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2-5 Addition Equations
 2-5 Addition Equations




              Warm Up
              Problem of the Day
              Lesson Presentation




Course 1
Course 1
Course 1
2-5 Addition Equations


    Warm Up
    Determine whether each value is a solution.

    1. 86 + x = 102 for x = 16    yes

    2. 18 + x = 26 for x = 4      no
    3. x + 46 = 214 for x = 168 yes
    4. 9 + x = 35 for x = 26      yes



Course 1
2-5 Addition Equations


    Problem of the Day
    After Renee used 40 m of string for her kite
    and gave 5 m to her sister for her wagon,
    she had 8 m of string left. How much string
    did she have to start with?
    53 m




Course 1
2-5 Addition Equations




      Learn to solve whole-number addition
      equations.




Course 1
2-5 Addition Equations

     h + 14    82
                    The equation h + 14 = 82 can be
                    represented as a balanced scale.

           h   ?
                    To find the value of h, you need h
                    by itself on one side of the scale.

     h + 14
               82   To get h by itself, first take away
                    14 from the left side of the scale.
                    Now the scale is unbalanced.

           h   68
                    To rebalance the scale, take away
                    14 from the other side.


Course 1
2-5 Addition Equations

       Taking away 14 from both sides of the scale is
       the same as subtracting 14 from both sides of
       the equation.

                       h + 14 = 82
                          –14 –14
                           h = 68

           Subtraction is the inverse, or opposite, of
           addition. If an equation contains addition,
           solve it by subtracting from both sides to
           “undo” the addition.

Course 1
2-5 Addition Equations

  Additional Example 1A: Solving Addition Equations
  Solve the equation. Check your answer.
   x + 87 = 152

       x + 87 = 152          87 is added to x.
         – 87 – 87          Subtract 87 from both sides
           x = 65           to undo the addition.

      Check x + 87 = 152    Substitute 65 for x in the
                      ?
           65 + 87 = 152    equation.
                   ?
               152 = 152  65 is the solution.



Course 1
2-5 Addition Equations

  Additional Example 1B: Solving Addition Equations
  Solve the equation. Check your answer.
  72 = 18 + y

      72 = 18 + y           18 is added to y.
     –18 –18                Subtract 18 from both sides
      54 =      y           to undo the addition.

      Check 72 = 18 + y     Substitute 54 for y in the
                ?
             72 = 18 + 54   equation.
                ?
             72 = 72       54 is the solution.


Course 1
2-5 Addition Equations

                    Check It Out: Example 1A
  Solve the equation. Check your answer.
   u + 43 = 78
           u + 43 = 78          43 is added to u.
             – 43 – 43          Subtract 43 from both sides
           u      = 35          to undo the addition.

      Check u + 43 = 78         Substitute 35 for u in the
                         ?
               35 + 43 = 78     equation.
                       ?
                    78 = 78    35 is the solution.



Course 1
2-5 Addition Equations

                     Check It Out: Example 1B
  Solve the equation. Check your answer.
   68 = 24 + g
           68 = 24 + g           24 is added to g.
      –24      –24               Subtract 24 from both sides
           44 =          g       to undo the addition.

      Check 68 = 24 + g          Substitute 44 for g in the
                     ?
                  68 = 24 + 44   equation.
                     ?
                  68 = 68       44 is the solution.


Course 1
2-5 Addition Equations
   Additional Example 2: Social Studies Application
  Johnstown, Cooperstown, and Springfield are located
  in that order in a straight line along a highway. It is
  12 miles from Johnstown to Cooperstown and 95
  miles from Johnstown to Springfield. Find the distance
  d between Cooperstown and Springfield.

   distance between        distance between       distance between
   Johnstown and       =   Johnstown and      +   Cooperstown and
   Springfield             Cooperstown            Springfield

           95          =           12         +         d
            95 = 12 + d       12 is added to d.
           –12   –12          Subtract 12 from both sides to undo
                              the addition.
            83 =       d
   It is 83 miles from Cooperstown to Springfield.
Course 1
2-5 Addition Equations
                    Check It Out: Example 2
  Patterson, Jacobsville, and East Valley are located in
  that order in a straight line along a highway. It is 17
  miles from Patterson to Jacobsville and 35 miles from
  Patterson to East Valley. Find the distance d between
  Jacobsville and East Valley.

   distance between         distance between       distance between
   Patterson and East   =   Patterson and      +   Jacobsville and
   Valley                   Jacobsville            East Valley
           35           =           17         +         d
           35 = 17 + d         17 is added to d.

           –17 –17             Subtract 17 from both sides to
                               undo the addition.
           18 =         d
     It is 18 miles from Jacobsville to East Valley.
Course 1
2-5 Addition Equations

                        Lesson Quiz

  Solve each equation.

