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A questionnaire was distributed to students from various programs at a university to collect data about their demographics, interests, and opinions on marketing campaigns. The questionnaire collected information on gender, program of study, GPA, and interests of respondents. Most students responded positively to the questions regarding whether they would like to try the products, buy them if seen in a store, and actively seek them out. Analysis of the responses showed most students agreed or were neutral that the marketing campaign was attractive, well-executed, and beneficial for society.

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Stat final presentation
Stat final presentation
 A data has been collected with the help of questionnaire from the students of different age, group at university of arid agriculture.  The questionnaire has been divided into two sections, which indicate the gender, course, CGPA and interest of the students.  The accumulative response is positive which shows that it is a good.
Q:1 Would you like to try such products? Q:2 Would you buy such products if you happened to see it in a store? Q:3 Would you actively seek out such products in a store in order to purchase it? Q:4 I would favor such Marketing Campaign? Q:5 It is good Marketing Campaign? Q:6 Such Marketing Campaigns are beneficial for society? Q:7 This marketing campaign has attractive contents? Q:8 This marketing campaign has excellent execution? Q:9 I like this campaign?
 Frequency Distribution  Cumulative frequency distribution  Graphical representation of data  Measure of central tendency • Mean • Median • Mode • Percentile • Quartile  Measure of dispersion: • Range • Variance • Standard Deviation • Co-efficient of variance  Relative Measure • Z-Score • Outlier
Q:1 Would you like to try such products? Would you like to try such products? Classes Frequency Relative frequency Percent frequency Cumulative Frequency Cumulative Percent Strongly Disagree 3 0.06 6.0 3 6.0 Disagree 11 0.22 22.0 14 28.0 Neutral 13 0.26 26.0 27 54.0 Agree 17 0.34 34.0 44 88.0 Strongly Agree 6 0.12 12.0 50 100.0 Total 50 1.0 100.0 •Frequency distribution : Cross Tabulation With respect to class: Would you like to try such products? * Class Crosstabulation Questions Class Total BBA MBA MS MDM OTHERS Strongly Disagree 0 3 0 0 0 3 Disagree 0 6 2 3 0 11 Neutral 2 5 1 2 3 13 Agree 0 15 0 2 0 17 Strongly Agree 0 4 0 2 0 6 Total 2 33 3 9 3 50
Bar Graph and Pie chart: Histogram and Dot plot:
Interpretation: In the above we analyze the 50 student about their class who gave the opinion about the “Would you like to try such products” in it we collect the data from MBA, MDM, BBA, MS and Others And conclude that many student like the product. Particulars Formulas Analysis Mean 3.2400 Median Middle Value or Average middle Value 3.00 Mode Most Repeated Value 4.00 Percentile(m=64) 4.00 Quartile Q1 Q2 Q3 25% 50% 75% 2.00 3.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 2.00 3.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 1.247 Standard Deviation 1.1168 Co-efficient of Variance 34.50% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output
-.21489 -.21489 -2.0056 1.57587 .68049 -.21489 -.21489 .68049 .68049 -1.11027 -.21489 .68049 -.21489 -.21489 -.21489 -.21489 -2.00565 1.57587 .68049 -1.11027 -.21489 -1.11027 -1.11027 -.21489 1.57587 -.21489 .68049 .68049 .68049 1.57587 -1.11027 .68049 .68049 .68049 -1.11027 .68049 1.57587 .68049 -1.11027 .68049 -1.1102 -1.11027 -2.00565 .68049 -.21489 -1.11027 .68049 1.57587 .68049 -1.11027
In the above we describe the opinion of the Student from which we collect the information about the “Would you like to try such products?” In the tabular and graphical form. Now we go our next Question which is Q:2 Would you buy such products if you happened to see it in a store? Frequency Distribution : Would you buy such products if you happened to see it in a store? Frequency Relative Frequency Percent frequency Cumulative Frequency Cumulative percent Strongly Disagree 1 0.02 2 1 2 Disagree 5 0.10 10 6 12 Neutral 16 0.32 32 22 44 Agree 23 0.46 46 45 90 Strongly Agree 5 0.10 10 50 100 Total 50 1.00 100 Cross Tabulation With Respect to Class: Questions Class Total BBA MBA MS MDM OTHERS Strongly Disagree 0 1 0 0 0 1 Disagree 0 2 1 1 1 5 Neutral 1 11 2 2 0 16 Agree 1 14 0 6 2 23 Strongly Agree 0 5 0 0 0 5 Total 2 33 3 9 3 50
