The moon motion basic equation (modified) (part ii)
0 likes31 views
This document presents research by Gerges Francis Tawadrous, a physics student at the People's Friendship University of Russia, regarding a modified equation for the moon's orbital motion. The new equation attempts to improve accuracy by adjusting angular displacement to 1.7 degrees and includes tests from June to October 2020 to validate its effectiveness. The results indicate that the modified equation is a reliable tool for studying the moon's orbital dynamics.
The moon motion basic equation (modified) (part ii)
- 1. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 1 The Moon Motion Basic Equation (modified) (Part II) The Author Authorized To Be Used By Mr. Gerges Francis Tawdrous A Student–Physics Department- Physics & Mathematics Faculty – Peoples' Friendship University of Russia (RUDN University) – Moscow – Russia Dr. Budochkina, Svetlana Aleksandrovna Associate Professor (Mathematical Analysis and Theory of Functions Department) Peoples' Friendship University of Russia (RUDN University) – Moscow – Russia Phone +201022532292 E-Mail: mrwaheid@gmail.com Curriculum Vitae http://vixra.org/abs/1902.0044 Phone +7 (495) 952-35-83 E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru Website http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024 The Assumption Of S. Virgin Mary -Written in Cairo – Egypt – 17th December 2020 Abstract 3rd Modification In The Moon Orbital Motion Equation The Old Forms θ1 (Per Solar Day) = θ0 (of Previous Day) + 0.98562 degrees θ1 (Per Solar Day) = θ0 (of Previous Day) + 1.5 degrees θ1 (Per Solar Day) = θ0 (of Previous Day) + 1.6 degrees The 3rd Modified form θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.7 degrees (The Equation uses 1.7 degrees to minimize the error as possible) The Equation Concept - The needs to decrease its real displacement, to be able to move through more near orbits around Earth than apogee orbit (r=0.406 mkm). - To do that, the moon uses Pythagoras triangle, creating an angle between its motion direction and its orbit horizontal level, which cause the real displacement through the orbit (L =88000 Cos θ) less than the moon displacement (88000 km). - In paper appendix the Equation concept is discussed with some details. - This paper tests the new modification by 2 tests, (1st test for June 2020) and (2nd test for October 2020). Paper conclusion - The equation is correct and trustee, and should be considered a useful tool in the moon orbital motion study and analysis.
- 2. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 2 1- The 3rd Modified Form The Modified form θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.7 degrees 1st test (June 2020) 1-1 The Equation Test (6-30 June 2020) I-Data Date The Earth Moon Distance 6-6-2020 369418 7-6-2020 373729 8-6-2020 378917 9-6-2020 384534 10-6-2020 390096 11-6-2020 395156 12-6-2020 399345 13-6-2020 402395 14-6-2020 404153 15-6-2020 404574 16-6-2020 403718 17-6-2020 401733 18-6-2020 398840 19-6-2020 395303 20-6-2020 391409 21-6-2020 387432 22-6-2020 383607 23-6-2020 380110 24-6-2020 377044 25-6-2020 374451 26-6-2020 372338 27-6-2020 370703 28-6-2020 369571 29-6-2020 369005 Data Reference is https://www.timeanddate.com/moon/egypt/cairo?month=1 Note Please - In the ascending motion from perigee to apogee the angle (1.6 deg) will be minus - In the descending motion from apogee to perigee the angle (1.6 deg) will be positive.
- 3. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 3 II- The Equation Test θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.7 degrees 1st The Ascending Motion (1) 6 –June -2020 Jun 6 369418 km Jun 7 373729km (The Next Day) On 6/6/2020 the moon Earth distance was 369418 km So we need to know where the moon will be on the next day (7/6/2020)? Let's try to do that…. - The radius =369418 km so C (orbital circumference) = 369418 x 2π=2.321 mkm - The moon moves it during 29.53 days ( L0= 2.321 mkm/29.53) = 78602.1 km - L0= 78602.1 km but L0 = 88000 km Cos θ0 - θ0= 26.721 degrees - θ1= θ0- 1.7 = 26.721 – 1.7 = 25.021 degrees - L1 = 88000 km (Cos 25.021 degrees) = 79741.5 km - During 29.53 days = L1 x29.53 = 79741.5 km x 29.53 = 2.354 mkm - 2.354 mkm = 2π x 374772.5 km - i.e. The moon on next day (7/6/2020) should be on 374772.5 km The registered value on 7/6/2020 (373729 km) The difference = 373729 km – 374772.5 km = - 1044 km
- 4. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 4 (2) 7 –June -2020 Jun 7 373729 km Jun 8 378917km (The Next Day) On 7/6/2020 the moon Earth distance was 373729 km So we need to know where the moon will be on the next day (8/6/2020)? Let's try to do that…. - The radius =373729 km so C (orbital circumference) = 373729 x 2π=2.348 mkm - The moon moves it during 29.53 days ( L0= 2.348 mkm/29.53) = 79519.4 km - L0= 79519.4 km but L0 = 88000 km Cos θ0 - θ0= 25.36 degrees - θ1= θ0- 1.7 = 25.36 – 1.7 = 23.66 degrees - L1 = 88000 km (Cos 23.66 degrees) = 80603 km - During 29.53 days = L1 x29.53 = 80603 km x 29.53 = 2.38 mkm - 2.38 mkm = 2π x 378821.5 km - i.e. The moon on next day (8/6/2020) should be on 378821.5 km The registered value on 8/6/2020 (378917 km) The difference = 378917 km –378821.5 km = 95.5 km
- 5. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 5 (3) 8 – June -2020 Jun 8 378917 km Jun 9 384534km (The Next Day) On 8/6/2020 the moon Earth distance was 378917 km So we need to know where the moon will be on the next day (9/6/2020)? Let's try to do that…. - The radius =378917 km so C (orbital circumference) = 378917 x 2π=2.3808 mkm - The moon moves it during 29.53 days ( L0= 2.3808 mkm/29.53) = 80623.3 km - L0= 80623.3 km but L0 = 88000 km Cos θ0 - θ0= 23.627 degrees - θ1= θ0- 1.7 = 23. 627 – 1.7 = 21.927 degrees - L1 = 88000 km (Cos 21.927 degrees) = 81634.1 km - During 29.53 days = L1 x29.53 =81634.1 km x 29.53 = 2.41 mkm - 2.41 mkm = 2π x 383667.7 km - i.e. The moon on next day (9/6/2020) should be on 383667.7 km The registered value on 9/6/2020 (384534 km) The difference = 384534 km – 383667.7 km = 867 km
