Here are the steps to solve this problem:
1) Number of storage compartments in each aisle = 40 x 8 = 320
2) Since there are 5 aisles, total storage compartments = 5 x 320 = 1600
3) Therefore, total number of unit loads that can be stored = 1600
4) Width of each aisle W = 3(x + a) = 3(30 + 6) = 3(36) = 108 in
5) Length of each aisle L = ny(y + b) = 40(40 + 8) = 40(48) = 1920 in
6) Height of each aisle H = nz(z + c) = 8(25 + 10) = 8(35)
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