Bar Graph and Pie chart: Histogram and Dot Plot:
Interpretation: In the above we analyze the 50 student about their class who gave the opinion about the “Would you buy such products if you happened to see it in a store?” in it we collect the data from MBA, MDM, BBA, MS and Others And conclude that many student like the product. Particulars Formulas Analysis Mean 3.5200 Geometric Mean Harmonic mean Median Middle Value or Average middle Value 4.00 Mode Most Repeated Value 4.00 Percentile(m=67) 4.00 Quartile Q1 Q2 Q3 25% 50% 75% 3.00 4.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 3.00 4.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 0.785 Standard Deviation .8861 Co-efficient of Variance 25.17% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output
-.58679 -.58679 -1.71524 .54165 .54165 -.58679 .54165 1.67010 .54165 .54165 .54165 -2.84368 .54165 -.58679 -1.71524 -1.71524 -.58679 .54165 .54165 -.58679 .54165 .54165 -.58679 .5416 1.67010 .54165 .54165 .54165 .54165 -1.71524 .54165 1.67010 -.58679 -.58679 -.58679 .54165 -.58679 .54165 -.58679 -.58679 -.58679 -.58679 -1.71524 .54165 .54165 -.58679 1.67010 1.67010 .54165 .54165
Q:3 Would you actively seek out such products in a store in order to purchase it? Would you actively seek out such products in a store in order to purchase it? Question Frequency Relative Frequency Percent Frequency Cumulative Frequency Cumulative Percent Strongly Disagree 4 0.08 8.0 4 8.0 Disagree 8 0.16 16.0 12 24.0 Neutral 17 0.34 34.0 29 58.0 Agree 13 0.26 26.0 42 84.0 Strongly agree 8 0.16 16.0 50 100.0 Total 50 1.0 100.0 •Frequency Distribution: Would you actively seek out such products in a store in order to purchase it? Questions Class Total BBA MBA MS MDM OTHERS Strongly Disagree 0 3 1 0 0 4 Disagree 1 3 1 2 1 8 Neutral 0 14 0 2 1 17 Agree 1 9 0 2 1 13 Strongly agree 0 4 1 3 0 8 Total 2 33 3 9 3 50 •Cross Tabulation:
•Bar graph and Pie chart: •Histogram And Dot Plot:
Interpretation: The above graph and table shown the response of the students about the actively Seek out the goods. In the store or not and we analyze that Neutral Student are more in it which means they neither interested active seek out the Goods. Particulars Formulas Analysis Mean 3.2600 Harmonic mean Median Middle Value or Average middle Value 3.00 Mode Most Repeated Value 3.00 Percentile(m=67) 3.00 Quartile Q1 Q2 Q3 25% 50% 75% 2.7500 3.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 2.7500 3.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 1.399 Standard Deviation 1.1572 Co-efficient of Variance 35.50% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output
1.42993 -1.31993 .51331 -.40331 -.40331 -1.31993 .51331 -.40331 -.40331 -.40331 .51331 -1.31993 .51331 .51331 1.42993 -.40331 -.40331 1.42993 .51331 .51331 -.40331 .51331 .51331 1.42993 -2.23655 .51331 -.40331 .51331 -.40331 1.42993 1.42993 -.40331 -2.23655 -.40331 1.42993 -.40331 -.40331 -.40331 -.40331 1.42993 .51331 .51331 .51331 1.42993 -.40331 -1.31993 -2.23655 .51331 -1.31993 -.40331
Q:4 I would favor such Marketing Campaign. I would favor such Marketing Campaign. Frequency Relative Frequency Percent Frequency Cumulative Frequency Cumulative Percent strongly disagree 6 0.12 12.0 6 12.0 disagree 7 0.14 14.0 13 26.0 Neutral 14 0.28 28.0 27 54.0 Agree 14 0.28 28.0 41 82.0 Strongly agree 9 0.18 18.0 50 100.0 Total 50 1.0 100.0 •Frequency Distribution: I would favor such Marketing Campaign. * Class Cross tabulation Question Class Total BBA MBA MS MDM OTHERS strongly disagree 0 2 1 2 1 6 disagree 1 4 1 0 1 7 Neutral 0 10 0 4 0 14 Agree 0 12 0 1 1 14 Strongly agree 1 5 1 2 0 9 Total 2 33 3 9 3 50 •Cross Tabulation with Respect to Class:
•Bar Graph and Pie chart: •Histogram and Dot Plot:
Particulars Formulas Analysis Mean 3.2600 Geometric Mean Harmonic mean Median Middle Value or Average middle Value 3.00 Mode Most Repeated Value 3.00 Percentile(m=67) 3.0300 Quartile Q1 Q2 Q3 25% 50% 75% 2.00 3.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 2.00 3.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 1.584 Standard Deviation 1.2586 Co-efficient of Variance 38.61% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output Interpretation: In it we take the Suggestion from the Student about the Product, and the result is mostly agree or neutral. Which help us to makes the decision making.
