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Linear Algebra Exam Solutions:
Comprehensive Review and Analysis
LiveExamHelper.com
Linear Algebra: Exam
Review and Solutions
Welcome to our presentation on Linear Algebra, focusing on key
concepts and solutions from past exams. In this session, we will
delve into essential topics such as row reduction, nullspaces, and
column spaces, providing clear explanations and detailed solutions
to help you master these fundamental principles.
LiveExamHelper.com
1. Forward elimination changes Ax = b to a row reduced Rx = d: the
complete solution is
(a) What is the 3 by 3 reduced row echelon matrix R and what is d?
Solution: First, since R is in reduced row echelon form, we must
have
The other two vectors provide special solutions for R, showing that
R has rank 1: again, since it is in reduced row echelon form, the
bottom two rows must be all 0, and
the top row is
(b) If the process of elimination subtracted 3 times row 1 from row
2 and then 5 times row 1 from row 3, what matrix connects R and d
to the original A and b? Use this matrix to find A and b.
Solution: The matrix connecting R and d to the original A and b is
That is, R = EA and Eb = d. Thus, A = E−1R and b = E−1d, giving
LiveExamHelper.com
2. Suppose A is the matrix
LiveExamHelper.com
(a) Find all special solutions to Ax = 0 and describe in words the
whole nullspace of A.
Solution: First, by row reduction
so the special solutions are
LiveExamHelper.com
Thus, N(A) is a plane in R4 given by all linear combinations of the
special solutions.
(b) Describe the column space of this particular matrix A. “All
combinations of the four columns” is not a sufficient answer.
Solution: C(A) is a plane in R3 given by all combinations of the pivot
columns, namely
(c) What is the reduced row echelon form R∗ = rref(B) when B is the
6 by 8 block matrix
LiveExamHelper.com
using the same A?
Solution: Note that B immediately reduces to
We reduced A above: the row reduced echelon form of of B is thus
LiveExamHelper.com
3. Circle the words that correctly complete the following sentence:
(a) Suppose a 3 by 5 matrix A has rank r = 3. Then the equation Ax =
b
( always / sometimes but not always )
has ( a unique solution / many solutions / no solution ).
Solution: the equation Ax = b always has many solutions .
(b) What is the column space of A? Describe the nullspace of A.
Solution: The column space is a 3-dimensional space inside a 3-
dimensional space , i.e. it contains all the vectors, and the nullspace
has dimension 5 − 3 = 2 > 0 inside R5.
LiveExamHelper.com
4. Suppose that A is the matrix
(a) Explain in words how knowing all solutions to Ax = b decides if a
given vector b is in the column space of A.
Solution: The column space of A contains all linear combinations of
the columns of A, which are precisely vectors of the form Ax for an
arbitrary vector x. Thus,
Ax = b has a solution if and only if b is in the column space of A .
(b) Is the vector b = in the column space of A?
LiveExamHelper.com
Solution: Yes . Reducing the matrix combining A and b give
Thus, x = is a solution to Ax = b, and b is in the column space
of A.
LiveExamHelper.com
Conclusion:
To conclude, we have explored various aspects of Linear Algebra
through exam-style questions and detailed solutions. We hope this
presentation has enhanced your understanding of key concepts
such as row reduction, special solutions, and the relationship
between matrices and their solutions. Thank you for joining us, and
we wish you continued success in your studies of Linear Algebra.
LiveExamHelper.com

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Linear Algebra Exam Review: Key Concepts and Expert Solutions

  • 1. For Any Exam Related Queries, Text/ WhatsApp Us At : - +1(315) 557-6473 You Can Mail Us At : - support@liveexamhelper.com or Reach Us At : - https://www.liveexamhelper.com/ Linear Algebra Exam Solutions: Comprehensive Review and Analysis
  • 2. LiveExamHelper.com Linear Algebra: Exam Review and Solutions Welcome to our presentation on Linear Algebra, focusing on key concepts and solutions from past exams. In this session, we will delve into essential topics such as row reduction, nullspaces, and column spaces, providing clear explanations and detailed solutions to help you master these fundamental principles.
  • 3. LiveExamHelper.com 1. Forward elimination changes Ax = b to a row reduced Rx = d: the complete solution is (a) What is the 3 by 3 reduced row echelon matrix R and what is d? Solution: First, since R is in reduced row echelon form, we must have The other two vectors provide special solutions for R, showing that R has rank 1: again, since it is in reduced row echelon form, the bottom two rows must be all 0, and
  • 4. the top row is (b) If the process of elimination subtracted 3 times row 1 from row 2 and then 5 times row 1 from row 3, what matrix connects R and d to the original A and b? Use this matrix to find A and b. Solution: The matrix connecting R and d to the original A and b is That is, R = EA and Eb = d. Thus, A = E−1R and b = E−1d, giving LiveExamHelper.com
  • 5. 2. Suppose A is the matrix LiveExamHelper.com
  • 6. (a) Find all special solutions to Ax = 0 and describe in words the whole nullspace of A. Solution: First, by row reduction so the special solutions are LiveExamHelper.com
  • 7. Thus, N(A) is a plane in R4 given by all linear combinations of the special solutions. (b) Describe the column space of this particular matrix A. “All combinations of the four columns” is not a sufficient answer. Solution: C(A) is a plane in R3 given by all combinations of the pivot columns, namely (c) What is the reduced row echelon form R∗ = rref(B) when B is the 6 by 8 block matrix LiveExamHelper.com
  • 8. using the same A? Solution: Note that B immediately reduces to We reduced A above: the row reduced echelon form of of B is thus LiveExamHelper.com
  • 9. 3. Circle the words that correctly complete the following sentence: (a) Suppose a 3 by 5 matrix A has rank r = 3. Then the equation Ax = b ( always / sometimes but not always ) has ( a unique solution / many solutions / no solution ). Solution: the equation Ax = b always has many solutions . (b) What is the column space of A? Describe the nullspace of A. Solution: The column space is a 3-dimensional space inside a 3- dimensional space , i.e. it contains all the vectors, and the nullspace has dimension 5 − 3 = 2 > 0 inside R5. LiveExamHelper.com
  • 10. 4. Suppose that A is the matrix (a) Explain in words how knowing all solutions to Ax = b decides if a given vector b is in the column space of A. Solution: The column space of A contains all linear combinations of the columns of A, which are precisely vectors of the form Ax for an arbitrary vector x. Thus, Ax = b has a solution if and only if b is in the column space of A . (b) Is the vector b = in the column space of A? LiveExamHelper.com
  • 11. Solution: Yes . Reducing the matrix combining A and b give Thus, x = is a solution to Ax = b, and b is in the column space of A. LiveExamHelper.com
  • 12. Conclusion: To conclude, we have explored various aspects of Linear Algebra through exam-style questions and detailed solutions. We hope this presentation has enhanced your understanding of key concepts such as row reduction, special solutions, and the relationship between matrices and their solutions. Thank you for joining us, and we wish you continued success in your studies of Linear Algebra. LiveExamHelper.com