Practical no 5
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This program verifies if a user-input number is completely divisible by 5 and 2. The code takes in a number, uses the modulo (%) operator to check if the number is divisible by 2 and 5, and prints a message if it meets both criteria. It was tested by inputting 10, which returned the message that the number is divisible by 5 and 2.
Practical no 5
- 1. Practical No.-5 Aim : To demonstrate the program for verifying The numbers which is completely divisible By 5 & 2. Source code : #include<iostream.h> #include<conio.h> void main() { int a; cout <<”Enter the value of a”; cin >>a; if (a%2=0)&&(a%5=0) cout<<”the number is divisible by 5&2”; } Output : Enter the value of a=10 the number is divisible by 5&2