1.38249 -1.00111 -1.00111 -.20658 -1.00111 -.20658 .58795 .58795 .58795 .58795 1.38249 -1.79564 -.20658 -.20658 .58795 -1.00111 -1.79564 1.38249 -1.00111 -.20658 -1.79564 -.20658 -1.79564 1.38249 1.38249 .58795 -.20658 -1.00111 -.20658 -1.79564 -.20658 1.38249 -.20658 1.38249 .58795 -.20658 -.20658 .58795 -.20658 1.38249 -1.79564 -.20658 .58795 .58795 .58795 -1.00111 .58795 .58795 .58795 1.38249
Q:5 It is good Marketing Campaign. It is good Marketing Campaign. Question: Frequency Relative Frequency Percent Frequency Cumulative frequency Cumulative Percent strongly disagree 7 0.14 14.0 7 14.0 Disagree 5 0.10 10.0 12 24.0 Neutral 10 0.20 20.0 22 44.0 Agree 22 0.44 44.0 44 88.0 Strongly Agree 6 0.12 12.0 50 100.0 Total 50 1.0 100.0 •Frequency Distribution: It is good Marketing Campaign. * Class Cross tabulation Question: Class Total BBA MBA MS MDM OTHERS strongly disagree 1 4 0 2 0 7 disagree 0 2 1 0 2 5 Neutral 0 8 1 1 0 10 Agree 1 15 1 4 1 22 Strongly Agree 0 4 0 2 0 6 Total 2 33 3 9 3 50 • Cross tabulation With respect to Class:
Bar Graph And Pie chart: •Histogram and Dot Plot:
Particulars Formulas Analysis Mean 3.3000 Geometric Mean Harmonic mean Median Middle Value or Average middle Value 4.00 Mode Most Repeated Value 4.00 Percentile(m=43) 4.00 Quartile Q1 Q2 Q3 25% 50% 75% 2.7500 4.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 2.7500 4.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 1.520 Standard Deviation 1.2330 Co-efficient of Variance 37.36% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output Interpretation: In it we take the opinion from the students about the campaign of the product, and we conclude that many students agree from the marketing campaign about the product and we show it graph and table in the above.
.56770 -1.86530 -1.86530 -.24330 -.24330 -.24330 .56770 .56770 .56770 .56770 1.37870 -1.86530 .56770 .56770 .56770 -1.05430 -1.86530 -.24330 -.24330 .56770 -1.05430 .56770 .56770 .56770 1.37870 .56770 -1.05430 .56770 .56770 -1.86530 .56770 1.37870 .56770 .56770 -.24330 .56770 -1.86530 -1.86530 -.24330 1.37870 -1.05430 -1.05430 .56770 -.24330 1.37870 -.24330 1.37870 .56770 -.24330 .56770
Q:6 Such Marketing Campaigns are beneficial for society. Such Marketing Campaigns are beneficial for society. Question: Frequency Relative Frequency Percent Frequency C.F Cumulative Percent Strongly disagree 3 0.06 6.0 3 6.0 disagree 5 0.10 10.0 8 16.0 Neutral 18 0.36 36.0 26 52.0 Agree 15 0.30 30.0 41 82.0 Strongly agree 9 0.18 18.0 50 100.0 Total 50 1.00 100.0 Questions Class Total BBA MBA MS MDM OTHERS Strongly disagree 0 2 0 1 0 3 disagree 1 3 1 0 0 5 Neutral 0 12 1 3 2 18 Agree 0 11 1 2 1 15 Strongly agree 1 5 0 3 0 9 Total 2 33 3 9 3 50 •Frequency Distribution: •Cross Tabulation:
•Bar Graph and pie chart: •Dot Plot and Histogram:
Particulars Formulas Analysis Mean 3.4400 Geometric Mean Harmonic mean Median Middle Value or Average middle Value 3.00 Mode Most Repeated Value 3.00 Percentile(m=67) 4.00 Quartile Q1 Q2 Q3 25% 50% 75% 3.00 3.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 3.00 3.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 1.190 Standard Deviation 1.091 Co-efficient of Variance 31.72% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output Interpretation: In the above we shows the reaction of students about Marketing Campaigns are beneficial for society and we conclude that many student are agree of such kind of marketing campaign.
1.42993 -1.31993 .51331 -.40331 -.40331 -1.31993 .51331 -.40331 -1.31993 -.40331 .51331 -1.31993 .51331 -.40331 -.40331 -.40331 -.40331 .51331 1.42993 1.42993 1.42993 .51331 .51331 -.40331 1.42993 .51331 -.40331 1.42993 -.40331 1.42993 -.40331 -.40331 .51331 -.40331 -2.23655 -.40331 -.40331 .51331 1.42993 .51331 .51331 -2.23655 -2.23655 .51331 1.42993 -1.31993 .51331 -.40331 .51331 -.40331
Q:7 This marketing campaign has attractive contents This marketing campaign has attractive contents. Questions Frequency Relative Frequency Percent frequency Cumulative Frequency Cumulative percent Strongly disagree 2 0.04 4.0 2 2 disagree 6 0.12 12.0 8 16 Neutral 18 0.36 36.0 26 52 Agree 18 0.36 36.0 44 88 Strongly agree 6 0.12 12.0 50 100 Total 50 1.00 100.0 This marketing campaign has attractive contents. * Class Cross tabulation Questions: Class Total BBA MBA MS MDM OTHERS Strongly disagree 0 1 0 1 0 2 disagree 0 3 1 0 2 6 Neutral 1 13 1 3 0 18 agree 0 12 1 4 1 18 Strongly agree 1 4 0 1 0 6 Total 2 33 3 9 3 50 Frequency Distribution: Cross tabulation:
•Bar Graph and Pie chart •Histogram and Dot plot:
Interpretation: In the above we take opinion from the students and in position of to take the decision that many student agree or strongly agree about the marketing campaign has attractive context. Particulars Formulas Analysis Mean 3.3400 Geometric Mean Harmonic mean Median Middle Value or Average middle Value 3.00 Mode Most Repeated Value 3.00 Percentile(m=87) 4.3700 Quartile Q1 Q2 Q3 25% 50% 75% 3.00 3.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 3.00 3.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance .980 Standard Deviation .9897 Co-efficient of Variance 29.63% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output
1.61658 -.40415 -1.41451 -.40415 -.40415 -.40415 1.61658 .60622 .60622 1.61658 -1.41451 -.40415 -1.41451 -.40415 .60622 .60622 .60622 -.40415 -.40415 1.61658 .60622 1.61658 .60622 -.40415 -.40415 .60622 .60622 .60622 -.40415 .60622 -1.41451 .60622 -.40415 -.40415 -2.42487 -1.41451 -.40415 .60622 -.40415 .60622 -.40415 -2.42487 -.40415 1.61658 .60622 .60622 -.40415 -.40415 .60622 .60622
Q:8 This marketing campaign has excellent execution. This marketing campaign has excellent execution. Questions Frequency Relative Frequency Percent Frequency Cumulative Frequency Cumulative Percent strongly disagree 3 0.06 6.0 3 6 disagree 7 0.14 14.0 10 20 Neutral 13 0.26 26.0 23 46 Agree 17 0.34 34.0 40 80 Strongly agree 10 0.20 20.0 50 100 Total 50 1.00 100.0 This marketing campaign has excellent execution. * Class Cross tabulation Questions: Class Total BBA MBA MS MDM OTHERS strongly disagree 1 1 0 1 0 3 disagree 0 1 2 2 2 7 Neutral 1 10 1 1 0 13 Agree 0 13 0 3 1 17 Strongly agree 0 8 0 2 0 10 Total 2 33 3 9 3 50 Frequency Distribution: Cross tabulation:
•Bar Graph and Pie chart: •Histogram and Dot Plot:
Particulars Formulas Analysis Mean 3.4800 Geometric Mean Harmonic mean Median Middle Value or Average middle Value 4.00 Mode Most Repeated Value 4.00 Percentile(m=31) 3.00 Quartile Q1 Q2 Q3 25% 50% 75% 3.00 4.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 3.00 4.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 1.316 Standard Deviation 1.1471 Co-efficient of Variance 32.96% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output Interpretation: In the above we plot the suggestion of the students about the marketing campaign has excellent execution. And at the end we conclude that many student are the favor of the Agree to the execution of the marketing.
-.41843 -2.16191 .45330 -.41843 .45330 -1.29017 1.32504 .45330 .45330 1.32504 -1.29017 -1.29017 -.41843 .45330 -.41843 .45330 -.41843 1.32504 -.41843 .45330 .45330 .45330 .45330 .45330 1.32504 .45330 1.32504 -.41843 .45330 -2.16191 -1.29017 1.32504 -.41843 1.32504 1.32504 -1.29017 .45330 1.32504 -.41843 .45330 .45330 -.41843 -1.29017 -1.29017 1.32504 -.41843 -2.16191 .45330 -.41843 -.41843
Q:9 I like this campaign. I like this campaign. Questions Frequency Relative Frequency Percent Frequency Cumulative Frequency Cumulative Percent strongly disagree 5 0.10 10.0 5 10 Disagree 4 0.08 8.0 9 18 Neutral 14 0.28 28.0 23 46 Agree 16 0.32 32.0 39 78 strongly agree 11 0.22 22.0 50 100 Total 50 1.00 100.0 I like this campaign. * Class Cross tabulation Questions Class Total BBA MBA MS MDM OTHERS strongly disagree 1 4 0 0 0 5 Disagree 0 3 0 0 1 4 Neutral 0 12 1 0 1 14 Agree 1 9 2 3 1 16 strongly agree 0 5 0 6 0 11 Total 2 33 3 9 3 50 Frequency Distribution: •Cross tabulation:
•Bar Graph and Pie chart: •Histogram and Dot Plot:
Particulars Formulas Analysis Mean 3.4800 Geometric Mean Harmonic mean Median Middle Value or Average middle Value 4.00 Mode Most Repeated Value 4.00 Percentile(m=46) 3.4600 Quartile Q1 Q2 Q3 25% 50% 75% 3.00 4.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 3.00 4.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 1.479 Standard Deviation 1.2162 Co-efficient of Variance 34.95% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output Interpretation: In it we take the opinion of the student that the like the marketing campaign of the product or not, and at the end we conclude that many student are in the Favor of the Marketing and they like the such type of Marketing campaign.
.42756 -2.03911 -2.03911 .42757 .42756 -.39467 -1.21689 .42756 -.39467 1.24978 1.24978 -2.03911 -.39467 -.39467 .42756 -1.21689 -2.03911 1.24978 .42756 1.24978 -.39467 1.24978 1.24978 -.39467 .42756 .42756 -.39467 -.39467 -2.03911 1.24978 .42756 1.24978 -.39467 -.39467 -1.21689 -.39467 -.39467 1.24978 .42756 .42756 .42756 -.39467 -.39467 -1.21689 1.24978 .42756 .42756 .42756 -.39467 1.24978
Stat final presentation

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Stat final presentation

  • 3.  A data has been collected with the help of questionnaire from the students of different age, group at university of arid agriculture.  The questionnaire has been divided into two sections, which indicate the gender, course, CGPA and interest of the students.  The accumulative response is positive which shows that it is a good.