- 6. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 6 (4) 9 – June -2020 Jun 9 384534 km Jun 10 390096km (The Next Day) On 9/6/2020 the moon Earth distance was 384534 km So we need to know where the moon will be on the next day (10/6/2020)? Let's try to do that…. - The radius =384534 km so C (orbital circumference) = 384534 x 2π=2.416 mkm - The moon moves it during 29.53 days ( L0= 2.416 mkm/29.53) = 81818.4 km - L0= 81818.4 km but L0 = 88000 km Cos θ0 - θ0= 21.60 degrees - θ1= θ0- 1.7 = 21. 60 -1.7 = 19.9 degrees - L1 = 88000 km (Cos 19.9 degrees) = 82745.35 km - During 29.53 days = L1 x29.53 = 82745.35 km x 29.53 = 2.443 mkm - 2.443 mkm = 2π x 388890 km - i.e. The moon on next day (10/6/2020) should be on 388890 km The registered value on 10/6/2020 (390096 km) The difference = 390096 km – 388890 km = 1206 km
- 7. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 7 (5) 10 – June -2020 Jun 10 390096 km Jun 11 395156km (The Next Day) On 10/6/2020 the moon Earth distance was 390096 km So we need to know where the moon will be on the next day (11/6/2020)? Let's try to do that…. - The radius =390096 km so C (orbital circumference) = 390096 x 2π=2.451 mkm - The moon moves it during 29.53 days ( L0= 2.451 mkm/29.53) = 83002 km - L0= 83002 km but L0 = 88000 km Cos θ0 - θ0= 19.4033 degrees - θ1= θ0- 1.7 = 19.4033 – 1.7 = 17.7033 degrees - L1 = 88000 km (Cos 17.7033 degrees) = 83832.6 km - During 29.53 days = L1 x29.53 = 83832.6 km x 29.53 = 2.475 mkm - 2.475 mkm = 2π x 394000 km - i.e. The moon on next day (11/6/2020) should be on 394000 km The registered value on 11/6/2020 (395156 km) The difference = 395156 km –394000 km = 1156 km
- 8. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 8 (5) 11 – June -2020 Jun 11 395156 km Jun 12 399345 km (The Next Day) On 11/6/2020 the moon Earth distance was 395156 km So we need to know where the moon will be on the next day (12/6/2020)? Let's try to do that…. - The radius =395156 km so C (orbital circumference) = 395156 x 2π=2.482 mkm - The moon moves it during 29.53 days ( L0= 2.482 mkm/29.53) = 84078.5 km - L0= 84078.5 km but L0 = 88000 km Cos θ0 - θ0= 17.169 degrees - θ1= θ0- 1.7 = 17.169 – 1.7 = 15.469 degrees - L1 = 88000 km (Cos 15.469 degrees) = 84812.2 km - During 29.53 days = L1 x29.53 = 84812.2 km x 29.53 = 2.504 mkm - 2.504 mkm = 2π x 398604.2 km - i.e. The moon on next day (12/6/2020) should be on 398604.2 km The registered value on 12/6/2020 (399345 km) The difference = 399345 km – 398604.2 km = 741 km
- 9. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 9 (6) 12 – June -2020 Jun 12 399345 km Jun 13 402395 km (The Next Day) On 12/6/2020 the moon Earth distance was 399345 km So we need to know where the moon will be on the next day (13/6/2020)? Let's try to do that…. - The radius =399345 km so C (orbital circumference) = 399345 x 2π=2.509 mkm - The moon moves it during 29.53 days ( L0= 2.509 mkm/29.53) = 84970 km - L0= 84970 km but L0 = 88000 km Cos θ0 - θ0= 15.0794 degrees - θ1= θ0-1.7 = 15.0794 – 1.7 = 13.3794 degrees - L1 = 88000 km (Cos 13.3794 degrees) = 85611.6 km - During 29.53 days = L1 x29.53 = 85611.6 km x 29.53 = 2.528 mkm - 2.528 mkm = 2π x 402361.3 km - i.e. The moon on next day (13/6/2020) should be on 402361.3 km The registered value on 13/6/2020 (402395 km) The difference = 402395 km –402361.3 km = 34 km
- 10. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 10 (7) 13 – June -2020 Jun 13 402395 km Jun 14 404153 km (The Next Day) On 13/6/2020 the moon Earth distance was 402395 km So we need to know where the moon will be on the next day (14/6/2020)? Let's try to do that…. - The radius =402395 km so C (orbital circumference) = 402395 x 2π=2.528 mkm - The moon moves it during 29.53 days ( L0= 2.528 mkm/29.53) = 85618.8 km - L0= 85618.8 km but L0 = 88000 km Cos θ0 - θ0= 13.3592 degrees - θ1= θ0- 1.7 = 13.3592 – 1.7 = 11.6592 degrees - L1 = 88000 km (Cos 11.6592 degrees) = 86184.3 km - During 29.53 days = L1 x29.53 = 86184.3 km x 29.53 = 2.545 mkm - 2.545 mkm = 2π x 405052.8 km - i.e. The moon on next day (14/6/2020) should be on 405052.8 km The registered value on 14/6/2020 (404153 km) The difference = 404153 km – 405052.8 km = (-) 900 km Note Please - This day is the last day in the moon ascending motion from Perigee to apogee, on the next day the moon will stay on apogee for one more day (404574 km) on (15th - 6-2020), and then on (16th -6-2020) will start its descending motion (403718 km). So we will start the descending motion analysis in next page, and because it's a descending motion we will add the value 0.985 degrees to the angle (θ)
- 11. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 11 1st The Descending Motion (8) 15 – June -2020 Jun 15 404574 km Jun 16 403718 km (The Next Day) On 15/6/2020 the moon Earth distance was 404574 km So we need to know where the moon will be on the next day (16/6/2020)? Let's try to do that…. - The radius =404574 km so C (orbital circumference) = 404574 x 2π=2.542 mkm - The moon moves it during 29.53 days ( L0= 2.542 mkm/29.53) = 86082.4 km - L0= 86082.4 km but L0 = 88000 km Cos θ0 - θ0= 11.983 degrees - θ1= θ0+ 1.7 = 11.983 +1.7 = 13.683 degrees - L1 = 88000 km (Cos 13.683 degrees) = 85502.5 km - During 29.53 days = L1 x29.53 =85502.5 km x 29.53 = 2.524 mkm - 2.524 mkm = 2π x 401848.5 km - i.e. The moon on next day (16/6/2020) should be on 401848.5 km The registered value on 16/6/2020 (403718 km) The difference = 403718 km – 401848.5 km = 1870 km
- 12. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 12 (9) 16 – June -2020 Jun 16 403718 km Jun 17 401733 km (The Next Day) On 16/6/2020 the moon Earth distance was 403718 km So we need to know where the moon will be on the next day (17/6/2020)? Let's try to do that…. - The radius =403718 km so C (orbital circumference) = 403718 x 2π=2.536 mkm - The moon moves it during 29.53 days ( L0= 2.536 mkm/29.53) = 85900 km - L0= 85900 km but L0 = 88000 km Cos θ0 - θ0= 12.5413 degrees - θ1= θ0+ 1.7 = 12.5413 +1.7 = 14.2413 degrees - L1 = 88000 km (Cos 14.2413 degrees) = 85295.6 km - During 29.53 days = L1 x29.53 = 85295.6 km x 29.53 = 2.518 mkm - 2.518 mkm = 2π x 400876.1 km - i.e. The moon on next day (17/6/2020) should be on 400876.1 km The registered value on 17/6/2020 (401733 km) The difference = 401733 km – 400876.1 km = 857 km
