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Amplitude, Period, and
Phase Shift
2
Objectives
• I can determine amplitude,
period, and phase shifts of trig
functions
• I can write trig equations given
specific period, phase shift, and
amplitude.
3
Section 4.5: Figure 4.49, Key
Points in the Sine and Cosine
Curves
4
Radian versus Degree
• We will use the following to graph or write
equations:
– “x” represents radians
– “” represents degrees
– Example: sin x versus sin 
5
sin ( )
a b x ps d
 
Amplitude
Period:
2π/b Phase Shift:
Left (+)
Right (-)
Vertical Shift
Up (+)
Down (-)
Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 6
The graph of y = A sin B(x – C) is obtained by horizontally shifting the graph
of y = A sin Bx so that the starting point of the cycle is shifted from x = 0 to
x = C. The number C is called the phase shift.
amplitude = | A|
period = 2 /B.
x
y
Amplitude: | A|
Period: 2/B
y = A sin Bx
Starting point: x = C
The Graph of y = AsinB(x - C)
7
The amplitude of y = a sin x (or y = a cos x) is half the distance
between the maximum and minimum values of the function.
amplitude = |a|
If |a| > 1, the amplitude stretches the graph vertically.
If 0 < |a| > 1, the amplitude shrinks the graph vertically.
If a < 0, the graph is reflected in the x-axis.
2
3
2

4
y
x
4


2

y = –4 sin x
reflection of y = 4 sin x y = 4 sin x
y = 2 sin x
2
1
y = sin x
y = sin x
8
y
x

 
2

sin x
y 

period: 2
2
sin 

y

period:
The period of a function is the x interval needed for the
function to complete one cycle.
For b  0, the period of y = a sin bx is .
b

2
For b  0, the period of y = a cos bx is also .
b

2
If 0 < b < 1, the graph of the function is stretched horizontally.
If b > 1, the graph of the function is shrunk horizontally.
y
x

 
2
 
3 
4
cos x
y 

period: 2
2
1
cos x
y 

period: 4
9
y
x

2

y = cos (–x)
Use basic trigonometric identities to graph y = f(–x)
Example 1: Sketch the graph of y = sin(–x).
Use the identity
sin(–x) = – sin x
The graph of y = sin(–x) is the graph of y = sin x reflected in
the x-axis.
Example 2: Sketch the graph of y = cos(–x).
Use the identity
cos(–x) = cos x
The graph of y = cos (–x) is identical to the graph of y = cos x.
y
x

2

y = sin x
y = sin(–x)
y = cos (–x)
10
Example
Determine the amplitude, period, and phase shift of
y = 2sin (3x - )
Solution:
First factor out the 3
y = 2 sin 3(x - /3)
Amplitude = |A| = 2
period = 2/B = 2/3
phase shift = C/B = /3 right
11
Find Amplitude, Period, Phase Shift
• Amplitude (the # in front of the trig. Function
• Period (360 or 2 divided by B, the #after the trig function
but before the angle)
• Phase shift (the horizontal shift after the angle and inside
the parenthesis)
• y = 4sin  y = 2cos1/2  y = sin (4x - )
Amplitude:
Phase shift:
Period:
4 2 1
NA NA )
(
4
Right


360 
720
2

12
y
1
1

2

3

2
x
 
3

2

 
4
Example: Sketch the graph of y = 3 cos x on the interval [–, 4].
Partition the interval [0, 2] into four equal parts. Find the five key
points; graph one cycle; then repeat the cycle over the interval.
max
x-int
min
x-int
max
3
0
-3
0
3
y = 3 cos x
2

0
x
2

2
3
(0, 3)
2
3
( , 0)
( , 0)
2


2
( , 3)

( , –3)
13
Writing Equations
• Write an equation for a positive sine curve with an amplitude
of 3, period of 90 and Phase shift of 45 left.
• Amplitude goes in front of the trig. function, write the eq.so
far:
• y = 3sin 
• period is 90. use P =
•
• rewrite the eq.
• y = 3 sin4
• 45 degrees left means +45
• Answer: y = 3sin4( + 45)
4
90
360
,
90
360


 B
so
B
14
Writing Equations
• Write an equation for a positive cosine curve with an
amplitude of 1/2, period of and Phase shift of right .
• Amplitude goes in front of the trig. function, write the eq.so
far:
• y = 1/2cos x
• period is /4. use P =
•
• rewrite the eq.
• y = 1/2cos 8x
• right  is negative, put this phase shift inside the parenthesis
w/ opposite sign.
• Answer: y = 1/2cos8(x - )
8
4
1
2
,
4
2








