Operating Systems Chapter 6 silberschatz

Silberschatz, Galvin and Gagne ©2018
Operating System Concepts – 10th Edition
Chapter 6: Synchronization
Tools

6.2 Silberschatz, Galvin and Gagne ©2018
Outline
 Background
 The Critical-Section Problem
 Peterson’s Solution
 Hardware Support for Synchronization
 Mutex Locks
 Semaphores
 Monitors
 Liveness
 Evaluation

Objectives
 Describe the critical-section problem and illustrate a
race condition
 Illustrate hardware solutions to the critical-section
problem using memory barriers, compare-and-swap
operations, and atomic variables
 Demonstrate how mutex locks, semaphores,
monitors, and condition variables can be used to
solve the critical section problem
 Evaluate tools that solve the critical-section problem
in low-, Moderate-, and high-contention scenarios

Background
 Processes can execute concurrently
• May be interrupted at any time, partially completing execution
 Concurrent access to shared data may result in data
inconsistency
 Maintaining data consistency requires mechanisms to ensure the
orderly execution of cooperating processes
 We illustrated in chapter 4 the problem when we considered the
Bounded Buffer problem with use of a counter that is updated
concurrently by the producer and consumer,. Which lead to race
condition.

Race Condition
 Processes P0 and P1 are creating child processes using the fork()
system call
 Race condition on kernel variable next_available_pid which
represents the next available process identifier (pid)
 Unless there is a mechanism to prevent P0 and P1 from accessing the
variable next_available_pid the same pid could be assigned to
two different processes!

Critical Section Problem
 Consider system of n processes {p0, p1, … pn-1}
 Each process has critical section segment of code
• Process may be changing common variables, updating table,
writing file, etc.
• When one process in critical section, no other may be in its
critical section
 Critical section problem is to design protocol to solve this
 Each process must ask permission to enter critical section in entry
section, may follow critical section with exit section, then
remainder section

Critical Section
 General structure of process Pi

Critical-Section Problem (Cont.)
1. Mutual Exclusion - If process Pi is executing in its critical section,
then no other processes can be executing in their critical sections
2. Progress - If no process is executing in its critical section and there
exist some processes that wish to enter their critical section, then the
selection of the process that will enter the critical section next cannot
be postponed indefinitely
3. Bounded Waiting - A bound must exist on the number of times that
other processes are allowed to enter their critical sections after a
process has made a request to enter its critical section and before that
request is granted
• Assume that each process executes at a nonzero speed
• No assumption concerning relative speed of the n processes
Requirements for solution to critical-section problem

Interrupt-based Solution
 Entry section: disable interrupts
 Exit section: enable interrupts
 Will this solve the problem?
• What if the critical section is code that runs for an hour?
• Can some processes starve – never enter their critical section.
• What if there are two CPUs?

Software Solution 1
 Two process solution
 Assume that the load and store machine-language
instructions are atomic; that is, cannot be interrupted
 The two processes share one variable:
• int turn;
 The variable turn indicates whose turn it is to enter the
critical section
 initially, the value of turn is set to i

Algorithm for Process Pi
while (true){
while (turn = = j);
/* critical section */
turn = j;
/* remainder section */
}

Correctness of the Software Solution
 Mutual exclusion is preserved
Pi enters critical section only if:
turn = i
and turn cannot be both 0 and 1 at the same time
 What about the Progress requirement?
 What about the Bounded-waiting requirement?

Peterson’s Solution
 Two process solution
 Assume that the load and store machine-language
instructions are atomic; that is, cannot be interrupted
 The two processes share two variables:
• int turn;
• boolean flag[2]
 The variable turn indicates whose turn it is to enter the
critical section
 The flag array is used to indicate if a process is ready to
enter the critical section.
• flag[i] = true implies that process Pi is ready!

Algorithm for Process Pi
while (true){
flag[i] = true;
turn = j;
while (flag[j] && turn = = j)
;
flag[i] = false;
}

Correctness of Peterson’s Solution
 Provable that the three CS requirement are met:
1. Mutual exclusion is preserved
Pi enters CS only if:
either flag[j] = false or turn = i
2. Progress requirement is satisfied
3. Bounded-waiting requirement is met

Peterson’s Solution and Modern Architecture
 Although useful for demonstrating an algorithm, Peterson’s
Solution is not guaranteed to work on modern architectures.
• To improve performance, processors and/or compilers may
reorder operations that have no dependencies
 Understanding why it will not work is useful for better
understanding race conditions.
 For single-threaded this is ok as the result will always be the
same.
 For multithreaded the reordering may produce inconsistent or
unexpected results!

