Holt Geometry
10-8 Spheres
Warm Up
Find each measurement.
1. the radius of circle M if the diameter is 25 cm
2. the circumference of circle X if the radius is
42.5 in.
3. the area of circle T if the diameter is 26 ft
4. the circumference of circle N if the area is
625 cm2
12.5 cm
85 in.
169 ft2
50 cm
Holt Geometry
10-8 Spheres
• Learn and apply the formula for the volume of a
sphere.
• Learn and apply the formula for the surface area
of a sphere.
Objectives
Holt Geometry
10-8 Spheres
• A sphere is the locus of points in space that are a
fixed distance from a given point called the center
of a sphere.
• A radius of a sphere connects the center of the
sphere to any point on the sphere.
• A hemisphere is half of a sphere.
• A great circle divides a sphere into two
hemispheres
Holt Geometry
10-8 Spheres
Holt Geometry
10-8 Spheres
Example 1A: Finding Volumes of Spheres
Find the volume of the sphere.
Give your answer in terms of .
= 2304 in3
Simplify.
Volume of a sphere.
Holt Geometry
10-8 Spheres
Example 1B: Finding Volumes of Spheres
Find the diameter of a sphere with volume
36,000 cm3
.
Substitute 36,000 for V.
27,000 = r3
r = 30
d = 60 cm d = 2r
Take the cube root of both sides.
Volume of a sphere.
Holt Geometry
10-8 Spheres
Example 1C: Finding Volumes of Spheres
Find the volume of the hemisphere.
Volume of a hemisphere
Substitute 15 for r.
= 2250 m3
Simplify.
Holt Geometry
10-8 Spheres
Example 3A: Finding Surface Area of Spheres
Find the surface area of a sphere with diameter
76 cm. Give your answers in terms of .
S = 4r2
S = 4(38)2
= 5776 cm2
Surface area of a sphere
Holt Geometry
10-8 Spheres
Example 3B: Finding Surface Area of Spheres
Find the volume of a sphere with surface area
324 in2
. Give your answers in terms of .
Substitute 324 for S.
324 = 4r2
r = 9 Solve for r.
Substitute 9 for r.
The volume of the sphere is 972 in2
.
S = 4r2
Surface area of a sphere
Holt Geometry
10-8 Spheres
Example 3C: Finding Surface Area of Spheres
Find the surface area of a
sphere with a great circle
that has an area of 49 mi2
.
Substitute 49 for A.
49 = r2
r = 7 Solve for r.
S = 4r2
= 4(7)2
= 196 mi2
Substitute 7 for r.
A = r2
Area of a circle
Holt Geometry
10-8 Spheres
Lesson Quiz: Part I
Find each measurement. Give your answers in
terms of .
1. the volume and surface area
of the sphere
2. the volume and surface area of a sphere with
great circle area 36 in2
3. the volume and surface area
of the hemisphere
V = 36 cm3
;
S = 36 cm2
V = 288 in3
;
S = 144 in2
V = 23,958 ft3
;
S = 3267 ft2
Holt Geometry
10-8 Spheres
Lesson Quiz: Part II
4. A sphere has radius 4. If the radius is multiplied
by 5, describe what happens to the surface area.
5. Find the volume and surface area of the
composite figure. Give your answer in terms of .
The surface area is multiplied by 25.
V = 522 ft3
; S = 267 ft2
Holt Geometry
10-8 Spheres
Homework
Worksheet
37-45
(10.7)

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Learn and apply the formula for the volume of a sphere.

  • 1. Holt Geometry 10-8 Spheres Warm Up Find each measurement. 1. the radius of circle M if the diameter is 25 cm 2. the circumference of circle X if the radius is 42.5 in. 3. the area of circle T if the diameter is 26 ft 4. the circumference of circle N if the area is 625 cm2 12.5 cm 85 in. 169 ft2 50 cm
  • 2. Holt Geometry 10-8 Spheres • Learn and apply the formula for the volume of a sphere. • Learn and apply the formula for the surface area of a sphere. Objectives
  • 3. Holt Geometry 10-8 Spheres • A sphere is the locus of points in space that are a fixed distance from a given point called the center of a sphere. • A radius of a sphere connects the center of the sphere to any point on the sphere. • A hemisphere is half of a sphere. • A great circle divides a sphere into two hemispheres
  • 5. Holt Geometry 10-8 Spheres Example 1A: Finding Volumes of Spheres Find the volume of the sphere. Give your answer in terms of . = 2304 in3 Simplify. Volume of a sphere.
  • 6. Holt Geometry 10-8 Spheres Example 1B: Finding Volumes of Spheres Find the diameter of a sphere with volume 36,000 cm3 . Substitute 36,000 for V. 27,000 = r3 r = 30 d = 60 cm d = 2r Take the cube root of both sides. Volume of a sphere.
  • 7. Holt Geometry 10-8 Spheres Example 1C: Finding Volumes of Spheres Find the volume of the hemisphere. Volume of a hemisphere Substitute 15 for r. = 2250 m3 Simplify.
  • 8. Holt Geometry 10-8 Spheres Example 3A: Finding Surface Area of Spheres Find the surface area of a sphere with diameter 76 cm. Give your answers in terms of . S = 4r2 S = 4(38)2 = 5776 cm2 Surface area of a sphere
  • 9. Holt Geometry 10-8 Spheres Example 3B: Finding Surface Area of Spheres Find the volume of a sphere with surface area 324 in2 . Give your answers in terms of . Substitute 324 for S. 324 = 4r2 r = 9 Solve for r. Substitute 9 for r. The volume of the sphere is 972 in2 . S = 4r2 Surface area of a sphere
  • 10. Holt Geometry 10-8 Spheres Example 3C: Finding Surface Area of Spheres Find the surface area of a sphere with a great circle that has an area of 49 mi2 . Substitute 49 for A. 49 = r2 r = 7 Solve for r. S = 4r2 = 4(7)2 = 196 mi2 Substitute 7 for r. A = r2 Area of a circle
  • 11. Holt Geometry 10-8 Spheres Lesson Quiz: Part I Find each measurement. Give your answers in terms of . 1. the volume and surface area of the sphere 2. the volume and surface area of a sphere with great circle area 36 in2 3. the volume and surface area of the hemisphere V = 36 cm3 ; S = 36 cm2 V = 288 in3 ; S = 144 in2 V = 23,958 ft3 ; S = 3267 ft2
  • 12. Holt Geometry 10-8 Spheres Lesson Quiz: Part II 4. A sphere has radius 4. If the radius is multiplied by 5, describe what happens to the surface area. 5. Find the volume and surface area of the composite figure. Give your answer in terms of . The surface area is multiplied by 25. V = 522 ft3 ; S = 267 ft2