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- 1. A copper conductor is measured at room temperature(20 °C) to be 6.5 Ω, I f the temperature of the room increased to 4 2 °C Calculate the new resistance of the conductor R = R 0 (1+ α 0 Δ t) copper α 0 =0.0045 at 20 °C
- 2. A copper conductor is measured at room temperature(20 °C) to be 6.5 Ω, I f the temperature of the room increased to 4 2 °C Calculate the new resistance of the conductor R = R 0 (1+ α 0 Δ t) copper α 0 =0.0045 at 20 °C Put values into formulae
- 3. A copper conductor is measured at room temperature(20 °C) to be 6.5 Ω , If the temperature of the room increased to 4 2 °C Calculate the new resistance of the conductor R = R 0 (1+ α 0 Δ t) copper α 0 = 0.0045 at 20 °C R = 6.5Ω (1+ 0.0045 ( 4 2 °C - 20 °C ))
- 4. A copper conductor is measured at room temperature(20 °C) to be 6.5 Ω , If the temperature of the room increased to 4 2 °C Calculate the new resistance of the conductor R = R 0 (1+ α 0 Δ t) copper α 0 = 0.0045 at 20 °C R = 6.5Ω (1+ 0.0045 ( 4 2 °C - 20 °C )) R = 6.5Ω (1+ 0.0045 x 22 )
- 5. A copper conductor is measured at room temperature(20 °C) to be 6.5 Ω , If the temperature of the room increased to 4 2 °C Calculate the new resistance of the conductor R = R 0 (1+ α 0 Δ t) copper α 0 = 0.0045 at 20 °C R = 6.5Ω (1+ 0.0045 ( 4 2 °C - 20 °C )) R = 6.5Ω (1+ 0.0045 x 22 ) R = 6.5Ω (1+ 0.099)
- 6. A copper conductor is measured at room temperature(20 °C) to be 6.5 Ω , If the temperature of the room increased to 4 2 °C Calculate the new resistance of the conductor R = R 0 (1+ α 0 Δ t) copper α 0 = 0.0045 at 20 °C R = 6.5Ω (1+ 0.0045 ( 4 2 °C - 20 °C )) R = 6.5Ω (1+ 0.0045 x 22 ) R = 6.5Ω (1+ 0.099) R = 6.5Ω x 1.099
- 7. A copper conductor is measured at room temperature(20 °C) to be 6.5 Ω , If the temperature of the room increased to 4 2 °C Calculate the new resistance of the conductor R = R 0 (1+ α 0 Δ t) copper α 0 = 0.0045 at 20 °C R = 6.5Ω (1+ 0.0045 ( 4 2 °C - 20 °C )) R = 6.5Ω (1+ 0.0045 x 22 ) R = 6.5Ω (1+ 0.099) R = 6.5Ω x 1.099 R = 7.135 Ω
- 8. A motor winding is measured at room temperature(20 °C) to be 12 Ω, after running the motor the resistance is measured to be 26 Ω. Calculate the new temperature of the motor R = R 0 (1+ α 0 Δ t) copper α 0 =0.0045 at 20 °C
- 9. A motor winding is measured at room temperature(20 °C) to be 12 Ω , after running the motor the resistance is measured to be 26 Ω . Calculate the new temperature of the motor R = R 0 (1+ α 0 Δ t) copper α 0 = 0.0045 at 20 °C 26Ω = 12Ω (1+ 0.0045 Δ t)
- 10. A motor winding is measured at room temperature(20 °C) to be 12 Ω , after running the motor the resistance is measured to be 26 Ω . Calculate the new temperature of the motor R = R 0 (1+ α 0 Δ t) copper α 0 = 0.0045 at 20 °C 26Ω = 12Ω (1+ 0.0045 Δ t) 26Ω/ 12Ω = (1+ 0.0045 Δ t)
- 11. A motor winding is measured at room temperature(20 °C) to be 12 Ω , after running the motor the resistance is measured to be 26 Ω . Calculate the new temperature of the motor R = R 0 (1+ α 0 Δ t) copper α 0 = 0.0045 at 20 °C 26Ω = 12Ω (1+ 0.0045 Δ t) 26Ω/ 12Ω = (1+ 0.0045 Δ t) 2.166 = (1+ 0.0045 Δ t)
- 12. A motor winding is measured at room temperature(20 °C) to be 12 Ω , after running the motor the resistance is measured to be 26 Ω . Calculate the new temperature of the motor R = R 0 (1+ α 0 Δ t) copper α 0 = 0.0045 at 20 °C 26Ω = 12Ω (1+ 0.0045 Δ t) 26Ω/ 12Ω = (1+ 0.0045 Δ t) 2.166 = (1+ 0.0045 Δ t) 2.166 -1 = 0.0045 Δ t
- 13. A motor winding is measured at room temperature(20 °C) to be 12 Ω , after running the motor the resistance is measured to be 26 Ω . Calculate the new temperature of the motor R = R 0 (1+ α 0 Δ t) copper α 0 = 0.0045 at 20 °C 26Ω = 12Ω (1+ 0.0045 Δ t) 26Ω/ 12Ω = (1+ 0.0045 Δ t) 2.166 = (1+ 0.0045 Δ t) 2.166 -1 = 0.0045 Δ t 1.166 = 0.0045 Δ t
- 14. R = R 0 (1+ α 0 Δ t) copper α 0 = 0.0045 at 20 °C 26Ω = 12Ω (1+ 0.0045 Δ t) 26Ω/ 12Ω = (1+ 0.0045 Δ t) 2.166 = (1+ 0.0045 Δ t) 2.166 -1 = 0.0045 Δ t 1.166 = 0.0045 Δ t Δ t = 1.166/ 0.0045
- 15. R = R 0 (1+ α 0 Δ t) copper α 0 = 0.0045 at 20 °C 26Ω = 12Ω (1+ 0.0045 Δ t) 26Ω/ 12Ω = (1+ 0.0045 Δ t) 2.166 = (1+ 0.0045 Δ t) 2.166 -1 = 0.0045 Δ t 1.166 = 0.0045 Δ t Δ t = 1.166/ 0.0045 Δ t = 259 °C
- 16. Δ t = 259 °C This is the change in the temperature
- 17. Δ t = 259 °C This is the change in the temperature The room temperature was 20 °C and we have changed by 259 °C, so therefore our new temperature will be,
- 18. Δ t = 259 °C This is the change in the temperature The room temperature was 20 °C and we have changed by 259 °C, so therefore our new temperature will be, t = Δ t + 20 °C
- 19. Δ t = 259 °C This is the change in the temperature The room temperature was 20 °C and we have changed by 259 °C, so therefore our new temperature will be, t = Δ t + 20 °C t = 279°C