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STD- X
CHAPTER- 1
REAL NUMBERS
PREVIOUS KNOWLEDGE
• Natural numbers : 1,2,3,4,5…………………
• Whole numbers : 0,1,2,3,4,………………..
• Integers : -3,-2,-1,0,1,2,3…………..
• Rational numbers - Numbers of the form where p and q are integers and q ≠
0
• Irrational Numbers -Numbers that cannot be written in the form
• Real numbers - Rational numbers and Irrational numbers together form set of
real numbers
• Decimal expansion of rational numbers are either terminating or non-
terminating recurring
• Decimal expansion of irrational numbers are non-terminating and non recurring
• Co-prime numbers - numbers having no common factor other than one
• Dividend = Divisor X Quotient + ramainder
NEW TERMS USED
• Algorithm - A series of well defined
steps which gives a procedure for
solving a type of problem
• Lemma : A proven statement used for
proving another statement
CONTENT
EUCLID ‘S DIVISION LEMMA
• Given positive integers a and b, there exist unique integers q and
r satisfying
• a = bq+ r where 0 ≤ r < b.
E UCLID’S DIVISION ALGORITHM
•This is based on Euclid’s division lemma. According to this, the
HCF of any two positive integers c and d, with c > d is obtained
as follows:
• Step 1: Apply the division lemma to candd.wecan find
wholenumbers q and r suchthat c = d q + r , 0 ≤ r < d.
• Step 2 : If r = 0, the HCF is d. If r ≠ 0, apply Euclid’s lemma to
d and r.
• Step 3 : Continue the process till the remainder is zero. The
divisor at this stage will be HCF ( c,d).
FUNDAMENTAL THEOREM OF ARITHMETIC
• Every composite number can be
expressed as a product of primes, and
this factorisation is unique, apart from
the order in which the prime factors
occur.
HOW TO FIND HCF AND LCM OF NUMBERS
HCF
• 1)Write the prime factorisation
of the numbers
• 2)List the common prime
factors of the numbers
• 3)Write the smallest power of
each common prime factor
• 4)Find the product of these
LCM
• 1)Write the prime factorisation
of the numbers
• 2)List all the factors involved in
the numbers
• 3)Write the greatest power of
the prime factors
• 4)Find the product of these
If a and b are two positive integers then
HCF(a,b)X LCM(a,b) =a X b
•If a and b are two co- prime positive
integers then
•HCF(a,b) = 1
SHOW THAT √ 2 IS IRRATIONAL.
Let us assume the contrary that√2 is rational.
• Then, √2 = a/b
• where a and b are co-prime integersandbnot zero. ……………………… (1)
• Or √2b = a or 2b² = a² It means 2 divides a²
•and hence 2 divides a. ……………………….(2)
•Let, a= 2c for some integer c.
•then, 2b² = (2c)² = 4c² or b² = 2c² It means 2 divides b²
• and hence 2 divides b. ……………………………(3)
• From statements (2) and (3), it is clear that 2 is a common factor of a and b both.
•But, from statement (1), p and q are co-prime which means that they cannot have any
common
• factor other than 1.
• This indicates that our supposition that √2 is rational, is wrong.
•Hence, √2 is irrational.
CONDITION FOR A RATIONAL NUMBER TO HAVE TERMINATING
OR NON-TERMINATING REPEATING DECIMAL EXPANSION.
• Terminating: A rational number p/q, where p and q are co-
prime integers will have a terminating decimal expansion if the
denominator is of the form 2ⁿ × 5m, where n and m are non-
negative integers.
•Non- Terminating: A rational number p/q, where p and q are
co- prime integers will havea non- terminating repeating decimal
expansion if the denominator is not of the form 2ⁿ × 5m, where n
and m are non- negative integers.
THANK YOU

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1 Real Number introduction for class 10th both CBSE and state syllabus students can go through this

  • 2. PREVIOUS KNOWLEDGE • Natural numbers : 1,2,3,4,5………………… • Whole numbers : 0,1,2,3,4,……………….. • Integers : -3,-2,-1,0,1,2,3………….. • Rational numbers - Numbers of the form where p and q are integers and q ≠ 0 • Irrational Numbers -Numbers that cannot be written in the form • Real numbers - Rational numbers and Irrational numbers together form set of real numbers • Decimal expansion of rational numbers are either terminating or non- terminating recurring • Decimal expansion of irrational numbers are non-terminating and non recurring • Co-prime numbers - numbers having no common factor other than one • Dividend = Divisor X Quotient + ramainder
  • 3. NEW TERMS USED • Algorithm - A series of well defined steps which gives a procedure for solving a type of problem • Lemma : A proven statement used for proving another statement
  • 5. EUCLID ‘S DIVISION LEMMA • Given positive integers a and b, there exist unique integers q and r satisfying • a = bq+ r where 0 ≤ r < b.
  • 6. E UCLID’S DIVISION ALGORITHM •This is based on Euclid’s division lemma. According to this, the HCF of any two positive integers c and d, with c > d is obtained as follows: • Step 1: Apply the division lemma to candd.wecan find wholenumbers q and r suchthat c = d q + r , 0 ≤ r < d. • Step 2 : If r = 0, the HCF is d. If r ≠ 0, apply Euclid’s lemma to d and r. • Step 3 : Continue the process till the remainder is zero. The divisor at this stage will be HCF ( c,d).
  • 7. FUNDAMENTAL THEOREM OF ARITHMETIC • Every composite number can be expressed as a product of primes, and this factorisation is unique, apart from the order in which the prime factors occur.
  • 8. HOW TO FIND HCF AND LCM OF NUMBERS HCF • 1)Write the prime factorisation of the numbers • 2)List the common prime factors of the numbers • 3)Write the smallest power of each common prime factor • 4)Find the product of these LCM • 1)Write the prime factorisation of the numbers • 2)List all the factors involved in the numbers • 3)Write the greatest power of the prime factors • 4)Find the product of these
  • 9. If a and b are two positive integers then HCF(a,b)X LCM(a,b) =a X b •If a and b are two co- prime positive integers then •HCF(a,b) = 1
  • 10. SHOW THAT √ 2 IS IRRATIONAL. Let us assume the contrary that√2 is rational. • Then, √2 = a/b • where a and b are co-prime integersandbnot zero. ……………………… (1) • Or √2b = a or 2b² = a² It means 2 divides a² •and hence 2 divides a. ……………………….(2) •Let, a= 2c for some integer c. •then, 2b² = (2c)² = 4c² or b² = 2c² It means 2 divides b² • and hence 2 divides b. ……………………………(3) • From statements (2) and (3), it is clear that 2 is a common factor of a and b both. •But, from statement (1), p and q are co-prime which means that they cannot have any common • factor other than 1. • This indicates that our supposition that √2 is rational, is wrong. •Hence, √2 is irrational.
  • 11. CONDITION FOR A RATIONAL NUMBER TO HAVE TERMINATING OR NON-TERMINATING REPEATING DECIMAL EXPANSION. • Terminating: A rational number p/q, where p and q are co- prime integers will have a terminating decimal expansion if the denominator is of the form 2ⁿ × 5m, where n and m are non- negative integers. •Non- Terminating: A rational number p/q, where p and q are co- prime integers will havea non- terminating repeating decimal expansion if the denominator is not of the form 2ⁿ × 5m, where n and m are non- negative integers.