Suppose a point is randomly selected along a line segment of length .pdf
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This document discusses the probability of a randomly selected point on a line segment of length l resulting in the longer segment being more than twice the length of the shorter segment. The critical point is identified as 1/3l, as segments longer than this point create proportions that satisfy the condition. The final probability calculated is 1/3.
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Suppose a point is randomly selected along a line segment of length .pdf
- 1. Suppose a point is randomly selected along a line segment of length L. What is the probability the longer of the two segments on either side of this point is more than twice as long as the shorter segment? Solution ok..see....the critical point is 1/3L because (1-1/3L) = 2L/3 which is twice the shorter length. so..divide the line by a point at 1/3L or before it. So, (1L/3)/L = 1/3