1. CS in tap water develops different potential from that of SS in s.pdf
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The document discusses various electrochemical properties related to carbon steel (cs) and stainless steel (ss) in different environments, explaining their differing potentials due to their material compositions. It states that cs is more reactive and prone to corrosion in tap water compared to hydrogen, while different conditions in brine affect oxidation-reduction tendencies. The document also addresses measurement discrepancies in standard reduction potentials due to factors like temperature and metal ion concentrations.
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1. CS in tap water develops different potential from that of SS in s.pdf
- 1. 1. CS in tap water develops different potential from that of SS in same environment. Explain why? 2. From the measured value of CS potential in tap water, determine whether it corrodes or not, knowing that E0(Fe/Fe+2) = - 440 mV vs. Standard Hydrogen Electrode (SHE.). 3. CS in tap water develops different potential from that of CS in brine. Explain why? 4. Are the measured values of potential (E0) for Zn / Zn+2 and Cu / Cu+2 under standard conditions same as those given in the text book? If Not, explain why? 5. What happens to E if metal ion concentration decreases. Explain why? Solution SOlution 1) Carbon steel is made up of iron and carbon while stainless steel is made up of chormium and iron . So reduction potential of two alloys are different based on the metals used. 2) The reduction potential of CS is less than that of hydrogen, so it will be more reactive or more prone to oxidation and will corrode. 3) Due to difference in the enviroment the tendency to undergo oxidation or reduction changes. In water we are considering only hydrogen reduction while in brine salts are also included. 4) They are not exactly same , might me due to some erroe in measurements or due to difference in temperature conditions.Since, standard reduction potential depends upon the temperature, pressure and concentration 5) decreaing the concentration of metal ion will decrease the value of potential of cell(E) .