Metodo de penman
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This document uses the Penman method to calculate the evapotranspiration (ETP) for a location based on meteorological data. It provides the input data and calculations. The key steps are: 1) It determines net radiation (Rn) based on factors like daylight hours, wind speed, and relative humidity. 2) It calculates the vapor pressure deficit (eD) based on maximum relative humidity and vapor pressure (eA). 3) It calculates various correction factors based on temperature, vapor pressure deficit, and wind speed. 4) It calculates the ETP as a combination of the net radiation and vapor pressure deficit terms, weighted by an empirical coefficient. The final ETP is 3.8
![πΈππ = πΆ{(π β π
(π)) + (1 β π) β [π(π’)(π π β π π)]}
πΈππ = 0.998{(0.69 β 3.13) + (1 β 0.69) β [0.629 β (18.20 β 9.65)]}
πΈππ = 3.819 ππ/πππ](https://image.slidesharecdn.com/metododepenman-140611132709-phpapp02/85/Metodo-de-penman-3-320.jpg)
Metodo de penman
- 1. MΓTODO DE PENMAN Datos: π π(ΒΊπΆ) = 16 π»π πππππ (%) = 53% π»π πππ₯πππ (%) = 60% πππ‘ππ‘π’π πππππ π£ππππ‘π = 4π/π ππ π ( ππ πππ ) = 132 πππ‘ππ‘π’π = 2000 π = 8 πππ‘ππ‘π’π π π’π = 14ΒΊπΆ πππ = πππ¦π π£ππππππππ ππ π£ππππ‘π = 3π/π ππ π πππ π πππβπ = 3 1 πΌ = 0.30 ππππππππ: οΆ π (π‘ππππ 2.20 π) π = 11.76 βππππ /πππ π π = 8 11.76 = 0.68 π π = 12.10 πππ»π (π‘ππππ 2.19 π) π π = (0.25 + 0.50 β π/π)π π π π = (0.25 + 0.50 β 8 11.76 ) β 12.10 π π =7.14 mm/dΓa π ππ = (1ββ) β π π π ππ = (1 β 0.30) β 12.10 π ππ = 4.99 ππ πππ
- 2. π π = 18.20ππππ π‘ππππ 2.16 π π = π πβπ»π % 100 π π = 18.20β53 100 π π = 9.65ππππ π(π‘)=13.8 π‘ππππ 2.22 π(ππ)=0.202 (Se interpola) π(π/π)=0.666 (Se interpola) π (ππ)= π(π‘) β π(ππ) β π(π/π) π (ππ)=13.8 β 0.202 β 0.666 π (ππ)=1.86 ππ πππ π (π)= π ππ β π (ππ) π (π)=4.99 β 1.86 π (π)=3.13 ππ πππ π(π§)=0.88 π‘ππππ 2.17 ππ§ = π(π§) β π ππ§ = 0.88 β 132 ππ§ = 116.16 ππ πππ π(π’)=0.27 β (1 + π π§ 100 ) π(π’)=0.27 β (1 + 116.16 100 ) π(π’)=0.584 πΉπ΄πΆπππ πΆ π‘ππππ 2.23 β΄ πΆ = 0.998 (Se interpola) W= 0.690 π‘ππππ 2.18
- 3. πΈππ = πΆ{(π β π (π)) + (1 β π) β [π(π’)(π π β π π)]} πΈππ = 0.998{(0.69 β 3.13) + (1 β 0.69) β [0.629 β (18.20 β 9.65)]} πΈππ = 3.819 ππ/πππ