LET US C (5th EDITION) CHAPTER 2 ANSWERS

LET US C (5th
EDITION) CHAPTER 3 ANSWERS
[A] What would be the output of the following programs:
(a) main( )
{
int a = 300, b, c ;
if ( a >= 400 )
b = 300 ;
c = 200 ;
printf ( "n%d %d", b, c ) ;
}
Ans) garbage_value 200
(b) main( )
{
int a = 500, b, c ;
if ( a >= 400 )
b = 300 ;
c = 200 ;
printf ( "n%d %d", b, c ) ;
Ans) 300 200
(c) main( )
{
int x = 10, y = 20 ;
if ( x == y ) ;
printf ( "n%d %d", x, y ) ;
}
Ans) nothing is going to print
(d) main( )
{
int x = 3, y = 5 ;
if ( x == 3 )
printf ( "n%d", x ) ;
else ;
printf ( "n%d", y ) ;
}
Ans) 3
(e) main( )
{
int x = 3 ;
float y = 3.0 ;
if ( x == y )
printf ( "nx and y are equal" ) ;
else
printf ( "nx and y are not equal" ) ;
Ans) x and y are equal
(f) main( )
{

LET US C (5th
int x = 3, y, z ;
y = x = 10 ;
z = x < 10 ;
printf ( "nx = %d y = %d z = %d", x, y, z ) ;
}
Ans) x=10 y=10 z=0
(g) main( )
{
int k = 35 ;
printf ( "n%d %d %d", k == 35, k = 50, k > 40 ) ;
}
Ans) 0 50 0
(h) main( )
{
int i = 65 ;
char j = ‘A’ ;
if ( i == j )
printf ( “C is WOW” ) ;
else
printf( "C is a headache" ) ;
}
Ans) C is WOW
(i) main( )
{
int a = 5, b, c ;
b = a = 15 ;
c = a < 15 ;
printf ( "na = %d b = %d c = %d", a, b, c ) ;
}
Ans) a = 15 b = 15 c = 0
(j) main( )
{
int x = 15 ;
printf ( "n%d %d %d", x != 15, x = 20, x < 30 ) ;
}
Ans) 1 20 1
[B] Point out the errors, if any, in the following programs:
(a) main( )
{
float a = 12.25, b = 12.52 ;
if ( a = b )
printf ( "na and b are equal" ) ;
}
Ans) We need to use == instead of = in the if statement

LET US C (5th
(b) main( )
{
int j = 10, k = 12 ;
if ( k >= j )
{
{
k = j ;
j = k ;
}
}
}
Ans) There should be only one pair of curved brackets.
(c) main( )
{
if ( 'X' < 'x' )
printf ( "nascii value of X is smaller than that of x" ) ;
}
Ans) There is no error.
(d) main( )
{
int x = 10 ;
if ( x >= 2 ) then
}
Ans) No then is required.
(e) main( )
{
int x = 10 ;
if x >= 2
}
Ans) The statement after the if should be in braces
(f) main( )
{
int x = 10, y = 15 ;
if ( x % 2 = y % 3 )
printf ( "nCarpathians" ) ;
}
Ans) We need to use == instead of =
(g) main( )
{
int x = 30 , y = 40 ;
if ( x == y )
printf( "x is equal to y" ) ;
Else if ( x > y )
printf( "x is greater than y" ) ;

LET US C (5th
Else if ( x < y )
printf( "x is less than y" ) ;
}
Ans) There is no error.
(h) main( )
{
int x = 10 ;
if ( x >= 2 ) then
}
Ans) No then is required
(i) main( )
{
int a, b ;
scanf ( "%d %d",a, b ) ;
if ( a > b ) ;
printf ( "This is a game" ) ;
else
printf ( "You have to play it" ) ;
}
Ans) There should be no semicolon after the if statement.
[C] Attempt the following:
(a) If cost price and selling price of an item is input through the keyboard, write a program to
determine whether the seller has made profit or incurred loss. Also determine how much profit he
made or loss he incurred.
#include <stdio.h>
int main()
{
int sp,cp;
printf("Enter the cost price: ");
scanf("%d",&cp);
printf("Enter the selling price: ");
scanf("%d",&sp);
int gain = 0;
int loss = 0;
if (cp>sp)
{
loss = cp-sp;
printf("You have incurred loss. The loss is: %d",loss);
}
else if(cp<sp)
{
gain = sp-cp;
printf("You have incurred gain, The gain is: %d",gain);
return 0;
}
}

