The moon creation effect on the solar system geometry (revised)

IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Moon Creation Effect On The Solar System Geometry (Revised)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo –Egypt –30th
March 2021
Abstract
Paper Question
Can Jupiter effect on Earth motion?
The Question Explanation
- 142984 km (Jupiter diameter) x 1047 = 149.6 mkm (Earth orbital distance)
- Where
- 1047 = The sun Mass / Jupiter Mass
- Many data shows that, Jupiter can effect on Earth & its moon motions, for example
- 10921 km (The moon circumference) x 449197 km (Jupiter circumference) = 4900
mkm (Jupiter orbital circumference)
Paper Claim
- The masses gravity forces is one of many ways by which Planets motions can
effect on each other- but it's not the only way – where there are many other ways
by which far planets can effect on the inner planets motions
- These ways depend on the solar system geometrical design, because the
geometrical rules based on which the solar planets data is created provide different
ways of Planets motions effect ability on each other.

I do this research
2nd
2
1- Introduction
- Jupiter (13.1 km/s) moves during 10921 seconds a distance = 142984 km = Jupiter
diameter
- But, The Earth moon circumference =10921 km
- We are astonished, and asked, how a planet circumference can be used as a period
of time? But the answer was "It's Just Pure Coincidence Of Numbers!"
- There's no doubt that this answer is mistaken
- Even if, we provide more examples – as this one –
- Uranus (6.8 km/s) moves during 7510 seconds a distance = 51118 km = Uranus
Diameter!
- But, Pluto circumference =7510 km
- The question is the same, and the answer also is the same ….!
- I try to do my best, and provide the last example:
o Pluto (4.7 km/s) moves during 10921 seconds a distance = 51118 km =
Uranus Diameter!
o Pluto (4.7 km/s) moves during 51118 seconds a distance = 2 x 120536 km =
Saturn Diameter!
- No matter what data is provided –The Golden Answer is engraved …
- Why is there no another answer?
- Because the theory considers the solar planets as rigid bodies revolve around the
sun depending on the masses gravity, each planet is created independent from the
others and by that, each planet creation and motion data is independent from the
other planets and because of that any such rate be found among planets data has no
any theoretical explanation ….
- But What's the fact?
- The fact is that,

I do this research
2nd
3
- The solar planets are created from one light beam, this light beam creates the
planet matter and its orbital distance in addition to define this planet motion
features (Orbital Inclination- Axial Tilt- Orbital Period…..etc)
- Because all solar planets are created from one light beam (or one trajectory of
energy), Each planet data be complementary with the others – and also - The solar
planets move together in one unified motion as a train carriages spite of their
different velocities –
- The double production experiment is my best example to explain the meaning of
(Complementary Data), where an electron and a positron are created from
Gamma ray, 2 particles equal in mass but different in charges. Without observation
I expect simply to catch a positron with the electron produced from Gamma ray!
Because of The Charge Reservation Law – that tells the positron charge is
created complementary to the electron charge by force of Law – perfectly as that-
each planet data is created complementary to other planets data by force of law –
otherwise they can't be found in existence.
- It's a new vision – and based on it – The solar group should be considered as one
building – each planet is a part of this same building – and because of that- each
planet data is created (Complementary) with other planets data because of the
necessity of performance the building general task – and because of that- each
planet data be complementary with the other planets data based on geometrical
rules – which means- the solar planets creation and motion data are controlled by
many geometrical rules consisted together one geometrical design belong to the
general building.
- This vision tells us
- The Earth Moon Creation is a process effective on all solar planets – So- the paper
title be understandable – because the moon creation is a process done by a general
cooperation between all planets – even if – the direct effect made by Earth – but
it's done based on the planets motion cooperation to provide a room for the new
born planet.

I do this research
2nd
4
Paper argument
- Because, by one light beam all planets are created – this light beam can use a
planet circumference as a period of time for another planet – it's a light motion
feature- but we need to know for what geometrical necessity it's done?
- I want to say that, this light beam travels from one planet to anther, and provides
the energy by which the planet builds its data, that shows why the data should be
complementary with one another – also- shows why light motion features are
discovered frequently in planets motion – but – this process is done based on
geometrical rules by which planets motions are done – that means- if we can catch
these geometrical rules we will have chance to prove this fact by Planets Motions
Explanations –
Paper Objective
- This paper picks up a number (12430) is not found in the planets data, but the
paper claims that this number is a required value for – The Moon Creation –
- What will we do?
- We will search for this number origin and moves with this number from planet to
another to see how this number effects on planets motions data – and then we
should discover this number role in the moon creation process – and at end we
should conclude the planets cooperation effect on the moon creation process –