- 13. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 13 (10) 17 – June -2020 Jun 17 401733 km Jun 18 398840 km (The Next Day) On 17/6/2020 the moon Earth distance was 401733 km So we need to know where the moon will be on the next day (18/6/2020)? Let's try to do that…. - The radius =401733 km so C (orbital circumference) = 401733 x 2π=2.524 mkm - The moon moves it during 29.53 days ( L0= 2.524 mkm/29.53) = 85478 km - L0= 85478 km but L0 = 88000 km Cos θ0 - θ0= 13.75 degrees - θ1= θ0+ 1.7 = 13.75 +1.7 = 15.45 degrees - L1 = 88000 km (Cos 15.45 degrees) = 84819.9 km - During 29.53 days = L1 x29.53 = 84819.9 km x 29.53 = 2.504 mkm - 2.504 mkm = 2π x 398640.7 km - i.e. The moon on next day (18/6/2020) should be on 398640.7 km The registered value on 18/6/2020 (398840 km) The difference = 398840 km –398640.7 km = 200 km
- 14. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 14 (11) 18 – June -2020 Jun 18 398840 km Jun 19 395303 km (The Next Day) On 18/6/2020 the moon Earth distance was 398840 km So we need to know where the moon will be on the next day (19/6/2020)? Let's try to do that…. - The radius =398840 km so C (orbital circumference) = 398840 x 2π=2.505 mkm - The moon moves it during 29.53 days ( L0= 2.505 mkm/29.53) = 84862.36 km - L0= 84862.36 km but L0 = 88000 km Cos θ0 - θ0= 15.346 degrees - θ1= θ0+ 1.7 = 15.346 +1.7 = 17.046 degrees - L1 = 88000 km (Cos 17.046 degrees) = 84134.1 km - During 29.53 days = L1 x29.53 = 84134.1 km x 29.53 = 2.484 mkm - 2.484 mkm = 2π x 395417.4 km - i.e. The moon on next day (19/6/2020) should be on 395417.4 km The registered value on 19/6/2020 (395303 km) The difference = 395303 km – 395417.4 km = (-) 115 km
- 15. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 15 (12) 19 – June -2020 Jun 19 395303 km Jun 20 391409 km (The Next Day) On 19/6/2020 the moon Earth distance was 395303 km So we need to know where the moon will be on the next day (20/6/2020)? Let's try to do that…. - The radius =395303 km so C (orbital circumference) = 395303 x 2π=2.483 mkm - The moon moves it during 29.53 days ( L0= 2.483 mkm/29.53) = 84109.8 km - L0= 84109.8 km but L0 = 88000 km Cos θ0 - θ0= 17.1 degrees - θ1= θ0+ 1.7 = 17.1 +1.7 = 18.8 degrees - L1 = 88000 km (Cos 18.8 degrees) = 83305.1 km - During 29.53 days = L1 x29.53 = 83305.1 km x 29.53 = 2.460 mkm - 2.460 mkm = 2π x 391521.2 km - i.e. The moon on next day (20/6/2020) should be on 391521.2 km The registered value on 20/6/2020 (391409 km) The difference = 391409 km – 391521.2 km = - (113) km
- 16. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 16 (13) 20 – June -2020 Jun 20 391409 km Jun 21 387432 km (The Next Day) On 20/6/2020 the moon Earth distance was 391409 km So we need to know where the moon will be on the next day (21/6/2020)? Let's try to do that…. - The radius =391409 km so C (orbital circumference) = 391409 x 2π=2.459 mkm - The moon moves it during 29.53 days ( L0= 2.459 mkm/29.53) = 83281.3 km - L0= 83281.3 km but L0 = 88000 km Cos θ0 - θ0= 18.848 degrees - θ1= θ0+ 1.7 = 18.848 +1.7 = 20.548 degrees - L1 = 88000 km (Cos 20.548 degrees) = 82401.3 km - During 29.53 days = L1 x29.53 = 82401.3 km x 29.53 = 2.433 mkm - 2.433 mkm = 2π x 387273.4 km - i.e. The moon on next day (21/6/2020) should be on 387273.4 km The registered value on 21/6/2020 (387432 km) The difference = 387432 km – 387273.4 km = 159 km
- 17. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 17 (14) 21 – June -2020 Jun 21 387432 km Jun 22 383607 km (The Next Day) On 21/6/2020 the moon Earth distance was 387432 km So we need to know where the moon will be on the next day (22/6/2020)? Let's try to do that…. - The radius =387432 km so C (orbital circumference) = 387432 x 2π=2.434 mkm - The moon moves it during 29.53 days ( L0= 2.434 mkm/29.53) = 82435 km - L0= 82435 km but L0 = 88000 km Cos θ0 - θ0= 20.485 degrees - θ1= θ0+ 1.7 = 20.485 +1.7 = 22.185 degrees - L1 = 88000 km (Cos 22.185 degrees) = 81485.3 km - During 29.53 days = L1 x29.53 = 81485.3 km x 29.53 = 2.406 mkm - 2.406 mkm = 2π x 382968.4 km - i.e. The moon on next day (22/6/2020) should be on 382968.4 km The registered value on 22/6/2020 (383607 km) The difference = 383607 km – 382968.4 km =639 km
- 18. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 18 (15) 22 – June -2020 Jun 22 383607 km Jun 23 380110 km (The Next Day) On 22/6/2020 the moon Earth distance was 383607 km So we need to know where the moon will be on the next day (23/6/2020)? Let's try to do that…. - The radius =383607 km so C (orbital circumference) = 383607 x 2π=2.41 mkm - The moon moves it during 29.53 days ( L0= 2.41 mkm/29.53) = 81621.2 km - L0= 81621.2 km but L0 = 88000 km Cos θ0 - θ0= 21.9495 degrees - θ1= θ0+ 1.7 = 21.9495 +1.7 =23.6495 degrees - L1 = 88000 km (Cos 23.6495 degrees) = 80609.5 km - During 29.53 days = L1 x29.53 = 80609.5 km x 29.53 = 2.380 mkm - 2.380 mkm = 2π x 378852 km - i.e. The moon on next day (23/6/2020) should be on 378852 km The registered value on 23/6/2020 (380110 km) The difference = 380110 km – 378852 km =1258 km
- 19. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 19 (16) 23 – June -2020 Jun 23 380110 km Jun 24 377044 km (The Next Day) On 23/6/2020 the moon Earth distance was 380110 km So we need to know where the moon will be on the next day (24/6/2020)? Let's try to do that…. - The radius =380110 km so C (orbital circumference) = 380110 x 2π=2.388 mkm - The moon moves it during 29.53 days ( L0= 2.388 mkm/29.53) = 80877 km - L0= 80877 km but L0 = 88000 km Cos θ0 - θ0= 23.2112 degrees - θ1= θ0+ 1.7 = 23.2112 +1.7 = 24.9112 degrees - L1 = 88000 km (Cos 24.9112 degrees) = 79812.6 km - During 29.53 days = L1 x29.53 = 79812.6 km x 29.53 = 2.356 mkm - 2.356 mkm = 2π x 375107 km - i.e. The moon on next day (24/6/2020) should be on 375107 km The registered value on 24/6/2020 (377044 km) The difference = 377044 km – 375107 km =1937 km