LET US C (5th
(b) Any integer is input through the keyboard. Write a program to find out whether it is an odd
number or even number
#include <stdio.h>
int main()
{
int number=0;
printf("Enter a number:");
scanf("%d",&number);
if(number%2==0)
{
printf("The number is an even number");
}
else
{
printf("The number is an odd number");
return 0;
}
(c) Any year is input through the keyboard. Write a program to determine whether the year is a leap
year or not.
(Hint: Use the % (modulus) operator)
#include <stdio.h>
int main()
{
int number=0;
printf("Enter a year:");
if(number%4==0)
{
printf("The year is a leap year");
}
else
{
printf("The year is not a leap year");
}
return 0;
}
(d) According to the Gregorian calendar, it was Monday on the date 01/01/1900. If any year is input
through the keyboard write a program to find out what is the day on 1st January of this year.
#include <stdio.h>
int main()
{
int month=1,year,a,day=1;
printf("Enter the year: ");
scanf("%d",&year);
a=(14-month)/12;

LET US C (5th
year=year-a;
month=month+12*a-2;
day=(day+year+(year/4)-(year/100)+(year/400)+((31*month)/12)) % 7;
if (day == 0)
printf("The day is sunday.");
else if (day == 1)
printf("The day is monday.");
else if (day == 2)
printf("The day is tuesday.");
else if (day == 3)
printf("The day is wednesday.");
else if (day == 4)
printf("The day is thursday.");
else if (day == 5)
printf("The day is friday.");
else if (day == 6)
printf("The day is saturday.");
return 0;
}
(e) A five-digit number is entered through the keyboard. Write a program to obtain the reversed
number and to determine whether the original and reversed numbers are equal or not.
#include <stdio.h>
int main()
{
int num,reversed_num,a,b,c,d,e,d1,d2,d3,d4,d5;
printf("Enter any five digit number: ");
scanf("%d",&num);
a = num/10;
d5 = num%10;
b = a/10;
d4 = a%10;
c = b/10;
d3 = b%10;
d = c/10;
d2 = c%10;
e = d/10;
d1 = d%10;
reversed_num = (d5*10000) + (d4*1000) + (d3*100) + (d2*10) + (d1*1);
printf("The sum of the reversed digits of the five-digit number you had entered is:
%d",reversed_num);
return 0;
}
(f) If the ages of Ram, Shyam and Ajay are input through the keyboard, write a program to determine
the youngest of the three.
#include <stdio.h>
int main()
{

LET US C (5th
int shyam_age,ram_age,ajay_age,highestage;
printf("Enter the age of shyam: ");
scanf("%d",&shyam_age);
printf("Enter the age of Ram: ");
scanf("%d",&ram_age);
printf("Enter the age of ajay: ");
scanf("%d",&ajay_age);
if (shyam_age<ajay_age && shyam_age<ram_age)
printf("Shyam is the youngest");
else if(ajay_age<shyam_age && ajay_age<ram_age)
printf("Ajay is the youngest.");
else
printf("Ram is the youngest");
return 0;
}
(g) Write a program to check whether a triangle is valid or not, when the three angles of the triangle
are entered through the keyboard. A triangle is valid if the sum of all the three angles is equal to 180
degrees.
#include <stdio.h>
int main()
{
int ang1,ang2,ang3,ang_sum=180;
printf("Enter the value of angle 1: ");
scanf("%d",&ang1);
printf("Enyter the value of angle 2: ");
scanf("%d",&ang2);
printf("Enyter the value of angle 3: ");
scanf("%d",&ang3);
if (ang_sum == ang1 + ang2 + ang3)
printf("The triangle is valid.");
else
printf("The triangle is not valid.");
return 0;
}
(h) Find the absolute value of a number entered through the keyboard.
#include <stdio.h>
int main()
{
int num,absolute_num;
printf("Enter a number: ");
scanf("%d",&num);
absolute_num = -(num);
if (num >= 0)
printf("The absolute value of the number you had entered is: %d",num);
else
printf("The absolute value of the number you had entered is: %d",absolute_num);
return 0;
}

