Titration experiment report
- 1. Titration Experiment Report<br />Rolla Tyas Amalia- Grade 10<br />Aim:<br />To find how many NaOH needed for titrating 10 ml of vinegar
- 2. To find concentration of the vinegar <br />Materials:<br />Vinegar6. 2 beakers
- 3. Conical flask7. Phenophtalyn
- 4. Measuring pipette8. Dropper
- 5. 2 grm of NaOH (0,1 M)9. 50 ml burette
- 6. Retord stand 10. 2 volumetric flasks (500 ml)Procedure:<br />Fill a beaker with 2 grm of NaOH granule
- 7. Add water to the beaker
- 8. Stir the water until the NaOH granule dissolved
- 9. Put the dissolved NaOH to a 500 ml volumetric flask (1st volumetric flask)
- 10. Set the retord stand, conical flask, and burette like the picture below
- 11. Fill another 500 ml volumetric flask (2nd volumetric flask) by water and 10 ml of vinegar, then mix them (to make concentration of the vinegar lesser)
- 12. Pour the conical flask by 10 ml of vinegar from the 2nd volumetric flask, by measuring pipette
- 13. Add 3 small drop of phenophtalyn to the conical flask
- 14. Fill the 50 ml burette with 50 ml of NaOH from the 1st volumetric flask
- 15. Titrate the NaOH in the burette to 10 ml of vinegar in the conical flask
- 16. Observe until the solution in the conical flask change color into light purple (not dark purple)
- 17. Measure how many ml of NaOH take to make the solution change into purple color
- 18. Repeat step 7 until 12 for second and third timesData/Experiment result:<br />Titrant: NaOH<br />Concentration: 0,1 M<br />Volume:<br />1st Experiment result: 49, 1 ml<br />2nd Experiment result: 49,3 ml<br />3rd Experiment result: 49, 5 ml<br />Average volume: 49,1 ml + 49,3 ml +49,5 ml<br /> _______________________________ = 49,3 ml<br />3<br />Analyte: Vinegar<br />Volume: 10 ml<br />Concentration: V1 x M1 = V2 x M2<br />49,3 ml x 0,1 M = 10 ml x M2<br /> 4,93 : 10 = M2<br />0,493 =M2<br />0,5 M = M2<br />Analysis: <br />It takes 49,3 ml of NaOH in average, for titrating 10 ml of vinegar, and the concentration of the vinegar is 0,5 M. <br />