- 20. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 20 (17) 24 – June -2020 Jun 24 377044 km Jun 25 374451 km (The Next Day) On 24/6/2020 the moon Earth distance was 377044 km So we need to know where the moon will be on the next day (25/6/2020)? Let's try to do that…. - The radius =377044 km so C (orbital circumference) = 377044 x 2π=2.369 mkm - The moon moves it during 29.53 days ( L0= 2.369 mkm/29.53) = 80224.8 km - L0= 80224.8 km but L0 = 88000 km Cos θ0 - θ0= 24.266 degrees - θ1= θ0+ 1.7 = 24.266 +1.7 = 25.966 degrees - L1 = 88000 km (Cos 25.966 degrees) = 79116.7 km - During 29.53 days = L1 x29.53 = 79116.7 km x 29.53 = 2.336 mkm - 2.336 mkm = 2π x 371836.5 km - i.e. The moon on next day (25/6/2020) should be on 371836.5 km The registered value on 25/6/2020 (374451 km) The difference = 374451 km – 371836.5 km =2615 km
- 21. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 21 (18) 25 – June -2020 Jun 25 374451 km Jun 26 372338 km (The Next Day) On 25/6/2020 the moon Earth distance was 374451 km So we need to know where the moon will be on the next day (26/6/2020)? Let's try to do that…. - The radius =374451 km so C (orbital circumference) = 374451 x 2π=2.352 mkm - The moon moves it during 29.53 days ( L0= 2.352 mkm/29.53) = 79673 km - L0= 79673 km but L0 = 88000 km Cos θ0 - θ0= 25.126 degrees - θ1= θ0+ 1.7 = 25.126 +1.7 = 26.826 degrees - L1 = 88000 km (Cos 26.826 degrees) = 78529.5 km - During 29.53 days = L1 x29.53 =78529.5 km x 29.53 = 2.318 mkm - 2.318 mkm = 2π x 369077 km - i.e. The moon on next day (26/6/2020) should be on 369077 km The registered value on 26/6/2020 (372338 km) The difference = 372338 km – 369077 =3262 km
- 22. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 22 (19) 26 – June -2020 Jun 26 372338 km Jun 27 370703 km (The Next Day) On 26/6/2020 the moon Earth distance was 372338 km So we need to know where the moon will be on the next day (27/6/2020)? Let's try to do that…. - The radius =372338 km so C (orbital circumference) = 372338 x 2π=2.339 mkm - The moon moves it during 29.53 days ( L0= 2.339 mkm/29.53) = 79223.4 km - L0= 79223.4 km but L0 = 88000 km Cos θ0 - θ0= 25.8 degrees - θ1= θ0+ 1.7 = 25.8 +1.7 = 27.5 degrees - L1 = 88000 km (Cos 27.5 degrees) = 78057 km - During 29.53 days = L1 x29.53 = 78057 km x 29.53 = 2.305 mkm - 2.305 mkm = 2π x 366855.6 km - i.e. The moon on next day (27/6/2020) should be on 366855.6 km The registered value on 27/6/2020 (370703 km) The difference = 370703 km –366855.6 =3847 km Note Please - This day is the last day in the moon descending motion, after it the moon stay in perigee 3 days!! (28-6-2020 369571 km), (29-6-2020 369005 km), (30-6-2020 369106 km) – - That tells, when the moon changes its motion from ascending to descending and vice versa, the moon consumes long time in this process which causes great error for the calculations… - i.e. there's specific reason at perigee and apogee point causes the moon to stay longer time there than expected… - based on that, we have to analyze the equation test results for 20 days only
- 23. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 23 2-2 The Test Results Discussion And Analysis Let's take a look on the different distances between the equation results and the registered data in following Day Registered Data Results (1.7) Difference 6-6-2020 369418 km 7-6-2020 373729 km 374772.5 - 1044 8-6-2020 378917 km 378821.5 96 9-6-2020 384534 km 383667.7 867 10-6-2020 390096 km 388890 1206 11-6-2020 395156 km 394000 1156 12-6-2020 399345 km 398604.2 741 13-6-2020 402395 km 402361.3 34 14-6-2020 404153 km 405052.8 -900 15-6-2020 404574 km ---- --- 16-6-2020 403718 km 401848.5 1870 17-6-2020 401733 km 400876.1 857 18-6-2020 398840 km 398640.7 200 19-6-2020 395303 km 395417.4 115 20-6-2020 391409 km 391521.2 -113 21-6-2020 387432 km 387273.4 159 22-6-2020 383607 km 382968.4 639 23-6-2020 380110 km 378852 1258 24-6-2020 377044 km 375107 1937 25-6-2020 374451 km 371836.5 2615 26-6-2020 372338 km 369077 3262 27-6-2020 370703 km 366855.6 3847 [
- 24. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 24 The Test Results Analysis: - The Total Results Are 20 Values (1st Category) o 15 values, defines the moon position in range 1300 km (Error 3%) (2nd Category) o 2 values, defines the moon position in range 1300-2000 km (Error 4.6 %) (3rd Category) o 3 values, defines the moon position in range 2000-3500 km (Error 8 %) - The Results Explanation - The distance from perigee to apogee =43000 km… o 1st Category of results defines the moon position in error range (1300 km) = error (3%), that means, (15 values of 20) defines the moon position with error (3%) only (Small Error Range) o 2nd Category of results defines the moon position in error range from (1300 km to 2000 km) = error (4.5%), that means (2 values of 20) defines the moon position with error (4.5%) (Average Error Range) o 3rd Category of results defines the moon position in error range from (2000 km to 3500 km) = error (8%), that means (3 values of 20) defines the moon position with error (8%) (Great Error Range) - The Equation Accuracy o The previous explanation shows that, the equation has a good range of accuracy and its error is in the acceptable error range The Conclusion The Equation Is correct and trustee And It's a useful tool to define the moon position daily
- 25. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 25 1-3 The Equation 2nd Test (1-31 October 2020) The Modified form θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.7 degrees 2nd test (October 2020) I-Data Date The Earth Moon Distance 1-10-2020 405,190 2-10-2020 Moon does not pass the meridian on this day. 3-10-2020 406,102 4-10-2020 406,299 5-10-2020 405,690 6-10-2020 404,171 7-10-2020 401,649 8-10-2020 398,073 9-10-2020 393,464 10-10-2020 387,944 11-10-2020 381,763 12-10-2020 375,302 13-10-2020 369,063 14-10-2020 363,617 15-10-2020 359,530 16-10-2020 357,269 17-10-2020 357,105 18-10-2020 359,048 19-10-2020 362,851 20-10-2020 368,058 21-10-2020 374,101 22-10-2020 380,412 23-10-2020 386,497 24-10-2020 391,989 25-10-2020 396,659 26-10-2020 400,395 27-10-2020 403,181 28-10-2020 405,059 29-10-2020 406,104 30-10-2020 406,391 31-10-2020 405,979 Data Reference is https://www.timeanddate.com/moon/egypt/cairo?month=1 Note Please (In the ascending motion from perigee to apogee the angle (1.7 deg) will be minus and In the descending motion from apogee to perigee the angle (1.7 deg) will be positive.