I do this research
2nd
5
2- The Moon Creation Process
2-1 Preface
2-2 Mars Migration Theory
2-3 The Number 12430
2-4 Jupiter effect on The Earth Motion
2-1 Preface
- The moon creation is done by some collision between a planet and Earth, from
these collision debris Earth has created its moon.. in the next point we should
discuss this story in details
- But
- Does that mean, The Moon Diameter Is Created By Random, Without
Geometrical Calculations? The data disproves that clearly…
o 10921 km (the moon circumference) x 449197 km (Jupiter circumference) =
4900 mkm = Jupiter orbital circumference
o 10921 km (the moon circumference) x 86400 seconds = 940 mkm (Earth
orbital circumference)
o 10921 km (the moon circumference) x 27.3 days =300000 km (light motion
distance for 1 second)
- This data is just example of similar huge number of data – it's hard to create the
moon diameter by some random process without geometrical calculations
- The data tells, the moon diameter is created as (3475 km) to be in harmony with
Jupiter and Earth motions data - the moon is created by planets collisions but the
data is created based on geometrical calculations –
- How that can be possible?
- Let's consider a surgery, a surgeon tries to plant a piece of liver for some patient
the process is done by opening in body and causing for bleeding – as any accident
does, but the surgeon makes calculations for each step to do the task –

I do this research
2nd
6
- We look at the patient after the surgery and find that he's in safe – but – in fact –
tens of devices monitor its body components to be sure that every thing is done
according to the general law-
- The moon is created by Earth gravity attraction for the debris produced by the
collision between Earth and another planet – this is the fact – BUT
- This process is done under geometrical rules – so – every thing is done by
geometrical calculations – and because of that- the new born planet data is defined
based on geometrical rules.
Shortly
- What does this point try to tell?
o (1) The point explains in details the collisions by which the moon is created
Then
o (2) the point will follow the number (12430) to show that, all planets data is
created based on geometrical rules – and even if the planet is created by
collision – that will not cause the data to be created by any random process.
Because all planets data is created depends on geometrical rules.
That's why the solar system is consisted of one light beam
- Because
- The light beam created the solar planets matters and distances, causing the planets
to move in harmony.
- After the planets matters creation, the light beam be found in geometrical rules
form – that mean- the light energy cause to create the matter and its motion – but
after creation the light will be disappeared and the matter will be controlled by the
geometrical rules created by this light beam
- The electron and position produced by Gamma ray still after creation move
according to the charges they have by Gamma ray effect (Because Gamma Ray =
Zero charge, so the produced particles be (+ and -) and both particles motions are
controlled by their charges).

I do this research
2nd
7
2-2 Mars Migration Theory
- How is the Earth Moon Created?
- The Giant –impact hypothesis suggests that, a planet in Mars size had collided
with Earth and from this collision debris the moon is created.
- But the Giant-impact hypothesis still has questions need to be solved – for
example:
- Venus also had suffered a similar collision as Earth but Venus couldn't a moon for
it, but The Earth could! Why?
- Mars Migration Theory answer these questions, let's summarize it in following:
o Mars was the next planet after Mercury, and its original orbital distance was
84 mkm.
o Mars had migrated from its original orbital distance (84 mkm) to its new
orbital distance (227.9 mkm)
o That means, Mars has passed a displacement =144 mkm, and through this
motion Mass passed Venus and then Passed the Earth
o Mars itself (and not another) had collided with Venus (at first) and then
collided again with Earth
o After the collision between Mars and Venus, Mars had pushed all debris in
its motion direction – because of that – Venus found no debris around it and
couldn't create its moon
o When Mars had collided with Earth, the debris which came from Venus
collision lost some of its momentum, and Earth Gravity is greater than
Venus, because of that, Earth attracted these debris and created its moon
o After Mars and Earth Collision, Mars still moved toward its new orbital
distance point (227.9 mkm) and push with it some of the collisions debris
from which Mars could create its 2 moons
o The rest debris are attracted by Jupiter gravity and created the asteroid belt.

I do this research
2nd
8
This theory answers the Giant-impact hypothesis questions
o (1st
question) Why Venus could not create its moon?
o This question is answered already
o (2nd
question) What's the origin of the moon Magma ocean?
o Venus is its origin, because the moon rocks are produced by the 3 planets
collisions, means, Venus rocks are found inside the moon
But this story isn't complete yet, let's do that in following…
- Pluto was the Mercury Moon
- Pluto had migrated with Mars migration, and because Pluto is a small planet, Mars
Migration caused Pluto to be thrown at the end of the solar group range.
- Neptune original orbital distance was 5906 mkm = Pluto current orbital distance
- Pluto had pushed Neptune out of its orbit (by strong force pushed Pluto through
the solar group), and Pluto had occupied Neptune orbital distance point, forcing
Neptune to be more near to the sun
- For that reason (Pluto Neptune distance = Pluto eccentricity distance =1433 mkm)
- Neptune be on the orbital distance 4495.1 mkm
- But
- No orbit was designed in this point– Neptune was in a point as desert for a human
- For that reason, Neptune seized 14% of Jupiter total energy to create its orbital
circumference (28255 mkm)
- This story can be proved simply by data – let's see it in following
Data
(a)
Light supposed velocity (1.16 mkm/s) travels during 86400 S x 2 a distance = 200448 mkm
(b)
(Pluto Orbital Circumference 37110 mkm) – (Jupiter orbital Circumference 4900
mkm) x 2π = 202372 mkm
The difference between No. (1) and No. (2) = 1%

I do this research
2nd
9
(II)
(Neptune orbital circumference 28255 mkm–Venus orbital circumference 680 mkm)
=27575 mkm But
27575 mkm x 2π = 2 x 86400 mkm
Where
2 x 86400 mkm + 28255 mkm (Neptune orbital circumference) = 201055 mkm
The data shows, the light energy = the orbital circumferences between Neptune and
(Mercury and Earth) where Venus is used as a middle point for both.