LET US C (5th
(I) Given the length and breadth of a rectangle, write a program to find whether the area of the
rectangle is greater than its perimeter. For example, the area of the rectangle with length = 5 and
breadth = 4 is greater than its perimeter.
#include <stdio.h>
int main()
{
int length,breadth,perimeter,area;
printf("Enter the length of the rectangle: ");
scanf("%d",&length);
printf("Enter the breadth of the rectangle: ");
scanf("%d",&breadth);
perimeter = 2*(length + breadth);
area = length*breadth;
if(perimeter>area)
printf("The perimeter of the rectangle with dimensions %d and %d is greater than the area of this
rectangle.",length,breadth);
else
printf("The area of the rectangle with dimensions %d and %d is greater than the perimeter of this
rectangle.",length,breadth);
return 0;
}
(j) Given three points (x1, y1), (x2, y2) and (x3, y3), write a program to check if all the three points
fall on one straight line.
#include <stdio.h>
int main()
{
int x1,y1,x2,y2,x3,y3,slope1,slope2;
printf("Enter the coordinates of first point (x1 and y1) : ");
scanf("%d,%d",&x1,&y1);
printf("Enter the coordinates of second point (x2 and y2) :");
scanf("%d,%d",&x2,&y2);
printf("nEnter the coordinates of third point (x3 and y3) : ");
scanf("%d,%d",&x3,&y3);
slope1 = (y2-y1)/(x2-x1);
slope2 = (y3-y2)/(x3-x2);
if (slope1 == slope2)
printf("The given points fall on a straight line.");
else
printf("The given points do not fall on a straight line.");
return 0;
}
(k) Given the coordinates (x, y) of a center of a circle and it’s radius, write a program which will
determine whether a point lies inside the circle, on the circle or outside the circle. (Hint: Use sqrt( )
and pow( ) functions)
#include <stdio.h>
#include <math.h>
int main()
{

LET US C (5th
float x1,y1,x,y,r,a,a1;
printf("Enter the coordinates of the center of the circle(x and y) : ");
scanf("%f,%f",&x,&y);
printf("Enter the radius of the circle: ");
scanf("%f",&r);
printf("Enter the coordinates of a point in the plane of the circle(x and y) : ");
scanf("%f,%f",&x1,&y1);
a = (((x-x1)*(x-x1))+((y-y1)*(y-y1)));
a1 = sqrt(a);
if (a1 < r)
printf("The point lies inside the circle.");
else if (a1 == r)
printf("The point lies on the circle.");
else if (a1 > r)
printf("The point lies outside the circle.");
return 0;
}
(l) Given a point (x, y), write a program to find out if it lies on the x-axis, y-axis or at the origin, viz. (0,
0).
#include <stdio.h>
int main()
{
int x,y;
printf("Enter the coordinates of a point (x,y) : ");
scanf("%d,%d",&x,&y);
if (x == 0 && y != 0 )
printf("The point lies on x axis.");
else if (x != 0 && y == 0)
printf("The point lies on y axis.");
else if (x == 0 && y == 0)
printf("The point lies on origin.");
return 0;
}
Logical Operators
If a = 10, b = 12, c = 0, find the values of the expressions in the following table:
Expression Value
a != 6 && b > 5 1
a == 9 || b < 3 0
! ( a < 10 ) 1
! ( a > 5 && c ) 0
5 && c != 8 || !c 1
[D] What would be the output of the following programs:
(a) main( )

LET US C (5th
{
int i = 4, z = 12 ;
if ( i = 5 || z > 50 )
printf ( "nDean of students affairs" ) ;
else
printf ( "nDosa" ) ;
}
Ans) Dean of student affairs
(b) main( )
{
int i = 4, z = 12 ;
if ( i = 5 && z > 5 )
printf ( "nLet us C" ) ;
else
printf ( "nWish C was free !" ) ;
}
Ans) Let us C
(c) main( )
{
int i = 4, j = -1, k = 0, w, x, y, z ;
w = i || j || k ;
x = i && j && k ;
y = i || j && k ;
z = i && j || k ;
printf ( "nw = %d x = %d y = %d z = %d", w, x, y, z ) ;
}
Ans) w = 1 x = 0 y = 1 z = 1
(d) main( )
{
int i = 4, j = -1, k = 0, y, z ;
y = i + 5 && j + 1 || k + 2 ;
z = i + 5 || j + 1 && k + 2 ;
printf ( "ny = %d z = %d", y, z ) ;
}
Ans) y = 1 z = 1
(e) main( )
{
int i = -3, j = 3 ;
if ( !i + !j * 1 )
printf ( "nMassaro" ) ;
else
printf ( "nBennarivo" ) ;
}
Ans) Bennarivo
(f) main( )
{

