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1

 Subtraction of a number from another can be
accomplished by adding the complement of the
subtrahend to the minuend.
Introduction
2

1’s Complement Subtraction
 Subtraction of binary numbers using the 1’s
complement method allows subtraction only by
addition.
3

 The 1’s complement of a binary number can be
obtained by changing all 1s to 0s and all 0s and 1s.
Cont.,
4

 To subtract a smaller number from a larger number,
the 1’s complement method is as follows
1’s complement method
1. Determine the 1’s complement of the smaller number.
2. Add this to the larger number
3. Remove the carry and add it to the result. This carry is
called end-around-carry
5

Subtract (1010)2 from (1111)2
Example of 1’s complement
Direct Subtraction
1 1 1 1
1 0 1 0
1
0
1
0
1’s complement method
1 1 1 1
1’s complement 0 1 0 1
Carry 0
0
1
1 0
Add Carry 1
1
0
1
0
6

 Subtraction of a large number a smaller one by the 1’s
complement method involves the following steps
Subtraction Steps
1. Determine the 1’s complement of a large number
2. Add this to the smaller number
3. The answer is the 1’s complement of the result and is
opposite in sign. There is no carry.
7

 The 2’s complement of a binary number can be
obtained by adding 1 to its 1’s complement.
2’s Complement Subtraction
8

 Subtraction of a smaller number from a larger one by
the 2’s complement method involves the following
steps
Steps
1. Determine the 2’s complement of the smaller number
2. Add this to the larger number
3. Omit the carry ( there is always a carry in this case )
9

Example of 2’s complement
Subtract (1010)2 from (1111)2
Direct Subtraction
1 1 1 1
1 0 1 0
1
0
1
0
2’s complement method
1 1 1 1
2’s complement 0 1 1 0
Carry 1
0
1
1 0
10

 The carry is discarded. Thus answer is (0101)2
 The 2’s complement method for subtraction of a large
number from a smaller one is as follows.
Subtraction Steps
1. Determine the 2’s complement of the larger number
2. Add the 2’s complement to the smaller number
3. There is no carry . The result is in 2’s complement form is
negative
4. To get an answer in true form, take the 2’s complement
and change the sign. 11

1’s Complement 2’s Complement
It can be easily obtained using
an Inverter
It has to be arrived at by first
obtaining the 1’s complement
and then adding one (1) to it
It requires two operations Only one arithmetic operation
is required
It is often used in logical
manipulations for inversion
operation
It is used only for arithmetic
applications
Comparison between 1’s and
2’s complements
12

….. Thank You ……
The End
13

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1sand2scomplement r004

  • 1. 1
  • 2.   Subtraction of a number from another can be accomplished by adding the complement of the subtrahend to the minuend. Introduction 2
  • 3.  1’s Complement Subtraction  Subtraction of binary numbers using the 1’s complement method allows subtraction only by addition. 3
  • 4.   The 1’s complement of a binary number can be obtained by changing all 1s to 0s and all 0s and 1s. Cont., 4
  • 5.   To subtract a smaller number from a larger number, the 1’s complement method is as follows 1’s complement method 1. Determine the 1’s complement of the smaller number. 2. Add this to the larger number 3. Remove the carry and add it to the result. This carry is called end-around-carry 5
  • 6.  Subtract (1010)2 from (1111)2 Example of 1’s complement Direct Subtraction 1 1 1 1 1 0 1 0 1 0 1 0 1’s complement method 1 1 1 1 1’s complement 0 1 0 1 Carry 0 0 1 1 0 Add Carry 1 1 0 1 0 6
  • 7.   Subtraction of a large number a smaller one by the 1’s complement method involves the following steps Subtraction Steps 1. Determine the 1’s complement of a large number 2. Add this to the smaller number 3. The answer is the 1’s complement of the result and is opposite in sign. There is no carry. 7
  • 8.   The 2’s complement of a binary number can be obtained by adding 1 to its 1’s complement. 2’s Complement Subtraction 8
  • 9.   Subtraction of a smaller number from a larger one by the 2’s complement method involves the following steps Steps 1. Determine the 2’s complement of the smaller number 2. Add this to the larger number 3. Omit the carry ( there is always a carry in this case ) 9
  • 10.  Example of 2’s complement Subtract (1010)2 from (1111)2 Direct Subtraction 1 1 1 1 1 0 1 0 1 0 1 0 2’s complement method 1 1 1 1 2’s complement 0 1 1 0 Carry 1 0 1 1 0 10
  • 11.   The carry is discarded. Thus answer is (0101)2  The 2’s complement method for subtraction of a large number from a smaller one is as follows. Subtraction Steps 1. Determine the 2’s complement of the larger number 2. Add the 2’s complement to the smaller number 3. There is no carry . The result is in 2’s complement form is negative 4. To get an answer in true form, take the 2’s complement and change the sign. 11
  • 12.  1’s Complement 2’s Complement It can be easily obtained using an Inverter It has to be arrived at by first obtaining the 1’s complement and then adding one (1) to it It requires two operations Only one arithmetic operation is required It is often used in logical manipulations for inversion operation It is used only for arithmetic applications Comparison between 1’s and 2’s complements 12
  • 13.  ….. Thank You …… The End 13