B
so
B
4

15

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trigonometry amplitude and period explanation

  • 2. 2 Objectives • I can determine amplitude, period, and phase shifts of trig functions • I can write trig equations given specific period, phase shift, and amplitude.
  • 3. 3 Section 4.5: Figure 4.49, Key Points in the Sine and Cosine Curves
  • 4. 4 Radian versus Degree • We will use the following to graph or write equations: – “x” represents radians – “” represents degrees – Example: sin x versus sin 
  • 5. 5 sin ( ) a b x ps d   Amplitude Period: 2π/b Phase Shift: Left (+) Right (-) Vertical Shift Up (+) Down (-)
  • 6. Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 6 The graph of y = A sin B(x – C) is obtained by horizontally shifting the graph of y = A sin Bx so that the starting point of the cycle is shifted from x = 0 to x = C. The number C is called the phase shift. amplitude = | A| period = 2 /B. x y Amplitude: | A| Period: 2/B y = A sin Bx Starting point: x = C The Graph of y = AsinB(x - C)
  • 7. 7 The amplitude of y = a sin x (or y = a cos x) is half the distance between the maximum and minimum values of the function. amplitude = |a| If |a| > 1, the amplitude stretches the graph vertically. If 0 < |a| > 1, the amplitude shrinks the graph vertically. If a < 0, the graph is reflected in the x-axis. 2 3 2  4 y x 4   2  y = –4 sin x reflection of y = 4 sin x y = 4 sin x y = 2 sin x 2 1 y = sin x y = sin x
  • 8. 8 y x    2  sin x y   period: 2 2 sin   y  period: The period of a function is the x interval needed for the function to complete one cycle. For b  0, the period of y = a sin bx is . b  2 For b  0, the period of y = a cos bx is also . b  2 If 0 < b < 1, the graph of the function is stretched horizontally. If b > 1, the graph of the function is shrunk horizontally. y x    2   3  4 cos x y   period: 2 2 1 cos x y   period: 4
  • 9. 9 y x  2  y = cos (–x) Use basic trigonometric identities to graph y = f(–x) Example 1: Sketch the graph of y = sin(–x). Use the identity sin(–x) = – sin x The graph of y = sin(–x) is the graph of y = sin x reflected in the x-axis. Example 2: Sketch the graph of y = cos(–x). Use the identity cos(–x) = cos x The graph of y = cos (–x) is identical to the graph of y = cos x. y x  2  y = sin x y = sin(–x) y = cos (–x)
  • 10. 10 Example Determine the amplitude, period, and phase shift of y = 2sin (3x - ) Solution: First factor out the 3 y = 2 sin 3(x - /3) Amplitude = |A| = 2 period = 2/B = 2/3 phase shift = C/B = /3 right
  • 11. 11 Find Amplitude, Period, Phase Shift • Amplitude (the # in front of the trig. Function • Period (360 or 2 divided by B, the #after the trig function but before the angle) • Phase shift (the horizontal shift after the angle and inside the parenthesis) • y = 4sin  y = 2cos1/2  y = sin (4x - ) Amplitude: Phase shift: Period: 4 2 1 NA NA ) ( 4 Right   360  720 2 
  • 12. 12 y 1 1  2  3  2 x   3  2    4 Example: Sketch the graph of y = 3 cos x on the interval [–, 4]. Partition the interval [0, 2] into four equal parts. Find the five key points; graph one cycle; then repeat the cycle over the interval. max x-int min x-int max 3 0 -3 0 3 y = 3 cos x 2  0 x 2  2 3 (0, 3) 2 3 ( , 0) ( , 0) 2   2 ( , 3)  ( , –3)
  • 13. 13 Writing Equations • Write an equation for a positive sine curve with an amplitude of 3, period of 90 and Phase shift of 45 left. • Amplitude goes in front of the trig. function, write the eq.so far: • y = 3sin  • period is 90. use P = • • rewrite the eq. • y = 3 sin4 • 45 degrees left means +45 • Answer: y = 3sin4( + 45) 4 90 360 , 90 360    B so B
  • 14. 14 Writing Equations • Write an equation for a positive cosine curve with an amplitude of 1/2, period of and Phase shift of right . • Amplitude goes in front of the trig. function, write the eq.so far: • y = 1/2cos x • period is /4. use P = • • rewrite the eq. • y = 1/2cos 8x • right  is negative, put this phase shift inside the parenthesis w/ opposite sign. • Answer: y = 1/2cos8(x - ) 8 4 1 2 , 4 2         B so B 4 
  • 15. 15