6,8,10,12,14)
  f (4,5,6,7,12,13,14,15)
  f (0,1,2,3,8,9,10,11)
 
f D
 f D
 f B
 f B


Four-Variable K-Maps Examples
CD
00
00
01
01
11
11
10
10
AB
CD
00
00
01
01
11
11
10
10
AB
CD
00
00
01
01
11
11
10
10
AB
CD
00
00
01
01
11
11
10
10
AB
CD
00
00
01
01
11
11
10
10
AB
CD
00
00
01
01
11
11
10
10
AB
1
1
1
1
1
1
1
1
1
1
1
1 1 1
1
1 1 1
1
1
1
1
1
1
1
1 1 1 1
1 1
1 1
1
1

Four-Variable K-Maps Examples
CD
00
00
01
01
11
11
10
10
AB
CD
00
00
01
01
11
11
10
10
AB
CD
00
00
01
01
11
11
10
10
AB
CD
00
00
01
01
11
11
10
10
AB
CD
00
00
01
01
11
11
10
10
AB
CD
00
00
01
01
11
11
10
10
AB

Design of combinational digital circuits
• Steps to design a combinational digital circuit:
– From the problem statement derive the truth table
– From the truth table derive the unsimplified logic expression
– Simplify the logic expression
– From the simplified expression draw the logic circuit
• Example: Design a 3-input (A,B,C) digital circuit that will give at its output (X) a logic
1 only if the binary number formed at the input has more ones than zeros.
BC
AB
AC
X +
+

A B C
0
0
0
0
0
0
0
0
0
0
0
0
1
1
1
1
1
1
1
1
1
1
1
1
X
0
0
0
1
0
1
1
1
Inputs Output
0
1
2
3
4
5
6
7
BC
00
0
01
1
11 10
A
0 0 1 0
0 1 1 1
A B C
X

 7)
6,
5,
(3,
X

Design of combinational digital circuits (Cont.)
• Example: Design a 4-input (A,B,C,D) digital circuit that will give at its output (X) a
logic 1 only if the binary number formed at the input is between 2 and 9 (including).
C
B
A
B
A
C
A
X +
+

A B C
X

 ,7,8,9)
(2,3,4,5,6
X
A B C
0
0
0
0
0
1
X
0
0
Inputs Output
0
1
D
0
0
0 0 0 1
2 1
0 0 1 1
3 1
0 1 0 1
4 0
0 1 1 1
5 0
0 1 0 1
6 1
0 1 1 1
7 1
1 0 0 1
8 0
1 0 1 1
9 0
1 0 0 0
10 1
1 0 1 0
11 1
1 1 0 0
12 0
1 1 1 0
13 0
1 1 0 0
14 1
1 1 1 0
15 1 D
CD
00
00
01
01
11
11
10
10
AB
0 0 1 1
1 1 1 1
0 0 0 0
1 1 0 0
X
Same

Design of combinational digital circuits (Example)
• Example: Design a 4-input (A,B,C,D) digital circuit that will give at its output (X) a
logic 1 only if there more ones than zeros in the binary number formed at the input.
A B C
A B C
0
0
0
0
0
1
Inputs
0
1
D
0
0
0 0 0
2 1
0 0 1
3 1
0 1 0
4 0
0 1 1
5 0
0 1 0
6 1
0 1 1
7 1
1 0 0
8 0
1 0 1
9 0
1 0 0
10 1
1 0 1
11 1
1 1 0
12 0
1 1 1
13 0
1 1 0
14 1
1 1 1
15 1 D
CD
00
00
01
01
11
11
10
10
AB
X X
Output
X =
X =

Kmaps.ppt

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Kmaps.ppt