2. The power of a hypothesis test is the probability that the test correctly rejects the
null hypothesis (H0
) when the alternative hypothesis (H1
) is true.
In other words, it measures the test’s ability to detect a true effect.
Mathematical Definition
• The power of a test is given by:
• Power=1−β
where:
• β is the probability of making a Type II error (failing to reject H0when H1is true).
• 1−β represents the probability of correctly rejecting H0when H1is true.
3. Key Factors Affecting Power
1.Sample Size (n): Larger sample sizes reduce variability, making it easier to detect differences
and increasing power.
2.Significance Level (α): A higher significance level (e.g., 0.05 vs. 0.01) increases power but
also raises the chance of a Type I error.
3.Effect Size: Larger differences between the null and alternative hypotheses are easier to detect,
increasing power.
4.Variability (Standard Deviation, σ): Lower variability in the data leads to higher
power.
5.Test Type: One-tailed tests generally have more power than two-tailed tests when the direction
of the effect is known.
4. Interpretation
A high power (e.g., 0.8 or 80%) means the test is likely to
detect a real effect.
A low power means there's a high chance of missing a real
effect (Type II error).
5. Problem :-
A researcher wants to test if a new tutoring program improves exam scores. Historical
data shows scores average 75 (σ = 10). The program is expected to increase scores
to 79 (a 4-point gain). Using a sample of 25 students and a 5% significance level,
calculate the power of the test.
Solution
1.Hypotheses:
H0:μ=75H0 :μ=75 (No improvement).
H1:μ>75H1 :μ>75 (One-tailed test: scores increase).
2.Significance Level:
α=0.05α=0.05.
3.Critical Value:
For α=0.05α=0.05 (one-tailed), the critical zz-value is 1.645
6. Step :- 4 Find β (Type II Error Probability):
β is the probability that we fail to reject H0 when H1 is actually true (i.e.,
the mean is really 79).
We compute the z-score for Xc=78.29 under H1(mean = 79):
z=78.29−79
2
=-0.355
From the z-table, the probability of getting a z-score less than -0.355 is
0.3612.
Thus, β=0.3612(36.12%), meaning there is a 36.12% chance of failing to
detect an improvement.
7. Step :- 5 Calculate Power:
Using the formula:
Power =1−β
=1−0.3612
=0.6388
the power of the test is 63.88%.
consclusion :- Since the power is around 64%, it's moderately strong, but
researchers often prefer power to be at least 80%. If a higher power is needed