- 26. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 26 The Equation Test θ1 (Per Solar Day) = θ0 ( of Previous Day) + 1.7 degrees 1st The descending Motion (So +1.7) (1) 5 –October -2020 October 5 405690 km October 6 404171 km (The Next Day) On 5/10/2020 the moon Earth distance was 405690km So we need to know where the moon will be on the next day (6/10/2020)? Let's try to do that…. - The radius =405690 km so C (orbital circumference) = 405690 x 2π=2.549 mkm - The moon moves it during 29.53 days ( L0= 2.549mkm/29.53) = 86319.8 km - L0= 86319.8 km but L0 = 88000 km Cos θ0 - θ0= 11.214 degrees - θ1= θ0+ 1.7 = 11.214 + 1.7 = 12.914 degrees - L1 = 88000 km (Cos 12.914 degrees) = 85774.16 km - During 29.53 days = L1 x29.53 = 85774.16 km x 29.53 = 2.532 mkm - 2. 532 mkm = 2π x 403125.3 km - i.e. The moon on next day (6/10/2020) should be on 403125.3 km The registered value on 7/6/2020 (404171 km) The difference = 404171 km – 403125.3 km = 1046 km
- 27. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 27 (2) 6 –October -2020 October 6 404171 km October 7 401649 km (The Next Day) On 6/10/2020 the moon Earth distance was 404171 km So we need to know where the moon will be on the next day (7/10/2020)? Let's try to do that…. - The radius = 404171 km so C (orbital circumference) = 404171 x 2π=2.539 mkm - The moon moves it during 29.53 days ( L0= 2.539mkm/29.53) = 85996.6 km - L0= 85996.6 km but L0 = 88000 km Cos θ0 - θ0= 12.249 degrees - θ1= θ0+ 1.7 = 12.249 + 1.7 = 13.949 degrees - L1 = 88000 km (Cos 13.949 degrees) = 85404.9 km - During 29.53 days = L1 x29.53 = 85404.9 km x 29.53 = 2.522 mkm - 2. 522 mkm = 2π x 401390 km - i.e. The moon on next day (7/10/2020) should be on 401390 km The registered value on 7/10/2020 (404171 km) The difference = 401649 – 401390 km = 259 km
- 28. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 28 (3) 7 –October -2020 October 7 401649 km October 8 398073 km (The Next Day) On 7/10/2020 the moon Earth distance was 401649 km So we need to know where the moon will be on the next day (8/10/2020)? Let's try to do that…. - The radius = 401649 km so C (orbital circumference) = 401649 x 2π=2.523 mkm - The moon moves it during 29.53 days ( L0= 2.523mkm/29.53) = 85460 km - L0= 85460 km but L0 = 88000 km Cos θ0 - θ0= 13.799 degrees - θ1= θ0+ 1.7 = 13.799 + 1.7 = 15.499 degrees - L1 = 88000 km (Cos 15.499 degrees) = 84800 km - During 29.53 days = L1 x29.53 = 84800 km x 29.53 = 2.504 mkm - 2.504 mkm = 2π x 398545.6 km - i.e. The moon on next day (8/10/2020) should be on 398545.6 km The registered value on 8/10/2020 (398073 km) The difference = 398073 – 398545.6 km = (- 473 km)
- 29. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 29 (4) 8 –October -2020 October 8 398073 km October 9 393464 km (The Next Day) On 8/10/2020 the moon Earth distance was 398073 km So we need to know where the moon will be on the next day (9/10/2020)? Let's try to do that…. - The radius = 398073 km so C (orbital circumference) = 398073 x 2π=2.50 mkm - The moon moves it during 29.53 days ( L0= 2.50mkm/29.53) = 84700 km - L0= 84700 km but L0 = 88000 km Cos θ0 - θ0= 15.742 degrees - θ1= θ0+ 1.7 = 15.742 + 1.7 = 17.44 degrees - L1 = 88000 km (Cos 17.44 degrees) = 83953.5 km - During 29.53 days = L1 x29.53 = 83953.5 km x 29.53 = 2.479 mkm - 2.479 mkm = 2π x 394568.8 km - i.e. The moon on next day (9/10/2020) should be on 394568.8 km The registered value on 9/10/2020 (393464 km) The difference = 393464 – 394568.8 km = (- 1105 km)
- 30. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 30 (5) 9 –October -2020 October 9 393464 km October 10 387944 km (The Next Day) On 9/10/2020 the moon Earth distance was 393464 km So we need to know where the moon will be on the next day (10/10/2020)? Let's try to do that…. - The radius = 393464 km so C (orbital circumference) = 393464 x 2π=2.47 mkm - The moon moves it during 29.53 days ( L0= 2.47mkm/29.53) = 83718.5 km - L0= 83718.5 km but L0 = 88000 km Cos θ0 - θ0= 17.946 degrees - θ1= θ0+ 1.7 = 17.946 + 1.7 = 19.646 degrees - L1 = 88000 km (Cos 19.646 degrees) = 82877.3 km - During 29.53 days = L1 x29.53 = 82877.3 km x 29.53 = 2.447 mkm - 2.447 mkm = 2π x 389510 km - i.e. The moon on next day (10/10/2020) should be on 389510 km The registered value on 10/10/2020 (387944 km) The difference = 387944 – 389510 km = (- 1567 km)
- 31. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 31 (6) 10 –October -2020 October 10 387944 km October 11 381763 km (The Next Day) On 10/10/2020 the moon Earth distance was 387944 km So we need to know where the moon will be on the next day (11/10/2020)? Let's try to do that…. - The radius = 387944 km so C (orbital circumference) = 387944 x 2π=2.43 mkm - The moon moves it during 29.53 days ( L0= 2.43mkm/29.53) = 82544 km - L0= 82544 km but L0 = 88000 km Cos θ0 - θ0= 20.28 degrees - θ1= θ0+ 1.7 = 20.28 + 1.7 = 21.981 degrees - L1 = 88000 km (Cos 21.981 degrees) = 81602.7 km - During 29.53 days = L1 x29.53 = 81602.7 km x 29.53 = 2.409 mkm - 2.409 mkm = 2π x 383520 km - i.e. The moon on next day (11/10/2020) should be on 383520 km The registered value on 11/10/2020 (381763 km) The difference = 381763 – 383520 km = (- 1758 km)
- 32. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 32 (7) 11 –October -2020 October 11 381763 km October 12 375302 km (The Next Day) On 11/10/2020 the moon Earth distance was 381763 km So we need to know where the moon will be on the next day (12/10/2020)? Let's try to do that…. - The radius = 381763 km so C (orbital circumference) = 381763 x 2π=2.39 mkm - The moon moves it during 29.53 days ( L0= 2.39mkm/29.53) = 81229 km - L0= 81229 km but L0 = 88000 km Cos θ0 - θ0= 22.623 degrees - θ1= θ0+ 1.7 = 22.623 + 1.7 = 24.323 degrees - L1 = 88000 km (Cos 24.323 degrees) = 80189 km - During 29.53 days = L1 x29.53 = 80189 km x 29.53 = 2.368 mkm - 2.368 mkm = 2π x 376875.3 km - i.e. The moon on next day (12/10/2020) should be on 376875.3 km The registered value on 12/10/2020 (375302 km) The difference = 375302 – 376875.3 km = (- 1574 km)
- 33. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 33 (8) 12 –October -2020 October 12 375302 km October 13 369063 km (The Next Day) On 12/10/2020 the moon Earth distance was 375302 km So we need to know where the moon will be on the next day (13/10/2020)? Let's try to do that…. - The radius = 375302 km so C (orbital circumference) = 375302 x 2π=2.358 mkm - The moon moves it during 29.53 days ( L0= 2.358 mkm/29.53) = 79854.1 km - L0= 79854.1 km but L0 = 88000 km Cos θ0 - θ0= 24.847 degrees - θ1= θ0+ 1.7 = 24.847 + 1.7 = 26.547 degrees - L1 = 88000 km (Cos 26.547 degrees) = 78722 km - During 29.53 days = L1 x29.53 = 78722 km x 29.53 = 2.324 mkm - 2.324 mkm = 2π x 369981.1 km - i.e. The moon on next day (13/10/2020) should be on 369981.1 km The registered value on 13/10/2020 (369063 km) The difference = 369063 – 369981.1 km = (- 919 km)
