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Rational Number Theorem:If a polynomial function, written in descending order, has integer coefficients, then any rational zero must be of the form ± p/q, where p is a factor of the constant term and q is a factor of the leading coefficient.
List all of the possible rational zeros ofFactors of 4:   1,   2, 4Factors of 3:   1 ,  31122441     3     1     3     1     3                                   Example 6-1a
List all of the possible rational zeros of Factors of 6:   1,   2,  3,  6Factors of 2:   1 ,  2112233661     2     1     2     1     2    1     2                                               Example 6-1c
Find all zeros of the function f(x) = 2x3 + 3x2 – 8x + 3What are the possible rational zeros? Factors of 3:  1,  3Factors of 2:  1,  2Possible zeros :    1  ,  1  ,  3  ,  3                                1      2       1       2
Find all zeros of the function f(x) = 2x3 + 3x2 – 8x + 3Possible zeros :    1  ,  1  ,  3  ,  3                                1      2       1       2      2    3    -8    31          2     5   -3     2    5    -3     02x2 + 5x - 3 = 0(2x - 1)(x + 3) = 0x = 1/2      x = -3Zeros: 1, 1/2, -3

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Alg2 lesson 7-6

  • 1. Rational Number Theorem:If a polynomial function, written in descending order, has integer coefficients, then any rational zero must be of the form ± p/q, where p is a factor of the constant term and q is a factor of the leading coefficient.
  • 2. List all of the possible rational zeros ofFactors of 4: 1, 2, 4Factors of 3: 1 , 31122441 3 1 3 1 3     Example 6-1a
  • 3. List all of the possible rational zeros of Factors of 6: 1, 2, 3, 6Factors of 2: 1 , 2112233661 2 1 2 1 2 1 2       Example 6-1c
  • 4. Find all zeros of the function f(x) = 2x3 + 3x2 – 8x + 3What are the possible rational zeros? Factors of 3: 1, 3Factors of 2: 1, 2Possible zeros :  1 ,  1 ,  3 ,  3 1 2 1 2
  • 5. Find all zeros of the function f(x) = 2x3 + 3x2 – 8x + 3Possible zeros :  1 ,  1 ,  3 ,  3 1 2 1 2 2 3 -8 31 2 5 -3 2 5 -3 02x2 + 5x - 3 = 0(2x - 1)(x + 3) = 0x = 1/2 x = -3Zeros: 1, 1/2, -3