  • 4. Q:1 Would you like to try such products? Q:2 Would you buy such products if you happened to see it in a store? Q:3 Would you actively seek out such products in a store in order to purchase it? Q:4 I would favor such Marketing Campaign? Q:5 It is good Marketing Campaign? Q:6 Such Marketing Campaigns are beneficial for society? Q:7 This marketing campaign has attractive contents? Q:8 This marketing campaign has excellent execution? Q:9 I like this campaign?
  • 5.  Frequency Distribution  Cumulative frequency distribution  Graphical representation of data  Measure of central tendency • Mean • Median • Mode • Percentile • Quartile  Measure of dispersion: • Range • Variance • Standard Deviation • Co-efficient of variance  Relative Measure • Z-Score • Outlier
  • 6. Q:1 Would you like to try such products? Would you like to try such products? Classes Frequency Relative frequency Percent frequency Cumulative Frequency Cumulative Percent Strongly Disagree 3 0.06 6.0 3 6.0 Disagree 11 0.22 22.0 14 28.0 Neutral 13 0.26 26.0 27 54.0 Agree 17 0.34 34.0 44 88.0 Strongly Agree 6 0.12 12.0 50 100.0 Total 50 1.0 100.0 •Frequency distribution : Cross Tabulation With respect to class: Would you like to try such products? * Class Crosstabulation Questions Class Total BBA MBA MS MDM OTHERS Strongly Disagree 0 3 0 0 0 3 Disagree 0 6 2 3 0 11 Neutral 2 5 1 2 3 13 Agree 0 15 0 2 0 17 Strongly Agree 0 4 0 2 0 6 Total 2 33 3 9 3 50
  • 7. Bar Graph and Pie chart: Histogram and Dot plot:
  • 8. Interpretation: In the above we analyze the 50 student about their class who gave the opinion about the “Would you like to try such products” in it we collect the data from MBA, MDM, BBA, MS and Others And conclude that many student like the product. Particulars Formulas Analysis Mean 3.2400 Median Middle Value or Average middle Value 3.00 Mode Most Repeated Value 4.00 Percentile(m=64) 4.00 Quartile Q1 Q2 Q3 25% 50% 75% 2.00 3.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 2.00 3.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 1.247 Standard Deviation 1.1168 Co-efficient of Variance 34.50% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output
  • 9. -.21489 -.21489 -2.0056 1.57587 .68049 -.21489 -.21489 .68049 .68049 -1.11027 -.21489 .68049 -.21489 -.21489 -.21489 -.21489 -2.00565 1.57587 .68049 -1.11027 -.21489 -1.11027 -1.11027 -.21489 1.57587 -.21489 .68049 .68049 .68049 1.57587 -1.11027 .68049 .68049 .68049 -1.11027 .68049 1.57587 .68049 -1.11027 .68049 -1.1102 -1.11027 -2.00565 .68049 -.21489 -1.11027 .68049 1.57587 .68049 -1.11027
  • 10. In the above we describe the opinion of the Student from which we collect the information about the “Would you like to try such products?” In the tabular and graphical form. Now we go our next Question which is Q:2 Would you buy such products if you happened to see it in a store? Frequency Distribution : Would you buy such products if you happened to see it in a store? Frequency Relative Frequency Percent frequency Cumulative Frequency Cumulative percent Strongly Disagree 1 0.02 2 1 2 Disagree 5 0.10 10 6 12 Neutral 16 0.32 32 22 44 Agree 23 0.46 46 45 90 Strongly Agree 5 0.10 10 50 100 Total 50 1.00 100 Cross Tabulation With Respect to Class: Questions Class Total BBA MBA MS MDM OTHERS Strongly Disagree 0 1 0 0 0 1 Disagree 0 2 1 1 1 5 Neutral 1 11 2 2 0 16 Agree 1 14 0 6 2 23 Strongly Agree 0 5 0 0 0 5 Total 2 33 3 9 3 50
  • 11. Bar Graph and Pie chart: Histogram and Dot Plot:
  • 12. Interpretation: In the above we analyze the 50 student about their class who gave the opinion about the “Would you buy such products if you happened to see it in a store?” in it we collect the data from MBA, MDM, BBA, MS and Others And conclude that many student like the product. Particulars Formulas Analysis Mean 3.5200 Geometric Mean Harmonic mean Median Middle Value or Average middle Value 4.00 Mode Most Repeated Value 4.00 Percentile(m=67) 4.00 Quartile Q1 Q2 Q3 25% 50% 75% 3.00 4.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 3.00 4.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 0.785 Standard Deviation .8861 Co-efficient of Variance 25.17% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output
  • 13. -.58679 -.58679 -1.71524 .54165 .54165 -.58679 .54165 1.67010 .54165 .54165 .54165 -2.84368 .54165 -.58679 -1.71524 -1.71524 -.58679 .54165 .54165 -.58679 .54165 .54165 -.58679 .5416 1.67010 .54165 .54165 .54165 .54165 -1.71524 .54165 1.67010 -.58679 -.58679 -.58679 .54165 -.58679 .54165 -.58679 -.58679 -.58679 -.58679 -1.71524 .54165 .54165 -.58679 1.67010 1.67010 .54165 .54165