  1. x + 15 = 72    x = 57

  2. 81 = x + 24    x = 57

  3. x + 22 = 67    x = 45

  4. 93 = x + 14    x = 79

  5. Kaitlin is 2 inches taller than Reba. Reba is 54
     inches tall. How tall is Kaitlin?
     56 inches

Course 1

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Addition equations

  • 1. 2-5 Addition Equations 2-5 Addition Equations Warm Up Problem of the Day Lesson Presentation Course 1 Course 1 Course 1
  • 2. 2-5 Addition Equations Warm Up Determine whether each value is a solution. 1. 86 + x = 102 for x = 16 yes 2. 18 + x = 26 for x = 4 no 3. x + 46 = 214 for x = 168 yes 4. 9 + x = 35 for x = 26 yes Course 1
  • 3. 2-5 Addition Equations Problem of the Day After Renee used 40 m of string for her kite and gave 5 m to her sister for her wagon, she had 8 m of string left. How much string did she have to start with? 53 m Course 1
  • 4. 2-5 Addition Equations Learn to solve whole-number addition equations. Course 1
  • 5. 2-5 Addition Equations h + 14 82 The equation h + 14 = 82 can be represented as a balanced scale. h ? To find the value of h, you need h by itself on one side of the scale. h + 14 82 To get h by itself, first take away 14 from the left side of the scale. Now the scale is unbalanced. h 68 To rebalance the scale, take away 14 from the other side. Course 1
  • 6. 2-5 Addition Equations Taking away 14 from both sides of the scale is the same as subtracting 14 from both sides of the equation. h + 14 = 82 –14 –14 h = 68 Subtraction is the inverse, or opposite, of addition. If an equation contains addition, solve it by subtracting from both sides to “undo” the addition. Course 1
  • 7. 2-5 Addition Equations Additional Example 1A: Solving Addition Equations Solve the equation. Check your answer. x + 87 = 152 x + 87 = 152 87 is added to x. – 87 – 87 Subtract 87 from both sides x = 65 to undo the addition. Check x + 87 = 152 Substitute 65 for x in the ? 65 + 87 = 152 equation. ? 152 = 152  65 is the solution. Course 1
  • 8. 2-5 Addition Equations Additional Example 1B: Solving Addition Equations Solve the equation. Check your answer. 72 = 18 + y 72 = 18 + y 18 is added to y. –18 –18 Subtract 18 from both sides 54 = y to undo the addition. Check 72 = 18 + y Substitute 54 for y in the ? 72 = 18 + 54 equation. ? 72 = 72  54 is the solution. Course 1
  • 9. 2-5 Addition Equations Check It Out: Example 1A Solve the equation. Check your answer. u + 43 = 78 u + 43 = 78 43 is added to u. – 43 – 43 Subtract 43 from both sides u = 35 to undo the addition. Check u + 43 = 78 Substitute 35 for u in the ? 35 + 43 = 78 equation. ? 78 = 78  35 is the solution. Course 1
  • 10. 2-5 Addition Equations Check It Out: Example 1B Solve the equation. Check your answer. 68 = 24 + g 68 = 24 + g 24 is added to g. –24 –24 Subtract 24 from both sides 44 = g to undo the addition. Check 68 = 24 + g Substitute 44 for g in the ? 68 = 24 + 44 equation. ? 68 = 68  44 is the solution. Course 1
  • 11. 2-5 Addition Equations Additional Example 2: Social Studies Application Johnstown, Cooperstown, and Springfield are located in that order in a straight line along a highway. It is 12 miles from Johnstown to Cooperstown and 95 miles from Johnstown to Springfield. Find the distance d between Cooperstown and Springfield. distance between distance between distance between Johnstown and = Johnstown and + Cooperstown and Springfield Cooperstown Springfield 95 = 12 + d 95 = 12 + d 12 is added to d. –12 –12 Subtract 12 from both sides to undo the addition. 83 = d It is 83 miles from Cooperstown to Springfield. Course 1
  • 12. 2-5 Addition Equations Check It Out: Example 2 Patterson, Jacobsville, and East Valley are located in that order in a straight line along a highway. It is 17 miles from Patterson to Jacobsville and 35 miles from Patterson to East Valley. Find the distance d between Jacobsville and East Valley. distance between distance between distance between Patterson and East = Patterson and + Jacobsville and Valley Jacobsville East Valley 35 = 17 + d 35 = 17 + d 17 is added to d. –17 –17 Subtract 17 from both sides to undo the addition. 18 = d It is 18 miles from Jacobsville to East Valley. Course 1
  • 13. 2-5 Addition Equations Lesson Quiz Solve each equation. 1. x + 15 = 72 x = 57 2. 81 = x + 24 x = 57 3. x + 22 = 67 x = 45 4. 93 = x + 14 x = 79 5. Kaitlin is 2 inches taller than Reba. Reba is 54 inches tall. How tall is Kaitlin? 56 inches Course 1