LET US C (5th
int a = 40 ;
if ( a > 40 && a < 45 )
printf ( "a is greater than 40 and less than 45" ) ;
else
printf ( "%d", a ) ;
}
Ans) 40
(g) main( )
{
int p = 8, q = 20 ;
if ( p == 5 && q > 5 )
printf ( "nWhy not C" ) ;
else
printf ( "nDefinitely C !" ) ;
}
Ans) Definitely C
(h) main( )
{
int i = -1, j = 1, k ,l ;
k = i && j ;
l = i || j ;
printf ( "%d %d", I, j ) ;
}
Ans) -1 1
(i) main( )
{
int x = 20 , y = 40 , z = 45 ;
if ( x > y && x > z )
printf( "x is big" ) ;
else if ( y > x && y > z )
printf( "y is big" ) ;
else if ( z > x && z > y )
printf( "z is big" ) ;
}
Ans) z is big
(j) main ()
{
int i = -1, j = 1, k ,l ;
k = !i && j ;
l = !i || j ;
printf ( "%d %d", i, j ) ;
}
Ans) -1 1
(k) main( )
{
int j = 4, k ;

LET US C (5th
k = !5 && j ;
printf ( "nk = %d", k ) ;
}
Ans) k = 0
[E] Point out the errors, if any, in the following programs:
(a) /* This program
/* is an example of
/* using Logical operators */
main( )
{
int i = 2, j = 5 ;
if ( i == 2 && j == 5 )
printf ( "nSatisfied at last" ) ;
}
Ans) Incorrect comment: it should be:
/* This program
Is an example of
Using logical operators/*
(b) main( )
{
int code, flag ;
if ( code == 1 & flag == 0 )
printf ( "nThe eagle has landed" ) ;
}
Ans) There is no such logical operator as '&' it should be changed to '&&'
(c) main( )
{
char spy = 'a', password = 'z' ;
if ( spy == 'a' or password == 'z' )
printf ( "nAll the birds are safe in the nest" ) ;
}
Ans) There is no such logical operator as 'or' it should be changed to '||'
(d) main( )
{
int i = 10, j = 20 ;
if ( i = 5 ) && if ( j = 10 )
printf ( "nHave a nice day" ) ;
}
Ans) Incorrect statement : 4th statement
Correct statement : if( i == 5 && j == 10)
(e) main( )
{
int x = 10 , y = 20;
if ( x >= 2 and y <=50 )

LET US C (5th
}
Ans) There is no such logical operator as 'and' it should be changed to '&&'
(f) main( )
{
int a, b ;
if ( a == 1 & b == 0 )
printf ( "nGod is Great" ) ;
}
Ans) There is no such logical operator as '&' it should be changed to '&&'
(g) main( )
{
int x = 2;
if ( x == 2 && x != 0 ) ;
{
printf ( "nHi" ) ;
printf( "nHello" ) ;
}
else
printf( "Bye" ) ;
}
Ans) There is No error
(h) main( )
{
int i = 10, j = 10 ;
if ( i && j == 10)
printf ( "nHave a nice day" ) ;
}
Ans) There is No error
[F] Attempt the following:
(a) Any year is entered through the keyboard, write a program to determine whether the year is leap
or not. Use the logical operators && and ||.
#include <stdio.h>
int main()
{
int number=0;
if(number%4==0)
{
printf("The year is a leap year");
}
else
{
printf("The year is not a leap year");
}