- 34. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 34 (9) 13 –October -2020 October 13 369063 km October 14 363617 km (The Next Day) On 13/10/2020 the moon Earth distance was 369063 km So we need to know where the moon will be on the next day (14/10/2020)? Let's try to do that…. - The radius = 369063 km so C (orbital circumference) = 369063 x 2π=2.318 mkm - The moon moves it during 29.53 days ( L0= 2.318 mkm/29.53) = 78526.6 km - L0= 78526.6 km but L0 = 88000 km Cos θ0 - θ0= 26.83 degrees - θ1= θ0+ 1.7 = 26.83 + 1.7 = 28.53 degrees - L1 = 88000 km (Cos 28.53 degrees) = 77313.9 km - During 29.53 days = L1 x29.53 =77313.9 km x 29.53 = 2.283 mkm - 2.283 mkm = 2π x 363363.4 km - i.e. The moon on next day (14/10/2020) should be on 363363.4 km The registered value on 14/10/2020 (363617 km) The difference = 363617 km – 363363.4 km = 254 km
- 35. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 35 (10) 14 –October -2020 October 14 363617 km October 15 359530 km (The Next Day) On 14/10/2020 the moon Earth distance was 363617 km So we need to know where the moon will be on the next day (14/10/2020)? Let's try to do that…. - The radius = 363617 km so C (orbital circumference) = 363617 x 2π=2.28 mkm - The moon moves it during 29.53 days ( L0= 2.28 mkm/29.53) = 77367.8 km - L0= 77367.8 km but L0 = 88000 km Cos θ0 - θ0= 28.456 degrees - θ1= θ0+ 1.7 = 28.456 + 1.7 = 30.156 degrees - L1 = 88000 km (Cos 30.156 degrees) = 76090 km - During 29.53 days = L1 x29.53 = 76090 km x 29.53 = 2.246 mkm - 2.246 mkm = 2π x 357612 km - i.e. The moon on next day (15/10/2020) should be on 357612 km The registered value on 15/10/2020 (359530 km) The difference = 359530 km – 357612 km = 1918 km
- 36. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 36 (11) 15 –October -2020 October 15 359530 km October 16 357269 km (The Next Day) On 11/10/2020 the moon Earth distance was 359530 km So we need to know where the moon will be on the next day (16/10/2020)? Let's try to do that…. - The radius = 359530 km so C (orbital circumference) = 359530 x 2π=2.25 mkm - The moon moves it during 29.53 days ( L0= 2.25 mkm/29.53) = 76498.3 km - L0= 76498.3 km but L0 = 88000 km Cos θ0 - θ0= 29.622 degrees - θ1= θ0+ 1.7 = 29.622 + 1.7 = 31.322 degrees - L1 = 88000 km (Cos 31.322 degrees) = 75174.2 km - During 29.53 days = L1 x29.53 =75174.2 km x 29.53 = 2.219 mkm - 2.219 mkm = 2π x 353307 km - i.e. The moon on next day (16/10/2020) should be on 353307 km The registered value on 16/10/2020 (357269 km) The difference = 357269 km – 353307 km = 3962 km Note Please - the moon stays in perigee one more day before to start its ascending motion, so the day (17-10-2020) (the distance is 357105 km) can't be defined by the equation, so we will start the ascending motion with the day (18-10-2020)
- 37. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 37 2nd The ascending Motion (So -1.7) (12) 18 –October -2020 October 18 359048 km October 19 362851 km (The Next Day) On 18/10/2020 the moon Earth distance was 359048 km So we need to know where the moon will be on the next day (19/10/2020)? Let's try to do that…. - The radius = 359048 km so C (orbital circumference) = 359048 x 2π=2.255 mkm - The moon moves it during 29.53 days ( L0= 2.255 mkm/29.53) = 76395.7 km - L0= 76395.7 km but L0 = 88000 km Cos θ0 - θ0= 29.757 degrees - θ1= θ0- 1.7 = 29.757 - 1.7 = 28.057 degrees - L1 = 88000 km (Cos 28.057 degrees) = 77657.8 km - During 29.53 days = L1 x29.53 =77657.8 km x 29.53 = 2.293 mkm - 2.293 mkm = 2π x 364979.7 km - i.e. The moon on next day (19/10/2020) should be on 364979.7 km The registered value on 19/10/2020 (362851 km) The difference = 362851 km – 364979.7 km = - (2129 km)
- 38. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 38 (13) 19 –October -2020 October 19 362851 km October 20 368058 km (The Next Day) On 19/10/2020 the moon Earth distance was 362851 km So we need to know where the moon will be on the next day (20/10/2020)? Let's try to do that…. - The radius = 362851 km so C (orbital circumference) = 362851 x 2π=2.279 mkm - The moon moves it during 29.53 days ( L0=2.279 mkm/29.53) = 77205 km - L0= 77205 km but L0 = 88000 km Cos θ0 - θ0= 28.67 degrees - θ1= θ0- 1.7 = 28.67 - 1.7 = 26.978 degrees - L1 = 88000 km (Cos 26.978 degrees) = 78423.7 km - During 29.53 days = L1 x29.53 =78423.7 km x 29.53 = 2.3158 mkm - 2.3158 mkm = 2π x 368579.3 km - i.e. The moon on next day (20/10/2020) should be on 368579.3 km The registered value on 20/10/2020 (368058 km) The difference = 368058 km – 368579.3 km = - (522 km)
- 39. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 39 (14) 20 –October -2020 October 20 368058 km October 21 374101 km (The Next Day) On 20/10/2020 the moon Earth distance was 368058 km So we need to know where the moon will be on the next day (21/10/2020)? Let's try to do that…. - The radius = 368058 km so C (orbital circumference) = 368058 x 2π=2.31 mkm - The moon moves it during 29.53 days ( L0=2.31 mkm/29.53) = 78313 km - L0= 78313 km but L0 = 88000 km Cos θ0 - θ0= 27.137 degrees - θ1= θ0- 1.7 =27.137- 1.7 = 25.437 degrees - L1 = 88000 km (Cos 25.437 degrees) =79470 km - During 29.53 days = L1 x29.53 =79470 km x 29.53 = 2.346 mkm - 2.346 mkm = 2π x 373492.4 km - i.e. The moon on next day (21/10/2020) should be on 373492.4 km The registered value on 21/10/2020 (374101 km) The difference = 374101 km – 373492.4 km = 609 km
- 40. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 40 (15) 21 –October -2020 October 21 374101 km October 22 380412 km (The Next Day) On 21/10/2020 the moon Earth distance was 374101 km So we need to know where the moon will be on the next day (22/10/2020)? Let's try to do that…. - The radius = 374101 km so C (orbital circumference) = 374101 x 2π=2.35 mkm - The moon moves it during 29.53 days ( L0=2.35 mkm/29.53) = 79598.6 km - L0= 79598.6 km but L0 = 88000 km Cos θ0 - θ0= 25.24 degrees - θ1= θ0- 1.7 =25.24- 1.7 = 23.54 degrees - L1 = 88000 km (Cos 23.54 degrees) =80676.7 km - During 29.53 days = L1 x29.53 =80676.7 km x 29.53 = 2.382 mkm - 2.382 mkm = 2π x 379168.3 km - i.e. The moon on next day (22/10/2020) should be on 379168.3 km The registered value on 22/10/2020 (380412 km) The difference = 380412 km – 379168.3 km = 1244 km