I do this research
2nd
10
2-3 The Number 12430
I- Data
(1)
(12756 km /12430 km ) = (12430 km /12104 km )
(2)
120536 km = 9.7 km/s x 12430 seconds
300000 km = 24.1 km/s x 12430 seconds
(3)
1.163 mkm = 29.8 km/s x 39050 seconds
(4)
39050 seconds x 0.3 mkm/s = 2 x 5848 mkm
(6)
142984 km = 3.66 x 39050 km
But
(39050/ km /12756 km) = 3.1 (1%)
(6)
(39444 km)2
= 2 x 778.6 mkm
(7)
39050 km = 8 x 4879 km
(8)
100224 mkm x 2 = 4900 mkm x 41
(9)
2.5735 mkm x 39050 = 1.16 mkm/s x 86640 seconds
(10)
39050 deg = 1259.3 deg x π3
(11)
12430 km = 4.7 km/s x 2645 seconds
(12)
51118 km x 12430 km x 0.99 = 629 mkm
But 168464 km x 12430 mkm = 2094 mkm and 2 x 168464 km = 6.8 x 49528

I do this research
2nd
11
II- Discussion
Equation No. (1)
(12756 km /12430 km ) = (12430 km /12104 km )
Where
- 12756 km = Earth Diameter
- 12104 km = Venus Demeter
- The value 12430 km is the middle rate between these 2 planets diameters, where
Earth diameter is different from Venus diameter with 5% the value 12430 km is
found on the rate 2.5% from both diameters – that means – this value is an unique
value and there's no other rate between these 2 diameters can perform this
Equation.
- i.e.
- The value 12430 km is defined as the unique middle point between the Earth and
Venus Diameters.
- This is an important conclusion – because – if the planets diameters are created
independent from each other – the middle point between 2 planets diameters
should be a random point – means – the value 12430 km should have no any
geometrical effect on any planet motion – because – Earth and Venus diameters
are created by random process independent from each other –BUT
- If the value 12430 km has a geometrical effect, that tells, some geometrical design
mentioned the Earth diameter to be 12756 and Venus diameter to be 12104 km by
geometrical rules which necessitates to create the value 12430 km as a middle
point between both.

I do this research
2nd
12
Equation No. (2)
120536 km = 9.7 km/s x 12430 s 300000 km = 24.1 km/s x 12430 s
Equation No. (2) (Part I)
120536 km = 9.7 km/s x 12430 seconds
- Saturn (9.7 km/s) moves during 12430 seconds a distance =120536 km = Saturn
diameter
- This data is similar to the examples which we have seen in the paper introduction,
let's remember them here
o Jupiter (13.1 km/s) moves during 10921 seconds a distance = 142984 km =
Jupiter diameter
o Uranus (6.8 km/s) moves during 7510 seconds a distance = 51118 km =
Uranus Diameter!
o Pluto (4.7 km/s) moves during 10921 seconds a distance = 51118 km =
Uranus Diameter!
o Pluto (4.7 km/s) moves during 51118 seconds a distance = 2 x 120536 km =
Saturn Diameter!
- These examples are just some of many similar data – I have no ability to consider
this data is created by pure coincidences of numbers – but on the other side I have
no geometrical rule can explain how does that happen?
- The magician words (Light motion Features are discovered in Planets motions)
don't help at all! We need to know how a planet as Saturn whose velocity (9.7
km/s) can use anther planet diameter or circumference as a period of time?
- The next question is (WHY?), Why Uranus moves during 7510 seconds a distance
= Uranus diameter (While 7510 km = Pluto Circumference)?
- The only useful result is that– as Jupiter uses (10921 km as 10921 seconds) and
Uranus uses (7510 km as 7510 seconds…..etc) similar to that, Saturn uses 12430
km as 12430 seconds to move a distance = its diameter – that means – the value
12430 km or seconds is found in the geometrical design as the other values.

I do this research
2nd
13
Equation No. (2) (Part II)
300000 km = 24.1 km/s x 12430 seconds
- Mars (24.1 km/s) moves during 12430 seconds a distance = 300000 km = light
motion distance during 1 second
- This equation makes the value 12430 km a very specific value – that tells – this
value is created based on light known velocity (0.3 mkm/s)
- But
- It's hard to discover this value origin – because to whom this value 12430 is
belonged now? Of course it's 12430 km and belonged to Earth and Venus
Diameters Creation – but – light velocity is more trustee than any planet diameter
– and it's impossible to create the value 12430 seconds based on Earth and Venus
and by chance Mars moves by this period (12430 s) a distance = light motion for 1
second! the only solution is that, Mars velocity is defined based on these 2 values
(300000 km and 12430 seconds)!
- But
- The planets velocities are ordered relative to their distances to the sun (if no Sun
gravity why the planets velocities are ordered based on their distances to the sun?)
that means, Mars by found in this position has an obligation to have a specific
velocity ranged from (29.8 km/s Earth velocity to 13.1 km/s Jupiter Velocity), so
Mars may choose the velocity 24.1 km/s because of these 2 values (300000 km
and 12430 km) BUT
- Why does Mars move during 12430 seconds a distance = light motion distance
during 1 second?
- This data still needs more analysis – let's try to do that in following