Modern Architecture Example
 Two threads share the data:
boolean flag = false;
int x = 0;
 Thread 1 performs
while (!flag)
;
print x
 Thread 2 performs
x = 100;
flag = true
 What is the expected output?
100

Modern Architecture Example (Cont.)
 However, since the variables flag and x are independent
of each other, the instructions:
flag = true;
x = 100;
for Thread 2 may be reordered
 If this occurs, the output may be 0!

Peterson’s Solution Revisited
 The effects of instruction reordering in Peterson’s Solution
 This allows both processes to be in their critical section at the same
time!
 To ensure that Peterson’s solution will work correctly on modern
computer architecture we must use Memory Barrier.

Memory Barrier
 Memory model are the memory guarantees a computer
architecture makes to application programs.
 Memory models may be either:
• Strongly ordered – where a memory modification of one
processor is immediately visible to all other processors.
• Weakly ordered – where a memory modification of one
processor may not be immediately visible to all other
processors.
 A memory barrier is an instruction that forces any change in
memory to be propagated (made visible) to all other processors.

Memory Barrier Instructions
 When a memory barrier instruction is performed, the system
ensures that all loads and stores are completed before any
subsequent load or store operations are performed.
 Therefore, even if instructions were reordered, the memory
barrier ensures that the store operations are completed in
memory and visible to other processors before future load or
store operations are performed.

Memory Barrier Example
 Returning to the example of slides 6.17 - 6.18
 We could add a memory barrier to the following instructions
to ensure Thread 1 outputs 100:
 Thread 1 now performs
while (!flag)
memory_barrier();
print x
 Thread 2 now performs
x = 100;
memory_barrier();
flag = true
 For Thread 1 we are guaranteed that that the value of flag
is loaded before the value of x.
 For Thread 2 we ensure that the assignment to x occurs
before the assignment flag.

Synchronization Hardware
 Many systems provide hardware support for implementing the
critical section code.
 Uniprocessors – could disable interrupts
• Currently running code would execute without preemption
• Generally too inefficient on multiprocessor systems
 Operating systems using this not broadly scalable
 We will look at three forms of hardware support:
1. Hardware instructions
2. Atomic variables

Hardware Instructions
 Special hardware instructions that allow us to either
test-and-modify the content of a word, or two swap the
contents of two words atomically (uninterruptedly.)
• Test-and-Set instruction
• Compare-and-Swap instruction

The test_and_set Instruction
 Definition
boolean test_and_set (boolean *target)
{
boolean rv = *target;
*target = true;
return rv:
}
 Properties
• Executed atomically
• Returns the original value of passed parameter
• Set the new value of passed parameter to true

Solution Using test_and_set()
 Shared boolean variable lock, initialized to false
 Solution:
do {
while (test_and_set(&lock))
; /* do nothing */
lock = false;
} while (true);
 Does it solve the critical-section problem?

The compare_and_swap Instruction
 Definition
int compare_and_swap(int *value, int expected, int new_value)
{
int temp = *value;
if (*value == expected)
*value = new_value;
return temp;
}
 Properties
• Executed atomically
• Returns the original value of passed parameter value
• Set the variable value the value of the passed parameter
new_value but only if *value == expected is true. That is, the
swap takes place only under this condition.

Solution using compare_and_swap
 Shared integer lock initialized to 0;
 Solution:
while (true){
while (compare_and_swap(&lock, 0, 1) != 0)
; /* do nothing */
lock = 0;
}
 Does it solve the critical-section problem?

Bounded-waiting with compare-and-swap
while (true) {
waiting[i] = true;
key = 1;
while (waiting[i] && key == 1)
key = compare_and_swap(&lock,0,1);
waiting[i] = false;
j = (i + 1) % n;
while ((j != i) && !waiting[j])
j = (j + 1) % n;
if (j == i)
lock = 0;
else
waiting[j] = false;
}

Atomic Variables
 Typically, instructions such as compare-and-swap are used
as building blocks for other synchronization tools.
 One tool is an atomic variable that provides atomic
(uninterruptible) updates on basic data types such as
integers and booleans.
 For example:
• Let sequence be an atomic variable
• Let increment() be operation on the atomic variable
sequence
• The Command:
increment(&sequence);
ensures sequence is incremented without interruption:

Atomic Variables
 The increment() function can be implemented as follows:
void increment(atomic_int *v)
{
int temp;
do {
temp = *v;
}
while (temp != (compare_and_swap(v,temp,temp+1));
}