  • 14. Q:3 Would you actively seek out such products in a store in order to purchase it? Would you actively seek out such products in a store in order to purchase it? Question Frequency Relative Frequency Percent Frequency Cumulative Frequency Cumulative Percent Strongly Disagree 4 0.08 8.0 4 8.0 Disagree 8 0.16 16.0 12 24.0 Neutral 17 0.34 34.0 29 58.0 Agree 13 0.26 26.0 42 84.0 Strongly agree 8 0.16 16.0 50 100.0 Total 50 1.0 100.0 •Frequency Distribution: Would you actively seek out such products in a store in order to purchase it? Questions Class Total BBA MBA MS MDM OTHERS Strongly Disagree 0 3 1 0 0 4 Disagree 1 3 1 2 1 8 Neutral 0 14 0 2 1 17 Agree 1 9 0 2 1 13 Strongly agree 0 4 1 3 0 8 Total 2 33 3 9 3 50 •Cross Tabulation:
  • 15. •Bar graph and Pie chart: •Histogram And Dot Plot:
  • 16. Interpretation: The above graph and table shown the response of the students about the actively Seek out the goods. In the store or not and we analyze that Neutral Student are more in it which means they neither interested active seek out the Goods. Particulars Formulas Analysis Mean 3.2600 Harmonic mean Median Middle Value or Average middle Value 3.00 Mode Most Repeated Value 3.00 Percentile(m=67) 3.00 Quartile Q1 Q2 Q3 25% 50% 75% 2.7500 3.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 2.7500 3.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 1.399 Standard Deviation 1.1572 Co-efficient of Variance 35.50% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output
  • 17. 1.42993 -1.31993 .51331 -.40331 -.40331 -1.31993 .51331 -.40331 -.40331 -.40331 .51331 -1.31993 .51331 .51331 1.42993 -.40331 -.40331 1.42993 .51331 .51331 -.40331 .51331 .51331 1.42993 -2.23655 .51331 -.40331 .51331 -.40331 1.42993 1.42993 -.40331 -2.23655 -.40331 1.42993 -.40331 -.40331 -.40331 -.40331 1.42993 .51331 .51331 .51331 1.42993 -.40331 -1.31993 -2.23655 .51331 -1.31993 -.40331
  • 18. Q:4 I would favor such Marketing Campaign. I would favor such Marketing Campaign. Frequency Relative Frequency Percent Frequency Cumulative Frequency Cumulative Percent strongly disagree 6 0.12 12.0 6 12.0 disagree 7 0.14 14.0 13 26.0 Neutral 14 0.28 28.0 27 54.0 Agree 14 0.28 28.0 41 82.0 Strongly agree 9 0.18 18.0 50 100.0 Total 50 1.0 100.0 •Frequency Distribution: I would favor such Marketing Campaign. * Class Cross tabulation Question Class Total BBA MBA MS MDM OTHERS strongly disagree 0 2 1 2 1 6 disagree 1 4 1 0 1 7 Neutral 0 10 0 4 0 14 Agree 0 12 0 1 1 14 Strongly agree 1 5 1 2 0 9 Total 2 33 3 9 3 50 •Cross Tabulation with Respect to Class:
  • 19. •Bar Graph and Pie chart: •Histogram and Dot Plot:
  • 20. Particulars Formulas Analysis Mean 3.2600 Geometric Mean Harmonic mean Median Middle Value or Average middle Value 3.00 Mode Most Repeated Value 3.00 Percentile(m=67) 3.0300 Quartile Q1 Q2 Q3 25% 50% 75% 2.00 3.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 2.00 3.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 1.584 Standard Deviation 1.2586 Co-efficient of Variance 38.61% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output Interpretation: In it we take the Suggestion from the Student about the Product, and the result is mostly agree or neutral. Which help us to makes the decision making.
  • 21. 1.38249 -1.00111 -1.00111 -.20658 -1.00111 -.20658 .58795 .58795 .58795 .58795 1.38249 -1.79564 -.20658 -.20658 .58795 -1.00111 -1.79564 1.38249 -1.00111 -.20658 -1.79564 -.20658 -1.79564 1.38249 1.38249 .58795 -.20658 -1.00111 -.20658 -1.79564 -.20658 1.38249 -.20658 1.38249 .58795 -.20658 -.20658 .58795 -.20658 1.38249 -1.79564 -.20658 .58795 .58795 .58795 -1.00111 .58795 .58795 .58795 1.38249
  • 22. Q:5 It is good Marketing Campaign. It is good Marketing Campaign. Question: Frequency Relative Frequency Percent Frequency Cumulative frequency Cumulative Percent strongly disagree 7 0.14 14.0 7 14.0 Disagree 5 0.10 10.0 12 24.0 Neutral 10 0.20 20.0 22 44.0 Agree 22 0.44 44.0 44 88.0 Strongly Agree 6 0.12 12.0 50 100.0 Total 50 1.0 100.0 •Frequency Distribution: It is good Marketing Campaign. * Class Cross tabulation Question: Class Total BBA MBA MS MDM OTHERS strongly disagree 1 4 0 2 0 7 disagree 0 2 1 0 2 5 Neutral 0 8 1 1 0 10 Agree 1 15 1 4 1 22 Strongly Agree 0 4 0 2 0 6 Total 2 33 3 9 3 50 • Cross tabulation With respect to Class:
  • 23. Bar Graph And Pie chart: •Histogram and Dot Plot:
  • 24. Particulars Formulas Analysis Mean 3.3000 Geometric Mean Harmonic mean Median Middle Value or Average middle Value 4.00 Mode Most Repeated Value 4.00 Percentile(m=43) 4.00 Quartile Q1 Q2 Q3 25% 50% 75% 2.7500 4.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 2.7500 4.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 1.520 Standard Deviation 1.2330 Co-efficient of Variance 37.36% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output Interpretation: In it we take the opinion from the students about the campaign of the product, and we conclude that many students agree from the marketing campaign about the product and we show it graph and table in the above.