I do this research
2nd
14
Additional data (no. A)
2 x 21346.6 km x (300000/24.1) = 532 mkm
- Where
- 21346.6 km = Mars Circumference
- 12430 seconds = 300000 km (light velocity for 1s) /24.1 Mars velocity for 1s
- 532 mkm = 2π x 84 mkm
- Mars Migration Theory tells that Mars orbital distance was 84 mkm and Mars
had migrated from its original orbital distance to its new one (227.9 mkm), so the
distance 532 mkm = Mars Original Orbital Circumference
- This distance is defined based on Mars Circumference relative to the rate between
light and Mars velocities -
- The meaning is so hard to be caught – simply we don't know why?
- Is there any other planet use this rule?!
- Venus does!
Additional data (no. B)
2 x 38041 km x (300000/35) = 652 mkm
- Where
- 38041 km = Venus Circumference
- 680 mkm = Venus Orbital Circumference (652 mkm is different with 4%)
- 300000 km/s = light known velocity
- 35 km/s = Venus velocity
- Even we don't know why this using is found? Why just 2 planets use it?
- I wish more analysis can help us to get any better understanding

I do this research
2nd
15
Equation No. (3)
1.163 mkm = 29.8 km/s x 39050 seconds
- 39050 km = π x 12430 km
- We have seen that the value 12430 km is used as 12430 seconds
- So we use also 39050 km as 39050 seconds
- Equation no. (3) tells, Earth moves during 39050 seconds a distance = 1.163 mkm,
I have supposed that there's a light velocity =1.16 mkm/s
- Earth during 39050 seconds moves a distance = light supposed velocity (1.16
mkm/s) motion during 1 second.
- That makes the period 39050 seconds a specific period for Earth motion – but
doesn't produce the velocity 1.16 mkm/s by Earth motion! why?
- Because Earth depends on its own Circumference and during a period =40268
seconds Earth (29.8 km/s) moves distance =1.2 Million km
- This value (1.2 mkm) we should discuss later in some deep details – but let's
provide a short summary about it in following
o Earth during 40268 seconds (different 0.4% from Earth Circumference
40080 km and later we should know why?) Earth moves a distance = 1.2
Million km
o Earth discounted from this value (40080 km = Earth Circumference)
o The rest is (1.16 mkm)
o This is the energy found in Jupiter Data
o Because
o Jupiter Energy is found by Earth Motion
o And
o The solar group is created based on The Earth Motion
o And
o The Earth is the Mother of the Solar Group Generally and The Earth is
found before all other planets and before the sun herself.

I do this research
2nd
16
Equation No. (4)
39050 seconds x 0.3 mkm/s = 2 x 5848 mkm
- Light velocity (0.3mkm/s) travels during 39050 s a distance =5848 mkm x 2
- 5848 mkm = Mercury Pluto Distance
- BUT
- Light supposed velocity (1.16 mkm/s) travels during 5040 s a distance =5848 mkm
- Mercury day period needs 5040 seconds to be 176 solar days
- Because of that, the period 5040 seconds is defined with Mercury Day Period
- We have 2 light beams here
o Light known velocity (0.3 mkm) travels during 39050 seconds
o Light supposed velocity (1.16 mkm) travels during 5040 seconds
- The 2 light beams travel during 2 defined periods (39050 sec and 5040 sec), no
conclusion we can provide here – what we know perfectly is that- the light
supposed velocity (1.16 km/s) is used by Jupiter distances frequently – Whether
the light supposed velocity (1.16 mkm/s) is found or not – Jupiter all distances
depends on this rate 1.16
- Based on that – We may think this value 39050 seconds (or km) must be belonged
to Jupiter Data? That means – Spite the value 12430 km is originated from many
basic data – but it's created almost from Jupiter data basically – let's try to discover
that in following

I do this research
2nd
17
Equation No. (5) (Part I)
142984 km = 3.66 x 39050 km
- Where
- 142984 km = Jupiter Diameter
- 39050 km = π x 12430 km
- (Earth diameter 12756 km/ the moon diameter 3475 km) =3.66
- The rate 3.66 is so effective because
(1)
- 365.25 days (Earth orbital period) = 27.3 days (the moon orbital period) x (3.66)2
(2)
- 4331 days (Jupiter orbital period) = 324 days (the moon year =327.6 days) x(3.66)2
(error 1.3%)
(3)
- 778.6 mkm (Jupiter orbital distance) = 58 mkm (Mercury orbital distance) x(3.66)2
(4)
(2667 x 1024
kg) = 199 x 1024
kg x (3.66)2
Where
- 2667 x 1024
kg = The Solar Planets Masses Total
- 199 x 1024
kg = The Solar Planets Masses Total (without Jupiter and Saturn)
- The data tells that, Jupiter is the basic planet in the solar system and the rate
(3.66)2
is used for the planets general order or design, because of that, there's a
deep relationship between this rate (3.66)2
and Jupiter data.
- Shortly
- (Earth diameter / the moon diameter) = (3.66), and if Jupiter diameter / Earth
diameter (or circumference) = (3.66), that will create a series of dependency
between Jupiter, Earth and its moon – but NOT – the rate is used with 39050 km
and not with Earth Circumference 40080 km and this difference between the 2
values tell us there are more geometrical rules need to be discovered…