- 41. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 41 (16) 22 –October -2020 October 22 380412 km October 23 386497 km (The Next Day) On 22/10/2020 the moon Earth distance was 380412 km So we need to know where the moon will be on the next day (23/10/2020)? Let's try to do that…. - The radius = 380412 km so C (orbital circumference) = 380412 x 2π=2.39 mkm - The moon moves it during 29.53 days ( L0=2.39 mkm/29.53) = 80941.4 km - L0= 80941.4 km but L0 = 88000 km Cos θ0 - θ0= 23.1 degrees - θ1= θ0- 1.7 = 23.1 - 1.7 = 21.404 degrees - L1 = 88000 km (Cos 21.404 degrees) =81930 km - During 29.53 days = L1 x29.53 =81930 km x 29.53 = 2.419 mkm - 2.419 mkm = 2π x 385059.3 km - i.e. The moon on next day (23/10/2020) should be on 385059.3 km The registered value on 23/10/2020 (386497 km) The difference = 386497 km –385059.3 km = 1438 km
- 42. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 42 (17) 23 –October -2020 October 23 386497 km October 24 391989 km (The Next Day) On 23/10/2020 the moon Earth distance was 386497 km So we need to know where the moon will be on the next day (24/10/2020)? Let's try to do that…. - The radius = 386497 km so C (orbital circumference) = 386497 x 2π=2.42 mkm - The moon moves it during 29.53 days ( L0=2.42 mkm/29.53) = 82236.1 km - L0= 82236.1 km but L0 = 88000 km Cos θ0 - θ0= 20.852 degrees - θ1= θ0- 1.7 = 20.852 - 1.7 = 19.152 degrees - L1 = 88000 km (Cos 19.152 degrees) =83129.2 km - During 29.53 days = L1 x29.53 =83129.2 km x 29.53 = 2.4548 mkm - 2.4548 mkm = 2π x 390694.3 km - i.e. The moon on next day (24/10/2020) should be on 390694.3 km The registered value on 24/10/2020 (391989 km) The difference = 391989 km –390694.3 km = 1295 km
- 43. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 43 (18) 24 –October -2020 October 24 391989 km October 25 396659 km (The Next Day) On 24/10/2020 the moon Earth distance was 391989 km So we need to know where the moon will be on the next day (25/10/2020)? Let's try to do that…. - The radius = 391989 km so C (orbital circumference) = 391989 x 2π=2.462 mkm - The moon moves it during 29.53 days ( L0=2.462 mkm/29.53) = 83404.6 km - L0= 83404.6 km but L0 = 88000 km Cos θ0 - θ0= 18.597 degrees - θ1= θ0- 1.7 = 18.597 - 1.7 = 16.897 degrees - L1 = 88000 km (Cos 16.897 degrees) =84200 km - During 29.53 days = L1 x29.53 =84200 km x 29.53 = 2.486 mkm - 2.486 mkm = 2π x 395729.5 km - i.e. The moon on next day (25/10/2020) should be on 395729.5 km The registered value on 25/10/2020 (396659 km) The difference = 396659 km –395729.5 km = 930 km
- 44. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 44 (19) 25 –October -2020 October 25 396659 km October 26 400395 km (The Next Day) On 25/10/2020 the moon Earth distance was 396659 km So we need to know where the moon will be on the next day (26/10/2020)? Let's try to do that…. - The radius = 391989 km so C (orbital circumference) = 396659 x 2π=2.49 mkm - The moon moves it during 29.53 days ( L0=2.49 mkm/29.53) = 84398.3 km - L0= 84398.3 km but L0 = 88000 km Cos θ0 - θ0= 16.449 degrees - θ1= θ0- 1.7 = 16.449 - 1.7 = 14.749 degrees - L1 = 88000 km (Cos 14.749 degrees) = 85100.4 km - During 29.53 days = L1 x29.53 = 85100.4 km x 29.53 = 2.513 mkm - 2.513 mkm = 2π x 399958.7 km - i.e. The moon on next day (26/10/2020) should be on 399958.7 km The registered value on 26/10/2020 (400395 km) The difference = 400395 km –399958.7 km =437 km
- 45. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 45 (20) 26 –October -2020 October 26 400395 km October 27 403181 km (The Next Day) On 26/10/2020 the moon Earth distance was 400395 km So we need to know where the moon will be on the next day (27/10/2020)? Let's try to do that…. - The radius = 400395 km so C (orbital circumference) = 400395 x 2π=2.515 mkm - The moon moves it during 29.53 days ( L0=2.515 mkm/29.53) = 85193.22 km - L0= 85193.22 km but L0 = 88000 km Cos θ0 - θ0= 14.5 degrees - θ1= θ0- 1.7 = 14.5 - 1.7 = 12.809 degrees - L1 = 88000 km (Cos 12.809 degrees) = 85809.8 km - During 29.53 days = L1 x29.53 = 85809.8 km x 29.53 = 2.533 mkm - 2.533 mkm = 2π x 403299 km - i.e. The moon on next day (27/10/2020) should be on 403299 km The registered value on 27/10/2020 (403181 km) The difference = 403181 km – 403299 km =112 km
- 46. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 46 (21) 27 –October -2020 October 27 403181 km October 28 405059 km (The Next Day) On 27/10/2020 the moon Earth distance was 403181 km So we need to know where the moon will be on the next day (28/10/2020)? Let's try to do that…. - The radius = 403181 km so C (orbital circumference) = 403181 x 2π=2.533 mkm - The moon moves it during 29.53 days ( L0=2.533 mkm/29.53) = 85786 km - L0= 85786 km but L0 = 88000 km Cos θ0 - θ0= 12.879 degrees - θ1= θ0- 1.7 = 12.879 - 1.7 = 11.179 degrees - L1 = 88000 km (Cos 11.179 degrees) = 86330 km - During 29.53 days = L1 x29.53 = 86330 km x 29.53 = 2.549 mkm - 2.549 mkm = 2π x 405738.5 km - i.e. The moon on next day (28/10/2020) should be on 405738.5 km The registered value on 28/10/2020 (405059 km) The difference = 405059 km – 405738.5 km = - (680) km
- 47. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 47 (22) 28 –October -2020 October 28 405059 km October 29 406104 km (The Next Day) On 28/10/2020 the moon Earth distance was 405059 km So we need to know where the moon will be on the next day (29/10/2020)? Let's try to do that…. - The radius = 405059 km so C (orbital circumference) = 405059 x 2π=2.54 mkm - The moon moves it during 29.53 days ( L0=2.54 mkm/29.53) = 86185.6 km - L0= 86185.6 km but L0 = 88000 km Cos θ0 - θ0= 11.655 degrees - θ1= θ0- 1.7 = 11.655 - 1.7 = 9.955 degrees - L1 = 88000 km (Cos 9.955 degrees) = 86675 km - During 29.53 days = L1 x29.53 = 86675 km x 29.53 = 2.559 mkm - 2.559 mkm = 2π x 407359.4 km - i.e. The moon on next day (29/10/2020) should be on 407359.4 km The registered value on 29/10/2020 (406104 km) The difference = 406104 km – 407359.4 km = - (1256) km
- 48. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 48 2-4 The Test Results Discussion And Analysis Let's take a look on the different distances between the equation results and the registered data in following Day Registered Data Results (1.7) Difference 5-10-2020 405,690 km --- --- 6-10-2020 404,171 km 403125.3 km 1046 km 7-10-2020 401,649 km 401390 km 259 km 8-10-2020 398,073 km 398545.6 Km - 473 km 9-10-2020 393,464 km 394568.8 km -1105 km 10-10-2020 387,944 km 389510 km -1567 km 11-10-2020 381,763 km 383520 km -1758 km 12-10-2020 375,302 km 376875.3km -1574 km 13-10-2020 369,063 km 369981km -919 km 14-10-2020 363,617 km 363363.4km 254 km 15-10-2020 359,530 km 357612 km 1918 km 16-10-2020 357,269 km 353307 km 3962 km 17-10-2020 357,105 km ---- -- 18-10-2020 359,048 km --- -- 19-10-2020 362,851 km 364979.7 km - 2129 km 20-10-2020 368,058 km 368579.3 km -522 km 21-10-2020 374,101 km 373492.4 km 609 km 22-10-2020 380,412 km 379168.3 Km 1244 Km 23-10-2020 386,497 km 385059.3Km 1438 km 24-10-2020 391,989 km 390694.3 km 1295 km 25-10-2020 396,659 km 395729.5 km 930 km 26-10-2020 400,395 km 399958.7 km 437 km 27-10-2020 403,181 km 403299 km 112 km 28-10-2020 405,059 km 405738.5 km -680 km 29-10-2020 406,104 km 407359.4 km -1256 km [
