2- The Reynolds number for a particular microchannel flow is found to.docx
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This document discusses the Reynolds number (Re) for microchannel flow, initially given as Re = 2. When channel dimensions are reduced by a factor of ten and the time for particle traversal remains unchanged, Re decreases to 0.02; however, if the flow velocity remains constant instead, Re changes to 0.2.
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2- The Reynolds number for a particular microchannel flow is found to.docx
- 1. 2. The Reynolds number for a particular microchannel flow is found to be Re = 2. a. If all channel dimensions (length, width, and height) are reduced by a factor of 10, and the time required for a particle to traverse the length of the channel is invariant, what is the value of Re for the smaller channel? b. If the flow velocity is constant for both channels, rather than the time scale, what is the value of Re for the smaller channel? Solution Initial Case Re = rho*V*L/mu = 2 Time req to travel the distance t = L/V------(1) a) When dimensions are reduced by 10 L1, W1, H1 L1 = L/10 W1 = W/10 H1 = H/10 Time required to travel the distance L1 is t = L1/V1-----(2) Given
- 2. 1 = 2 L1/V1 = L/V (Since L1 = L/10) V1 = 0.1*V Re = Rho*V1*L1/mu = (1/00)*rho*V*L/mu = 0.02 b) Now Velocity remains constant Re = rhi*V*L1/mu =0.1*rho*V*L/mu = 0.2