4. How many towers required to cover Bangladeshi land mass?
❑ Assume-
▪ Bangladesh land area = 148460 Km2
▪ Mobile tower cover a radius of 1 Km
▪ All towers are interconnected to provide all Bangladesh coverage
▪ Calculate number of mobile towers required to fully cover Bangladesh
❑Calculation:
▪ Mobile tower coverage with 1Km radius = 3.14 Km2
▪ Number of towers = 148460/3.14 = 47280
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7. Satellite Communication
❑ What is the satellite communications?
▪ Satellite communication is the communication between two or more earth stations
(user terminals) by using artificial earth satellites as relay stations to forward radio
waves.
❑Satellite communication has three forms:
▪ Between satellite and earth station;
▪ Between satellites;
▪ Between earth stations via satellites.
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8. Features
▪ Launch and control
technology is complex
▪ Propagation delay is large
▪ Affected by outer space
▪ Communication distance is long
▪ Service scope is wide
▪ Communication quality is good
▪ Not restricted by geographical
conditions
▪ Wide available bandwidth
▪ Large communication capacity
▪ Independent of the ground
communication
▪ Network routing is simple.
▪ Network construction is fast and low
cost.
▪ Secure communication.
▪ Communication costs are independent
of communication distance.
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9. Early Idea
❑ The idea of satellite communications was first proposed by British Air Force officer Arthur C. Clarke
(science fiction writer) in the “Wireless World" magazine "Extra-Terrestrial Relays" (1945).
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10. Early Idea
Use of three satellites in geosynchronous orbit to enable international coverage.
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11. v.s. Cell
❑ More than 80% of the land and more than 95% of the sea area in the world lack
effective broadband information coverage.
❑ Problems of terrestrial networks:
▪ Cells: constantly split, base station
configuration problem
▪ Expensive infrastructure
investment in low population
density areas
▪ Limited communication in the air,
ocean and special occasions
▪ multi-hop network, high
complexity, service quality cannot
be guaranteed
❑ Advantages of satellite
communications
▪ Broadcast to very large area
▪ Reliable solution to last mile
problem
▪ Quick set up time with
Bandwidth on demand
▪ Provide fairness of service as
demanded
▪ Long life
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23. Orbits
23
Johannes Kepler
1571 - 1630
Laws of Planetary motion
The planets orbit in elliptical path with sun at focus
Same is true for the satellite around earth
The line joining a planet to sun sweeps out equal space in equal time
Velocity of satellite is slower at apogee and faster at perigee
24. Orbits
24
Third Law of Planetary motion
‘The square of the period of a planet to the orbit is proportional to
the cube of mean distance from the sun’
Derivation for a circular orbit
Centripetal Force = Centrifugal Force
m = mass of the body in Kg
v = velocity of the body in Km/s
r = radius of circle in Km
a = acceleration in Km/s2
F = ma Newton
28. Orbits
28
For continuous visibility –
Either put a constellation of satellites at lower earth
Orbit
Or make it relatively stable with respect to earth
If satellite period is made same as that of earth
revolution around its own axis, Satellite
apparently remains stable with respect to an
observer on earth
30. Orbits
30
Assuming spherical earth with radius of 6378 Km
Orbital height = 42164 – 6378 = 35786 Km
At these height the satellite is moving in synchronism with earth
rotation when it moves in the same direction as the earth revolves
(west to East). It is called Geo Synchronous Orbit or GSO.
What is the orbital height of a circular orbit satellite
with a period of one sidereal day?
31. When this orbital plane is same as equatorial plane then for observer
on earth surface the satellite seems to be at a stationery point above
the equator.
Orbits
31
Then it is called a Geostationary Orbit or GEO.
32. A geostationary orbit satellite will have
- satellite moves in the same direction as the earth revolves
- Orbital period is one sidereal day
- It should be in circular orbit, and
- Orbital plane have 0 angles with equatorial plane.
Bangabandhu Satellite-I (BS-I) is placed in GEO.
Orbits
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33. Satellite locations are referred with subsatellite point ( lat, long).
Orbits
33
Satellite Locations
Bangabandhu Satellite-I (BS-I) is at 119.1E.
Sub satellite point of BS-I is on equator at 119.1E
longitude.
34. Orbits
❑ GEO (geostationary earth orbit)
▪ Height: 36,000 km
▪ Orbital period: 24 hours.
▪ Propagation delay: 250ms.
▪ The coverage area is stable.
❑ LEO (low earth orbit)
▪ Height: 500~1,500km
▪ Orbital period: 1.5~2 hours
▪ Propagation delay: < 10ms
▪ Doppler effect
▪ Maximum visible time: 20 minutes.
▪ Signal propagation distance: short
▪ Link loss: small
▪ Transmission power: low
❑ MEO (medium earth orbit)
▪ Height: 5000km~20000km
▪ Orbital period: 5-10 hours
▪ Propagation delay: 50ms.
▪ Maximum visible time: a few hours.
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35. Orbits
35
Elevation: Angle between local horizontal
plane to satellite.
Azimuth: Angle from north to the line joining
the point created by satellite to earth-center
line on the horizontal plane with east wise
movement.
Antenna has been pointed skyward in angle of
elevation and from the north eastward on the
horizontal plane in angle of azimuth.
Elevation and Azimuth
39. Orbits
39
Range and Look angle
Using spherical triangles and law of cosine:
For GEO, LS is zero:
40. Orbits
40
Elevation angle
BS-1 at 119.1E, 0N at Gazipur (90.4E, 24N). Find earth station elevation angle to BS-1.
Le = 24
Ls = 0
le = 90.4
ls = 119.1
36.740
= 0.80
For 36.74, re = 6378 Km, rs = 42164 Km, El = ?
41. Orbits
41
Azimuth angle
Azimuth angle is found through an intermediate angle α.
Azimuth angle should be found from the following table:
ES at Northern Hemisphere ES at Southern Hemisphere
SSP East of ES 180 - α SSP East of ES α
SSP West of ES 180 + α SSP West of ES 360 - α
44. Orbits
44
Satellite visibility
Earth station at equator can see satellite within an arc of ± 81.3 from its longitude.
What is the GSO visibility arc for an earth station located at 87E?
87 – 81.3 = 5.7 E
87 + 81.3 = 168.3 E
45. Orbits
45
Satellite visibility
To cover whole earth with at least one satellite visibility any time in the orbital plane.
Number of satellites in the constellation ≥ 360 ∕ 2γ
46. Orbits
❑ Track height selection
▪ Van Allen belt: A harsh electric radiation environment, strong electromagnetic radiation. α
particles, protons and high energy particles are destructive to the circuit.
➢ Inner layer: 1,500-5,000 km
➢ Outer layer: 13,000-20,000 km
▪ Atmospheric resistance on satellite motion: altitude < 700 km.
▪ Three suitable windows: 700~1,500km; 5,000~Near 13,000km; more than 20,000 km.
❑ Factors to select the track
▪ Height: Higher the satellite -> Larger the coverage area -> Greater the fading
▪ Elevation angle: Angle between the earth station antenna and the ground plane: 0 ~ 70 degree.
▪ Propagation time: Propagation distance / speed of light.
▪ Interference: Same and adjacent channel interference.
▪ Launch vehicle performance: Rocket technology and reliability.
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