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3.5 
Equation 
Solving and 
Modeling 
Copyright © 2011 Pearson, Inc.
What you’ll learn about 
 Solving Exponential Equations 
 Solving Logarithmic Equations 
 Orders of Magnitude and Logarithmic Models 
 Newton’s Law of Cooling 
 Logarithmic Re-expression 
… and why 
The Richter scale, pH, and Newton’s Law of Cooling, are 
among the most important uses of logarithmic and 
exponential functions. 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 2
One-to-One Properties 
For any exponential function f (x)  bx , 
g If bu  bv , then u  v. 
For any logarithmic function f (x)  logb x, 
g If logb u  logb v, then u  v. 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 3
Example Solving an Exponential 
Equation Algebraically 
Solve 401/ 2x/2 
 5. 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 4
Example Solving an Exponential 
Equation Algebraically 
Solve 401/ 2x/2 
401 / 2x/2 
 5. 
 5 
1 / 2x/2 
 
1 
8 
divide by 40 
1 
2 
 
  
 
  
x/2 
 
1 
2 
 
  
 
  
3 
1 
8 
 
1 
2 
 
  
 
  
3 
x / 2  3 one-to-one property 
x  6 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 5
Example Solving a Logarithmic 
Equation 
Solve log x3  3. 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 6
Example Solving a Logarithmic 
Equation 
Solve log x3  3. 
log x3  3 
log x3  log103 
x3  103 
x  10 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 7
Example Solving a Logarithmic 
Equation 
Solve log2x 1 lnx  3 ln8  2x 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 8
Example Solving a Logarithmic 
Equation 
Solve log2x 1 lnx  3 ln8  2x 
Solve Graphically 
To use the x-intercept method, we rewrite the equation 
log2x 1 lnx  3 ln8  2x 0 
and graph f x log2x 1 lnx  3 ln8  2x. 
The x-intercept is x  
1 
2 
, 
which is a solution to the equation. 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 9
Example Solving a Logarithmic 
Equation 
Solve log2x 1 lnx  3 ln8  2x 
Confirm Algebraically 
log2x 1 lnx  3 ln8  2x 
log 2x 1   x  3     ln 8  2x   
2x 1x  3 8  2x 
2x2  9x  5  0 
2x 1x  5 0 x  
1 
2 
or x  5 
Notice x  5 is an extraneous solution. So the only solution 
is x  
1 
2 
. 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 10
Orders of Magnitude 
The common logarithm of a positive quantity is its order 
of magnitude. 
Orders of magnitude can be used to compare any like 
quantities: 
 A kilometer is 3 orders of magnitude longer than a 
meter. 
 A dollar is 2 orders of magnitude greater than a penny. 
 New York City with 8 million people is 6 orders of 
magnitude bigger than Earmuff Junction with a 
population of 8. 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 11
Richter Scale 
The Richter scale magnitude R of an earthquake is 
R  log 
a 
T 
 B, where a is the amplitude in 
micrometers (m) of the vertical ground motion at 
the receiving station, T is the period of the associated 
seismic wave in seconds, and B accounts for the 
weakening of the seismic wave with increasing 
distance from the epicenter of the earthquake. 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 12
pH 
In chemistry, the acidity of a water-based solution is 
measured by the concentration of hydrogen ions in the 
solution (in moles per liter). The hydrogen-ion 
concentration is written [H+]. The measure of acidity 
used is pH, the opposite of the common log of the 
hydrogen-ion concentration: 
pH = –log [H+] 
More acidic solutions have higher hydrogen-ion 
concentrations and lower pH values. 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 13
Newton’s Law of Cooling 
An object that has been heated will cool to the temperature 
of the medium in which it is placed. The temperature T of 
the object at time t can be modeled by 
T (t )  Tm  (T0  Tm )e kt 
for an appropriate value of k, where 
Tm  the temperature of the surrounding medium, 
T0  the temperature of the object. 
This model assumes that the surrounding medium maintains 
a constant temperature. 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 14
Example Newton’s Law of Cooling 
A hard-boiled egg at temperature 100ºC is placed in 
15ºC water to cool. Five minutes later the temperature 
of the egg is 55ºC. When will the egg be 25ºC? 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 15
Example Newton’s Law of Cooling 
A hard-boiled egg at temperature 100ºC is placed in 
15ºC water to cool. Five minutes later the temperature 
of the egg is 55ºC. When will the egg be 25ºC? 
Given T0  100, Tm  15, and T (5)  55. 
T (t )  Tm  (T0  Tm )e kt 
55  15  85e5k 
40  85e5k 
40 
85 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 16 
 