Mutex Locks
 Previous solutions are complicated and generally inaccessible to
application programmers
 OS designers build software tools to solve critical section problem
 Simplest is mutex lock
• Boolean variable indicating if lock is available or not
 Protect a critical section by
• First acquire() a lock
• Then release() the lock
 Calls to acquire() and release() must be atomic
• Usually implemented via hardware atomic instructions such as
compare-and-swap.
 But this solution requires busy waiting
• This lock therefore called a spinlock

Solution to CS Problem Using Mutex Locks
while (true) {
acquire lock
critical section
release lock
remainder section
}

Semaphore
 Synchronization tool that provides more sophisticated ways
(than Mutex locks) for processes to synchronize their activities.
 Semaphore S – integer variable
 Can only be accessed via two indivisible (atomic) operations
• wait() and signal()
 Originally called P() and V()
 Definition of the wait() operation
wait(S) {
while (S <= 0)
; // busy wait
S--;
}
 Definition of the signal() operation
signal(S) {
S++;
}

Semaphore (Cont.)
 Counting semaphore – integer value can range over
an unrestricted domain
 Binary semaphore – integer value can range only
between 0 and 1
• Same as a mutex lock
 Can implement a counting semaphore S as a binary
semaphore
 With semaphores we can solve various synchronization
problems

Semaphore Usage Example
 Solution to the CS Problem
• Create a semaphore “mutex” initialized to 1
wait(mutex);
CS
signal(mutex);
 Consider P1 and P2 that with two statements S1 and S2 and
the requirement that S1 to happen before S2
• Create a semaphore “synch” initialized to 0
P1:
S1;
signal(synch);
P2:
wait(synch);
S2;

Semaphore Implementation
 Must guarantee that no two processes can execute the wait()
and signal() on the same semaphore at the same time
 Thus, the implementation becomes the critical section problem
where the wait and signal code are placed in the critical
section
 Could now have busy waiting in critical section implementation
• But implementation code is short
• Little busy waiting if critical section rarely occupied
 Note that applications may spend lots of time in critical sections
and therefore this is not a good solution

Semaphore Implementation with no Busy waiting
 With each semaphore there is an associated waiting queue
 Each entry in a waiting queue has two data items:
• Value (of type integer)
• Pointer to next record in the list
 Two operations:
• block – place the process invoking the operation on the
appropriate waiting queue
• wakeup – remove one of processes in the waiting queue
and place it in the ready queue

Implementation with no Busy waiting (Cont.)
 Waiting queue
typedef struct {
int value;
struct process *list;
} semaphore;

Implementation with no Busy waiting (Cont.)
wait(semaphore *S) {
S->value--;
if (S->value < 0) {
add this process to S->list;
block();
}
}
signal(semaphore *S) {
S->value++;
if (S->value <= 0) {
remove a process P from S->list;
wakeup(P);
}
}

Problems with Semaphores
 Incorrect use of semaphore operations:
• signal(mutex) …. wait(mutex)
• wait(mutex) … wait(mutex)
• Omitting of wait (mutex) and/or signal (mutex)
 These – and others – are examples of what can occur when
semaphores and other synchronization tools are used
incorrectly.

Monitors
 A high-level abstraction that provides a convenient and effective
mechanism for process synchronization
 Abstract data type, internal variables only accessible by code within
the procedure
 Only one process may be active within the monitor at a time
 Pseudocode syntax of a monitor:
monitor monitor-name
{
// shared variable declarations
procedure P1 (…) { …. }
procedure P2 (…) { …. }
procedure Pn (…) {……}
initialization code (…) { … }
}

Schematic view of a Monitor

Monitor Implementation Using Semaphores
 Variables
semaphore mutex
mutex = 1
 Each procedure P is replaced by
wait(mutex);
…
body of P;
…
signal(mutex);
 Mutual exclusion within a monitor is ensured

Condition Variables
 condition x, y;
 Two operations are allowed on a condition variable:
• x.wait() – a process that invokes the operation is suspended
until x.signal()
• x.signal() – resumes one of processes (if any) that invoked
x.wait()
 If no x.wait() on the variable, then it has no effect on the
variable

Monitor with Condition Variables

Usage of Condition Variable Example
 Consider P1 and P2 that that need to execute two statements S1 and
S2 and the requirement that S1 to happen before S2
• Create a monitor with two procedures F1 and F2 that are
invoked by P1 and P2 respectively
• One condition variable “x” initialized to 0
• One Boolean variable “done”
• F1:
S1;
done = true;
x.signal();
• F2:
if done = false
x.wait()
S2;