LET US C (5th
return 0;
}
I don't think it is valuable to try to make this program complex. It should be left as simple as we can.
(b)Any character is entered through the keyboard, write a program to determine whether the
character entered is a capital letter, a small case letter, a digit or a special symbol. The following
table shows the range of ASCII values for various characters.
Characters ASCII Values
a-z 65 – 90
A-Z 97 – 122
0-9 48 – 57
Special Symbols 0 - 47, 58 - 64, 91 - 96, 123 - 127
#include <stdio.h>
int main()
{
char c;
printf("Enter any character: ");
scanf("%c",&c);
if ((c >= 65) && c <= 90 )
printf("Your character you had enterd is a capital letter.");
else if ((c >= 97) && c <= 122)
printf("The character you had entered is a small case letter.");
else if ((c >= 48) && c <= 57)
printf("The character you ahd entered is a number.");
else if ((((c >= 0 && c<= 47) || c >= 58 && c <= 64) || c >= 91 && c <= 96) || c >= 123 && c <= 127)
printf("The character you had entered is a special character.");
return 0;
}
(c) An Insurance company follows following rules to calculate premium.
(1) If a person’s health is excellent and the person is between 25 and 35 years of age and lives in a
city and is a male then the premium is Rs. 4 per thousand and his policy amount cannot exceed Rs. 2
lakhs.
(2) If a person satisfies all the above conditions except that the sex is female then the premium is Rs.
3 per thousand and her policy amount cannot exceed Rs. 1 lakh.
(3) If a person’s health is poor and the person is between 25 and 35 years of age and lives in a village
and is a male
then the premium is Rs. 6 per thousand and his policy cannot exceed Rs. 10,000.
(4) In all other cases the person is not insured.
Write a program to output whether the person should be insured or not, his/her premium rate and
maximum amount for which he/she can be insured.
#include <stdio.h>
int main()
{
char place,health,gender;
int age,premium_rate,exceed;
printf("Enter your health. If it is E(Excellent or P(Poor): ");
scanf(" %c",&health);

LET US C (5th
fflush(stdin);
printf("Enter the place where you live. If you live in V(village) or C(city): ");
scanf(" %c",&place);
fflush(stdin);
printf("Enter your gender. If it is M(male) or F(female): ");
scanf(" %c",&gender);
fflush(stdin);
printf("Enter your age: ");
scanf(" %d",&age);
if ((((health == 69) && age >= 25 && age <= 35) && place == 67) && gender == 77 )
{
printf("You are ensured.");
printf("nThe premium is rupees 4 per thousand.");
printf("nThe policy amount cannot exceed rupees 2 lakhs");
}
else if ((((health == 69) && age >= 25 && age <= 35) && place == 67) && gender == 70 )
{
printf("nThe policy amount cannot exceed rupees 1 lakhs.");
}
else if ((((health == 80) && age >= 25 && age <= 35) && place == 86) && gender == 77 )
{
printf("nThe policy amount cannot exceed rupees 10,000");
}
else
printf("You are not ensured.");
return 0;
}
(d) A certain grade of steel is graded according to the following conditions:
(i) Hardness must be greater than 50
(ii) Carbon content must be less than 0.7
(iii) Tensile strength must be greater than 5600
The grades are as follows:
Grade is 10 if all three conditions are met
Grade is 9 if conditions (i) and (ii) are met
Grade is 8 if conditions (ii) and (iii) are met
Grade is 7 if conditions (i) and (iii) are met
Grade is 6 if only one condition is met
Grade is 5 if none of the conditions are met
Write a program, which will require the user to give values of hardness, carbon content and tensile
strength of the steel under consideration and output the grade of the steel.
#include <stdio.h>
int main()
{
float carbon_content;
int tensile_strength,hardness;

LET US C (5th
printf("Enter the hardness of steel: ");
scanf(" %d",&hardness);
printf("Enter the carbon content of steel: ");
scanf(" %f",&carbon_content);
printf("Enter the tensile strength of steel: ");
scanf(" %d",&tensile_strength);
if (((hardness > 50) && carbon_content > 0.7) && tensile_strength > 5600)
printf("The grade of steel is grade 10.");
else if (((hardness > 50) && carbon_content > 0.7) && tensile_strength < 5600)
else if (((hardness < 50) && carbon_content < 0.7) && tensile_strength > 5600)
else if (((hardness > 50) && carbon_content > 0.7) && tensile_strength > 5600)
else if (((hardness > 50) || carbon_content < 0.7) || tensile_strength > 5600)
else
return 0;
}
(e) A library charges a fine for every book returned late. For first 5 days the fine is 50 paise, for 6-10
days fine is one rupee and above 10 days fine is 5 rupees. If you return the book after 30 days your
membership will be cancelled. Write a program to accept the number of days the member is late to
return the book and display the fine or the appropriate message.
#include <stdio.h>
int main()
{
int day;
printf("Enter the number of days youa re late to return the book: ");
scanf(" %d",&day);
if ((day >= 0) && day <= 5)
printf("Your fine is 50 paise.");
else if ((day >= 6) && day <= 10)
printf("Your fine is 1 rupee.");
else if ((day > 10) && day <= 30)
printf("The fine is 5 rupees.");
else if (day > 30)
printf("Your membership is cancelled.");
return 0;
}
(f) If the three sides of a triangle are entered through the keyboard, write a program to check
whether the triangle is valid or not. The triangle is valid if the sum of two sides is greater than the
largest of the three sides.
#include <stdio.h>
int main()
{
int side1,side2,side3;
printf("Enter the length of greatest side: ");