  
 
  
 e5k 
ln 
40 
85 
 
 
 
   5k 
k  0.1507... 
Now find t when T (t )  25. 
25  15  85e0.1507t 
10  85e0.1507t 
ln 
10 
85 
 
  
 
  
 0.1507t 
t  14.2min.
Regression Models Related by 
Logarithmic Re-Expression 
 Linear regression: y = ax + b 
 Natural logarithmic regression: y = a + blnx 
 Exponential regression: y = a·bx 
 Power regression: y = a·xb 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 17
Three Types of Logarithmic 
Re-Expression 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 18
Three Types of Logarithmic 
Re-Expression (cont’d) 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 19
Three Types of Logarithmic 
Re-Expression (cont’d) 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 20
Quick Review 
Prove that each function in the given pair is the inverse 
of the other. 
1. f (x)  e3x and g(x)  ln x1/3   
2. f (x)  log x2 and g(x)  10x/2 
Write the number in scientific notation. 
3. 123,400,000 
Write the number in decimal form. 
4. 5.67 108 
5. 8.9110-4 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 21
Quick Review Solutions 
Prove that each function in the given pair is the inverse 
of the other. 
1. f (x)  e3x and g(x)  ln x1/3   f (g(x))  e 
3ln x1/3   
 elnx  x 
2. f (x)  log x2 and g(x)  10x/2 f (g(x))  log 10x/2  2 
 log10x  x 
Write the number in scientific notation. 
3. 123,400,000 1.234 108 
Write the number in decimal form. 
4. 5.67 108 567,000,000 
5. 8.9110-4 0.000891 
Copyright © 2011 Pearson, Inc. Slide 3.5 - 22