  • 25. .56770 -1.86530 -1.86530 -.24330 -.24330 -.24330 .56770 .56770 .56770 .56770 1.37870 -1.86530 .56770 .56770 .56770 -1.05430 -1.86530 -.24330 -.24330 .56770 -1.05430 .56770 .56770 .56770 1.37870 .56770 -1.05430 .56770 .56770 -1.86530 .56770 1.37870 .56770 .56770 -.24330 .56770 -1.86530 -1.86530 -.24330 1.37870 -1.05430 -1.05430 .56770 -.24330 1.37870 -.24330 1.37870 .56770 -.24330 .56770
  • 26. Q:6 Such Marketing Campaigns are beneficial for society. Such Marketing Campaigns are beneficial for society. Question: Frequency Relative Frequency Percent Frequency C.F Cumulative Percent Strongly disagree 3 0.06 6.0 3 6.0 disagree 5 0.10 10.0 8 16.0 Neutral 18 0.36 36.0 26 52.0 Agree 15 0.30 30.0 41 82.0 Strongly agree 9 0.18 18.0 50 100.0 Total 50 1.00 100.0 Questions Class Total BBA MBA MS MDM OTHERS Strongly disagree 0 2 0 1 0 3 disagree 1 3 1 0 0 5 Neutral 0 12 1 3 2 18 Agree 0 11 1 2 1 15 Strongly agree 1 5 0 3 0 9 Total 2 33 3 9 3 50 •Frequency Distribution: •Cross Tabulation:
  • 27. •Bar Graph and pie chart: •Dot Plot and Histogram:
  • 28. Particulars Formulas Analysis Mean 3.4400 Geometric Mean Harmonic mean Median Middle Value or Average middle Value 3.00 Mode Most Repeated Value 3.00 Percentile(m=67) 4.00 Quartile Q1 Q2 Q3 25% 50% 75% 3.00 3.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 3.00 3.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 1.190 Standard Deviation 1.091 Co-efficient of Variance 31.72% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output Interpretation: In the above we shows the reaction of students about Marketing Campaigns are beneficial for society and we conclude that many student are agree of such kind of marketing campaign.
  • 29. 1.42993 -1.31993 .51331 -.40331 -.40331 -1.31993 .51331 -.40331 -1.31993 -.40331 .51331 -1.31993 .51331 -.40331 -.40331 -.40331 -.40331 .51331 1.42993 1.42993 1.42993 .51331 .51331 -.40331 1.42993 .51331 -.40331 1.42993 -.40331 1.42993 -.40331 -.40331 .51331 -.40331 -2.23655 -.40331 -.40331 .51331 1.42993 .51331 .51331 -2.23655 -2.23655 .51331 1.42993 -1.31993 .51331 -.40331 .51331 -.40331
  • 30. Q:7 This marketing campaign has attractive contents This marketing campaign has attractive contents. Questions Frequency Relative Frequency Percent frequency Cumulative Frequency Cumulative percent Strongly disagree 2 0.04 4.0 2 2 disagree 6 0.12 12.0 8 16 Neutral 18 0.36 36.0 26 52 Agree 18 0.36 36.0 44 88 Strongly agree 6 0.12 12.0 50 100 Total 50 1.00 100.0 This marketing campaign has attractive contents. * Class Cross tabulation Questions: Class Total BBA MBA MS MDM OTHERS Strongly disagree 0 1 0 1 0 2 disagree 0 3 1 0 2 6 Neutral 1 13 1 3 0 18 agree 0 12 1 4 1 18 Strongly agree 1 4 0 1 0 6 Total 2 33 3 9 3 50 Frequency Distribution: Cross tabulation:
  • 31. •Bar Graph and Pie chart •Histogram and Dot plot:
  • 32. Interpretation: In the above we take opinion from the students and in position of to take the decision that many student agree or strongly agree about the marketing campaign has attractive context. Particulars Formulas Analysis Mean 3.3400 Geometric Mean Harmonic mean Median Middle Value or Average middle Value 3.00 Mode Most Repeated Value 3.00 Percentile(m=87) 4.3700 Quartile Q1 Q2 Q3 25% 50% 75% 3.00 3.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 3.00 3.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance .980 Standard Deviation .9897 Co-efficient of Variance 29.63% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output
  • 33. 1.61658 -.40415 -1.41451 -.40415 -.40415 -.40415 1.61658 .60622 .60622 1.61658 -1.41451 -.40415 -1.41451 -.40415 .60622 .60622 .60622 -.40415 -.40415 1.61658 .60622 1.61658 .60622 -.40415 -.40415 .60622 .60622 .60622 -.40415 .60622 -1.41451 .60622 -.40415 -.40415 -2.42487 -1.41451 -.40415 .60622 -.40415 .60622 -.40415 -2.42487 -.40415 1.61658 .60622 .60622 -.40415 -.40415 .60622 .60622