I do this research
2nd
18
Equation No. (5) (Part II)
(39050/ km /12756 km) = 3.1 (error 1%)
- 39050 km = 12430 km x π
- 12756 km = Earth diameter
- 3.1 degrees = Jupiter Axial Tilt
- Equation no. (5) tells that, Jupiter axial tilt is created as a rate between these 2
values (39050 km and 12756 km)
- We still don't know why?
Equation No. (6)
(39444 km)2
= 2 x 778.6 mkm
- Where
- 778.6 mkm = Jupiter Orbital Distance
- 39444 km x 0.99 = 39050 km
-
- Equation No. (6) tells that, Jupiter orbital distance is defined based on the distance
39050 km (with error 1%)
- So, (39444 km)2
= Jupiter Orbital Distance
- This behavior is found also by many other planets for example
- (Uranus diameter 51118 km)2
= 2644 mkm (Mars Uranus Distance) (1%)
- Also
- (Mars Circumference 21346.6 km)2
= 2x 227.9 mkm (Mars orbital distance)
- That tells
- Jupiter depends on the value 39050 km is it's own diameter! but why? as if the rate
(3.66)2
creates a strong connection between both and Jupiter diameter and this
value became just one thing! We still don't know why or how? But Why??

I do this research
2nd
19
Equation No. (7)
39050 km = 8 x 4900 km
Let's modify this equation form as in following
39050 mkm = 8 x 4900 mkm
Where
- 4900 mkm = Jupiter Orbital Circumference
- 39050 km = π x 12430 km
- We multiply this number (39050 km) with 1 mkm, So became 39050 mkm
- Based on that,
- Equation No. (7) tells, 39050 mkm = 8 Jupiter orbital circumference (4900 mkm)
- Why this is important data?
- Because
- Jupiter has a cycle of 8 days… let's remember it in following
o Jupiter moves during its day period (9.9 h) a distance = 466884 km
o Jupiter Circumference =449197 km
o i.e. 466884 km = 449197 km +17687 km
o During 8 Jupiter Days (9.9 h x 8) Jupiter moves
o 3735072 km = 8 Jupiter Circumferences +141500 km
o The value 141500 = Jupiter diameter 142984 km with difference (1%)
o Because the small distances (17687 km) summation created (141500 km =
Jupiter diameter), it's concluded that, it's a cycle for Jupiter motion during 8
of its days – this cycle we have discussed before – But we don't know what
geometrical effect is created by it.
o We have just the number (8) which is used in our Equation no (7)…
- Equation no. (7) tells that, Jupiter motion creates the number 39050 mkm depends
on its (8 days cycle) and its orbital circumference – that tells- the value 39050
mkm has a relationship with Jupiter motion-
- But

I do this research
2nd
20
- What's the relationship between this value 39050 mkm and our discussion value
39050 km?
- The same question, what’s the relationship between Jupiter orbital circumference
4900 mkm and Mercury diameter 4900 km?!
- 4900 mkm = 4900 km x 1 million km ! Why this is significant? Because
- Jupiter diameter 142984 km = 1 Million km /7
- Where 7 degrees = Mercury Orbital Inclination
Notice (1)
- About what does this discussion argue? About different vision concerning the solar
group – let's summarize the argument in following
o The current theories suppose that, the solar planets are rigid bodies created
by some random effects of masses gravity forces and revolve around the sun
by this mass gravity – and each planet is created independent from the other
planets and by that each planet motion data is independent from the other
planets motions data – based on this theory – no proportionality can be
expected between planets creation and motion data – where all data is
independent from each other –
o The fact is that, the solar planets are created by one light beam (or one
trajectory to energy) and by that each planet data is created depending and in
proportionality with the other planets (complementary one another)
o It's another vision – but
o It gives also other explanations for the data – it's another approach for the
general understanding –
o The current theory considers Planet diameter as a piece of rock found by
some random effects - but in fact –a planet diameter is produced based on
this planet motion interaction with the other planets motions – that means -
Matter Dimensions are defined based on the motions – also space
dimensions are defined accordingly

I do this research
2nd
21
o So we can say, Earth diameter =12756 km because Earth velocity =29.8
km/s – this sentence must be true and correct – but – the whole geometrical
mechanism by which this process is done is still absent.
o means, There's no a simple equation by which planet diameter is created as a
function in its velocity – On The Contrary - there's a complex geometrical
mechanism causes Earth velocity to create its diameter in its proportionality
o At first, we need to take planets data into consideration- It's impossible to
find hundreds of equations use planets diameters and circumferences as
periods of time and produce other planets diameters and circumferences and
neglect this huge data under claim that's created by pure coincidences - that
means simply we deceive ourselves because our theory can't explain Planets
motions real data –
o We have to accept that – planet circumference can be used as a period of
time – the fact proved itself –
o Then we need to search behind a method by which a planet with low
velocity can use another planet circumference as a period of time?!
Notice (2)
- Why Mercury diameter 4900 km x 1 mkm = Jupiter orbital circumference
4900 mkm?
o There's one thread connects them – Mercury Jupiter distance 720.7 mkm x
1.0725 = 778.6 mkm (Jupiter orbital distance), because of the rate (1.0725)
we can consider both distances are equal – means – Jupiter orbital
circumference connected Jupiter with Mercury – this connection depends on
the light beam (1.16 mkm/s) travels during 4222.6 seconds (4900 mkm)
where this value is received by Mercury as 4222.6 hours (Mercury day
period)
o That means, the light beam causes to connect Mercury and Jupiter motions
together – and based on this light beam both planets created their data.