LET US C (5th
scanf(" %d",&side1);
printf("Enter the length of second greatest side: ");
printf("Enter the length of smallest side: ");
if ((side3 + side2 > side1) && side1 - side2 < side3)
printf("The triangle is valid.");
else
printf("The triangle is not valid.");
return 0;
}
(g) If the three sides of a triangle are entered through the keyboard, write a program to check
whether the triangle is isosceles, equilateral, scalene or right angled triangle.
#include <stdio.h>
int main()
{
int side1,side2,side3;
printf("Enter the length of first side: ");
printf("Enter the length of second side: ");
printf("Enter the length of third side: ");
if (side1 == side2 == side3)
printf("The triangle is equilateral.");
else if (((side1 == side2 ) || side2 == side3 ) || side1 == side3 )
printf("The triangle is isosceles.");
else
printf("The triangle is scalene.");
return 0;
}
(h) In a company, worker efficiency is determined on the basis of the time required for a worker to
complete a particular job. If the time taken by the worker is between 2 – 3 hours, then the worker is
said to be highly efficient. If the time required by the worker is between 3 – 4 hours, then the worker
is ordered to improve speed. If the time taken is between 4 – 5 hours, the worker is given training to
improve his speed, and if the time taken by the worker is more than 5 hours, then the worker has to
leave the company. If the time taken by the worker is input through the keyboard, find the efficiency
of the worker.
#include <stdio.h>
int main()
{
int hour;
printf("Enter the number of hours for you to complete a job: ");
scanf(" %d",&hour);
if ((hour >= 1) && hour <= 3)
printf("Your work is highly efficient.");
else if ((hour > 3) && hour <= 4)
printf("You are ordered to improve your speed.");
else if ((hour > 4) && hour <= 5)

LET US C (5th
printf("You are given training to improve your speed.");
else if (hour > 5)
printf("You have to leave the company.");
return 0;
}
(I) A university has the following rules for a student to qualify for a degree with A as the main
subject and B as the subsidiary subject:
(a) He should get 55 percent or more in A and 45 percent or more in B.
(b) If he gets than 55 percent in A he should get 55 percent or more in B. However, he should get at
least 45 percent in A.
(c) If he gets less than 45 percent in B and 65 percent or more in A he is allowed to reappear in an
examination in B to qualify.
(d) In all other cases he is declared to have failed.
Write a program to receive marks in A and B and Output whether the student has passed, failed or is
allowed to reappear in B.
#include <stdio.h>
int main()
{
int mark1,mark2;
printf("Enter the percentage you got in subject A: ");
scanf(" %d",&mark1);
printf("Enter the percentage you got in subject B: ");
scanf(" %d",&mark2);
if ((mark1 > 55) && mark2 > 45)
printf("You have passed.");
else if ((mark1 > 45) && mark2 > 55)
printf("You have passed.");
else if ((mark1 > 65) && mark2 < 45)
printf("You are allowed to reappear for examination of subject B.");
else
printf("You have failed");
return 0;
}
Conditional operators
[G] What would be the output of the following programs:
(a) main( )
{
int i = -4, j, num ;
j = ( num < 0 ? 0 : num * num ) ;
printf ( "n%d", j ) ;
}
Ans) 0
(b) main( )
{
int k, num = 30 ;
k = ( num > 5 ? ( num <= 10 ? 100 : 200 ) : 500 ) ;

LET US C (5th
printf ( "n%d", num ) ;
}
Ans) 30
(c) main( )
{
int j = 4 ;
( !j != 1 ? printf ( "nWelcome") : printf ( "nGood Bye") ) ;
}
Ans) Welcome
[H] Point out the errors, if any, in the following programs:
(a) main( )
{
int tag = 0, code = 1 ;
if ( tag == 0 )
( code > 1 ? printf ( "nHello" ) ? printf ( "nHi" ) ) ;
else
printf ( "nHello Hi !!" ) ;
}
Ans) Incorrect statement : ( code > 1 ? printf ( "nHello" ) ? printf ( "nHi" ) ) ;
Correct statement : (code > 1 ? Printf("nHello") : printf ("nHi")
(b) main( )
{
int ji = 65 ;
printf ( "nji >= 65 ? %d : %c", ji ) ;
}
Ans) 'ji' is a integer not character and there is no other character variable mentioned.
(c) main( )
{
int i = 10, j ;
i >= 5 ? ( j = 10 ) : ( j = 15 ) ;
printf ( "n%d %d", i, j ) ;
}
Ans) No error
(d) main( )
{
int a = 5 , b = 6 ;
( a == b ? printf( "%d",a) ) ;
}
Ans) There is no ':' in the statement which states it wrong.
(e) main( )
{
int n = 9 ;
( n == 9 ? printf( "You are correct" ) ; : printf( "You are wrong" ) ;) ;
}