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Unit 3.5

  • 1. 3.5 Equation Solving and Modeling Copyright © 2011 Pearson, Inc.
  • 2. What you’ll learn about  Solving Exponential Equations  Solving Logarithmic Equations  Orders of Magnitude and Logarithmic Models  Newton’s Law of Cooling  Logarithmic Re-expression … and why The Richter scale, pH, and Newton’s Law of Cooling, are among the most important uses of logarithmic and exponential functions. Copyright © 2011 Pearson, Inc. Slide 3.5 - 2
  • 3. One-to-One Properties For any exponential function f (x)  bx , g If bu  bv , then u  v. For any logarithmic function f (x)  logb x, g If logb u  logb v, then u  v. Copyright © 2011 Pearson, Inc. Slide 3.5 - 3
  • 4. Example Solving an Exponential Equation Algebraically Solve 401/ 2x/2  5. Copyright © 2011 Pearson, Inc. Slide 3.5 - 4
  • 5. Example Solving an Exponential Equation Algebraically Solve 401/ 2x/2 401 / 2x/2  5.  5 1 / 2x/2  1 8 divide by 40 1 2       x/2  1 2       3 1 8  1 2       3 x / 2  3 one-to-one property x  6 Copyright © 2011 Pearson, Inc. Slide 3.5 - 5
  • 6. Example Solving a Logarithmic Equation Solve log x3  3. Copyright © 2011 Pearson, Inc. Slide 3.5 - 6
  • 7. Example Solving a Logarithmic Equation Solve log x3  3. log x3  3 log x3  log103 x3  103 x  10 Copyright © 2011 Pearson, Inc. Slide 3.5 - 7
  • 8. Example Solving a Logarithmic Equation Solve log2x 1 lnx  3 ln8  2x Copyright © 2011 Pearson, Inc. Slide 3.5 - 8
  • 9. Example Solving a Logarithmic Equation Solve log2x 1 lnx  3 ln8  2x Solve Graphically To use the x-intercept method, we rewrite the equation log2x 1 lnx  3 ln8  2x 0 and graph f x log2x 1 lnx  3 ln8  2x. The x-intercept is x  1 2 , which is a solution to the equation. Copyright © 2011 Pearson, Inc. Slide 3.5 - 9
  • 10. Example Solving a Logarithmic Equation Solve log2x 1 lnx  3 ln8  2x Confirm Algebraically log2x 1 lnx  3 ln8  2x log 2x 1   x  3     ln 8  2x   2x 1x  3 8  2x 2x2  9x  5  0 2x 1x  5 0 x  1 2 or x  5 Notice x  5 is an extraneous solution. So the only solution is x  1 2 . Copyright © 2011 Pearson, Inc. Slide 3.5 - 10
  • 11. Orders of Magnitude The common logarithm of a positive quantity is its order of magnitude. Orders of magnitude can be used to compare any like quantities:  A kilometer is 3 orders of magnitude longer than a meter.  A dollar is 2 orders of magnitude greater than a penny.  New York City with 8 million people is 6 orders of magnitude bigger than Earmuff Junction with a population of 8. Copyright © 2011 Pearson, Inc. Slide 3.5 - 11
  • 12. Richter Scale The Richter scale magnitude R of an earthquake is R  log a T  B, where a is the amplitude in micrometers (m) of the vertical ground motion at the receiving station, T is the period of the associated seismic wave in seconds, and B accounts for the weakening of the seismic wave with increasing distance from the epicenter of the earthquake. Copyright © 2011 Pearson, Inc. Slide 3.5 - 12
  • 13. pH In chemistry, the acidity of a water-based solution is measured by the concentration of hydrogen ions in the solution (in moles per liter). The hydrogen-ion concentration is written [H+]. The measure of acidity used is pH, the opposite of the common log of the hydrogen-ion concentration: pH = –log [H+] More acidic solutions have higher hydrogen-ion concentrations and lower pH values. Copyright © 2011 Pearson, Inc. Slide 3.5 - 13
  • 14. Newton’s Law of Cooling An object that has been heated will cool to the temperature of the medium in which it is placed. The temperature T of the object at time t can be modeled by T (t )  Tm  (T0  Tm )e kt for an appropriate value of k, where Tm  the temperature of the surrounding medium, T0  the temperature of the object. This model assumes that the surrounding medium maintains a constant temperature. Copyright © 2011 Pearson, Inc. Slide 3.5 - 14
  • 15. Example Newton’s Law of Cooling A hard-boiled egg at temperature 100ºC is placed in 15ºC water to cool. Five minutes later the temperature of the egg is 55ºC. When will the egg be 25ºC? Copyright © 2011 Pearson, Inc. Slide 3.5 - 15
  • 16. Example Newton’s Law of Cooling A hard-boiled egg at temperature 100ºC is placed in 15ºC water to cool. Five minutes later the temperature of the egg is 55ºC. When will the egg be 25ºC? Given T0  100, Tm  15, and T (5)  55. T (t )  Tm  (T0  Tm )e kt 55  15  85e5k 40  85e5k 40 85 Copyright © 2011 Pearson, Inc. Slide 3.5 - 16        e5k ln 40 85       5k k  0.1507... Now find t when T (t )  25. 25  15  85e0.1507t 10  85e0.1507t ln 10 85        0.1507t t  14.2min.
  • 17. Regression Models Related by Logarithmic Re-Expression  Linear regression: y = ax + b  Natural logarithmic regression: y = a + blnx  Exponential regression: y = a·bx  Power regression: y = a·xb Copyright © 2011 Pearson, Inc. Slide 3.5 - 17
  • 18. Three Types of Logarithmic Re-Expression Copyright © 2011 Pearson, Inc. Slide 3.5 - 18
  • 19. Three Types of Logarithmic Re-Expression (cont’d) Copyright © 2011 Pearson, Inc. Slide 3.5 - 19
  • 20. Three Types of Logarithmic Re-Expression (cont’d) Copyright © 2011 Pearson, Inc. Slide 3.5 - 20
  • 21. Quick Review Prove that each function in the given pair is the inverse of the other. 1. f (x)  e3x and g(x)  ln x1/3   2. f (x)  log x2 and g(x)  10x/2 Write the number in scientific notation. 3. 123,400,000 Write the number in decimal form. 4. 5.67 108 5. 8.9110-4 Copyright © 2011 Pearson, Inc. Slide 3.5 - 21
  • 22. Quick Review Solutions Prove that each function in the given pair is the inverse of the other. 1. f (x)  e3x and g(x)  ln x1/3   f (g(x))  e 3ln x1/3    elnx  x 2. f (x)  log x2 and g(x)  10x/2 f (g(x))  log 10x/2  2  log10x  x Write the number in scientific notation. 3. 123,400,000 1.234 108 Write the number in decimal form. 4. 5.67 108 567,000,000 5. 8.9110-4 0.000891 Copyright © 2011 Pearson, Inc. Slide 3.5 - 22