I do this research
2nd
22
Equation No. (8)
100224 mkm x 2 = 4900 mkm x 41
- Where
- 4900 mkm = Jupiter Orbital Circumference
- 41 degrees = The Solar Planets Orbital Inclinations Total
- 100224 mkm x 2 = 2 x 86400 seconds x 1.16 mkm/s (light supposed velocity)
- The value 100224 mkm x 2 (Jupiter energy) is a subject we have discussed before
frequently –
- Equation no. (8) tells that, (Jupiter energy) defines the solar planets basic motions
features (the orbital inclinations) – that because – depends on Jupiter energy the
planets move
Equation No. (9)
2.5735 mkm x 39050 = 1.16 mkm/s x 86640 seconds
- Where
- 2.573 mkm = Earth velocity per solar day
- 39050 = our number used in days units
- 1.16 mkm/s = Light supposed velocity
- 86400 seconds = the solar day
- But (86640 s/86400s) = (361 degrees/360 degrees)
- Equation No. (9) tells that, Earth moves during 39050 days a distance = light
supposed velocity (1.16 mkm/s) motion distance during a solar day
- But this comparison depends on the rate (361/360) because… the moon orbit
regresses 19 degrees per a year and during 19 years (Mtonic Cycle) it be 361
degrees - that means- this comparison is one factor among the factors causes the
moon orbit regression

I do this research
2nd
23
Equation No. (10)
39050 deg = 1259.3 deg x π3
Or 12430 deg = 1259.3 deg x π2
The equation uses 1 degree = 1 km
- Let's analyze this equation as possible
(I)
- How to find the number 1259.3 degrees?
- 177.4 deg (Venus axial tilt) +2.5 deg (Saturn orbital inclination) =179.9 deg
- 179.9 deg x 7 deg (Mercury orbital inclination) = 1259.3 degrees
- So,
- 3 planets are partners in this number 1259.3 degrees
(II)
- Why does this number (1259.3 degrees) is important?
- Because
- 1259.3 seconds x 1.16 mkm/s (light supposed velocity) =1461 mkm
- This value 1461 mkm is seen by us as 1461 days (= Earth Cycle = 365+365+365+
366 days= 1461 days)
(III)
- 1259.3 seconds x 47.4 km/s (Mercury velocity) = 60268 km (Saturn Radius) (1%)
- 1259.3sec. x 29.8 km/s (Earth velocity) =38041 km (Venus Circumference) (1.3%)
- 1259.3sec. x 9.7 km/s (Saturn velocity) =12104 km (Venus Diameter) (1%)
- Also
- 1259.3 sec. x 0.3 mkm/s (Light known velocity) =2.5x 149.6 mkm (Earth orbital
distance) (1%).
- This data tells us, the planets which cooperate to create the number (1259.3
degrees) use this number in their motions for defined distances – as we have seen –
but the other planets don't

I do this research
2nd
24
(IV)
(a)
205 km (the planets velocities total) x 1461 s =300000 km
(b)
300000 km = 2.5 x 120536 km (Saturn diameter)
24.1 km/s (Mars velocity) = 2.5 x 9.7 km/s (Saturn velocity)
(c)
124300 km =2.5 x 4970 km
(d)
1461 mkm x 2 = 4970 days x 0.5875 mkm (Uranus velocity daily)
(e)
4970 mkm = 2.5 x 1980 mkm
(f)
2872.5 mkm = 4900 days x 0.5875 mkm (Uranus velocity daily)
Equation No. (a)
- The planets velocities total pass during 1461 seconds a distance = light known
velocity (0.3 mkm/s) during 1 second.
- That shows how the value 1461 seconds (or days) is a specific cycle
Equation No. (b)
300000 km = 2.5 x 120536 km (Saturn diameter)
24.1 km/s (Mars velocity) = 2.5 x 9.7 km/s (Saturn velocity)
- Equation No. (b) is very similar to Equation no. (2), Mars and Saturn use the same
period of time, Saturn to pass a distance = its diameter and Mars to pass a distance
= light motion for 1 second
- This comparison between the 2 motions produced the rate 2.5, this rate is seen in
Saturn as 2.5 deg = (Saturn orbital inclination) but for Mars the rate is seen as,
Mars velocity =2.5 Saturn Velocity