Monitor Implementation Using Semaphores
 Variables
semaphore mutex; // (initially = 1)
semaphore next; // (initially = 0)
int next_count = 0; // number of processes waiting
inside the monitor
 Each function P will be replaced by
wait(mutex);
…
body of P;
…
if (next_count > 0)
signal(next)
else
signal(mutex);
 Mutual exclusion within a monitor is ensured

Implementation – Condition Variables
 For each condition variable x, we have:
semaphore x_sem; // (initially = 0)
int x_count = 0;
 The operation x.wait() can be implemented as:
x_count++;
if (next_count > 0)
signal(next);
else
signal(mutex);
wait(x_sem);
x_count--;

Implementation (Cont.)
 The operation x.signal() can be implemented as:
if (x_count > 0) {
next_count++;
signal(x_sem);
wait(next);
next_count--;
}

Resuming Processes within a Monitor
 If several processes queued on condition variable x,
and x.signal() is executed, which process should
be resumed?
 FCFS frequently not adequate
 Use the conditional-wait construct of the form
x.wait(c)
where:
• c is an integer (called the priority number)
• The process with lowest number (highest priority) is
scheduled next

 Allocate a single resource among competing processes using priority
numbers that specifies the maximum time a process plans to use the
resource
R.acquire(t);
...
access the resurce;
...
R.release;
 Where R is an instance of type ResourceAllocator
Single Resource allocation

 Allocate a single resource among competing processes using priority
numbers that specifies the maximum time a process plans to use the
resource
 The process with the shortest time is allocated the resource first
 Let R is an instance of type ResourceAllocator (next slide)
 Access to ResourceAllocator is done via:
R.acquire(t);
...
access the resurce;
...
R.release;
 Where t is the maximum time a process plans to use the resource
Single Resource allocation

A Monitor to Allocate Single Resource
monitor ResourceAllocator
{
boolean busy;
condition x;
void acquire(int time) {
if (busy)
x.wait(time);
busy = true;
}
void release() {
busy = false;
x.signal();
}
initialization code() {
busy = false;
}
}

Single Resource Monitor (Cont.)
 Usage:
acquire
...
release
 Incorrect use of monitor operations
• release() … acquire()
• acquire() … acquire())
• Omitting of acquire() and/or release()

Liveness
 Processes may have to wait indefinitely while trying to acquire a
synchronization tool such as a mutex lock or semaphore.
 Waiting indefinitely violates the progress and bounded-waiting criteria
discussed at the beginning of this chapter.
 Liveness refers to a set of properties that a system must satisfy to
ensure processes make progress.
 Indefinite waiting is an example of a liveness failure.

 Deadlock – two or more processes are waiting indefinitely for an
event that can be caused by only one of the waiting processes
 Let S and Q be two semaphores initialized to 1
P0 P1
wait(S); wait(Q);
wait(Q); wait(S);
... ...
signal(S); signal(Q);
signal(Q); signal(S);
 Consider if P0 executes wait(S) and P1 wait(Q). When P0 executes
wait(Q), it must wait until P1 executes signal(Q)
 However, P1 is waiting until P0 execute signal(S).
 Since these signal() operations will never be executed, P0 and P1 are
deadlocked.
Liveness

 Other forms of deadlock:
 Starvation – indefinite blocking
• A process may never be removed from the semaphore queue in
which it is suspended
 Priority Inversion – Scheduling problem when lower-priority process
holds a lock needed by higher-priority process
• Solved via priority-inheritance protocol
Liveness

Priority Inheritance Protocol
 Consider the scenario with three processes P1, P2, and P3.
• P1 has the highest priority, P2 the next highest, and P3 the
lowest.
 Assume that P3 is holding semaphore S and that P1 is waiting to S to
be released
 Assume that P2 is assigned the CPU and preempts P3
• P3 is still holding semaphore S
• P1 is waiting to S to be released
 What has happened is that P2 - a process with a lower priority than
P1 - has indirectly prevented P3 from gaining access to the resource.
 To prevent this from occurring, a priority inheritance protocol is
used. This simply allows the priority of the highest thread waiting to
access a shared resource to be assigned to the thread currently using
the resource. Thus, the current owner of the resource is assigned the
priority of the highest priority thread wishing to acquire the resource.

Usage of Condition Variable Example
 Consider P1 and P2 that that need to execute two statements S1 and
S2 and the requirement that S1 to happen before S2
• Create a monitor with two procedures F1 and F2 that are
invoked by P1 and P2 respectively
• One condition variable “x” initialized to 0
• One Boolean variable “done”
• F1:
S1;
done = true;
x.signal();
• F2:
if done = false
x.wait()
S2;

Operating Systems Chapter 6 silberschatz

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