- 49. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 49 The Test Results Analysis: - The Total Results Are 22 Values (1st Category) o 15 values, defines the moon position in range 1300 km (Error 3%) (2nd Category) o 5 values, defines the moon position in range 1300-2000 km (Error 4.6 %) (3rd Category) o 2 values, defines the moon position in range 2000-3500 km (Error 8 %) - The Results Explanation - The distance from perigee to apogee =43000 km… o 1st Category of results defines the moon position in error range (1300 km) = error (3%), that means, (15 values of 22) defines the moon position with error (3%) only (Small Error Range) o 2nd Category of results defines the moon position in error range from (1300 km to 2000 km) = error (4.5%), that means (5 values of 22) defines the moon position with error (4.5%) (Average Error Range) o 3rd Category of results defines the moon position in error range from (2000 km to 3500 km) = error (8%), that means (2 values of 22) defines the moon position with error (8%) (Great Error Range) - The Equation Accuracy o The previous explanation shows that, the equation has a good range of accuracy and its error is in the acceptable error range The Conclusion The Equation Is correct and trustee And It's a useful tool to define the moon position daily
- 50. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 50 Appendix No. 1 (The Moon Orbital Motion Equation Concept) - The moon moves daily (88000 km) on the right triangle hypotenuse (AC), but the moon creates an angle (θ) between its motion direction and its orbital horizontal level, by that the real displacement will be (L= 88000 km cos (θ)) through the moon orbit, and by that, spite the moon moves 88000 km and the orbital horizontal distance be less than (88000 km) and this is the objective for which the moon uses Pythagoras triangle – - As an example, if (θ) =28.63 degrees So the real displacement (L) = 77237 km, So, if the moon real displacement daily be equal this value during 29.53 days the moon will move a distance = 2.28 million km and this will be the moon orbital circumference, BUT for what radius? 2.28 mkm = 2π x (0.363 mkm) - The Moon Orbital Perigee Radius =0.363 mkm - That means, the moon by a real displacement =77237 km can move around Earth through the perigee orbit (radius =0.363 mkm), this is the useful result the moon performs by using Pythagoras triangle, - Now let's suppose the moon doesn't use Pythagoras triangle, what would happen? - The moon daily displacement = 88000 km, during 29.53 days the moon moves a distance = 2.598 mkm BUT for what radius? 2.598 mkm = 2π x (0.413 mkm) - The Moon Orbital Apogee Radius =0.406 mkm - So the moon will move along month revolving round Earth through its apogee orbit (or even far from apogee orbit) because the total distance can't be passed through any more near orbit around Earth… - The data shows how Pythagoras triangle is so useful for the moon orbital motion.
- 51. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 51 The Angle θ - The angle (θ) needs to pay some attention for its specific effect…let's summarize the idea in following o The angle (θ) changes the real displacement (L = 88000 cos (θ)), through the moon orbit.. o We know that, when the real displacement (L) be shorter the moon can move through near orbits to Earth and that means the moon will be near or at Perigee radius (0.363 mkm) o When the real displacement (L) be greater the moon has to move through orbits far from Earth and by that the moon will be near or at to apogee orbit o That means, the angle (θ) does change the real displacement (L) and also change the distance between the moon to perigee or to apogee, shortly, the angle defines the moon position (as a ship) between 2 river banks…. - Let's analyze the angle (θ) in some deep o We know that (363000)2 + (86000)2 = (373000)2 o In Pythagoras triangle with the previous dimensions, what's the angle (θ) value? (θ) = 13.33 degrees o Also (396800)2 + (86000)2 = (406000)2 the angle (θ) = 12.229 degrees o I have used (363000 km and 406000 km) because they are the perigee and apogee radiuses between which the moon moves. o The difference between angles = 1.1 degrees i.e., The angle (1.1 deg.) controls the moon motion from perigee to apogee.
- 52. IN THE ALMIGHTY GOD NAME Through the Mother of God mediation I do this research Gerges Francis Tawadrous/ 2nd Course student – physics Faculty – People's Friendship University – Moscow –Russia.. mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292 52 References The Moon Motion Trajectory Analysis (II) https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_ The Moon Motion Basic Equation (III) (Test No.2) https://www.academia.edu/s/e493aec33a or https://www.slideshare.net/Gergesfrancis/the-moon-motion-basic-equation-iii-test-no2 Light Motion Features Are Discovered in Planet Motion https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion or https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion Can Different Rates Of Time Be Found In The Solar System Motion?(II) https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_ Dr. Budochkina, Svetlana Aleksandrovna Associate professor - Candidate of physico-mathematical sciences (2005) http://www.mathnet.ru/eng/person22119 List of publications on Google Scholar List of publications on ZentralBlatt https://mathscinet.ams.org/mathscinet/MRAuthorID/757317 http://elibrary.ru/author_items.asp?spin=6087-3245 http://orcid.org/0000-0003-3447-0425 http://www.researcherid.com/rid/G-7453-2014 http://www.scopus.com/authid/detail.url?authorId=6507007003 https://www.researchgate.net/profile/Svetlana_Budochkina Full list of publications: http://web-local.rudn.ru/web- local/prep/rj/index.php?id=2944&p=15209 Mr.Gerges Francis Tawdrous +201022532292 Physics Department- Physics & Mathematics Faculty Gerges Francis Tawdrous +201022532292 Curriculum Vitae http://vixra.org/abs/1902.0044 E-mail mrwaheid@gmail.com Linkedln https://eg.linkedin.com/in/gerges-francis-86a351a1 Facebook https://www.facebook.com Researcherid https://publons.com/researcher/3510834/gerges-tawadrous/ ORCID https://orcid.org/0000-0002-1041-7147 Quora https://www.quora.com/profile/Gerges-F-Tawdrous Google https://scholar.google.com/citations?user=2Y4ZdTUAAAAJ&hl=en Academia https://rudn.academia.edu/GergesTawadrous List of publications http://vixra.org/author/gerges_francis_tawdrous