I do this research
2nd
25
- Why this rate (2.5) is required by the two planets? Both planets use the value
12430 seconds – so this rate (2.5) is found for both through this value
Equation No. (c)
12430 km =2.5 x 4970 km
- So, the rate 2.5 is found inside 12430 km
- And the equation procures the value 4970 km
- Why this value is required?
Equation No. (d)
1461 mkm x 2 = 4970 days x 0.5875 mkm (Uranus velocity daily)
- Uranus moves during 4970 days a distance = 1461 mkm x 2
- We remember, light supposed velocity (1.16 mkm/s) travels during 1259.3 seconds
distance =1461 mkm –
- The equation tells some relationship is found behind with Uranus!
Equation No. (e)
4970 mkm = 2.5 x 1980 mkm
- 1980 mkm = 360 mkm (Mercury) +680 mkm (Venus) +940 mkm (Earth)
- This is the total of the three planets orbital circumferences
- This value also is used as a period of time 1980 seconds where light known
velocity travels during 1980 seconds a distance =595 mkm (we have discussed
before)
- That tells the rate 2.5 is used here also –
- There's some feature of one motion transported from one point to another – but
how that's happening?

I do this research
2nd
26
Equation No. (f)
2872.5 mkm = 4900 days x 0.5875 mkm (Uranus velocity daily)
- Where
- 2872.5 mkm = Uranus Orbital Distance
- 4900 mkm = Jupiter Orbital Circumference (is used here as days)
- Equation (f) tells, Uranus during 4900 days Uranus moves a distance = 2872.5
mkm = its orbital distance - Why?
- What's the geometrical mechanism based on which this data is created?
Notice
1461 = 2.4 mkm x 609 (days)
= 1.1318 mkm x 1290 (days)
= 0.838 mkm x1737 (days)
= 0.406 mkm x 3600 (days)
Equation No. (11)
12430 km = 4.7 km/s x 2645 seconds
- 4.7 km/s = Pluto velocity
- 2645 mkm = Mars Uranus Distance (used as seconds)
- Equation No. 11 tells that, Pluto moves during 2645 seconds a distance = 124300
km,
- The equation shows an interaction between Pluto and Mars Motions.

I do this research
2nd
27
Equation No. (12)
51118 km x 12430 km x 0.99 = 629 mkm
But 168464 km x 12430 mkm = 2094 mkm and 2 x 168464 km = 6.8 x 49528
Where
- 629 mkm = Jupiter Earth Distance
- 2094 mkm = Jupiter Uranus Distance
- And
- 49528 km = Neptune Diameter (used in seconds)
- Equation no (12) shows that, Jupiter is a connection point between Earth and
Uranus motions – but – there's a complex geometrical mechanism, where Uranus
motion interacted with the value 12430 to produce the distance 2094 mkm (Jupiter
Uranus Distance).

I do this research
2nd
28
2-4 Jupiter effect on The Earth Motion
I-Data
(2-1)
1259.3 h x 3600 s x 29.8 km/s = 135 mkm
(2-2)
(a)
135 mkm = 12430 km x 10921 km (error 0.5%)
(b)
135 mkm = 2 x 778.6 days x 88000 (error 1%)
(c)
327.6 days x 0.413 mkm = 135 mkm
(d)
687 days = 5.09 x 135
(e)
(1259.3 h/708.7h) =(12104 km/6792 km)
(f)
1433 mkm = 135 mkm x 10.7 (1%)
108.2 mkm = 135 mkm x 0.8
(2-3)
153 mkm = 135 days x 1.1318 mkm
(2-4)
119.7 = 13.1 km/s x 2 x 1259.3 h x 3600 s
But
940 x 142984 km = 135 mkm
(2-5)
93.4 x 1.1318 = 105.7 mkm
105.7 x 1.1318 = 119.7 mkm
119.7 x 1.1318 =135 mkm

I do this research
2nd
29
II-Discussion
Equation no. (2-1)
1259.3 h x 3600 s x 29.8 km/s = 135 mkm
- Equation No. (1-2) tells that, Earth (29.8 km/s) moves during 1259.3 hours a
distance = 135 mkm
- The distance 135 mkm is an important distance in the solar system geometry
because.. if this distance started from the sun, So the orbital distance 135 mkm will
reach to a point between Earth and Venus (after Venus by 26.8 mkm and before
Earth with 14.6 mkm)
- This point is important because… from this point (135 mkm) to Uranus the
distance =2737 mkm
- And we remember the Cycle 2737 years, So this distance may have a relationship
with this cycle 2737 years.
But
- I claim the orbital distance 135 mkm has a relationship with the Earth moon
motion, we need to analyze this distance to discover this relationship
Equation no. (2-2)
(a)
135 mkm = 12430 km x 10921 km (error 0.5%)
- Our number is 12430 km
- 10921 km = the moon circumference
(b)
135 mkm = 2 x 778.6 days x 88000 (error 1%)
- Equation no. (b) tells, the moon displacements total during a period = (2x 778.6
days) be = 135 mkm –
- 778.6 mkm = Jupiter orbital distance
- The equation tells, Jupiter orbital distance is used as a period of time by the moon
displacement motion.

