Presentation of the lesson area of a kite
- 1. Presentation of the Lesson Now, I Know everybody of you is already familiar with the kite right? Anyone can draw a kite on the board? Okay good job! Now, try to look at the drawing and observe. What can you say about it? That’s right! So if it’s like a diamond, how many sides are there in the kite? Yes Ma’am! ( One student will draw kite) Ma’am the kite is like diamond in shape. It has four sides.
- 2. Alright! And if it has four sides, in what group of geometric shape does it belong? That’s very good answer! The kite is a quadrilateral shape with two distinct pairs of adjacent sides, what do you call that? Correct! What else do you see? Correct! Now, try to look at the intersecting point. What kind of angles is formed? Good answer! If two lines formed right angle or measures 90 degrees, these 2 lines are also known as what? Very good answer! Now, after identifying all the properties of a kite. We will try to find the area of a kite. Okay? Ma’am quadrilateral shape. Congruent sides. There is an intersecting line Ma’am! Right angles Ma’am! Ma’am they are also known as perpendicular lines. Yes Ma’am!
- 3. This is the formula we are going to use in finding the area of a kite. Area = ½ d1 d2 Class can you follow? Now to satisfy each value in the given formula. We will put labels on the kite. Looking again to our formula, “d” stands for diagonal. In our kite we have two diagonal lines and that is our d1 ( the longer one) and the shorter is d2. By substituting the value in the given formula, what will be the value of our d1? Yes Ma’am! LineBD B A C D
- 4. Okay that’s right! And what will be the value of our d2? Okay let’s try. But before that we have 3 steps to solve the problem. What are those steps? Everybody read. Now, by following all those steps we can now solve the problem. Now what is the answer to our step 1? Okay very good! And how about on our step 2? And for the last step Very good! Is there any questions or clarification? I have two more kites here, who wants to answer on the board? d1 = 6cm and d2 = 3cm Line AC 1. Know what is given 2. Substitute the value 3. Solve Ma’am, for step 1 the given are line BD= 30 cm and line AC = 20 cm. Area= ½ d1 d2 = ½ ( 30 cm) (20cm) Area = ½ (600 cm2 ) = 300 cm2 None Ma’am! Area= ½ ( 6cm) (3cm) = ½ (18 cm2) = 9cm2
- 5. d1= 10cm and d2 = 5cm Class any questions? Area = ½ (10cm) (5cm) = ½ (50 cm2) = 25 cm2