Power of a hypothesis test
The power of a hypothesis test is the probability that the test correctly rejects the
null hypothesis (H0​
) when the alternative hypothesis (H1​
) is true.
In other words, it measures the test’s ability to detect a true effect.
Mathematical Definition
• The power of a test is given by:
• Power=1−β
where:
• β is the probability of making a Type II error (failing to reject H0​when H1​is true).
• 1−β represents the probability of correctly rejecting H0​when H1​is true.
Key Factors Affecting Power
1.Sample Size (n): Larger sample sizes reduce variability, making it easier to detect differences
and increasing power.
2.Significance Level (α): A higher significance level (e.g., 0.05 vs. 0.01) increases power but
also raises the chance of a Type I error.
3.Effect Size: Larger differences between the null and alternative hypotheses are easier to detect,
increasing power.
4.Variability (Standard Deviation, σ): Lower variability in the data leads to higher
power.
5.Test Type: One-tailed tests generally have more power than two-tailed tests when the direction
of the effect is known.
Interpretation
 A high power (e.g., 0.8 or 80%) means the test is likely to
detect a real effect.
 A low power means there's a high chance of missing a real
effect (Type II error).
Problem :-
A researcher wants to test if a new tutoring program improves exam scores. Historical
data shows scores average 75 (σ = 10). The program is expected to increase scores
to 79 (a 4-point gain). Using a sample of 25 students and a 5% significance level,
calculate the power of the test.
Solution
1.Hypotheses:
 H0:μ=75H0​ :μ=75 (No improvement).
 H1:μ>75H1​ :μ>75 (One-tailed test: scores increase).
2.Significance Level:
α=0.05α=0.05.
3.Critical Value:
For α=0.05α=0.05 (one-tailed), the critical zz-value is 1.645
Step :- 4 Find β (Type II Error Probability):
β is the probability that we fail to reject H0 when H1 is actually true (i.e.,
the mean is really 79).
We compute the z-score for Xc=78.29 under H1​(mean = 79):
z=78.29−79
2
=-0.355
From the z-table, the probability of getting a z-score less than -0.355 is
0.3612.
Thus, β=0.3612(36.12%), meaning there is a 36.12% chance of failing to
detect an improvement.
Step :- 5 Calculate Power:
Using the formula:
Power =1−β
=1−0.3612
=0.6388
the power of the test is 63.88%.
consclusion :- Since the power is around 64%, it's moderately strong, but
researchers often prefer power to be at least 80%. If a higher power is needed

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Power of a hypothesis test mathes probabality mca syllabus for probability and stats

  • 1. Power of a hypothesis test
  • 2. The power of a hypothesis test is the probability that the test correctly rejects the null hypothesis (H0​ ) when the alternative hypothesis (H1​ ) is true. In other words, it measures the test’s ability to detect a true effect. Mathematical Definition • The power of a test is given by: • Power=1−β where: • β is the probability of making a Type II error (failing to reject H0​when H1​is true). • 1−β represents the probability of correctly rejecting H0​when H1​is true.
  • 3. Key Factors Affecting Power 1.Sample Size (n): Larger sample sizes reduce variability, making it easier to detect differences and increasing power. 2.Significance Level (α): A higher significance level (e.g., 0.05 vs. 0.01) increases power but also raises the chance of a Type I error. 3.Effect Size: Larger differences between the null and alternative hypotheses are easier to detect, increasing power. 4.Variability (Standard Deviation, σ): Lower variability in the data leads to higher power. 5.Test Type: One-tailed tests generally have more power than two-tailed tests when the direction of the effect is known.
  • 4. Interpretation  A high power (e.g., 0.8 or 80%) means the test is likely to detect a real effect.  A low power means there's a high chance of missing a real effect (Type II error).
  • 5. Problem :- A researcher wants to test if a new tutoring program improves exam scores. Historical data shows scores average 75 (σ = 10). The program is expected to increase scores to 79 (a 4-point gain). Using a sample of 25 students and a 5% significance level, calculate the power of the test. Solution 1.Hypotheses:  H0:μ=75H0​ :μ=75 (No improvement).  H1:μ>75H1​ :μ>75 (One-tailed test: scores increase). 2.Significance Level: α=0.05α=0.05. 3.Critical Value: For α=0.05α=0.05 (one-tailed), the critical zz-value is 1.645
  • 6. Step :- 4 Find β (Type II Error Probability): β is the probability that we fail to reject H0 when H1 is actually true (i.e., the mean is really 79). We compute the z-score for Xc=78.29 under H1​(mean = 79): z=78.29−79 2 =-0.355 From the z-table, the probability of getting a z-score less than -0.355 is 0.3612. Thus, β=0.3612(36.12%), meaning there is a 36.12% chance of failing to detect an improvement.
  • 7. Step :- 5 Calculate Power: Using the formula: Power =1−β =1−0.3612 =0.6388 the power of the test is 63.88%. consclusion :- Since the power is around 64%, it's moderately strong, but researchers often prefer power to be at least 80%. If a higher power is needed