LET US C (5th
Ans) There is no requirement of ';' in this statement.
(f) main( )
{
int kk = 65 ,ll ;
ll = ( kk == 65 : printf ( "n kk is equal to 65" ) : printf ( "n kk is not equal to 65" ) ) ;
printf( "%d", ll ) ;
}
Ans) '||' cannot be a variable name. A variable name does not contain any special characters apart
from '_'
(g) main( )
{
int x = 10, y = 20 ;
x == 20 && y != 10 ? printf( "True" ) : printf( "False" ) ;
}
Ans) No error
[I] Rewrite the following programs using conditional operators.
(a) main( )
{
int x, min, max ;
scanf ( "n%d %d", &max, &x ) ;
if ( x > max )
max = x ;
else
min = x ;
}
int main( )
{
int x, min, max ;
scanf ( "n%d %d", &max, &x ) ;
(x > max) ? (max = x) : (min = x)
}
(b) main( )
{
int code ;
scanf ( "%d", &code ) ;
if ( code > 1 )
printf ( "nJerusalem" ) ;
else
if ( code < 1 )
printf ( "nEddie" ) ;
else
printf ( "nC Brain" ) ;
}
int main()
{
int code;

LET US C (5th
scanf(" %d",&code);
code > 1 ? printf("nJerusleum") : (code < 1) ? printf("Eddie") : printf("Brain")
}
(c) main( )
{
float sal ;
printf ("Enter the salary" ) ;
scanf ( "%f", &sal ) ;
if ( sal < 40000 && sal > 25000 )
printf ( "Manager" ) ;
else
if ( sal < 25000 && sal > 15000 )
printf ( "Accountant" ) ;
else
printf ( "Clerk" ) ;
}
int main( )
{
float sal ;
printf ("Enter the salary" ) ;
scanf ( "%f", &sal ) ;
sal < 40000 && sal > 25000 ? printf("Manager") : ( sal < 25000 && sal > 15000 ) ?
printf("Accountant") : printf("Clerk")
}
[J] Attempt the following:
(a) Using conditional operators determine:
(1) Whether the character entered through the keyboard is a lower case alphabet or not.
(2) Whether a character entered through the keyboard is a special symbol or not.
1. #include <stdio.h>
int main()
{
char c;
scanf("%c",&c);
printf("The character you had entered is a small case letter.");
((c >= 48) && c <= 57) ? printf("The character you had entered is a number.") : printf("The
number you entered was not a small case letter.)
Return 0;
2.
#include <stdio.h>
int main()
{
char c;
scanf("%c",&c);

LET US C (5th
((((c >= 0 && c<= 47) || c >= 58 && c <= 64) || c >= 91 && c <= 96) || c >= 123 && c <= 127) ?
printf("The character you had entered is a special character.") : printf("The number you had
enetered is not a special symbol.")
return 0;
}
(b) Write a program using conditional operators to determine whether a year entered through the
keyboard is a leap year or not.
#include <stdio.h>
int main()
{
int number=0;
(number%4==0) ? printf("The year is a leap year") : printf("The year is not a leap year");
return 0;
}
I don't think it is valuable to try to make this program complex. It should be left as simple as we can.
(c) Write a program to find the greatest of the three numbers entered through the keyboard using
conditional operators.
#include <stdio.h>
int main()
{
int num1,num2,num3;
printf("Enter the first number: ");
scanf("%d",&num1);
printf("Enter the second number: ");
scanf("%d",&num2);
printf("Enter the third number: ");
scanf("%d",&num3);
(num1>num2 && num1>num3) ? printf("The first number is the greatest") : (num2>num1 &&
num2>num3) ? printf("The second number is the greatest.") : printf("The third number is the
greatest.");
return 0;
}

LET US C (5th EDITION) CHAPTER 2 ANSWERS

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