  • 34. Q:8 This marketing campaign has excellent execution. This marketing campaign has excellent execution. Questions Frequency Relative Frequency Percent Frequency Cumulative Frequency Cumulative Percent strongly disagree 3 0.06 6.0 3 6 disagree 7 0.14 14.0 10 20 Neutral 13 0.26 26.0 23 46 Agree 17 0.34 34.0 40 80 Strongly agree 10 0.20 20.0 50 100 Total 50 1.00 100.0 This marketing campaign has excellent execution. * Class Cross tabulation Questions: Class Total BBA MBA MS MDM OTHERS strongly disagree 1 1 0 1 0 3 disagree 0 1 2 2 2 7 Neutral 1 10 1 1 0 13 Agree 0 13 0 3 1 17 Strongly agree 0 8 0 2 0 10 Total 2 33 3 9 3 50 Frequency Distribution: Cross tabulation:
  • 35. •Bar Graph and Pie chart: •Histogram and Dot Plot:
  • 36. Particulars Formulas Analysis Mean 3.4800 Geometric Mean Harmonic mean Median Middle Value or Average middle Value 4.00 Mode Most Repeated Value 4.00 Percentile(m=31) 3.00 Quartile Q1 Q2 Q3 25% 50% 75% 3.00 4.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 3.00 4.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 1.316 Standard Deviation 1.1471 Co-efficient of Variance 32.96% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output Interpretation: In the above we plot the suggestion of the students about the marketing campaign has excellent execution. And at the end we conclude that many student are the favor of the Agree to the execution of the marketing.
  • 37. -.41843 -2.16191 .45330 -.41843 .45330 -1.29017 1.32504 .45330 .45330 1.32504 -1.29017 -1.29017 -.41843 .45330 -.41843 .45330 -.41843 1.32504 -.41843 .45330 .45330 .45330 .45330 .45330 1.32504 .45330 1.32504 -.41843 .45330 -2.16191 -1.29017 1.32504 -.41843 1.32504 1.32504 -1.29017 .45330 1.32504 -.41843 .45330 .45330 -.41843 -1.29017 -1.29017 1.32504 -.41843 -2.16191 .45330 -.41843 -.41843
  • 38. Q:9 I like this campaign. I like this campaign. Questions Frequency Relative Frequency Percent Frequency Cumulative Frequency Cumulative Percent strongly disagree 5 0.10 10.0 5 10 Disagree 4 0.08 8.0 9 18 Neutral 14 0.28 28.0 23 46 Agree 16 0.32 32.0 39 78 strongly agree 11 0.22 22.0 50 100 Total 50 1.00 100.0 I like this campaign. * Class Cross tabulation Questions Class Total BBA MBA MS MDM OTHERS strongly disagree 1 4 0 0 0 5 Disagree 0 3 0 0 1 4 Neutral 0 12 1 0 1 14 Agree 1 9 2 3 1 16 strongly agree 0 5 0 6 0 11 Total 2 33 3 9 3 50 Frequency Distribution: •Cross tabulation:
  • 39. •Bar Graph and Pie chart: •Histogram and Dot Plot:
  • 40. Particulars Formulas Analysis Mean 3.4800 Geometric Mean Harmonic mean Median Middle Value or Average middle Value 4.00 Mode Most Repeated Value 4.00 Percentile(m=46) 3.4600 Quartile Q1 Q2 Q3 25% 50% 75% 3.00 4.00 4.00 Five Number summary Minimum value Q1 Q2 Q3 Maximum Value 1.00 3.00 4.00 4.00 5.00 Range range = xmaximum – xminimum 4.00 Variance 1.479 Standard Deviation 1.2162 Co-efficient of Variance 34.95% Z-score Give the below in the table Outlier Analyze With the Help of Z-Score There is no outlier in the given output Interpretation: In it we take the opinion of the student that the like the marketing campaign of the product or not, and at the end we conclude that many student are in the Favor of the Marketing and they like the such type of Marketing campaign.
  • 41. .42756 -2.03911 -2.03911 .42757 .42756 -.39467 -1.21689 .42756 -.39467 1.24978 1.24978 -2.03911 -.39467 -.39467 .42756 -1.21689 -2.03911 1.24978 .42756 1.24978 -.39467 1.24978 1.24978 -.39467 .42756 .42756 -.39467 -.39467 -2.03911 1.24978 .42756 1.24978 -.39467 -.39467 -1.21689 -.39467 -.39467 1.24978 .42756 .42756 .42756 -.39467 -.39467 -1.21689 1.24978 .42756 .42756 .42756 -.39467 1.24978