I do this research
2nd
30
(c)
327.6 days x 0.413 mkm = 135 mkm
- The moon displacements total during 29.53 days = 2.598mkm = 2π x0.413 mkm
- 327.6 days =the moon sidereal year
- This equation tells, the distance 135 mkm is defined by the moon displacements
total during a period = (29.53 x327.6 = 9674 days)..
(d)
687 days = 5.09 x 135
- 687 days = Mars orbital period
- 5.1 deg = The moon orbital inclination
- The equation shows the origin of interaction between Mars and the moon motions,
based on which their orbital periods are interacted where
- 687 days =27.3 days x 25.2 (25.2 deg = Mars Axial Tilt)
(e)
(1259.3 h/708.7h) =(12104 km/6792 km)
- 1259.3 hours = the period Earth needs to move 135 mkm
- 708.7 hours = the moon day period
- 12104 km = Venus diameter
- 6792 km = Mars diameter
(f)
1433 mkm = 135 mkm x 10.7 (1%)
- 1433 mkm = Saturn orbital distance
- 10.7 hours = Saturn day period
108.2 mkm = 135 mkm x 0.8
- 108.2 mkm = Venus orbital distance
- 0.8 deg = Uranus orbital inclination

I do this research
2nd
31
Equation no. (2-3)
153 mkm = 135 days x 1.1318 mkm
- 149.6 mkm = Earthy orbital distance
- 1.1318 mkm = Jupiter velocity per a solar day
- Equation no. (2-3) tells that, Jupiter moves during 135 days a distance =153 mkm
= Earth orbital distance (error 2.5%)
- Why?
- Earth moves during 1259.3 hours a distance = 135 mkm
- Jupiter uses this distance as 135 solar days and moves during it a distance = Earth
orbital distance -
- In equation (b) we have found that, the Earth moon uses Jupiter orbital distance
(778.6 mkm) as a period of time (778.6 solar days), that shows mutual similar
effect between the 3 planets motions
Equation no. (2-4)
119.7 = 13.1 km/s x 2 x 1259.3 h x 3600 s
- Jupiter (13.1 km/s) moves during 1259.3 x 2 hours a distance = 119.7 mkm =
Venus Mars Distance
- Equation no. (2-5) shows that Jupiter moves in a series to pass the distance 153
mkm which we have discussed in the previous equation – Jupiter motion effect on
different inner planets distances by its motion during this defined period which
shows interaction between Jupiter motion and the inner plant motions.
Notice
940 x 142984 km = 135 mkm
142984 km = Jupiter diameter 940 mkm = Earth Orbital Circumference

I do this research
2nd
32
Equation no. (2-5)
93.4 x 1.1318 = 105.7 mkm
- 93.4 deg = 90 deg +3.4 deg (Venus orbital inclination)
105.7 x 1.1318 = 119.7 mkm
- 119.7 mkm = Venus Mars Distance
119.7 x 1.1318 =135 mkm
1.1318 mkm = Jupiter motion distance during a solar day
More Data For Analysis
(1)
300000 km = 205.8 km/s x 1461 seconds
- 205.8 km = the solar planets velocities total (including the moon)
(2)
300000 km = 9.7 km/s x 30589 seconds
- 30589 days = Uranus orbital period
- 9.7 km/s = Saturn velocity
(3)
12430 mkm = 30589 days x 0.406 mkm
- This equation tells, Pluto (0.406 mkm per solar day) moves during 30589 days
(Uranus orbital period) a distance = 12430 mkm
(5)
1.16 mkm = 29.8 km/s x 39050 seconds
- This one tells, Earth (29.8 km/s) moves during 39050 seconds a distance =1.16
mkm
(6)
374 mkm = 0.3 mkm/s x 1259.3 s = 2.5 x 149.6 mkm

I do this research
2nd
33
Saturn Orbital Inclination Analysis
(a)
2.5 = 1.9 x 1.3
- 2.5 deg = Saturn Orbital Inclination
- 1.9 deg = Mars Orbital Inclination
- 1.3 deg = Jupiter Orbital Inclination
(b)
17.5 = 2.5 x 7
- 17.4 deg = The inner planets Orbital Inclinations Total
- 2.5 deg = Saturn Orbital Inclination
- 7 deg = Mercury Orbital Inclination
(c)
10747 = 2.5 x 4331
3600 = 2.5 x 1440
- 10747 days = Saturn Orbital Period
- 4331 days = Jupiter Orbital Period
- 1433 mkm = Saturn Orbital Distance

I do this research
2nd
34
References
The Moon Orbital Motion Geometry (II)
https://www.academia.edu/45181646/The_Moon_Orbital_Motion_Geometry_II_
or
https://www.slideshare.net/Gergesfrancis/the-moon-orbital-motion-geometry-ii
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
Does Particle Data Depend on Its Motion? (Lorentz Transformations Analysis)
https://vixra.org/abs/1912.0134
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1
Facebook https://www.facebook.com
Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/
ORCID https://orcid.org/0000-0002-1041-7147
Quora https://www.quora.com/profile/Gerges-F-Tawdrous
Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en
Academia https://rudn.academia.edu/GergesTawadrous
List of publications http://vixra.org/author/gerges_francis_tawdrous

The moon creation effect on the solar system geometry (revised)

More Related Content

What's hot (20)

Similar to The moon creation effect on the solar system geometry (revised) (20)

More from Gerges francis (20)

Recently uploaded (20)

The moon creation effect on the solar system geometry (revised)